I have a following sample string
ptv.test foo bar cc.any more words
I want a regular expression which can extract the patter text.text. For example in above string it should match ptv.test and cc.any
Thanks
You can use the following code:
string s = "ptv.test foo bar cc.any more words";
var matches = Regex.Matches(s, #"\w+\.\w+");
foreach(Match match in matches)
{
Console.WriteLine(match.Value);
}
Which outputs:
ptv.test
cc.any
\w+\.\w+
(one or more word characters, the period, one or more word characters)
[A-Za-z]+\.[A-Za-z]
You need to escape the period becuase it is a Regex special character that matches anything
Your question is vague one. The answer depends on what does the "text" actually mean. Some possibilities are below:
[a-z]+\.[a-z]+ English lower case letters a..z
[A-Za-z]+\.[A-Za-z]+ English letters A..Z or a..z
\p{L}+\.\p{L}+ Any unicode letters
\w+\.\w+ Any word symbols (letters + digits)
...
Another detail to concern with is should "text" be preceded / followed by white spaces or string start/end. E.g. for given
pt???v.test foo bar cc.an!!!y more words
should "v.test" or "cc.an" be considered as matches. If not, add \b before and after the required pattern, e.g.:
\b[a-z]+\.[a-z]+\b
The implementation can be something like this:
string source = #"ptv.test foo bar cc.any more words";
string pattern = #"\b[a-z]+\.[a-z]+\b";
string[] matches = Regex
.Matches(source, pattern)
.Cast<Match>()
.Select(match => match.Value)
.ToArray(); // let's organize matches as an array
// ptv.test
// cc.any
Console.Write(String.Join(Environment.NewLine, matches));
Related
I'm using Replace(#"[^a-zA-Z]+", "");
leave only letters, but I have a set of numbers or characters that I want to keep as well, ex: 122456 and 112466. But I'm having trouble leaving it only if it's this sequence:
ex input:
abc 1239 asm122456000
I want to:
abscasm122456
tried this: ([^a-zA-Z])+|(?!122456)
My answer doesn't applying Replace(), but achieves a similar result:
(?:[a-zA-Z]+|\d{6})
which captures the group (non-capturing group) with the alphabetic character(s) or a set of digits with 6 occurrences.
Regex 101 & Test Result
Join all the matching values into a single string.
using System.Linq;
Regex regex = new Regex("(?:[a-zA-Z]+|\\d{6})");
string input = "abc 1239 asm12245600";
string output = "";
var matches = regex.Matches(input);
if (matches.Count > 0)
output = String.Join("", matches.Select(x => x.Value));
Sample .NET Fiddle
Alternate way,
using .Split() and .All(),
string input = "abc 1239 asm122456000";
string output = string.Join("", input.Split().Where(x => !x.All(char.IsDigit)));
.NET Fiddle
It is very simple: you need to match and capture what you need to keep, and just match what you need to remove, and then utilize a backreference to the captured group value in the replacement pattern to put it back into the resulting string.
Here is the regex:
(122456|112466)|[^a-zA-Z]
See the regex demo. Details:
(122456|112466) - Capturing group with ID 1: either of the two alternatives
| - or
[^a-zA-Z] - a char other than an ASCII letter (use \P{L} if you need to match any char other than any Unicode letter).
Note the removed + quantifier as [^A-Za-z] also matches digits.
You need to use $1 in the replacement:
var result = Regex.Replace(text, #"(122456|112466)|[^a-zA-Z]", "$1");
I have a string as:
string subjectString = #"(((43*('\\uth\Hgh.Green.two.190ITY.PCV')*9.8)/100000+('VBNJK.PVI.10JK.PCV'))*('ASFGED.Height Density.1JKHB01.PCV')/476)";
My expected output is:
Hgh.Green.two.190ITY.PCV
VBNJK.PVI.10JK.PCV
ASFGED.Height Density.1JKHB01.PCV
Here's what I have tried:
Regex regexObj = new Regex(#"'[^\\]*.PCV");
Match matchResults = regexObj.Match(subjectString);
string val = matchResults.Value;
This works when the input string is :"#"(((43*('\\uth\Hgh.Green.two.190ITY.PCV')*9.8)/100000+"; but when the string grows and the number of substrings to be extracted is more than 1 , I am getting undesired results .
