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Getting values of both attribute and element in an xml

I have the following xml
<lists>
<list Group="3">More_lists_go_here</list>
</lists>
What I want is both the list element value which is More_lists_go_here and the Group attribute value which is 3.
What I have tried so far is
XmlDocument doc = new XmlDocument();
doc.LoadXml("<list Group=\"3\">More_lists_go_here</list>");
XmlElement root = doc.DocumentElement;
string value = root.Descendants("lists").Elements("list").Select(x => (string)x.Attribute("Group")).ToList();
what that gets me is
value = 3
what I want is both 3 and More_lists_go_here for string value

Use xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication40
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
string input = "<lists><list Group=\"3\">More_lists_go_here</list></lists>";
XDocument doc = XDocument.Parse(input);
var results = doc.Descendants("list").Select(x => new { group = (string)x.Attribute("Group"), value = (string)x }).ToList();
}
}
}

Retrieve list of xml tag of child nodes in linQ to xml

I'm trying to get all the list of the different child nodes (not starting from root) of a loaded XML into a list of strings, I had done using System.Xml library but I want to write the same code with LINQ to XML too.
I had found a code that helped me a lot but it starts from Root, here is the code:
List<string> nodesNames = new List<string>();
XDocument xdoc1 = XDocument.Load(destinationPath);
XElement root = xdoc1.Document.Root;
foreach (var name in root.DescendantNodes().OfType<XElement>()
.Select(x => x.Name).Distinct())
{
if (!nodesNames.Contains(name.ToString()))
nodesNames.Add(name.ToString());
}
With this, I get the list of all child nodes + the parent node too, which I don't want to use.FirstChild or to delete manually from the list because I want a TOTALLY dynamic code and I have in input the parent node passed by the user.
For a better comprehension, this is the code that working for me but with System.Xml:
List<string> nodesNames = new List<string>();
XmlDocument doc = new XmlDocument();
doc.Load(destinationPath);
XmlNodeList elemList = doc.GetElementsByTagName(inputParentNode);
for (int i = 0; i < elemList.Count; i++)
{
XmlNodeList cnList = (elemList[i].ChildNodes);
for (int j = 0; j < cnList.Count; j++)
{
string name = cnList[j].Name;
if (!nodesNames.Contains(name))
nodesNames.Add(name);
}
}
And this is an easy sample of the XML:
<?xml version='1.0' encoding='UTF-8'?>
<parentlist>
<parent>
<firstchild>someValue</firstchild>
<secondchild>someValue</secondchild>
</parent>
<parent>
<firstchild>someValue</firstchild>
<secondchild>someValue</secondchild>
<thirdchild>someValue</thirdchild>
</parent>
</parentlist>
To resume:
in the first case i obtain nodesNames = ["parent", "firstchild", "secondchild", "thirdchild"]
in the second case i obtain nodesNames = ["firstchild", "secondchild", "thirdchild"]
I just want to fix the first to obtain the same result as the second.

Try following :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication2
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement parentlist= doc.Root;
List<string> descendents = parentlist.Descendants().Where(x => x.HasElements).Select(x => string.Join(",", x.Name.LocalName, string.Join(",", x.Elements().Select(y => y.Name.LocalName)))).ToList();
}
}
}

Getting Values from XML

I have an XML File that is filled with values that look like :
<property name ="Web Application" value="\Fxnet2\Web\webpl\" />
<property name="Web Service" value="\FXnet2\Web\FXnet_SC_WS\" />
For each line i would like to import the name into one string (Lets call it serviceName) and the value in a different one (Lets call it servicePath)
I got around 250 lines of the sort in the xml , is it possible to do it in the current xml format? and if it does how ? , or should i change the format of my list?
Thanks in advance .

You can get all nodes and access their attributes in a loop. In the example below I'm adding the values of both attributes to 2 different arrays that you can easily manipulate later.
XmlDocument doc = new XmlDocument();
doc.Load("yourfile.xml");
XmlNodeList usernodes = doc.SelectNodes("//property");
//Declare arrays
List<string> serviceName = new List<string>();
List<string> servicePath = new List<string>();
//iterate through all elements found
foreach (XmlNode usernode in usernodes)
{
serviceName.Add(usernode.Attributes["name"].Value);
serviceName.Add(usernode.Attributes["value"].Value);
}

