When users click on a button, I want it to run the logon script(launching from server), but each computer in different servers, so I get the server name. But the netlogon.StartInfo.Arguments = slnres + #"/c \netlogon\logon.cmd"; line is not working as it should be. It should run the logon.cmd on the PC(mapping network drivers, printers, etc), and then the CMD should close.
private void MapNetwork_Click(object sender, EventArgs e)
{
Process sln = new Process();
sln.StartInfo.UseShellExecute = false;
sln.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
sln.StartInfo.FileName = "cmd.exe";
sln.StartInfo.Arguments = "/c echo %logonserver%";
sln.StartInfo.RedirectStandardOutput = true;
sln.Start();
string slnres = sln.StandardOutput.ReadToEnd();
label1.Text = slnres;
Process netlogon = new Process();
netlogon.StartInfo.UseShellExecute = false;
netlogon.StartInfo.FileName = "cmd.exe";
netlogon.StartInfo.Arguments = slnres + #"/c \netlogon\logon.cmd";
netlogon.Start();
}
A couple things:
You don't need to run a command prompt to get an environment variable. You can use Environment.GetEnvironmentVariable.
Your Arguments property for your call to logon.cmd is being constructed into this:
\\myserver/c \netlogon\logon.cmd
When I think you want this:
/c \\myserver\netlogon\logon.cmd
So make sure you put slnres at the right place in your string. Your code should look like this:
private void MapNetwork_Click(object sender, EventArgs e)
{
string slnres = Environment.GetEnvironmentVariable("logonserver");
label1.Text = slnres;
Process netlogon = new Process();
netlogon.StartInfo.UseShellExecute = false;
netlogon.StartInfo.FileName = "cmd.exe";
netlogon.StartInfo.Arguments = "/c " + slnres + #"\netlogon\logon.cmd";
netlogon.Start();
}
i am a little confused about your question and i am not rly sure if i understand you correctly. some time ago i made a program where i had to run few powershell commands, so i made a class for it. redirected to your button it would look like that:
(and remember you need the fqdn to your file location => Reading File From Network Location)
using System.Diagnostics;
//class lvl scope vars
string output;
string ErrorOutput;
private void MapNetwork_Click(object sender, EventArgs e)
{
//define process arguments
ProcessStartInfo startInfo = new ProcessStartInfo();
startInfo.FileName = #"cmd.exe";
startInfo.Arguments = #"FQDN path to your file on the server; exit";
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardError = true;
//start process
Process process = new Process();
process.StartInfo = startInfo;
process.Start();
process.WaitForExit();
//outpunt handling
if (string.IsNullOrEmpty(ErrorOutput))
{
return output;
}
else
{
return ErrorOutput;
}
}
first of all i would check if your application is able to open the file one the shared network location. (server available? access rights to server? serer mapped?)
after that you can check if he is able to start the file locally. (does it need admin rights to run the *.cmd, *.bat file)
now you can check if your application runs it correctly.
I am using ImageMagick convert.exe(to re-size a image) in command line. It works great. But if I do the same in C# then It doesn't work. It does not show any error and all the lines run just fine. The StanderdErrorOutput is also empty. Any idea? Here is my code.