How do I extract three substrings from the original string?
It seems you want to match word and . chars before .PCV.
Use
[\w\s.]*\.PCV
See the regex demo
To force at least 1 word char at the start use
\w[\w\s.]*\.PCV
Optionally, if needed, add a word boundary at the start: #"\b\w[\w\s.]*\.PCV".
To force \w match only ASCII letters and digits (and _) compile the regex object with RegexOptions.ECMAScript option.
Here,
\w - matches any letter, digit or _
[\w\s.]* - matches 0+ whitespace, word or/and . chars
\. - a literal .
PCV - a PCV substring.
Sample usage:
var results = Regex.Matches(str, #"\w[\w\s.]*\.PCV")
.Cast<Match>()
.Select(m=>m.Value)
.ToList();
I want to be able to match the following examples and return array of matches
given text:
some word
another 50.00
some-more 10.10 text
another word
Matches should be (word, followed by space then decimal number (Optionally followed by another word):
another 50.00
some-more 10.10 text
I have the following so far:
string pat = #"\r\n[A-Za-z ]+\d+\.\d{1,2}([A-Za-z])?";
Regex r = new Regex(pat, RegexOptions.IgnoreCase);
Match m = r.Match(input);
but it only matches first item: another 50.00
You do not account for - with [A-Za-z ] and only match some text after a newline.
You can use the following regex:
[\p{L}-]+\p{Zs}*\d*\.?\d{1,2}(?:\p{Zs}*[\p{L}-]+)?
See the regex demo
The [\p{L}-]+ matches 1 or more letters and hyphens, \p{Zs}* matches 0 or more horizontal whitespace symbols, \d*\.?\d{1,2} matches a float number with 1 to 2 digits in the decimal part, and (?:\p{Zs}*[\p{L}-]+)? matches an optional word after the number.
Here is a C# snippet matching all occurrences based on Regex.Matches method:
var res = Regex.Matches(str, #"[\p{L}-]+\p{Zs}*\d*\.?\d{1,2}(?:\p{Zs}*[\p{L}-]+)?")
.Cast<Match>()
.Select(p => p.Value)
.ToList();
Just FYI: if you need to match whole words, you can also use word boundaries \b:
\b[\p{L}-]+\p{Zs}*\d*\.?\d{1,2}(?:\p{Zs}*[\p{L}-]+)?\b
And just another note: if you need to match diacritics, too, you may add \p{M} to the character class containing \p{L}:
[\p{L}\p{M}-]+\p{Zs}*\d*\.?\d{1,2}(?:\p{Zs}*[\p{L}\p{M}-]+)?\b
I need to extract a substring from an existing string. This String starts with uninteresting characters (include "," "space" and numbers) and ends with ", 123," or ", 57," or something like this where the numbers can change. I only need the Numbers.
Thanks
public static void Main(string[] args)
{
string input = "This is 2 much junk, 123,";
var match = Regex.Match(input, #"(\d*),$"); // Ends with at least one digit
// followed by comma,
// grab the digits.
if(match.Success)
Console.WriteLine(match.Groups[1]); // Prints '123'
}
Regex to match numbers: Regex regex = new Regex(#"\d+");
Source (slightly modified): Regex for numbers only
I think this is what you're looking for:
Remove all non numeric characters from a string using Regex
using System.Text.RegularExpressions;
...
string newString = Regex.Replace(oldString, "[^.0-9]", "");
(If you don't want to allow the decimal delimiter in the final result, remove the . from the regular expression above).
Try something like this :
String numbers = new String(yourString.TakeWhile(x => char.IsNumber(x)).ToArray());
You can use \d+ to match all digits within a given string
So your code would be
var lst=Regex.Matches(inp,reg)
.Cast<Match>()
.Select(x=x.Value);
lst now contain all the numbers
But if your input would be same as provided in your question you don't need regex
input.Substring(input.LastIndexOf(", "),input.LastIndexOf(","));
I have a long string composed of a number of different words.
I want to go through all of them, and if the word contains a special character or number (except '-'), or starts with a Capital letter, I want to delete it (the whole word not just that character). For all intents and purposes 'foreign' letters can count as special characters.
