C# for skipping some - c#

I am asking a question today because I look is skipping certain items and I think it is because its running too fast and doing too much, is there a way to fix this without manually putting a thread.sleep of like 10ms after each loop element?
Is this a known issue? any help would be appreciated! The for loop I am talking about is the 3rd one, the one after the two nested set of for's
There is about 104 items in squares after the first 2 foreach's are ran, there could be up to 1000, what is the best way to stop it skipping?
If I don't put a thread.sleep there, only the first occurence works, the rest of the items in the foreach DONT work
If I do 10ms, 3-4 miss
If I do 15ms they all work
List<string> squares = new List<string>();
var minX = 1;
var minY = 1;
var maxX = room.Model.MapSizeX;
var maxY = room.Model.MapSizeY;
for (var currentX = minX; currentX <= maxX; ++currentX)
{
for (var currentY = minY; currentY <= maxY; ++currentY)
{
if (!room.GetGameMap().ItemCanBePlacedHere(currentX, currentY))
{
continue;
}
squares.Add(currentX + "," + currentY);
}
}
foreach (string tileString in squares)
{
var x = Convert.ToInt32(tileString.Split(',')[0]);
var y = Convert.ToInt32(tileString.Split(',')[1]);
session.SendWhisper("Attempting to place an item in X" + x + " and Y" + y);
if (!room.GetGameMap().ItemCanBePlacedHere(x, y))
{
session.SendWhisper("Can't place an item in X" + x + " Y" + y);
continue;
}
var newItem = new Item(new Random().Next(), room.RoomId, 1536, "", x, y, 0, 0, session.GetPlayerData().Id, 0, 0, 0, "", room);
newItem.ExtraData = "1";
newItem.UpdateState();
room.SendMessage(new ObjectAddComposer(newItem, room));
room.GetGameMap().AddToMap(newItem);
// I only put this here because it skips
// This slows it down a little and doesnt
// Make it skip 3-5 of the items
System.Threading.Thread.Sleep(15);
}

Related

Looping over 3D array in parallel.for

I have a 3D array with arbitrary X, Y and Z lengths
I want to iterate over it in a parallel.for loop, which can't be nested without wasting tasks afaik
Instead, the single loop's length is ArrayLengthX * ArrayLengthY * ArrayLengthZ
Can I mathematically get the current 3D array element from the current iteration + the X, Y and Z length of the array? if so how?
edit : Example below, hope this is enough to understand what's going on
DimensionSettings dimensionSettings = dimension.Settings;
Vector3Int DimSize = dimensionSettings.GetDimensionSize();
TaskProgressMutex.WaitOne();
CurrentProgress = 0;
TotalProgress = DimSize.x * DimSize.y * DimSize.z;
TaskProgressMutex.ReleaseMutex();
int ChunkAmount = DimSize.x * DimSize.y * DimSize.z;
GD.Print("Chunks to generate : " + ChunkAmount);
ParallelLoopResult result = Parallel.For(0, ChunkAmount, (int i) =>
{
GD.Print(i);
int xcoords = ???;
int ycoords = ???;
int zcoords = ???;
Vector3Int ChunkCoords = new Vector3Int(xcoords, ycoords, zcoords);
GD.Print("Current Chunk : " + xcoords + " " + ycoords + " " + zcoords);
GenerateChunk(ChunkCoords, seed);
TaskProgressMutex.WaitOne();
CurrentProgress += 1;
//GD.Print("Chunk " + xcoords + " " + ycoords + " " + zcoords + " finished generating. Current Progress : " + CurrentProgress);
TaskProgressMutex.ReleaseMutex();
});
My suggestion is to parallelize only the outer loop (the X dimension), and do normal (non-parallel) inner loops for the Y and Z dimensions:
ParallelOptions options = new()
{
MaxDegreeOfParallelism = Environment.ProcessorCount
};
Parallel.For(0, dimSize.X, options, (int x) =>
{
for (int y = 0; y < dimSize.Y; y++)
{
for (int z = 0; z < dimSize.Z; z++)
{
Vector3Int chunkCoords = new (x, y, z);
GenerateChunk(chunkCoords, seed);
}
}
});
The idea is to increase the chunkiness of the parallel work. In general the more chunky is the workload, the less is the overall overhead of the parallelization. At the other extreme, if each unit of work is too chunky, the partitioning of the work may become imbalanced.
Also when you use the Parallel.For/Parallel.ForEach/Parallel.Invoke methods I am suggesting to specify always the MaxDegreeOfParallelism, although this suggestion deviates from the general advice offered in the official documentation.

