Subtracting UTC and non-UTC DateTime in C# - c#

I assumed that when subtracting 2 datetimes the framework will check their timezone and make the appropriate conversions.
I tested it with this code:
Console.WriteLine(DateTime.Now.ToUniversalTime() - DateTime.UtcNow.ToUniversalTime());
Console.WriteLine(DateTime.Now.ToUniversalTime() - DateTime.UtcNow);
Console.WriteLine(DateTime.Now - DateTime.UtcNow);
Output:
-00:00:00.0020002
-00:00:00.0020001
01:59:59.9989999
To my surprise, DateTime.Now - DateTime.UtcNow does not make the appropriate conversion automatically. At the same time, DateTime.UtcNow is the same as DateTime.UtcNow.ToUniversalTime(), so obviously there is some internal flag that indicates the time zone.
Is that correct, does that framework not perform the appropriate timezone conversion automatically, even if the information is already present? If so, is applying ToUniversalTime() safe for both UTC and non-UTC datetimes, i.e. an already UTC datetime will not be incorrectly corrected by ToUniversalTime()?

The type System.DateTime does not hold time zone information, only a .Kind property that specifies whether it is Local or UTC. But before .NET 2.0, there was not even a .Kind property.
When you subtract (or do other arithmetic, like == or >, on) two DateTime values, their "kinds" are not considered at all. Only the numbers of ticks are considered. This gives compatibility with .NET 1.1 when no kinds existed.
The functionality you ask for (and expect) is in the newer and richer type System.DateTimeOffset. In particular, if you do the subtraction DateTimeOffset.Now - DateTimeOffset.UtcNow you get the result you want. The DateTimeOffset structure does not have a local/UTC flag; instead, it holds the entire time zone, such as +02:00 in your area.

The framework does nothing with the date if it is already UTC:
internal static DateTime ConvertTimeToUtc(DateTime dateTime, TimeZoneInfoOptions flags)
{
if (dateTime.Kind == DateTimeKind.Utc)
{
return dateTime;
}
CachedData cachedData = s_cachedData;
return ConvertTime(dateTime, cachedData.Local, cachedData.Utc, flags, cachedData);
}