var myProcess = new Process();
myProcess.StartInfo.FileName = #"C:\Users\user\Desktop\ImageMagick-6.8.6-Q16\convert.exe";
myProcess.StartInfo.Arguments = #"icon.png -resize 64x64 icon1.png";
myProcess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
myProcess.StartInfo.CreateNoWindow = true;
myProcess.Start();
myProcess.WaitForExit();
Console.Read();
This is what I use to run processes, it's basically the same as what you have there except for the line that calls StandardError.ReadToEnd()
// create process start info
ProcessStartInfo startInfo = new ProcessStartInfo(fileName, arguments);
startInfo.UseShellExecute = false;
startInfo.CreateNoWindow = true;
startInfo.RedirectStandardOutput = true;
startInfo.RedirectStandardError = true;
// run the process
using (Process proc = System.Diagnostics.Process.Start(startInfo))
{
// This needs to be before WaitForExit() to prevent deadlocks, for details:
// http://msdn.microsoft.com/en-us/library/system.diagnostics.process.standardoutput%28v=VS.80%29.aspx
proc.StandardError.ReadToEnd();
// Wait for exit
proc.WaitForExit();
}
I found the solution by creating a temporary batch file,
static void Main(string[] args)
{
var guid = Guid.NewGuid().ToString();
var root = AppDomain.CurrentDomain.BaseDirectory;
var batchFilePath = root + guid + ".bat";
var cmd = #"cd C:\Users\user\Desktop\ImageMagick-6.8.6-Q16" + Environment.NewLine
+ "convert icon.png -resize 64x64 icon1.png";
CreateBatchFile(cmd, batchFilePath);// Temporary Batch file
RunBatchFile(batchFilePath);
DeleteBatchFile(batchFilePath);
}
private static void RunBatchFile(string batFilePath)
{
var myProcess = new Process();
myProcess.StartInfo.FileName = batFilePath;
myProcess.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
myProcess.StartInfo.CreateNoWindow = true;
myProcess.Start();
myProcess.WaitForExit();
}
private static void DeleteBatchFile(string file)
{
File.Delete(file);
}
private static void CreateBatchFile(string input, string filePath)
{
FileStream fs = new FileStream(filePath, FileMode.Create);
StreamWriter writer = new StreamWriter(fs);
writer.WriteLine(input);
writer.Close();
fs.Close();
}
I was having a similar problem on Mac when trying to run Convert, even with the ReadToEnd() suggested by the other poster.
I found that by adding
-debug 'All'
option caused it to work.
I have not ideas why!
i am build application who run Wireshark and start sniffing, Wireshark has dumpcap.exe file who receive arguments (interface number, output file etc) and start sniffing and meanwhile i can see in the cmd window the number of packet and this number growing all the time.
my question is how can i catch this number every few seconds in order to show this number on my application windows.
this is my class who start this sniffing:
public class DumpPcap
{
public int _interfaceNumber;
public string _pcapPath;
public string _dumPcapPath = #"C:\Program Files\Wireshark\dumpcap.exe";
public DumpPcap(int interfaceNumber, string pcapPath)
{
_interfaceNumber = interfaceNumber;
_pcapPath = pcapPath;
}
public void startTheCapture()
{
List<string> stList = new List<string>();
ProcessStartInfo process = new ProcessStartInfo(_dumPcapPath);
process.Arguments = string.Format("-i " + _interfaceNumber + " -s 65535 -w " + _pcapPath);
process.WindowStyle = ProcessWindowStyle.Hidden;
process.RedirectStandardOutput = true;
process.RedirectStandardError = true;
process.CreateNoWindow = true;
process.UseShellExecute = false;
process.ErrorDialog = false;
Process dumpcap = Process.Start(process);
StreamReader reader = dumpcap.StandardOutput;
//dumpcap.WaitForExit(100000);
while (!reader.EndOfStream)
{
stList.Add(reader.ReadLine());
}
}
}
and this is screenshot and i marked in red the field that i want to show in my application:
http://image.torrent-invites.com/images/641Untitled.jpg
Instead of trying to capture output text from the ProcessStartInfo how about doing it from the Process, and intercept the output data via the OutputDataReceived event handler?
Try this replacement to your block of code:
List<string> stList = new List<string>();
var process = new Process();
process.StartInfo.FileName = _dumPcapPath;
process.StartInfo.Arguments =
string.Format("-i " + _interfaceNumber + " -s 65535 -w " + _pcapPath);
process.Startinfo.WindowStyle = ProcessWindowStyle.Hidden;
process.Startinfo.RedirectStandardOutput = true;
process.Startinfo.RedirectStandardError = true;
process.Startinfo.CreateNoWindow = true;
process.Startinfo.UseShellExecute = false;
process.Startinfo.ErrorDialog = false;
// capture the data received event here...
process.OutputDataReceived +=
new DataReceivedEventHandler(process_OutputDataReceived);
process.Start();
process.BeginOutputReadLine();
private void process_OutputDataReceived(object sender, DataReceivedEventArgs arg)
{
// arg.Data contains the output data from the process...
