I want to copy a file from one folder to another folder using filestream.How this can be achived.when I try to use file.copy I was getting this file is using by another process, to avoid this I want to use file stream using c#. Can some one provide a sample for copying a file from one folder to another.
for copying i used below code :-
public static void Copy(string inputFilePath, string outputFilePath)
{
int bufferSize = 1024 * 1024;
using (FileStream fileStream = new FileStream(outputFilePath, FileMode.OpenOrCreate, FileAccess.Write,FileShare.ReadWrite))
//using (FileStream fs = File.Open(<file-path>, FileMode.Open, FileAccess.Read, FileShare.Read))
{
FileStream fs = new FileStream(inputFilePath, FileMode.Open, FileAccess.ReadWrite);
fileStream.SetLength(fs.Length);
int bytesRead = -1;
byte[] bytes = new byte[bufferSize];
while ((bytesRead = fs.Read(bytes, 0, bufferSize)) > 0)
{
fileStream.Write(bytes, 0, bytesRead);
}
}
}
You can use Stream.CopyTo method to copy the file like below:
public static string CopyFileStream(string outputDirectory, string inputFilePath)
{
FileInfo inputFile = new FileInfo(inputFilePath);
using (FileStream originalFileStream = inputFile.OpenRead())
{
var fileName = Path.GetFileName(inputFile.FullName);
var outputFileName = Path.Combine(outputDirectory, fileName);
using (FileStream outputFileStream = File.Create(outputFileName))
{
originalFileStream.CopyTo(outputFileStream);
}
return outputFileName;
}
}
string fileName = "Mytest.txt";
string sourcePath = #"C:\MyTestPath";
string targetPath = #"C:\MyTestTarget";
string sourceFile = System.IO.Path.Combine(sourcePath, fileName);
string destFile = System.IO.Path.Combine(targetPath, fileName);
{
System.IO.Directory.CreateDirectory(targetPath);
}
// To copy a file to another location and
// overwrite the destination file if it already exists.
System.IO.File.Copy(sourceFile, destFile, true);
Related
I have a variable which holds a pdf stream , this variable is of type System.Threading.Tasks.Task<Stream>. I want to save this pdf stream in a pdf file but I am not sure how to do so . Below is a piece of code I tried to work on . Any ideas as to what I can try to save this stream in a file
System.Threading.Tasks.Task<Stream> pdf = //Some logic here which gets a pdf stream
I want to store the pdf content in the variable in a file as a pdf
For that I worote the method
public static void SaveStreamAsFile(string filePath, System.Threading.Tasks.Task<Stream> inputStream, string fileName)
{
string path = Path.Combine(filePath, fileName);
using (FileStream outputFileStream = new FileStream(path, FileMode.Create))
{
// logic
}
}
Read the input stream and write it to the output stream..
public static async Task SaveStreamAsFile(string filePath, System.Threading.Tasks.Task<Stream> inputStream, string fileName)
{
var stream = await inputStream;
var path = Path.Combine(filePath, fileName);
var bytesInStream = new byte[stream.Length];
await stream.ReadAsync(bytesInStream, 0, (int) bytesInStream.Length);
using (var outputFileStream = new FileStream(path, FileMode.Create))
{
await outputFileStream.WriteAsync(bytesInStream, 0, bytesInStream.Length);
}
}
I'm developing a service to compress some files and I have been doing tests to the service and it is getting a major failure in bigger files. I'm using an outlook file with 6GB to test and I get an out of memory error after compressing 500Mb.
This is my code:
using (FileStream zipToOpen = new FileStream(#dir + ZipName, FileMode.Open))
{
using (ZipArchive archive = new ZipArchive(zipToOpen, ZipArchiveMode.Update))
{
foreach (string file in files)
{
if (File.GetCreationTime(#dir + file).AddSeconds(FileAge) < DateTime.Now)
{
ZipArchiveEntry fileEntry = archive.CreateEntry(file);
using (BinaryWriter writer = new BinaryWriter(fileEntry.Open()))
{
using (FileStream sr = new FileStream(#dir + file, FileMode.Open, FileAccess.Read))
{
byte[] block = new byte[1024];
int bytesRead = 0;
while ((bytesRead = sr.Read(block,0, block.Length)) >0)
{
writer.Write(block, 0, bytesRead);
}
}
}
File.Delete(#dir + file);
}
}
}
}
Any ideia how I can solve it?