Managed to Do it in the end
static void Main(string[] args)
{
List<Service> services;
using(StreamReader file = File.OpenText("c:\\projects.xml"))
{
XDocument doc = XDocument.Load(file);
services = (from node in doc.Root.Elements("property")
select new Service
{
serviceName = node.Attribute("name").Value,
servicePath = node.Attribute("value").Value,
dllFiles = System.IO.Directory.GetFiles( "servicePath", "*.dll" ),
}).ToList<Service>();
}

Using XML Linq
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string input =
"<Root>" +
"<property name =\"Web Application\" value=\"\\Fxnet2\\Web\\webpl\" />" +
"<property name=\"Web Service\" value=\"\\FXnet2\\Web\\FXnet_SC_WS\" />" +
"</Root>";
XElement root = XElement.Parse(input);
var results = root.Descendants("property").Select(x => new {
name = x.Attribute("name").Value,
value = x.Attribute("value").Value
}).ToList();
}
}
}
​

Failing To Parse the XML File in C#

I am a c++ developer and I started working on a C# WPF project. I have a method which should read the xml file. In my c++ application I could do it very efficiently but in WPF I am not sure how to approach the problem. Let me show you my code:
// When Browse Button is clicked this method is called
private void ExecuteScriptFileDialog()
{
var dialog = new OpenFileDialog { InitialDirectory = _defaultPath };
dialog.DefaultExt = ".xml";
dialog.Filter = "XML Files (*.xml)|*.xml";
dialog.ShowDialog();
ScriptPath = dialog.FileName; //ScriptPath contains the Path of the Xml File
if (File.Exists(ScriptPath))
{
LoadAardvarkScript(ScriptPath);
}
}
public void LoadAardvarkScript(string ScriptPath)
{
// I should read the xml file
}
I had achieved in C++ as follows:
File file = m_selectScript->getCurrentFile(); //m_selectScript is combobox name
if(file.exists())
{
LoadAardvarkScript(file);
}
void LoadAardvarkScript(File file)
{
XmlDocument xmlDoc(file);
//Get the main xml element
XmlElement *mainElement = xmlDoc.getDocumentElement();
XmlElement *childElement = NULL;
XmlElement *e = NULL;
int index = 0;
if(!mainElement )
{
//Not a valid XML file.
return ;
}
//Reading configurations...
if(mainElement->hasTagName("aardvark"))
{
forEachXmlChildElement (*mainElement, childElement)
{
//Read Board Name
if (childElement->hasTagName ("i2c_write"))
{
// Some code
}
}
}
How can I get the tagname of both mainElement and childelem as done in my c++ code? :)

not knowing the layout of your xml file here is an example that you can use if you know how to use Linq
class Program
{
static void Main(string[] args)
{
XElement main = XElement.Load(#"users.xml");
var results = main.Descendants("User")
.Descendants("Name")
.Where(e => e.Value == "John Doe")
.Select(e => e.Parent)
.Descendants("test")
.Select(e => new { date = e.Descendants("Date").FirstOrDefault().Value, points = e.Descendants("points").FirstOrDefault().Value });
foreach (var result in results)
Console.WriteLine("{0}, {1}", result.date, result.points);
Console.ReadLine();
}
}
you could also use XPATH as well to parse xml file.. but would really need to see the xml file layout
if you want to do it using xmlreader
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
namespace XmlReading
{
class Program
{
static void Main(string[] args)
{
//Create an instance of the XmlTextReader and call Read method to read the file
XmlTextReader textReader = new XmlTextReader("C:\\myxml.xml");
textReader.Read();
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(textReader);
XmlNodeList BCode = xmlDoc.GetElementsByTagName("Brandcode");
XmlNodeList BName = xmlDoc.GetElementsByTagName("Brandname");
for (int i = 0; i < BCode.Count; i++)
{
if (BCode[i].InnerText == "001")
Console.WriteLine(BName[i].InnerText);
}
Console.ReadLine();
}
}
}

Use LINQ queries to extract data from xml (XDocument)
Refer this link for further insights on XLinq.
Sample XML :
<?xml version="1.0" encoding="utf-8" standalone="yes"?>
<People>
<Person id="1">
<Name>Joe</Name>
<Age>35</Age>
<Job>Manager</Job>
</Person>
<Person id="2">
<Name>Jason</Name>
<Age>18</Age>
<Job>Software Engineer</Job>
</Person>
</People>
Sample Linq query:
var names = (from person in Xdocument.Load("People.xml").Descendants("Person")
where int.Parse(person.Element("Age").Value) < 30
select person.Element("Name").Value).ToList();
Names will be list of string. This query will return Jason as he is 18 yrs old.