Related

DateTime in a TimeZone which is not UTC or Local

I have question pertaining to the DateTimeKind struct in C#.
If I have converted a DateTime to a new DateTime (which is not in my local Timezone) using something like:
TimeZoneInfo.ConvertTimeBySystemTimeZoneId(now, "Tokyo Standard Time");
what should I use for the Kind property of that new DateTime? Unspecified feels a bit weird and does not help much with conversions.
I get the feeling that as soon as you use a Timezone which is not your local and not UTC, then you absolutely have to start using the DateTimeOffset struct.
This is more a question about how to handle non-local TimeZones.
When you go beyond your local timezone, you really do need to use the DateTimeOffset class.
When writing a time service, you may want to add a method for converting a DateTime in one non-local timezone to another non-local timezone. This is pretty straight forward when using the DateTimeOffset class:
public DateTimeOffset ConvertToZonedOffset(DateTimeOffset toConvert, string timeZoneId)
{
var universalTime = toConvert.ToUniversalTime(); // first bring it back to the common baseline (or standard)
var dateTimeOffset = TimeZoneInfo.ConvertTime(universalTime, TimeZoneInfo.FindSystemTimeZoneById(timeZoneId));
return dateTimeOffset;
}
The incoming DateTimeOffset has the source offset and the timeZoneId being passed in gives enough information to realize the target timezone (and offset).
And the returned DateTimeOffset has the target offset.
It gets a bit clunkier when you do it with the DateTime struct, if you wanted to provide an equivalent method:
public DateTime ConvertToZonedOffset(DateTime toConvert, string sourceTimeZoneId, string targetTimeZoneId)
{
return TimeZoneInfo.ConvertTimeBySystemTimeZoneId(toConvert, sourceTimeZoneId, targetTimeZoneId);
}
And this is where the DateTimeKind comes in. If you:
pass the DateTime in with the Kind set to either UTC or Local; AND
the sourceTimeZone is neither of those,
then ConvertTimeBySystemTimeZoneId will throw an exception. So, when you are dealing with a "3rd timezone", Kind must be Unspecified. This tells the method to ignore the system clock, to not assume that it is UTC and to go by whatever is passed in as the sourceTimeZone.
It's not as good as the DateTimeOffset version in another way. The returned DateTime has no information about the timezone and the Kind is set to Unspecified. This basically means that it is the responsibility of the calling code to know and track what timezone that date and time is valid in. Not ideal. So much so that I decided to "be opinionated" and get rid of that method. I'll force the calling code to convert the DateTime they may be working with to a DateTimeOffset and to consume one upon return.
Note 1: if Kind is set to Local and the sourceTimeZone matches your local timezone, it will work fine.
Note 2: if Kind is set to Utc and the sourceTimeZone is set to "Coordinated Universal Time", you may get the following TimeZoneNotFoundException:
The time zone ID 'Coordinated Universal Time' was not found on the local computer
I assume that this is because UTC is a standard and not a timezone, despite being returned by TimeZoneInfo.GetSystemTimeZones as a Timezone.
what should I use for the Kind property of that new DateTime? Unspecified feels a bit weird...
...but it's the correct value in this case. The documentation of the DateTimeKind enum is quite clear on this subject:
Local (2): The time represented is local time.
Unspecified (0): The time represented is not specified as either local time or Coordinated Universal Time (UTC).
Utc (1): The time represented is UTC.
Your time is neither local time nor UTC, so the only correct value is Unspecified.
I get the feeling that as soon as you use a Timezone which is not your local and not UTC, then you absolutely have to start using the DateTimeOffset struct.
You don't have to, but it can definitely make your life easier. As you have noticed, DateTime does not provide an option to store the time zone information along with the date. This is exactly what DateTimeOffset is for.

TimeZoneInfo.ConvertTime method not converting the DateTime correctly

I have the following date string: 2015-11-10T23:52:18.5245011Z
And when I parse it using DateTime.Parse method it returns 11/11/2015 10:52:18 AM which is incorrect.
I also tried the follwing conversion:
TimeZoneInfo est = TimeZoneInfo.FindSystemTimeZoneById("AUS Eastern Standard Time");
DateTime targetTimeUtcconverted = TimeZoneInfo.ConvertTime(UtcDate, est);
and it still gives out: 11/11/2015 10:52:18 AM
Can't figure out what I am missing here.
Use:
DateTime.Parse(s, CultureInfo.InvariantCulture, DateTimeStyles.RoundtripKind)
Or:
DateTime.Parse(s, CultureInfo.InvariantCulture, DateTimeStyles.AdjustToUniversal)
Or (best option):
DateTimeOffset.Parse(s)
By default, DateTime.Parse will adjust to local time if there is any offset information present in the string. Since Z is the same as +00:00, it assumes the input is +00:00, then adjusts from UTC to the local time zone.
If there is no offset information present, it returns a DateTime with Unspecified kind.
Passing DateTimeStyles.RoundtripKind tells it to treat any value with an offset as local time (as before), but any value containing Z, UTC, GMT, etc. to have DateTimeKind.Utc.
Passing DateTimeStyles.AdjustToUniversal tells it that the output should always have DateTimeKind.Utc, and the value should be adjusted if necessary.
Parsing using DateTimeOffset.Parse bypasses all of that convoluted behavior and just returns a value with an offset matching what was provided. This is the best approach when an offset (or Z) is present in the input string. If you need a DateTime, you can use the UtcDateTime, LocalDateTime, or DateTime properties from the resulting DateTimeOffset.
The time zone conversion code you gave is correct, as long as the Kind is UTC. It would be more explicit to use ConvertTimeFromUtc, but that wouldn't really matter in this case. The best approach is to use the overload of ConvertTime that works with DateTimeOffset values. The resulting value will be a DateTimeOffset whose DateTime property matches the time in that time zone, and whose Offset property is the correct offset for that time in that time zone.

