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How to create a request that looks like this

I need to replicate a HTTP request using C# and the HttpWebRequest, that looks like this:
HEADER: POST /upnp/control/x_contact HTTP/1.1 Host: fritz.box:49000
Connection: Keep-Alive User-Agent:...
So far I got everything working, except for the part after the POST
"/upnp/control/x_contact HTTP/1.1".
How would I have to modify the HttpWebRequest to get these additional data to the server?
PS: This is how the java code looks, that generates the correct request. I would like to port this code to C# and send the same request from there:
socket = new Socket(InetAddress.getByName("fritz.box"), 49000);
// Send header
writer = new BufferedWriter(new OutputStreamWriter(socket.getOutputStream(),"UTF-8"));
writer.write("POST /igdupnp/control/WANIPConn1 HTTP/1.1");
writer.write("Host: fritz.box:49000\r\n");
writer.write("SOAPACTION: \"urn:schemas-upnp-org:service:WANIPConnection:1#GetStatusInfo\"\r\n");
writer.write("Content-Type: text/xml; charset=\"utf-8\""+"\r\n");
writer.write("Content-Length: " + myData.length() + "\r\n");
writer.write("\r\n");
// Send data
writer.write(myData);
writer.flush();
And this is my C# code so far (producing an incomplete HTML request):
HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create (#"http://fritz.box:49000");
webRequest.Headers.Add ("SOAPACTION", "urn:schemas-upnp-org:service:WANIPConnection:1#GetStatusInfo");
webRequest.ContentType = "text/xml;charset=\"utf-8\"";
webRequest.Accept = "text/xml";
webRequest.Method = "POST";

REST API PATCH request

I'm trying to send requests and get responses from MailChimp API . . so far, GET, POST and DELETE are working good however, PATCH always results to Bad Request can you identify the error in this code?
string data = "{\"name\": \"TestListTWOTWOTWO\"}";
HttpWebRequest request = (HttpWebRequest)HttpWebRequest.Create(uri);
request.Headers[HttpRequestHeader.Authorization] = accessToken;
request.Method = "PATCH";
request.ContentType = "text/plain;charset=utf-8";
System.Text.UTF8Encoding encoding = new System.Text.UTF8Encoding();
byte[] bytes = encoding.GetBytes(data);
request.ContentLength = bytes.Length;
using (Stream requestStream = request.GetRequestStream())
{
// Send the data.
requestStream.Write(bytes, 0, bytes.Length);
}
var response = (HttpWebResponse)request.GetResponse();
var responseString = new StreamReader(response.GetResponseStream()).ReadToEnd();
the error occus on the line with request.GetResponse();
it is an unhandled WebException saying The remote server returned an error: (400) Bad Request
after checking the error response, here's the what it says
"Your request doesn't appear to be valid JSON:
\nParse error on line 1:\nPATCH /3.0/lists/9bb\n^\n
Expected one of: 'STRING', 'NUMBER', 'NULL', 'TRUE', 'FALSE', '{', '['"

Many C# libraries seem to try to use the Expect: 100-Continue header, which MailChimp/Akamai has a problem with when combined with PATCH. You have two options.
Turn off Expect: 100-Continue in your HTTP library. In one C# library, you do that with a line of code like Client.DefaultRequestHeaders.ExpectContinue = False
Tunnel the PATCH request through HTTP POST using the X-Http-Method-Override header. Here's more details on that header.

Cause PATCH is a quite new RFC, so you would not expect that more then a few services support it at all. You'd better check that if the service supports it.
You send request using json format, but set content type to "text/plain" is that OK?