Using Linq2Xml,
var xDoc = XDocument.Load("myfile.xml");
var result = xDoc.Descendants("i2c_write")
.Select(x => new
{
Addr = x.Attribute("addr").Value,
Count = x.Attribute("count").Value,
Radix = x.Attribute("radix").Value,
Value = x.Value,
Sleep = ((XElement)x.NextNode).Attribute("ms").Value
})
.ToList();
var khz = xDoc.Root.Element("i2c_bitrate").Attribute("khz").Value;

Use XMLReader to access child nodes with duplicate names

Using the XML fragment below, how would I access the child node <amt> of the node <salesTaxAmt> using XMLReader? If I iterate over the nodes looking for a node name of "amt" I return the last node amount of <sourceCurrAmt> which is 0.00.
<transactionUnit>
<transactionDetails>
<transactionId>11883382</transactionId>
<currencyAmount>
<amt>30.00</amt>
<currCode>USD</currCode>
</currencyAmount>
<gstAmount>
<amt>60.00</amt>
<currCode>USD</currCode>
</gstAmount>
<pstNqstAmt>
<amt>0.00</amt>
<currCode>USD</currCode>
</pstNqstAmt>
<salesTaxAmt>
<amt>1.00</amt>
<currCode>USD</currCode>
</salesTaxAmt>
<sourceCurrAmt>
<amt>0.00</amt>
</sourceCurrAmt>
</transactionDetails>
</transactionUnit>
Is the code below even the best way to do this?
Test Code:
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.IO;
using System.Xml;
namespace TestConsole
{
public class ParseXML
{
static void Main(string[] args)
{
try
{
FileStream file;
XmlReader baseReader;
XmlTextReader reader;
XmlReaderSettings readerSettings;
file = new FileStream(#"C:\Data.xml", FileMode.Open, FileAccess.Read);
file.Seek(0, SeekOrigin.Begin);
reader = new XmlTextReader(file, XmlNodeType.Element, null);
reader.Normalization = false;
readerSettings = new XmlReaderSettings();
readerSettings.ConformanceLevel = ConformanceLevel.Fragment;
readerSettings.IgnoreWhitespace = false;
readerSettings.IgnoreComments = true;
readerSettings.CheckCharacters = false;
baseReader = XmlReader.Create(reader, readerSettings);
int x = 0;
while (baseReader.Read())
{
if (baseReader.Name.Equals("transactionUnit") && (baseReader.NodeType == XmlNodeType.Element))
{
string amt = null;
XmlReader inner = reader.ReadSubtree();
while (inner.Read())
{
if (inner.Name.Equals("ns:amt"))
{
amt = inner.ReadElementString();
}
}
Console.WriteLine("amt: {0}", amt);
inner.Close();
x = x + 1;
}
}
Console.WriteLine("{0} transactions found", x.ToString());
baseReader.Close();
file.Close();
}
catch (XmlException xe)
{
Console.WriteLine("XML Parsing Error: " + xe);
}
catch (IOException ioe)
{
Console.WriteLine("File I/O Error: " + ioe);
}
}
}
}

From your example code it looks like you can use LINQ to XML, this would be a more succinct solution for your problem:
XDocument xDoc = XDocument.Load(#"C:\Data.xml");
string amt = xDoc.Descendants("salesTaxAmt")
.Elements("amt")
.Single().Value;
If you can use it LINQ to XML should definitely be your choice, it provides an easy and powerful syntax for retrieving data from XML and plays nicely with LINQ to objects.

A simpler way to get the node value is to use XPath.
Note that this is possible only if you node the path to the node whose value is to be retreived.
private string GetNodeValue(string xmlFilePath, string xpath)
{
string nodeValue = string.Empty;
using (StreamReader reader = new StreamReader(xmlFilePath))
{
XPathDocument xPathDocument = new XPathDocument(reader);
XPathNavigator navigator = xPathDocument.CreateNavigator();
XPathNodeIterator iter = navigator.Select(xpath);
iter.MoveNext();
nodeValue = iter.Current.Value;
//iter.Current.ValueAsDouble;
}
return nodeValue;
}
The usage for your sample xml should be:
string nodeValue = GetNodeValue(#"C:\Data.xml", "//transactionUnit/transactionDetails/salesTaxAmt/amt");
In addition, you could rename the method as 'GetNodeValueAsDouble' and use iter.Current.ValueAsDouble instead of iter.Current.Value to get the double value.
More Information
XPathNavigator class
XPathDocument class