The obvious solution is to run a loop through each word (after splitting it) and then a loop through each character - but I'm hoping there's a faster way of doing it? Perhaps using Regex but I've almost no experience with it.
Thanks
ADDED:
(What I want for example:)
Input: "this Is an Example of 5 words in an input like-so from example.com"
Output: {this,an,of,words,in,an,input,like-so,from}
(What I've tried so far)
List<string> response = new List<string>();
string[] splitString = text.Split(' ');
foreach (string s in splitString)
{
bool add = true;
foreach (char c in s.ToCharArray())
{
if (!(c.Equals('-') || (Char.IsLetter(c) && Char.IsLower(c))))
{
add = false;
break;
}
if (add)
{
response.Add(s);
}
}
}
Edit 2:
For me a word should be a number of characters (a..z) seperated by a space. ,/./!/... at the end shouldn't count for the 'special character' condition (which is really mostly just to remove urls or the like)
So:
"I saw a dog. It was black!"
should result in
{saw,a,dog,was,black}
So you want to find all "words" that only contain characters a-z or -, for words that are separated by spaces?
A regex like this will find such words:
(?<!\S)[a-z-]+(?!\S)
To also allow for words that end with single punctuation, you could use:
(?<!\S)[a-z-]+(?=[,.!?:;]?(?!\S))
Example (ideone):
var re = #"(?<!\S)[a-z-]+(?=[,.!?:;]?(?!\S))";
var str = "this, Is an! Example of 5 words in an input like-so from example.com foo: bar?";
var m = Regex.Matches(str, re);
Console.WriteLine("Matched: ");
foreach (Match i in m)
Console.Write(i + " ");
Notice the punctuation in the string.
Output:
Matched:
this an of words in an input like-so from foo bar
How about this?
(?<=^|\s+)(?[a-z-]+)(?=$|\s+)
Edit: Meant (?<=^|\s+)(?<word>[a-z\-]+)(?=(?:\.|,|!|\.\.\.)?(?:$|\s+))
Rules:
Word can only be preceded by start of line or some number of whitespace characters
Word can only be followed by end of line or some number of whitespace characters (Edit supports words ending with periods, commas, exclamation points, and ellipses)
Word can only contain lower case (latin) letters and dashes
The named group containing each word is "word"
Have a look at Microsoft's How to: Search Strings Using Regular Expressions (C# Programming Guide) - it's about regexes in C#.
List<string> strings = new List<string>() {"asdf", "sdf-sd", "sdfsdf"};
for (int i = strings.Count-1; i > 0; i--)
{
if (strings[i].Contains("-"))
{
strings.Remove(strings[i]);
}
}
This could be a starting point. right now it just checks only for "." as a special char. This outputs : "this an of words in an like-so from"
string pattern = #"[A-Z]\w+|\w*[0-9]+\w*|\w*[\.]+\w*";
string line = "this Is an Example of 5 words in an in3put like-so from example.com";
System.Text.RegularExpressions.Regex r = new System.Text.RegularExpressions.Regex(pattern);
line = r.Replace(line,"");
You can do this in two ways, the white-list way and the black-list way. With a white-list you define the set of characters that you consider to be acceptable and with the black-list its the opposite.
Lets assume the white-list way and that you accept only characters a-z, A-Z and the - character. Additionally you have the rule that the first character of a word cannot be an upper case character.
With this you can do something like this:
string target = "This is a white-list example: (Foo, bar1)";
var matches = Regex.Matches(target, #"(?:\b)(?<Word>[a-z]{1}[a-zA-Z\-]*)(?:\b)");
string[] words = matches.Cast<Match>().Select(m => m.Value).ToArray();
Console.WriteLine(string.Join(", ", words));
Outputs:
// is, a, white-list, example
You can use look-aheads and look-behinds to do this. Here's a regex that matches your example:
(?<=\s|^)[a-z-]+(?=\s|$)
The explanation is: match one or more alphabetic characters (lowercase only, plus hyphen), as long as what comes before the characters is whitespace (or the start of the string), and as long as what comes after is whitespace or the end of the string.
All you need to do now is plug that into System.Text.RegularExpressions.Regex.Matches(input, regexString) to get your list of words.
Reference: http://www.mikesdotnetting.com/Article/46/CSharp-Regular-Expressions-Cheat-Sheet