}
NOTE: I just typed this in without compiling or any serious validating, so be warned, LOL...
I'm trying to use the following C# code to compile Java using javac:
Process p = new Process();
p.StartInfo.FileName = "javac";
Directory.CreateDirectory(Application.StartupPath + #"/TempJava");
p.StartInfo.Arguments = "-d "Application.StartupPath + #"/TempJava" + files;
p.Start();
"files" represents a string variable containing the name(s) of the *.java files.
All in all, I want to create a new folder, and then take the Java files (from where ever they may be located) and compile it into a class file(s) in TempJava.
For some reason, the code doesn't work, no errors, no warnings, but when I run it and check TempJava, there's no files in it.
Just because your child process ends with a possible error, it doesn't mean your parent process must be aware of it.
Inspect the process' exit code and standard output stream, and especially the standard error stream. Your answer lies in there...
here i have 2 buttons run and compile here is some code to help.
private void comp_Click(object sender, EventArgs e)
{
string text = "javac " + label1.Text + file + "#pause" + "#stop";
text = text.Replace("#", System.Environment.NewLine);
File.WriteAllText(label1.Text + "Compile.bat", text);
Process proc = null;
try
{
proc = new Process();
proc.StartInfo.FileName = label1.Text + "Compile.bat";
proc.StartInfo.CreateNoWindow = false;
proc.Start();
proc.WaitForExit();
}
catch
{
}
}
private void runp_Click(object sender, EventArgs e)
{
string news = file.Remove(file.Length - 5);
string text = "java " + news + "#pause";
text = text.Replace("#", System.Environment.NewLine);
File.WriteAllText(label1.Text + "Run.bat", text);
Process proc = null;
try
{
proc = new Process();
proc.StartInfo.FileName = label1.Text + "Run.bat";
proc.StartInfo.WorkingDirectory = label1.Text.Remove(label1.Text.Length - 1);
proc.StartInfo.CreateNoWindow = true;
proc.Start();
proc.WaitForExit();
}
catch
{
}
}
all i really do is create a batch and run it using c#.
How do I execute a command-line program from C# and get back the STD OUT results? Specifically, I want to execute DIFF on two files that are programmatically selected and write the results to a text box.
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "YOURBATCHFILE.bat";
p.Start();
// Do not wait for the child process to exit before
// reading to the end of its redirected stream.
// p.WaitForExit();
// Read the output stream first and then wait.
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Code is from MSDN.
Here's a quick sample:
//Create process
System.Diagnostics.Process pProcess = new System.Diagnostics.Process();
//strCommand is path and file name of command to run
pProcess.StartInfo.FileName = strCommand;
//strCommandParameters are parameters to pass to program
pProcess.StartInfo.Arguments = strCommandParameters;
pProcess.StartInfo.UseShellExecute = false;
//Set output of program to be written to process output stream
pProcess.StartInfo.RedirectStandardOutput = true;
//Optional
pProcess.StartInfo.WorkingDirectory = strWorkingDirectory;
//Start the process
pProcess.Start();
//Get program output
string strOutput = pProcess.StandardOutput.ReadToEnd();
//Wait for process to finish
pProcess.WaitForExit();
There one other parameter I found useful, which I use to eliminate the process window
pProcess.StartInfo.CreateNoWindow = true;
this helps to hide the black console window from user completely, if that is what you desire.
// usage
const string ToolFileName = "example.exe";
string output = RunExternalExe(ToolFileName);
public string RunExternalExe(string filename, string arguments = null)
{
var process = new Process();
process.StartInfo.FileName = filename;
if (!string.IsNullOrEmpty(arguments))
{
process.StartInfo.Arguments = arguments;
}
process.StartInfo.CreateNoWindow = true;
process.StartInfo.WindowStyle = ProcessWindowStyle.Hidden;
process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardError = true;
process.StartInfo.RedirectStandardOutput = true;
var stdOutput = new StringBuilder();
process.OutputDataReceived += (sender, args) => stdOutput.AppendLine(args.Data); // Use AppendLine rather than Append since args.Data is one line of output, not including the newline character.