Thank you in advance
I need to create a StreamWriter from a FileStream object and append some text to
the file. It is assumed that the FileStream object that is being used has been created with FileMode.OpenOrCreate and FileAccess.ReadWrite. I have:
using (FileStream fs = GetCurrentFileStream())
{
StreamWriter sw = new StreamWriter(fs);
sw.WriteLine("StringToAppend");
sw.Flush();
}
However this just overwrites the file from the beginning. How do I move to the end of the file? Is there perhaps a way to change the FileMode to Append and FileAccess to Write after the FileStream has been created?
Edit: As mentioned above I need to do this using a FileStream object. The answers from Open existing file, append a single line assume that I can create a new StreamWriter from the file path which I don't have.
Edit 2: Added truncated version of GetCurrentFileStream().
public static FileStream GetCurrentFileStream()
{
String fileName = getFileName();
FileStream fs = OpenFileWhenAvailable(fileName, FileMode.OpenOrCreate, FileAccess.ReadWrite, FileShare.None);
}
public static FileStream OpenFileWhenAvailable(String fileName, FileMode fileMode, FileAccess fileAccess, FileShare fileShare)
{
int tries = 0;
int timeout = 10 * 1000;
while (true)
{
tries++;
try
{
return new FileStream(fileName, fileMode, fileAccess, fileShare);
}
catch (IOException ex)
{
if (tries * 100 > timeout)
{
return null;
}
else
{
System.Threading.Thread.Sleep(100);
}
}
}
}
GetCurrentFileStream is used in several different contexts, so changing the FileMode and FileAccess directly is not an option. I do not wish to make a separate version of GetCurrentFileStream just for this one case, which is why I'm asking if there is a way to jump to the end of the stream and append a string when the FileStream object has already been created.
If I understood correctly, you want to append your line to a created file:
using (FileStream fs = GetCurrentFileStream())
{
StreamWriter sw = new StreamWriter(fs, true);
sw.WriteLine("StringToAppend");
sw.Flush();
}
With this overload of the StreamWriter constructor you choose if you append the file, or overwrite it.
It will be really cool if you show your implementation of method GetCurrentStream():
using (FileStream fileStream = new FileStream(fileName,FileMode.Append, FileAccess.Write))
using (StreamWriter sw = new StreamWriter(fs))
{
sw.WriteLine(something);
}
Update:
using (FileStream fs = GetCurrentFileStream())
{
StreamWriter sw = new StreamWriter(fs);
long endPoint=fs.Length;
// Set the stream position to the end of the file.
fs.Seek(endPoint, SeekOrigin.Begin);
sw.WriteLine("StringToAppend");
sw.Flush();
}
If you really really wanted to, you could pretty this up....
static int iMaxLogLength = 15000;
static int iTrimmedLogLength = -2000;
static public void writeToFile2(string strMessage, string strLogFileDirectory, int iLogLevel)
{
string strFile = strLogFileDirectory + "log.log";
try
{
FileInfo fi = new FileInfo(strFile);
Byte[] bytesRead = null;
if (fi.Length > iMaxLogLength)
{
using (BinaryReader br = new BinaryReader(File.Open(strFile, FileMode.Open)))
{
// Go to the end of the file and backup some
br.BaseStream.Seek(iTrimmedLogLength, SeekOrigin.End);
// Read that.