Difference between System.DateTime.Now and System.DateTime.Today

Can anyone explain the difference between System.DateTime.Now and System.DateTime.Today in C#.NET? Pros and cons of each if possible.
DateTime.Now returns a DateTime value that consists of the local date and time of the computer where the code is running. It has DateTimeKind.Local assigned to its Kind property. It is equivalent to calling any of the following:
DateTime.UtcNow.ToLocalTime()
DateTimeOffset.UtcNow.LocalDateTime
DateTimeOffset.Now.LocalDateTime
TimeZoneInfo.ConvertTime(DateTime.UtcNow, TimeZoneInfo.Local)
TimeZoneInfo.ConvertTimeFromUtc(DateTime.UtcNow, TimeZoneInfo.Local)
DateTime.Today returns a DateTime value that has the same year, month, and day components as any of the above expressions, but with the time components set to zero. It also has DateTimeKind.Local in its Kind property. It is equivalent to any of the following:
DateTime.Now.Date
DateTime.UtcNow.ToLocalTime().Date
DateTimeOffset.UtcNow.LocalDateTime.Date
DateTimeOffset.Now.LocalDateTime.Date
TimeZoneInfo.ConvertTime(DateTime.UtcNow, TimeZoneInfo.Local).Date
TimeZoneInfo.ConvertTimeFromUtc(DateTime.UtcNow, TimeZoneInfo.Local).Date
Note that internally, the system clock is in terms of UTC, so when you call DateTime.Now it first gets the UTC time (via the GetSystemTimeAsFileTime function in the Win32 API) and then it converts the value to the local time zone. (Therefore DateTime.Now.ToUniversalTime() is more expensive than DateTime.UtcNow.)
Also note that DateTimeOffset.Now.DateTime will have similar values to DateTime.Now, but it will have DateTimeKind.Unspecified rather than DateTimeKind.Local - which could lead to other errors depending on what you do with it.
So, the simple answer is that DateTime.Today is equivalent to DateTime.Now.Date.
But IMHO - You shouldn't use either one of these, or any of the above equivalents.
When you ask for DateTime.Now, you are asking for the value of the local calendar clock of the computer that the code is running on. But what you get back does not have any information about that clock! The best that you get is that DateTime.Now.Kind == DateTimeKind.Local. But whose local is it? That information gets lost as soon as you do anything with the value, such as store it in a database, display it on screen, or transmit it using a web service.
If your local time zone follows any daylight savings rules, you do not get that information back from DateTime.Now. In ambiguous times, such as during a "fall-back" transition, you won't know which of the two possible moments correspond to the value you retrieved with DateTime.Now. For example, say your system time zone is set to Mountain Time (US & Canada) and you ask for DateTime.Now in the early hours of November 3rd, 2013. What does the result 2013-11-03 01:00:00 mean? There are two moments of instantaneous time represented by this same calendar datetime. If I were to send this value to someone else, they would have no idea which one I meant. Especially if they are in a time zone where the rules are different.
The best thing you could do would be to use DateTimeOffset instead:
// This will always be unambiguous.
DateTimeOffset now = DateTimeOffset.Now;
Now for the same scenario I described above, I get the value 2013-11-03 01:00:00 -0600 before the transition, or 2013-11-03 01:00:00 -0700 after the transition. Anyone looking at these values can tell what I meant.
I wrote a blog post on this very subject. Please read - The Case Against DateTime.Now.
Also, there are some places in this world (such as Brazil) where the "spring-forward" transition happens exactly at Midnight. The clocks go from 23:59 to 01:00. This means that the value you get for DateTime.Today on that date, does not exist! Even if you use DateTimeOffset.Now.Date, you are getting the same result, and you still have this problem. It is because traditionally, there has been no such thing as a Date object in .Net. So regardless of how you obtain the value, once you strip off the time - you have to remember that it doesn't really represent "midnight", even though that's the value you're working with.
If you really want a fully correct solution to this problem, the best approach is to use NodaTime. The LocalDate class properly represents a date without a time. You can get the current date for any time zone, including the local system time zone:
using NodaTime;
...
Instant now = SystemClock.Instance.Now;
DateTimeZone zone1 = DateTimeZoneProviders.Tzdb.GetSystemDefault();
LocalDate todayInTheSystemZone = now.InZone(zone1).Date;