string stdError = null;
try
{
process.Start();
process.BeginOutputReadLine();
stdError = process.StandardError.ReadToEnd();
process.WaitForExit();
}
catch (Exception e)
{
throw new Exception("OS error while executing " + Format(filename, arguments)+ ": " + e.Message, e);
}
if (process.ExitCode == 0)
{
return stdOutput.ToString();
}
else
{
var message = new StringBuilder();
if (!string.IsNullOrEmpty(stdError))
{
message.AppendLine(stdError);
}
if (stdOutput.Length != 0)
{
message.AppendLine("Std output:");
message.AppendLine(stdOutput.ToString());
}
throw new Exception(Format(filename, arguments) + " finished with exit code = " + process.ExitCode + ": " + message);
}
}
private string Format(string filename, string arguments)
{
return "'" + filename +
((string.IsNullOrEmpty(arguments)) ? string.Empty : " " + arguments) +
"'";
}
The accepted answer on this page has a weakness that is troublesome in rare situations. There are two file handles which programs write to by convention, stdout, and stderr.
If you just read a single file handle such as the answer from Ray, and the program you are starting writes enough output to stderr, it will fill up the output stderr buffer and block. Then your two processes are deadlocked. The buffer size may be 4K.
This is extremely rare on short-lived programs, but if you have a long running program which repeatedly outputs to stderr, it will happen eventually. This is tricky to debug and track down.
There are a couple good ways to deal with this.
One way is to execute cmd.exe instead of your program and use the /c argument to cmd.exe to invoke your program along with the "2>&1" argument to cmd.exe to tell it to merge stdout and stderr.
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/c mycmd.exe 2>&1";
Another way is to use a programming model which reads both handles at the same time.
var p = new Process();
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = #"/c dir \windows";
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardError = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.RedirectStandardInput = false;
p.OutputDataReceived += (a, b) => Console.WriteLine(b.Data);
p.ErrorDataReceived += (a, b) => Console.WriteLine(b.Data);
p.Start();
p.BeginErrorReadLine();
p.BeginOutputReadLine();
p.WaitForExit();
System.Diagnostics.ProcessStartInfo psi =
new System.Diagnostics.ProcessStartInfo(#"program_to_call.exe");
psi.RedirectStandardOutput = true;
psi.WindowStyle = System.Diagnostics.ProcessWindowStyle.Hidden;
psi.UseShellExecute = false;
System.Diagnostics.Process proc = System.Diagnostics.Process.Start(psi); ////
System.IO.StreamReader myOutput = proc.StandardOutput;
proc.WaitForExit(2000);
if (proc.HasExited)
{
string output = myOutput.ReadToEnd();
}
You will need to use ProcessStartInfo with RedirectStandardOutput enabled - then you can read the output stream. You might find it easier to use ">" to redirect the output to a file (via the OS), and then simply read the file.
[edit: like what Ray did: +1]
One-liner run command:
new Process() { StartInfo = new ProcessStartInfo("echo", "Hello, World") }.Start();
Read output of command in shortest amount of reable code:
var cliProcess = new Process() {
StartInfo = new ProcessStartInfo("echo", "Hello, World") {
UseShellExecute = false,
RedirectStandardOutput = true
}
};
cliProcess.Start();
string cliOut = cliProcess.StandardOutput.ReadToEnd();
cliProcess.WaitForExit();
cliProcess.Close();
In case you also need to execute some command in the cmd.exe, you can do the following:
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.StartInfo.Arguments = "/C vol";
p.Start();
// Read the output stream first and then wait.
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine(output);
This returns just the output of the command itself:
You can also use StandardInput instead of StartInfo.Arguments:
// Start the child process.
Process p = new Process();
// Redirect the output stream of the child process.
p.StartInfo.UseShellExecute = false;
p.StartInfo.RedirectStandardInput = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.FileName = "cmd.exe";
p.Start();
// Read the output stream first and then wait.
p.StandardInput.WriteLine("vol");
p.StandardInput.WriteLine("exit");
string output = p.StandardOutput.ReadToEnd();
p.WaitForExit();
Console.WriteLine(output);
The result looks like this:
Since the most answers here dont implement the using statemant for IDisposable and some other stuff wich I think could be nessecary I will add this answer.