Find points with maximum visibility in a room-as-grid

I have a 2D grid of cells, like so:
I want to find the "centroids," or the places in each room that can see the most other cells. For example, "centroid" 1 can see 500 other cells, "centroid" 2 can see 400 other cells (NOT included in the first 500), and so on (if there's a better name for this let me know).
I'm currently doing this with the code below.
public void SetCentroids(CellWalkableState[,] grid)
{
centroids = new List<((int, int), int)>();
List<(int, int)> cellsCopy = new List<(int, int)>();
for (int i = 0; i < cells.Count; i++)
{
cellsCopy.Add(cells[i]);
}
Debug.Log(DateTime.Now.ToString("o") + " - Setting centroids for room with " + cells.Count + " cells");
var perCellInView = cellsCopy.AsParallel().Select(x => (x, StaticClass.FindInView(x, grid))).ToList();
var force_start = perCellInView.First();
Debug.Log(DateTime.Now.ToString("o") + " - got in view");
var perCellInViewOrdered = perCellInView.AsParallel().OrderByDescending(xxx => xxx.Item2.Count);
var force_start_1 = perCellInViewOrdered.First();
Debug.Log(DateTime.Now.ToString("o") + " - sorted");
List<(int, int)> roomCellsAdded = new List<(int, int)>();
while(roomCellsAdded.Count < (cells.Count*0.9))
{
if(cellsCopy.Count == 0)
{
Debug.LogError("something is wrong here.");
}
var centroid = perCellInViewOrdered.First().x;
var centroidCells = perCellInViewOrdered.First().Item2;
if(centroidCells.Count == 0)
{
Debug.Log("this shouldnt be happening");
break;
}
roomCellsAdded.AddRange(centroidCells);
centroids.Add((centroid, centroidCells.Count));
Debug.Log(DateTime.Now.ToString("o") + " - added centroids, " + roomCellsAdded.Count + " cells in view");
var loopPerCellInView = perCellInView.AsParallel().Where(x => centroids.Select(y => y.Item1).Contains(x.x) == false).Select(x => (x.x, x.Item2.Except(roomCellsAdded).ToList())).ToList();
Debug.Log(DateTime.Now.ToString("o") + " - excluded");
perCellInViewOrdered = loopPerCellInView.AsParallel().OrderByDescending(xxx => xxx.Item2.Count);
Debug.Log(DateTime.Now.ToString("o") + " - resorted");
}
}
public static List<(int, int)> FindInView((int,int) start, CellWalkableState[,] grid)
{
List<(int, int)> visible = new List<(int, int)>() { start };
bool alive = true;
int r = 1;
var length_x = grid.GetLength(0);
var length_y = grid.GetLength(1);
List<(int, int)> searched = new List<(int, int)>();
List<double> angles = new List<double>();
while(alive)
{
//alive = false;
int newR = r;
int count = CountFromR(newR);
var angleInc = 360.0 / count;
var rNexts = Enumerable.Repeat(1, count).ToArray();
for (int i = 0; i < count; i++)
{
var angle = angleInc * i;
if(angles.Contains(angle) == false)
{
angles.Add(angle);
float cos = Mathf.Cos((float)(Mathf.Deg2Rad * angle));
float sin = Mathf.Sin((float)(Mathf.Deg2Rad * angle));
var b = r;
var p = i % (r * 2);
var d = math.sqrt(math.pow(b, 2) + math.pow(p, 2));
var dScaled = d / r;
bool keepGoing = true;
while(keepGoing)
{
var rCur = dScaled * (rNexts[i]);
var loc = (start.Item1 + Mathf.RoundToInt(rCur * cos), start.Item2 + Mathf.RoundToInt(rCur * sin));
if (searched.Contains(loc) == false)
{
searched.Add(loc);
if (loc.Item1 >= 0 && loc.Item1 < length_x && loc.Item2 >= 0 && loc.Item2 < length_y)
{
if (grid[loc.Item1, loc.Item2] == CellWalkableState.Interactive || grid[loc.Item1, loc.Item2] == CellWalkableState.Walkable)
{
visible.Add(loc);
}
else
{
keepGoing = false;
}
}
else
{
keepGoing = false; // invalid, stop
}
}
else
{
if (visible.Contains(loc) == false)
{
keepGoing = false; // can stop, because we can't see past this place
}
}
if(keepGoing)
{
rNexts[i]++;
}
}
}
}