DateTimeZone zone2 = DateTimeZoneProviders.Tzdb["America/New_York"];
LocalDate todayInTheOtherZone = now.InZone(zone2).Date;
If you don't want to use Noda Time, there is now another option. I've contributed an implementation of a date-only object to the .Net CoreFX Lab project. You can find the System.Time package object in their MyGet feed. Once added to your project, you will find you can do any of the following:
using System;
...
Date localDate = Date.Today;
Date utcDate = Date.UtcToday;
Date tzSpecificDate = Date.TodayInTimeZone(anyTimeZoneInfoObject);
Time. .Now includes the 09:23:12 or whatever; .Today is the date-part only (at 00:00:00 on that day).
So use .Now if you want to include the time, and .Today if you just want the date!
.Today is essentially the same as .Now.Date
The DateTime.Now property returns the current date and time, for example 2011-07-01 10:09.45310.
The DateTime.Today property returns the current date with the time compnents set to zero, for example 2011-07-01 00:00.00000.
The DateTime.Today property actually is implemented to return DateTime.Now.Date:
public static DateTime Today {
get {
DateTime now = DateTime.Now;
return now.Date;
}
}
DateTime.Today represents the current system date with the time part set to 00:00:00
and
DateTime.Now represents the current system date and time
I thought of Adding these links -
A brief History of DateTime - By Anthony Moore by BCL team
Choosing between Datetime and DateTime Offset - by MSDN
Do not forget SQL server 2008 onwards has a new Datatype as DateTimeOffset
The .NET Framework includes the DateTime, DateTimeOffset, and
TimeZoneInfo types, all of which can be used to build applications
that work with dates and times.
Performing Arithmetic Operations with Dates and Times-MSDN
Coming back to original question , Using Reflector i have explained the difference in code
public static DateTime Today
{
get
{
return DateTime.Now.Date; // It returns the date part of Now
//Date Property
// returns same date as this instance, and the time value set to 12:00:00 midnight (00:00:00)
}
}
private const long TicksPerMillisecond = 10000L;
private const long TicksPerDay = 864000000000L;
private const int MillisPerDay = 86400000;
public DateTime Date
{
get
{
long internalTicks = this.InternalTicks; // Date this instance is converted to Ticks
return new DateTime((ulong) (internalTicks - internalTicks % 864000000000L) | this.InternalKind);
// Modulo of TicksPerDay is subtracted - which brings the time to Midnight time
}
}
public static DateTime Now
{
get
{
/* this is why I guess Jon Skeet is recommending to use UtcNow as you can see in one of the above comment*/
DateTime utcNow = DateTime.UtcNow;
/* After this i guess it is Timezone conversion */
bool isAmbiguousLocalDst = false;
long ticks1 = TimeZoneInfo.GetDateTimeNowUtcOffsetFromUtc(utcNow, out isAmbiguousLocalDst).Ticks;
long ticks2 = utcNow.Ticks + ticks1;
if (ticks2 > 3155378975999999999L)
return new DateTime(3155378975999999999L, DateTimeKind.Local);
if (ticks2 < 0L)
return new DateTime(0L, DateTimeKind.Local);
else
return new DateTime(ticks2, DateTimeKind.Local, isAmbiguousLocalDst);
}
}
DateTime dt = new DateTime();// gives 01/01/0001 12:00:00 AM
DateTime dt = DateTime.Now;// gives today date with current time
DateTime dt = DateTime.Today;// gives today date and 12:00:00 AM time
DateTime.Today is DateTime.Now with time set to zero.
It is important to note that there is a difference between a DateTime value, which represents the number of ticks that have elapsed since midnight of January 1, 0000, and the string representation of that DateTime value, which expresses a date and time value in a culture-specific-specific format:
https://msdn.microsoft.com/en-us/library/system.datetime.now%28v=vs.110%29.aspx
DateTime.Now.Ticks is the actual time stored by .net (essentially UTC time), the rest are just representations (which are important for display purposes).
If the Kind property is DateTimeKind.Local it implicitly includes the time zone information of the local computer. When sending over a .net web service, DateTime values are by default serialized with time zone information included, e.g. 2008-10-31T15:07:38.6875000-05:00, and a computer in another time zone can still exactly know what time is being referred to.
So, using DateTime.Now and DateTime.Today is perfectly OK.
You usually start running into trouble when you begin confusing the string representation with the actual value and try to "fix" the DateTime, when it isn't broken.
DateTime.Now.ToShortDateString() will display only the date part