For C# 8.0
// Start a process with the filename or path with filename e.g. "cmd". Please note the
//using statemant
using myProcess.StartInfo.FileName = "cmd";
// add the arguments - Note add "/c" if you want to carry out tge argument in cmd and
// terminate
myProcess.StartInfo.Arguments = "/c dir";
// Allows to raise events
myProcess.EnableRaisingEvents = true;
//hosted by the application itself to not open a black cmd window
myProcess.StartInfo.UseShellExecute = false;
myProcess.StartInfo.CreateNoWindow = true;
// Eventhander for data
myProcess.Exited += OnOutputDataRecived;
// Eventhandler for error
myProcess.ErrorDataReceived += OnErrorDataReceived;
// Eventhandler wich fires when exited
myProcess.Exited += OnExited;
// Starts the process
myProcess.Start();
//read the output before you wait for exit
myProcess.BeginOutputReadLine();
// wait for the finish - this will block (leave this out if you dont want to wait for
// it, so it runs without blocking)
process.WaitForExit();
// Handle the dataevent
private void OnOutputDataRecived(object sender, DataReceivedEventArgs e)
{
//do something with your data
Trace.WriteLine(e.Data);
}
//Handle the error
private void OnErrorDataReceived(object sender, DataReceivedEventArgs e)
{
Trace.WriteLine(e.Data);
//do something with your exception
throw new Exception();
}
// Handle Exited event and display process information.
private void OnExited(object sender, System.EventArgs e)
{
Trace.WriteLine("Process exited");
}
Here is small example:
using System;
using System.Diagnostics;
class Program
{
static void Main(string[] args)
{
var p = Process.Start(
new ProcessStartInfo("git", "branch --show-current")
{
CreateNoWindow = true,
UseShellExecute = false,
RedirectStandardError = true,
RedirectStandardOutput = true,
WorkingDirectory = Environment.CurrentDirectory
}
);
p.WaitForExit();
string branchName =p.StandardOutput.ReadToEnd().TrimEnd();
string errorInfoIfAny =p.StandardError.ReadToEnd().TrimEnd();
if (errorInfoIfAny.Length != 0)
{
Console.WriteLine($"error: {errorInfoIfAny}");
}
else {
Console.WriteLine($"branch: {branchName}");
}
}
}
I believe this is shortest form.
Please notice that most of command line tools easily confuse standard output and standard error, sometimes it makes sense just to clue those together into single string.
Also p.ExitCode might be sometimes useful.
Example above serves for purpose of writing command line utility like tools if you want to do it by yourself. Please note that for cli automation it's also possible to use Cake Frosten and Cake Git extension.
You can launch any command line program using the Process class, and set the StandardOutput property of the Process instance with a stream reader you create (either based on a string or a memory location). After the process completes, you can then do whatever diff you need to on that stream.
This might be useful for someone if your attempting to query the local ARP cache on a PC/Server.
List<string[]> results = new List<string[]>();
using (Process p = new Process())
{
p.StartInfo.CreateNoWindow = true;
p.StartInfo.RedirectStandardOutput = true;
p.StartInfo.UseShellExecute = false;
p.StartInfo.Arguments = "/c arp -a";
p.StartInfo.FileName = #"C:\Windows\System32\cmd.exe";
p.Start();
string line;
while ((line = p.StandardOutput.ReadLine()) != null)
{
if (line != "" && !line.Contains("Interface") && !line.Contains("Physical Address"))
{
var lineArr = line.Trim().Split(' ').Select(n => n).Where(n => !string.IsNullOrEmpty(n)).ToArray();
var arrResult = new string[]
{
lineArr[0],
lineArr[1],
lineArr[2]
};
results.Add(arrResult);
}
}
p.WaitForExit();
}
This may not be the best/easiest way, but may be an option:
When you execute from your code, add " > output.txt" and then read in the output.txt file.
There is a ProcessHelper Class in PublicDomain open source code which might interest you.