angles = angles.Distinct().ToList();
searched = searched.Distinct().ToList();
visible = visible.Distinct().ToList();
if(rNexts.All(x => x <= r))
{
alive = false;
}
else
{
r = rNexts.Max();
}
}
return visible;
}
static int CountFromR(int r)
{
return 8 * r;
}
The "short" summary of the code above is that each location first determines what cells around itself it can see. That becomes a list of tuples, List<((int,int), List<(int,int)>)>, where the first item is the location and the second is all cells it views. That main list is sorted by the count of the sublist, such that the item with the most cells-it-can-vew is first. That's added as a centroid, and all cells it can view are added to a second ("already handled") list. A modified "main list" is formed, with each sublist now excluding anything in the second list. It loops doing this until 90% of the cells have been added.
Some output:
2021-04-27T15:24:39.8678545-04:00 - Setting centroids for room with 7129 cells
2021-04-27T15:45:26.4418515-04:00 - got in view
2021-04-27T15:45:26.4578551-04:00 - sorted
2021-04-27T15:45:27.3168517-04:00 - added centroids, 4756 cells in view
2021-04-27T15:45:27.9868523-04:00 - excluded
2021-04-27T15:45:27.9868523-04:00 - resorted
2021-04-27T15:45:28.1058514-04:00 - added centroids, 6838 cells in view
2021-04-27T15:45:28.2513513-04:00 - excluded
2021-04-27T15:45:28.2513513-04:00 - resorted
2021-04-27T15:45:28.2523509-04:00 - Setting centroids for room with 20671 cells
This is just too slow for my purposes. Can anyone suggest alternate methods of doing this? For all of the cells essentially the only information one has is whether they're "open" or one can see through them or not (vs something like a wall).
An approximate solution with fixed integer slopes
For a big speedup (from quadratic in the number of rooms to linear), you could decide to check just a few integer slopes at each point. These are equivalence classes of visibility, i.e., if cell x can see cell y along such a line, and cell y can see cell z along the same line, then all 3 cells can see each other. Then you only need to compute each "visibility interval" along a particular line once, rather than per-cell.
You would probably want to check at least horizontal, vertical and both 45-degree diagonal slopes. For horizontal, start at cell (1, 1), and move right until you hit a wall, let's say at (5, 1). Then the cells (1, 1), (2, 1), (3, 1) and (4, 1) can all see each other along this slope, so although you started at (1, 1), there's no need to repeat the computation for the other 3 cells -- just add a copy of this list (or even a pointer to it, which is faster) to the visibility lists for all 4 cells. Keep heading right, and repeat the process as soon as you hit a non-wall. Then begin again on the next row.
Visibility checking for 45-degree diagonals is slightly harder, but not much, and checking for other slopes in which we advance 1 horizontally and some k vertically (or vice versa) is about the same. (Checking for for general slopes, like for every 2 steps right go up 3, is perhaps a bit trickier.)
Provided you use pointers rather than list copies, for a given slope, this approach spends amortised constant time per cell: Although finding the k horizontally-visible neighbours of some cell takes O(k) time, it means no further horizontal processing needs to be done for any of them. So if you check a constant number of slopes (e.g., the four I suggested), this is O(n) time overall to process n cells. In contrast, I think your current approach takes at least O(nq) time, where q is the average number of cells visible to a cell.