Safely comparing local and universal DateTimes

I just noticed what seems like a ridiculous flaw with DateTime comparison.
DateTime d = DateTime.Now;
DateTime dUtc = d.ToUniversalTime();
d == dUtc; // false
d.Equals(dUtc); //false
DateTime.Compare(d, dUtc) == 0; // false
It appears that all comparison operations on DateTimes fail to do any type of smart conversion if one is DateTimeKind.Local and one is DateTimeKind.UTC. Is the a better way to reliably compare DateTimes aside from always converting both involved in the comparison to utc time?
When you call .Equal or .Compare, internally the value .InternalTicks is compared, which is a ulong without its first two bits. This field is unequal, because it has been adjusted a couple of hours to represent the time in the universal time: when you call ToUniversalTime(), it adjusts the time with an offset of the current system's local timezone settings.
You should see it this way: the DateTime object represents a time in an unnamed timezone, but not a universal time plus timezone. The timezone is either Local (the timezone of your system) or UTC. You might consider this a lack of the DateTime class, but historically it has been implemented as "number of ticks since 1970" and doesn't contain timezone info.
When converting to another timezone, the time is — and should be — adjusted. This is probably why Microsoft chose to use a method as opposed to a property, to emphasize that an action is taken when converting to UTC.
Originally I wrote here that the structs are compared and the flag for System.DateTime.Kind is different. This is not true: it is the amount of ticks that differs:
t1.Ticks == t2.Ticks; // false
t1.Ticks.Equals(t2.Ticks); // false
To safely compare two dates, you could convert them to the same kind. If you convert any date to universal time before comparing you'll get the results you're after:
DateTime t1 = DateTime.Now;
DateTime t2 = someOtherTime;
DateTime.Compare(t1.ToUniversalTime(), t2.ToUniversalTime()); // 0
DateTime.Equals(t1.ToUniversalTime(), t2.ToUniversalTime()); // true
Converting to UTC time without changing the local time
Instead of converting to UTC (and in the process leaving the time the same, but the number of ticks different), you can also overwrite the DateTimeKind and set it to UTC (which changes the time, because it is now in UTC, but it compares as equal, as the number of ticks is equal).
var t1 = DateTime.Now
var t2 = DateTime.SpecifyKind(t1, DateTimeKind.Utc)
var areEqual = t1 == t2 // true
var stillEqual = t1.Equals(t2) // true
I guess that DateTime is one of those rare types that can be bitwise unequal, but compare as equal, or can be bitwise equal (the time part) and compare unequal.
Changes in .NET 6
In .NET 6.0, we now have TimeOnly and DateOnly. You can use these to store "just the time of day", of "just the date of the year". Combine these in a struct and you'll have a Date & Time struct without the historical nuisances of the original DateTime.
Alternatives
Working properly with DateTime, TimeZoneInfo, leap seconds, calendars, shifting timezones, durations etc is hard in .NET. I personally prefer NodaTime by Jon Skeet, which gives control back to the programmer in a meaningful an unambiguous way.
Often, when you’re not interested in the timezones per se, but just the offsets, you can get by with DateTimeOffset.
This insightful post by Jon Skeet explains in great depth the troubles a programmer can face when trying to circumvent all DateTime issues when just storing everything in UTC.
Background info from the source
If you check the DateTime struct in the .NET source, you'll find a note that explains how originally (in .NET 1.0) the DateTime was just the number of ticks, but that later they added the ability to store whether it was Universal or Local time. If you serialize, however, this info is lost.
This is the note in the source:
// This value type represents a date and time. Every DateTime
// object has a private field (Ticks) of type Int64 that stores the
// date and time as the number of 100 nanosecond intervals since
// 12:00 AM January 1, year 1 A.D. in the proleptic Gregorian Calendar.
//
// Starting from V2.0, DateTime also stored some context about its time
// zone in the form of a 3-state value representing Unspecified, Utc or
// Local. This is stored in the two top bits of the 64-bit numeric value
// with the remainder of the bits storing the tick count. This information
// is only used during time zone conversions and is not part of the
// identity of the DateTime. Thus, operations like Compare and Equals
// ignore this state. This is to stay compatible with earlier behavior
// and performance characteristics and to avoid forcing people into dealing
// with the effects of daylight savings. Note, that this has little effect
// on how the DateTime works except in a context where its specific time
// zone is needed, such as during conversions and some parsing and formatting
// cases.
To deal with this, I created my own DateTime object (let's call it SmartDateTime) that contains the DateTime and the TimeZone. I override all operators like == and Compare and convert to UTC before doing the comparison using the original DateTime operators.