bytesRead = br.ReadBytes((-1 * iTrimmedLogLength));
}
}
byte[] newLine = System.Text.ASCIIEncoding.ASCII.GetBytes(Environment.NewLine);
FileStream fs = null;
if (fi.Length < iMaxLogLength)
fs = new FileStream(strFile, FileMode.Append, FileAccess.Write, FileShare.Read);
else
fs = new FileStream(strFile, FileMode.Create, FileAccess.Write, FileShare.Read);
using (fs)
{
if (bytesRead != null)
{
fs.Write(bytesRead, 0, bytesRead.Length);
fs.Write(newLine, 0, newLine.Length);
Byte[] lineBreak = Encoding.ASCII.GetBytes("### " + DateTime.Now.ToString("yyyy-MM-dd HH:mm:ss") + " *** *** *** New Log Start Position *** *** *** *** ###");
fs.Write(lineBreak, 0, lineBreak.Length);
fs.Write(newLine, 0, newLine.Length);
}
Byte[] sendBytes = Encoding.ASCII.GetBytes(strMessage);
fs.Write(sendBytes, 0, sendBytes.Length);
fs.Write(newLine, 0, newLine.Length);
}
}
catch (Exception ex)
{
; // Write to event or something
}
}
I have created one WCF service that will upload the file. and after using that service I am trying to upload the file I am able to successfully upload the file but there is some issue with the FILESTREAM class.
The moment i clicked the button to upload the file when i checked by debugging the application i get to know that stream object is null.
I am passing the object of stream class to the WCF method.
But due to some issue that stream object is getting null.
due to that null object of stream class, image which is uploded getting empty in my folder
This is my code that I am using to upload the file
if (FileUpload1.HasFile)
{
System.IO.FileInfo fileInfo = new System.IO.FileInfo(FileUpload1.PostedFile.FileName);
FileTransferServiceReference.ITransferService clientUpload = new FileTransferServiceReference.TransferServiceClient("BasicHttpBinding_ITransferService");
FileTransferServiceReference.RemoteFileInfo uploadRequestInfo = new RemoteFileInfo();
string Path = System.IO.Path.GetDirectoryName(FileUpload1.FileName);
using (System.IO.FileStream stream = new System.IO.FileStream(FileUpload1.FileName, System.IO.FileMode.Open, System.IO.FileAccess.Read))
{
uploadRequestInfo.FileName = FileUpload1.FileName;
uploadRequestInfo.Length = fileInfo.Length;
uploadRequestInfo.FileByteStream = stream;
clientUpload.UploadFile(uploadRequestInfo);
}
}
Code for WCF Service
public RemoteFileInfo DownloadFile(DownloadRequest request)
{
RemoteFileInfo result = new RemoteFileInfo();
try
{
// get some info about the input file
string filePath = System.IO.Path.Combine(#"c:\Uploadfiles", request.FileName);
System.IO.FileInfo fileInfo = new System.IO.FileInfo(filePath);
// check if exists
if (!fileInfo.Exists) throw new System.IO.FileNotFoundException("File not found", request.FileName);
// open stream
System.IO.FileStream stream = new System.IO.FileStream(filePath, System.IO.FileMode.Open, System.IO.FileAccess.Read);
// return result
result.FileName = request.FileName;
result.Length = fileInfo.Length;
result.FileByteStream = stream;
}
catch (Exception ex)
{
}
return result;
}
public void UploadFile(RemoteFileInfo request)
{
FileStream targetStream = null;
Stream sourceStream = request.FileByteStream;
string uploadFolder = #"C:\upload\";
if (!Directory.Exists(uploadFolder))
{
Directory.CreateDirectory(uploadFolder);
}
string filePath = Path.Combine(uploadFolder, request.FileName);
using (targetStream = new FileStream(filePath, FileMode.Create, FileAccess.Write, FileShare.None))
{
const int bufferLen = 65000;
byte[] buffer = new byte[bufferLen];
int count = 0;
while ((count = sourceStream.Read(buffer, 0, bufferLen)) > 0)
{
targetStream.Write(buffer, 0, count);
}
targetStream.Close();
sourceStream.Close();
}
}
}
Spot the difference:
string uploadFolder = #"C:\upload\";
...
string filePath = System.IO.Path.Combine(#"c:\Uploadfiles", request.FileName);
As a general tip you might put your upload file path into an external configuration file, so that you can change it when you move your application onto a server where you need to store the data on a different drive or in a specific location.