Check if 2 objects from an array overlap and change their position on y if they do

So how can I update the position every time I call the StartRandomizingRightSpikePosition
private bool CheckOverlap(GameObject o1, GameObject o2)
{
return spikeRight.Select(t => t.GetComponent<Collider>().bounds.Intersects(t.GetComponent<Collider>().bounds)).FirstOrDefault();
}
public void StartRandomizingRightSpikesPosition()
{
foreach (var t in spikeRight)
{
foreach (var t1 in spikeRight)
{
if (t == t1) continue;
if (!CheckOverlap(t, t1)) continue;
yPosition = Random.Range(-7, 7);
var position = t1.transform.position;
desiredPosition = new Vector3(position.x, yPosition, position.z);
t1.transform.position = desiredPosition;
Debug.Log(t.gameObject + " intersects " + t1.gameObject);
}
}
}
The short answer is yes but I'm not sure you would want too. I'm not sure you're going to find a way to do this efficiently and you might be better off finding a way to generate the objects such that this step is not necessary.
I can't tell from your question how the objects are actually stored so I'm going to provide some sample code that just deals with a simple array of Rectangles. You should be able to adapt it to your specifics.
I tried to make it slightly more efficient by not checking both t1 == t and t == t1.
const int Bounds = 1000;
static bool RemovedOverlappingRects(Rectangle[] rects)
{
for (int pos = 0; pos < rects.Length; ++pos)
{
for (int check = pos +1; check < rects.Length; ++check)
{
var r1 = rects[pos];
var r2 = rects[check];
if (r1.IntersectsWith(r2))
{
r2.Y = Rng.Next(1, Bounds);
rects[check] = r2;
Console.WriteLine($"{pos} overlaps with {check}");
return true;
}
}
}
return false;
}
Once we've randomly generated a new rectangle we have to start over. Which means invoking the above method in a loop.
var rects = GetRandomeRects(20).ToArray();
while (RemovedOverlappingRects(rects))
;
Because of the random movement I'm not certain you can guarantee this will always end. If you can deal with the non-random look of the results changing it to stack the overlaps would I believe always finish. That would be this:
r2.Y = r1.Y + r1.Height + 1;
in place of
r2.Y = Rng.Next(1, Bounds);
But even then you're still dealing with a very unpredictable run time due to the random input.
Maybe someone else can show us a more efficient way...

Substract 1 from x-axis of all elements of List<PointF>

I am reading samples from a serial port continously and I want to show the last 400 samples in a graph.
So when the number of received samples becomes 400 I should shift the myPointFsList to left by 1 and add the last received sample
to the end of it. My below code works successfully while the first 400 samples.
List<PointF> myPointFs = new List<PointF>();
uint sampleNumber = 0; PointF Current_PointFs;
private void UpdateVar(object sender, EventArgs e){
...
Current_PointFs = new PointF((float)(sampleNumber), (float)newSample);
if (sampleNumber < 400)
{
myPointFs .Add(Current_PointFs);
++sampleNumber;
}
else
{
myPointFs = myPointFs .ShiftLeft(1); //ShiftLeft is an Extension Method
myPointFs.Add(Current_PointFs);
}
if (myPointFs.Count >= 2)
{
Configure_Graphs();// using Graphics.DrawLines(thin_pen, myPointFs.ToArray()) to draw chart
}
}
But after that the first 400 samples recieved, I need to substract 1 from myPointFs[i].X to shift X-axis to left by 1. Maybe a way is to run a for loop.
How can I implement it? Or is there any more elegant way? Or something that it exists out-of-the-box in C#?
Edit: (To make my question more clear)
myPointFs contains something like this:
myPointFs[0] = {X = 1, Y = 21}
myPointFs[1] = {X = 2, Y = 50}
myPointFs[2] = {X = 3, Y = 56}
now I will remove the first element by shifting left by 1 and add a new sample to the end.
myPointFs[0] = {X = 2, Y = 50}
myPointFs[1] = {X = 3, Y = 56}
myPointFs[2] = {X = 4, Y = 68}
But I need finally something like this:
myPointFs[0] = {X = 1, Y = 50}
myPointFs[1] = {X = 2, Y = 56}
myPointFs[2] = {X = 3, Y = 68}
So, you want to remove the first element and decrement the X value of each remaining point. You can do that in one go:
myPointFs = myPointFs.Skip(1).Select(p => new PointF(p.X-1, p.Y)).ToList();
That is job for Queue<T>. In your case X will be index and Y will be data inserted into Queue.
Here's some code to show how that works:
static void Main(string[] args)
{
var queue = new Queue<int>(10); //Capacity of Queue is 10
Console.WriteLine("=== Writing to Queue ===");
for (int i = 0; i < 23; ++i) //22 rounds for inserting data
{
DequeueIfFull(i, queue);
Console.WriteLine("Inserting number {0} into Queue", i);
queue.Enqueue(i); //Read and remove the first item in Queue
}
FlushQueue(queue); //Last time read all values from queue
Console.ReadKey();
}
private static void DequeueIfFull(int i, Queue<int> queue)
{
var tenthItemInserted = (i != 0) && (i % 10 == 0);
if (tenthItemInserted)
{
Console.WriteLine("Dequeuing from Queue");
for (int j = 0; j < 10; ++j)
{
Console.WriteLine(" Number dequeued on position {0} is {1}", j, queue.Dequeue());
}
}
}
private static void FlushQueue(Queue<int> queue)
{
Console.WriteLine();
Console.WriteLine("=== Reading final Queue state ===");
var index = 0;
foreach (var itemInQueue in queue)
{
Console.WriteLine("At position {0} is number {1} ", index, itemInQueue);
index++;
}
}
Documentation for Queue and link to nice articles about Data Structures.