Convert DateTime to Utc only if not already Utc

I'm using the DateTimeWithZone struct that Jon Skeet posted at Creating a DateTime in a specific Time Zone in c# fx 3.5
This didn't work exactly for my situation since it assumes that the DateTime passed in the constructor is the local time, and therefore converts it to Utc using the specified TimeZone.
In my case we will mostly be passing in DateTime objects already in Utc (since this is what we are storing) so we need to only perform the conversion if the source DateTime.Kind is not Utc.
Therefore I changed the constructor to:
public DateTimeWithZone(DateTime dateTime, TimeZoneInfo timeZone, DateTimeKind kind = DateTimeKind.Utc) {
dateTime = DateTime.SpecifyKind(dateTime, kind);
utcDateTime = TimeZoneInfo.ConvertTimeToUtc(dateTime, timeZone);
this.timeZone = timeZone;
}
Here we have an optional Kind parameter that defaults to Utc.
However, running this code and passing a Utc DateTime generates the following exception:
The conversion could not be completed because the supplied DateTime did not have the Kind property set correctly. For example, when the Kind property is DateTimeKind.Local, the source time zone must be TimeZoneInfo.Local.
According to the docs (http://msdn.microsoft.com/en-us/library/bb495915.aspx):
If the Kind property of the dateTime parameter equals DateTimeKind.Utc and the sourceTimeZone parameter equals TimeZoneInfo.Utc, this method returns dateTime without performing any conversion.
Since both the input time and the timezone both have a Kind property of Utc then I would not expect to get this exception.
Have I misunderstood?
Like the MSDN docs say if you pass in a DateTime with the kind set to anything besides DateTimeKind.Utc and specify a TimeZone other than Utc the conversion function will throw an exception. That Must be what is happening here. In your code you should check if the DateTime is already in Utc and skip the conversion if it is.
Also since the dateTime you are passing in will have a DateTime attached to it already you probably don't need to pass in a separate Kind parameter.
from the docs
Converts the time in a specified time
zone to Coordinated Universal Time
(UTC).
meaning that it converts from the time zone supplied to Utc
the function throws an argument exception if:
dateTime .Kind is DateTimeKind.Utc and
sourceTimeZone does not equal
TimeZoneInfo.Utc.
-or-
dateTime .Kind is DateTimeKind.Local
and sourceTimeZone does not equal
TimeZoneInfo.Local.
-or-
sourceTimeZone .IsInvalidDateTime(
dateTime ) returns true.

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