Julian's solution is tested working with some minor corrections. The following is an example that also used https://sourceforge.net/projects/bat-to-exe/ GenericConsole.cs and https://www.codeproject.com/Articles/19225/Bat-file-compiler program.txt for args part:
using System;
using System.Text; //StringBuilder
using System.Diagnostics;
using System.IO;
class Program
{
private static bool redirectStandardOutput = true;
private static string buildargument(string[] args)
{
StringBuilder arg = new StringBuilder();
for (int i = 0; i < args.Length; i++)
{
arg.Append("\"" + args[i] + "\" ");
}
return arg.ToString();
}
static void Main(string[] args)
{
Process prc = new Process();
prc.StartInfo = //new ProcessStartInfo("cmd.exe", String.Format("/c \"\"{0}\" {1}", Path.Combine(Environment.CurrentDirectory, "mapTargetIDToTargetNameA3.bat"), buildargument(args)));
//new ProcessStartInfo(Path.Combine(Environment.CurrentDirectory, "mapTargetIDToTargetNameA3.bat"), buildargument(args));
new ProcessStartInfo("mapTargetIDToTargetNameA3.bat");
prc.StartInfo.Arguments = buildargument(args);
prc.EnableRaisingEvents = true;
if (redirectStandardOutput == true)
{
prc.StartInfo.UseShellExecute = false;
}
else
{
prc.StartInfo.UseShellExecute = true;
}
prc.StartInfo.CreateNoWindow = true;
prc.OutputDataReceived += OnOutputDataRecived;
prc.ErrorDataReceived += OnErrorDataReceived;
//prc.Exited += OnExited;
prc.StartInfo.RedirectStandardOutput = redirectStandardOutput;
prc.StartInfo.RedirectStandardError = redirectStandardOutput;
try
{
prc.Start();
prc.BeginOutputReadLine();
prc.BeginErrorReadLine();
prc.WaitForExit();
}
catch (Exception e)
{
Console.WriteLine("OS error: " + e.Message);
}
prc.Close();
}
// Handle the dataevent
private static void OnOutputDataRecived(object sender, DataReceivedEventArgs e)
{
//do something with your data
Console.WriteLine(e.Data);
}
//Handle the error
private static void OnErrorDataReceived(object sender, DataReceivedEventArgs e)
{
Console.WriteLine(e.Data);
}
// Handle Exited event and display process information.
//private static void OnExited(object sender, System.EventArgs e)
//{
// var process = sender as Process;
// if (process != null)
// {
// Console.WriteLine("ExitCode: " + process.ExitCode);
// }
// else
// {
// Console.WriteLine("Process exited");
// }
//}
}
The code need to compile inside VS2007, using commandline csc.exe generated executable will not show console output correctly, or even crash with CLR20r3 error. Comment out the OnExited event process, the console output of the bat to exe will be more like the original bat console output.
Just for fun, here's my completed solution for getting PYTHON output - under a button click - with error reporting. Just add a button called "butPython" and a label called "llHello"...
private void butPython(object sender, EventArgs e)
{
llHello.Text = "Calling Python...";
this.Refresh();
Tuple<String,String> python = GoPython(#"C:\Users\BLAH\Desktop\Code\Python\BLAH.py");
llHello.Text = python.Item1; // Show result.
if (python.Item2.Length > 0) MessageBox.Show("Sorry, there was an error:" + Environment.NewLine + python.Item2);
}
public Tuple<String,String> GoPython(string pythonFile, string moreArgs = "")
{
ProcessStartInfo PSI = new ProcessStartInfo();
PSI.FileName = "py.exe";
PSI.Arguments = string.Format("\"{0}\" {1}", pythonFile, moreArgs);
PSI.CreateNoWindow = true;
PSI.UseShellExecute = false;
PSI.RedirectStandardError = true;
PSI.RedirectStandardOutput = true;
using (Process process = Process.Start(PSI))
using (StreamReader reader = process.StandardOutput)
{
string stderr = process.StandardError.ReadToEnd(); // Error(s)!!
string result = reader.ReadToEnd(); // What we want.
return new Tuple<String,String> (result,stderr);
}
}