Find symmetric points on a parabola C#

I have searched through many posts and cannot find what I need. I see solutions to find the closest number to a target but I need one that finds that number, then can select the closest number on the other side of a "parabola" shaped set of data that is not completely symmetrical. I essentially use:
List<int> list = new List<int> { 2, 5, 7, 10 };
int number = 9;
int closest = list.Aggregate((x,y) => Math.Abs(x-number) < Math.Abs(y-
number) ? x : y);
This is how I find my first target number. Now I need to find a second number that is almost equal in value but on the other side of a parabola (I really need the indexes of these numbers but I can put the pieces together). My methods keeps coming up a single number. Essentially I need to move to an approximately symmetric index across a parabola to select an equivalent number. To put this in context, I am calculating beam width, i.e. the distance between the sides of a parabola at a specific point. Please let me know if this makes sense and if I need to explain more before you down vote me. I have done extensive research and testing. It is difficult for me to provide more code because it is coming from a $500,000 testing system that does not have internet so I can't copy and paste my code. I can go the extra yard if more code is needed though, just trying to avoid compromising an expensive embedded Windows system.
Here is a related post that I need to go a step further from
located here
Edit adding full code:
fileName = textBox10.Text;
SetupControlState(true);
if (comboBox2.SelectedIndex == 0)
{
cent = false;
}
else if (comboBox2.SelectedIndex == 1)
{
cent = true;
}
testHPositions = new List<double>();
testHMeasurements = new List<double>();
testVPositions = new List<double>();
testVMeasurements = new List<double>();
double horzRange = Double.Parse(textBox12.Text);
double vertRange = Double.Parse(textBox11.Text);
double refGain = Double.Parse(textBox14.Text);
double stepSize = Double.Parse(textBox13.Text);
testBorePos = new double[1, 2];
_worker = new BackgroundWorker();
_worker.WorkerSupportsCancellation = true;
testBoreRun.Enabled = false;
button2.Enabled = true;
_worker.RunWorkerAsync();
_worker.DoWork += new DoWorkEventHandler((state, args) =>
{
// try
// {
dev1 = new VisaDevice("inst0", "TCPIP0::192.168.0.10::inst0::INSTR"); //textBox1.Text);
if (!cent)
{
Double startfreq = double.Parse(textBox2.Text) * 1000000000;
Double stopfreq = double.Parse(textBox1.Text) * 1000000000;
dev1.SendBlocking("FREQ:STAR " + startfreq.ToString(), true);
string responseFreq = "";
dev1.QueryBlocking("FREQ:STAR?", ref responseFreq, true);
dev1.SendBlocking("FREQ:STOP " + stopfreq.ToString(), true);
dev1.QueryBlocking("FREQ:STOP?", ref responseFreq, true);
}
else if (cent)
{
Double freq = double.Parse(textBox9.Text) * 1000000000;
Double span = double.Parse(textBox8.Text) * 1000000000;
dev1.SendBlocking("FREQ:CENT " + freq.ToString(), true);
string responseFreq = "";
dev1.QueryBlocking("FREQ:CENT?", ref responseFreq, true);
dev1.SendBlocking("FREQ:SPAN " + span.ToString(), true);
dev1.QueryBlocking("FREQ:SPAN?", ref responseFreq, true);
// this.InvokeEx(f => f.stringReadTextBox.AppendText("Spectrum Analyzer Connected" + Environment.NewLine));
}
string progID;
Util U = new Util();
progID = "ASCOM.iOptron.Telescope";
if (progID != "")
{
PauseClass pause;
pause = new PauseClass();
Telescope T = new Telescope(progID);
T.Connected = true;
pause.Pause(5000);
T.Tracking = false;
T.TargetDeclination = 1;
T.TargetRightAscension = 1;
this.InvokeEx(f => f.stringReadTextBox.AppendText(" Connected to " + progID + Environment.NewLine));