Malformed string exception while sending "&" in Json to AppEngine

I am trying to send Facebook graph link to the AppEngine server. I receive "Malformed string exception". Here is my method sending json to server:
public async Task<string> SendJSONData(string urlToCall, string JSONData)
{
// server to POST to
string url = urlToCall;
// HTTP web request
var httpWebRequest = (HttpWebRequest)WebRequest.Create(url);
httpWebRequest.ContentType = "application/x-www-form-urlencoded";
httpWebRequest.Method = "POST";
// Write the request Asynchronously
using (var stream = await Task.Factory.FromAsync<Stream>(httpWebRequest.BeginGetRequestStream,
httpWebRequest.EndGetRequestStream, null))
{
//create some json string
string json = "action=" + JSONData;
// convert json to byte array
byte[] jsonAsBytes = Encoding.UTF8.GetBytes(json);
// Write the bytes to the stream
await stream.WriteAsync(jsonAsBytes, 0, jsonAsBytes.Length);
}
WebResponse response = await httpWebRequest.GetResponseAsync();
StreamReader requestReader = new StreamReader(response.GetResponseStream());
String webResponse = requestReader.ReadToEnd();
return webResponse; }
Here is what I sniff using Fiddler:
POST http://x.appspot.com/register HTTP/1.1
Accept: */*
Content-Length: 376
Accept-Encoding: identity
Content-Type: application/x-www-form-urlencoded
User-Agent: NativeHost
Host: x.appspot.com
Connection: Keep-Alive
Pragma: no-cache
action={
"mailFb": "mail#gmail.com",
"userName": "Michael",
"userSurname": "w00t",
"nickname": "Michael w00t",
"userSex": "male",
"userAvatar": "https://graph.facebook.com/myperfectid/picture?type=large&access_token=BlahblahblahblahToken"
}
So everything looks fine, but the problem is that i receive the following error in AppEngine log:
2013-03-02 17:52:10.431 /register 500 56ms 0kb NativeHost
W 2013-03-02 17:52:10.427 /register com.google.gson.JsonSyntaxException: com.google.gson.stream.MalformedJsonException: Unterminated string at line 7 column 79 at com.google.g
C 2013-03-02 17:52:10.429 Uncaught exception from servlet com.google.gson.JsonSyntaxException: com.google.gson.stream.MalformedJsonException: Unterminated string at line 7 colu
I managed to narrow the problem to its source, which is "&" character. So my question is, how to fix the code, so that it works with AppEngine.
Oh, here is how i read the received data on the server:
gson.fromJson(reader, User.class);

The problem is highlighted by the fact you're claiming you are sending "Content-Type: application/x-www-form-urlencoded"
But it isn't. Hence the error.
The correct encoding for & is &.

.NET C# using HTTPrequest similar to Curl script

I´m using .NET C# and want to use HTTPrequest to make a POST in the same way as it is written in Curl:
curl
--header ’Accept: text/html’
--user ’test1:password’
--Form ’wait=0’
--Form ’data=#data.csv;type=text/csv’
some URL address here
I´m getting Error 500 Internal error from the Internet server.
The data to be send is a CSV file.
My source code in C#:
string data = "Time, A, B\n20120101, 100, 24\n20120102\n, 101, 27";
// Create a request using a URL that can receive a post.
request = WebRequest.Create(url);
//Set authorization
request.Credentials = new NetworkCredential(username, password);
// Set the Method property of the request to POST.
request.Method = "POST";
// Create POST data and convert it to a byte array.
byte[] byteArray = Encoding.UTF8.GetBytes(data);
// Set the ContentType property of the WebRequest.
request.ContentType = "application/x-www-form-urlencoded";
// Set the ContentLength property of the WebRequest.
request.ContentLength = byteArray.Length;
// Get the request stream.
dataStream = request.GetRequestStream();
// Write the data to the request stream.
dataStream.Write(byteArray, 0, byteArray.Length);
// Close the Stream object.
dataStream.Close();
// Get the original response.
WebResponse response = request.GetResponse();
this.Status = ((HttpWebResponse)response).StatusDescription;
// Get the stream containing all content returned by the requested server.
dataStream = response.GetResponseStream();
// Open the stream using a StreamReader for easy access.
StreamReader reader = new StreamReader(dataStream);
// Read the content fully up to the end.
string responseFromServer = reader.ReadToEnd();
// Clean up the streams.
reader.Close();
dataStream.Close();
response.Close();
What am I doing wrong?