Also that way you are always calling the same configuration entry so your upload path name is definitely going to be the same everywhere.
I am having two problems
My problems are
My file name is 20110505.txt , and it is compressing a zip file name as -> 20110505.txt.zip
But I need after compressing this file 20110505.txt as --> 20110505.zip only.
I am using this dll
using System.IO.Compression;
Here is my code for compress,
1)is my text format
string path = DayDestination + "\\" + txtSelectedDate.Text + ".txt";
StreamWriter Strwriter = new StreamWriter(path);
DirectoryInfo di = new DirectoryInfo(path);
FileInfo fi = new FileInfo(path);
Compress(fi);
public static void Compress(FileInfo fi)
{
// Get the stream of the source file.
using (FileStream inFile = fi.OpenRead())
{
// Prevent compressing hidden and already compressed files.
if ((File.GetAttributes(fi.FullName) & FileAttributes.Hidden)
!= FileAttributes.Hidden & fi.Name != ".zip")
{
// Create the compressed file.
using (FileStream outFile = File.Create(fi.FullName + ".zip"))
//using (FileStream outFile = File.Create( fi.Name+ ".zip"))
{
using (GZipStream Compress = new GZipStream(outFile,
CompressionMode.Compress))
{
// Copy the source file into the compression stream.
byte[] buffer = new byte[4096];
int numRead;
while ((numRead = inFile.Read(buffer, 0, buffer.Length)) != 0)
{
Compress.Write(buffer, 0, numRead);
}
Console.WriteLine("Compressed {0} from {1} to {2} bytes.",
fi.Name, fi.Length.ToString(), outFile.Length.ToString());
}
}
}
}
}
If my zip file name is 20110505.zip after uncompressing i want my file name to be 20110505.txt . after uncomressing the zip file to text file i want to delete the zip file after compressing
string Path2 = (string)(Application.StartupPath + "\\TEMP\\" + "\\" + name_atoz);
DirectoryInfo di = new DirectoryInfo(Path2);
FileInfo fi = new FileInfo(Path2);
Compress(fi);
public static void Decompress(FileInfo fi)
{
// Get the stream of the source file.
using (FileStream inFile = fi.OpenRead())
{
// Get original file extension, for example "doc" from report.doc.gz.
string curFile = fi.FullName;
string origName = curFile.Remove(curFile.Length - fi.Extension.Length);
//Create the decompressed file.
using (FileStream outFile = File.Create(origName))
{
using (GZipStream Decompress = new GZipStream(inFile,
CompressionMode.Decompress))
{
//Copy the decompression stream into the output file.
byte[] buffer = new byte[4096];
int numRead;
while ((numRead = Decompress.Read(buffer, 0, buffer.Length)) != 0)
{
outFile.Write(buffer, 0, numRead);
}
Console.WriteLine("Decompressed: {0}", fi.Name);
}
}
}
}
I want this because i am creating a project which reads the text file .
Is there any suggestion for my problem.
Thanks In Advance
As Mitch pointed out in the comments above, the problem seems to be with your file name being used for the zip file. You include the FullName, but that has the .txt at the end. Trim that off and you should have what you want.
The line I'm talking about is this one:
using (FileStream outFile = File.Create(fi.FullName + ".zip"))
A simple way to fix it would be as follows:
using (FileStream outFile = File.Create(System.Text.RegularExpressions.Regex.Replace(fi.FullName, ".txt$", "") + ".zip"))
To delete your zip file after you decompress it, put the following line in your Decompress method as the very last line (outside your outer-most using statement):
File.Delete(fi);
You probably want to wrap that in a try-catch but this is the basic code to run. Here is an article on how to delete a file safely:
http://www.dotnetperls.com/file-delete