this.InvokeEx(f => f.stringReadTextBox.AppendText(" Connected to Spectrum Analyzer" + Environment.NewLine));
T.SlewToAltAz(180.00, 45 - vertRange);
double Alt = T.Altitude;
for (int i = 0; i < ((vertRange * 2) / stepSize) + 1; i++)
{
if (_worker.CancellationPending)
break;
T.SlewToAltAz(180, Alt + stepSize * i);
this.InvokeEx(f => f.stringReadTextBox.AppendText("Test Altitude = " +(T.Altitude - 45).ToString("F") + Environment.NewLine));
testVPositions.Add(T.Altitude);
dev1.SendBlocking("INIT", true); //Start single measurement
string respOPC = "", responseState = "", responseMarkerY = "";
dev1.QueryBlocking("*OPC?", ref respOPC, true); //Wait for operation complete
dev1.QueryBlocking("STAT:QUES:MEAS?", ref responseState, true); //Check State
dev1.QueryBlocking("CALC:MARK:Y?", ref responseMarkerY, true); // Get the result
this.InvokeEx(f => f.stringReadTextBox.AppendText(responseMarkerY + Environment.NewLine));
testVMeasurements.Add(Double.Parse(responseMarkerY));
if (testVMeasurements.Count > ((vertRange * 2) / stepSize))
{
this.InvokeEx(f => f.stringReadTextBox.AppendText("Vertical Scanning Is Complete!" + Environment.NewLine));
double maxVamp = testVMeasurements.Max();
int index2 = testVMeasurements.IndexOf(testVMeasurements.Max());
double maxVPos = testVPositions[index2];
testBorePos[0, 1] = maxVPos;
this.InvokeEx(f => f.stringReadTextBox.AppendText("Vertical Max Amplitude = " + maxVamp + Environment.NewLine));
this.InvokeEx(f => f.stringReadTextBox.AppendText("Vertical Position of Max Amplitude = " + (maxVPos - 45).ToString("F") + Environment.NewLine));
}
}
if (!_worker.CancellationPending)
{
T.SlewToAltAz(180.00 - horzRange, testBorePos[0, 1]);
}
double Az = T.Azimuth;
for (int i = 0; i < ((horzRange * 2) / stepSize) + 1; i++)
{
if (_worker.CancellationPending)
break;
if (vertRange > 20)
{
this.InvokeEx(f => f.stringReadTextBox.AppendText("Vertical Range Cannot Be Greater than +/- 20 Degreez" + Environment.NewLine));
break;
}
T.SlewToAltAz(Az + stepSize * i,testBorePos[0,1]);
this.InvokeEx(f => f.stringReadTextBox.AppendText("Test Azimuth = " + (T.Azimuth-180).ToString("F") + Environment.NewLine));
testHPositions.Add(T.Azimuth);
dev1.SendBlocking("INIT", true); //Start single measurement
string respOPC = "", responseState = "", responseMarkerY = "", responseMarkerX = "";
// string responseFreq = "";
dev1.QueryBlocking("*OPC?", ref respOPC, true); //Wait for operation complete
dev1.QueryBlocking("STAT:QUES:MEAS?", ref responseState, true); //Check State
dev1.QueryBlocking("CALC:MARK:Y?", ref responseMarkerY, true); // Get the result
dev1.QueryBlocking("CALC:MARK:X?", ref responseMarkerX, true); // Get the result
this.InvokeEx(f => f.stringReadTextBox.AppendText(responseMarkerY + Environment.NewLine));
testHMeasurements.Add(Double.Parse(responseMarkerY));
if (testHMeasurements.Count > ((horzRange * 2) / stepSize))
{
_worker.CancelAsync();
stop = false;
this.InvokeEx(f => f.testBoreRun.Enabled = true);
this.InvokeEx(f => f.button2.Enabled = false);
this.InvokeEx(f => f.stringReadTextBox.AppendText("Horizontal Scanning Is Complete!" + Environment.NewLine));
double maxHamp =testHMeasurements.Max();
int index =testHMeasurements.IndexOf(testHMeasurements.Max());
double maxHPos =testHPositions[index];
testBorePos[0, 0] = maxHPos;
this.InvokeEx(f => f.stringReadTextBox.AppendText("Horizontal Max Amplitude = " + maxHamp + Environment.NewLine));
this.InvokeEx(f => f.stringReadTextBox.AppendText("Horizontal Position of Max Amplitude = " +( maxHPos-180).ToString("F") + Environment.NewLine));
this.InvokeEx(f => f.stringReadTextBox.AppendText("Antenna Under Test Peak Amplitude located at (" + (testBorePos[0, 0] - 180).ToString("F") + " , " + (testBorePos[0, 1] - 45).ToString("F") + ")" + Environment.NewLine));