cURL uses the multipart/form-data content type to create its requests. I think this is required in your case as you are passing both a text parameter and a file. Sadly the .Net framework does not appear to have built in support for creating this content type.
There is a question on SO that gives example code for how to do it yourself here: Multipart forms from C# client
For reference the HTTP request generated by that cURL command looks something like this:
POST http://www.example.com/example HTTP/1.1
Authorization: Basic J3Rlc3Q6cGFzc3dvcmQn
User-Agent: curl/7.33.0
Host: www.example.com
Accept: text/html
Connection: Keep-Alive
Content-Length: 335
Expect: 100-continue
Content-Type: multipart/form-data; boundary=------------------------99aa46d554951aa6
--------------------------99aa46d554951aa6
Content-Disposition: form-data; name="'wait"
0'
--------------------------99aa46d554951aa6
Content-Disposition: form-data; name="'data"; filename="data.csv"
Content-Type: text/csv'
Time, A, B\n20120101, 100, 24\n20120102\n, 101, 27
--------------------------99aa46d554951aa6--

Doesn't data need to be URL encoded for a form post? http://en.wikipedia.org/wiki/POST_%28HTTP%29#Use_for_submitting_web_forms

Web Service always return empty plain/text

Has been using Service Reference without any success:
Web service return only XML
Now I am using the raw SOAP message to do it:
XmlDocument doc = new XmlDocument();
doc.Load("Service.xml");
// create the request to your URL
Uri wsHost = new Uri("http://www.rrr.net/services/Connect");
HttpWebRequest request = (HttpWebRequest) WebRequest.Create(wsHost);
// add the headers
// the SOAPACtion determines what action the web service should use
request.Headers.Add("SOAPAction", "act");
// set the request type
request.ContentType = "text/xml;charset=\"utf-8\"";
request.Accept = "text/xml";
request.Method = "POST";
// add our body to the request
Stream stream = request.GetRequestStream();
doc.Save(stream);
stream.Close();
// get the response back
using( HttpWebResponse response = (HttpWebResponse)request.GetResponse() )
{
Stream dataStream = response.GetResponseStream();
StreamReader dataReader = new StreamReader(dataStream);
// Use Linq to read the xml response
using (XmlReader reader = XmlReader.Create(dataStream))
{
The post is correct, but response always give me text/plain empty result, the reponse header:
Headers = {Keep-Alive: timeout=5, max=100
Connection: Keep-Alive
Transfer-Encoding: chunked
Content-Type: text/plain
Date: Thu, 06 Sep 2012 15:59:28 GMT
}
The SOAP message is, act is the function:
<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" xmlns:web="http://webService">
<soapenv:Header/>
<soapenv:Body>
<web:act>
<web:d1>1</web:d1>
<web:d2>14</web:d2>
</web:act>
</soapenv:Body>
</soapenv:Envelope>
I use SoapUI, below is the raw request from SoapUI, it return a xml result:
POST http://www.rrr.net/services/Connect HTTP/1.1
Accept-Encoding: gzip,deflate
Content-Type: text/xml;charset=UTF-8
SOAPAction: ""
Content-Length: 516
Host: www.rrr.net
Connection: Keep-Alive
User-Agent: Apache-HttpClient/4.1.1 (java 1.5)
Thank you.

SOAP webservices require action/method to be specified (and NOT empty). If you don't know which action you want you can look at webservice WSDL by invoking the webservice with queryString "?WSDL". I.e. www.yourSite.com/your/Web/Service/URL?WSDL

You must specify an action in both the request and also the service interface. You can set the action value on the interface member using the attributes shown below and then in the request using the method you have used but by specifying the action name you used in the contract:
The attributes on the interface member
[OperationContract Name="YourActionName"]
[WebInvoke (Method = "POST", UriTemplate = "YourActionName")]
Message YourServiceFunction();
One method of specifying the action on the message
Message inputMessage = Message.CreateMessage (MessageVersion.Soap, "YourActionName", reader);