this.InvokeEx(f => f.SetupControlState(false));
T.SlewToAltAz(testBorePos[0, 0], testBorePos[0, 1]);
dev1.SendBlocking("INIT", true); //Start single measurement
maxAmpTest = new double();
string respOPC2 = "", responseState2 = "", responseMarkerY2 = "";
dev1.QueryBlocking("*OPC?", ref respOPC2, true); //Wait for operation complete
dev1.QueryBlocking("STAT:QUES:MEAS?", ref responseState2, true); //Check State
dev1.QueryBlocking("CALC:MARK:Y?", ref responseMarkerY2, true); // Get the result
maxAmpTest = Double.Parse(responseMarkerY2);
double target = maxAmpTest - 3;
Here is where I am stuck:
// int indexbeam = testHMeasurements.IndexOf(target);
// indexList = testHMeasurements.IndexOf(testHMeasurements.FindAll(s => s.Equals(target)).First());
double closest = testHMeasurements.Aggregate((x, y) => Math.Abs(x - target) < Math.Abs(y - target) ? x : y);
var result = Enumerable.Range(0, testHMeasurements.Count).Where(j => testHMeasurements[j] ==closest).ToList();
// int beamIndex1 = testHMeasurements.IndexOf(testHMeasurements.OrderBy(item => Math.Abs(target - item)).First());
// int beamIndex2 = testHMeasurements.IndexOf(testHMeasurements.OrderBy(item => Math.Abs((beamIndex1 + 1) - item)).First());
double beam1 =( testHPositions[result[0]]) - 180;
double beam2 = (testHPositions[result[1]]) - 180;
beamWidth = Math.Abs(beam1) + Math.Abs(beam2);
this.InvokeEx(f => f.stringReadTextBox.AppendText("Antenna Under Test Amplitude = " + responseMarkerY2 + Environment.NewLine));
this.InvokeEx(f => f.stringReadTextBox.AppendText(" Antenna Under Test Gain = " + (maxAmpTest - refAmp + refGain) + Environment.NewLine));
this.InvokeEx(f => f.stringReadTextBox.AppendText(" Antenna Under Test Beam Width = " +beamWidth.ToString("F") + Environment.NewLine));
testGain = maxAmpTest - refAmp + refGain;
}
}
T.Connected = false;
T.Dispose();
dev1.Dispose();
if (_worker.CancellationPending)
{
Save();
// Cleanup Excel resources
GC.Collect();
GC.WaitForPendingFinalizers();
}
}
});
First, you must find the parabola. Because your data only approximates the parabola, you need a statistical method called Quadratic Regression, or Polynomial Regression to find the parameters a, b and c of the equation
y = ax2 + bx + c
defining the parabola, that best fits the dataset given by the points
(xi, yi)
Use a math library or google for an algorithm.
Once you have the parabola, determine the symmetry axis of it, i.e. find the x-value of where the minimum or maximum (if the parabola is upside down) of the parabola is.
xs = -b / 2a
Now, once you have a given x-value, you can find a point at the opposite side of the parabola by mirroring x at xs
x' = 2xs - x
This is the explanation for a parabola in 2-D. If you have a parabola in 3-D, i.e. a Paraboloid the principle remains the same, but with more complex math. Google for Paraboloid Regression. A parabolic antenna has a curved surface with the cross-sectional shape of a parabola, called a paraboloid in geometrical terms.
Only once you have solved the mathematical problems, you can start programming and finding points in lists.
Turns out this question could actually be solved through programming with no advanced math required. Given a y-value and asked to find two corresponding x values on an asymmetrical/parabola arc you can simply split the arc at the vertex in two pieces then scan each of the two arrays for the matching x-value. It works like a charm - just requires a little critical thinking and a lot less over thinking it (math major stuff :p)

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