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How to Zip two Lists of different size to create a new list that is same as the size of the longest amongst the original lists?

I have two C# Lists of different sizes e.g.
List<int> list1 = new List<int>{1,2,3,4,5,6,7};
List<int> list2 = new List<int>{4,5,6,7,8,9};
I want to use the linq Zip method to combine these two into a list of tuples that is of the size list1. Here is the resulting list I am looking for
{(1,4), (2,5), (3,6), (4,7), (5,8), (6,9), (7,0)} //this is of type List<(int,int)
Since the last item of list1 does not has a counterpart in list2, I fill up my last item of the resulting list with a default value (in this case 0 as in my case it will never appear in any of the original lists).
Is there a way I can use the linq Zip method alone to achieve this?

You can use Concat to make them both the same size, and then zip it:
var zipped = list1.Concat(Enumerable.Repeat(0,Math.Max(list2.Count-list1.Count,0)))
.Zip(list2.Concat(Enumerable.Repeat(0,Math.Max(list1.Count-list2.Count,0))),
(a,b)=>(a,b));
Or create an extension method:
public static class ZipExtension{
public static IEnumerable<TResult> Zip<TFirst,TSecond,TResult>(
this IEnumerable<TFirst> first,
IEnumerable<TSecond> second,
Func<TFirst,TSecond,TResult> func,
TFirst padder1,
TSecond padder2)
{
var firstExp = first.Concat(
Enumerable.Repeat(
padder1,
Math.Max(second.Count()-first.Count(),0)
)
);
var secExp = second.Concat(
Enumerable.Repeat(
padder2,
Math.Max(first.Count()-second.Count(),0)
)
);
return firstExp.Zip(secExp, (a,b) => func(a,b));
}
}
So you can use like this:
//last 2 arguments are the padder values for list1 and list2
var zipped = list1.Zip(list2, (a,b) => (a,b), 0, 0);

There is a useful and popular MoreLinq library. Install it and use.
using MoreLinq;
var result = list1.ZipLongest(list2, (x, y) => (x, y));

Try this using Zip function-
static void Main(string[] args)
{
List<int> firstList = new List<int>() { 1, 2, 3, 4, 5, 6, 0, 34, 56, 23 };
List<int> secondList = new List<int>() { 4, 5, 6, 7, 8, 9, 1 };
int a = firstList.Count;
int b = secondList.Count;
for (int k = 0; k < (a - b); k++)
{
if(a>b)
secondList.Add(0);
else
firstList.Add(0);
}
var zipArray = firstList.Zip(secondList, (c, d) => c + " " + d);
foreach(var item in zipArray)
{
Console.WriteLine(item);
}
Console.Read();
}
Or you can try this using ZipLongest Function by installing MoreLinq nuget package-
static void Main(string[] args)
{
List<int> firstList = new List<int>() { 1, 2, 3, 4, 5, 6, 0, 34, 56, 23 };
List<int> secondList = new List<int>() { 4, 5, 6, 7, 8, 9, 1 };
var zipArray = firstList.ZipLongest(secondList, (c, d) => (c,d));
foreach (var item in zipArray)
{
Console.WriteLine(item);
}
Console.Read();
}

Try this code-
static void Main(string[] args)
{
List<int> firstList=new List<int>() { 1, 2, 3, 4, 5, 6,0,34,56,23};
List<int> secondList=new List<int>() { 4, 5, 6, 7, 8, 9,1};
int a = firstList.Count;
int b = secondList.Count;
if (a > b)
{
for(int k=0;k<(a-b);k++)
secondList.Add(0);
}
else
{
for (int k = 0; k < (b-a); k++)
firstList.Add(0);
}
for(int i=0;i<firstList.Count;i++)
{
for(int j=0;j<=secondList.Count;j++)
{
if(i==j)
Console.Write($"({Convert.ToInt32(firstList[i])},{ Convert.ToInt32(secondList[j])})" + "");
}
}
Console.Read();
}

How to sum up every array of a List<int[]> or jagged array via index?

I want to convert this part of code to LINQ.
Can anyone help me?
var list = new List<int[]>();
list.Add(new int[] { 1, 2, 3, 4 });
list.Add(new int[] { 5, 4, 2, 1 });
list.Add(new int[] { 5, 9, 3, 5 });
var result = new int[4];
foreach (var item in list)
{
for (int i = 0; i < 4; i++)
{
result[i] += item[i];
}
}
Result must be : { 11, 15, 8, 10 } because that is the sum-result

I think this is the most readable version. No need to GroupBy, you can Sum every index of every array:
int[] result = Enumerable.Range(0, 4)
.Select(index => list.Sum(arr => arr[index]))
.ToArray();
Since OP is also using a for-loop from 0-3 they all seem to have the same size.
If that's not the case you could use this super safe approach:
int maxLength = list.Max(arr => arr.Length);
int[] result = Enumerable.Range(0, maxLength)
.Select(index => list.Sum(arr => arr.ElementAtOrDefault(index)))
.ToArray();

First thing that pops to my head:
var list = new List<int[]>();
list.Add(new int[] { 1, 2, 3, 4 });
list.Add(new int[] { 5, 4, 2, 1 });
list.Add(new int[] { 5, 9, 3, 5 });
var result = list.SelectMany(item => item.Select((innerItem, index) => new { index, innerItem }))
.GroupBy(item => item.index, (key, group) => group.Sum(item => item.innerItem))
.ToList();
Tim's approach above is cleaner and is better

You can try this one
var list = new List<int[]>();
list.Add(new int[] { 1, 2, 3, 4 });
list.Add(new int[] { 5, 4, 2, 1 });
list.Add(new int[] { 5, 9, 3, 5 });
var result = list.SelectMany(x => x.Select((z, i) => new {z, i}))
.GroupBy(x=>x.i).Select(x=>x.Sum(z=>z.z)).ToArray();

Want to do aggregation, so why would not use linq aggregate?
var list = new List<int[]>();
list.Add(new int[] { 1, 2, 3, 4 });
list.Add(new int[] { 5, 4, 2, 1 });
list.Add(new int[] { 5, 9, 3, 5 });
var addArrayValues = new Func<int[], int[], int[]>(
(source, destination) =>
{
for (int i = 0; i < source.Length; i++)
destination[i] += source[i];
return destination;
});
var aggregateResult = list.Aggregate(new int[4],
(accumulator, current) => addArrayValues(current, accumulator));

Split array with LINQ

Assuming I have a list
var listOfInt = new List<int> {1, 2, 3, 4, 7, 8, 12, 13, 14}
How can I use LINQ to obtain a list of lists as follows:
{{1, 2, 3, 4}, {7, 8}, {12, 13, 14}}
So, i have to take the consecutive values and group them into lists.

You can create extension method (I omitted source check here) which will iterate source and create groups of consecutive items. If next item in source is not consecutive, then current group is yielded:
public static IEnumerable<List<int>> ToConsecutiveGroups(
this IEnumerable<int> source)
{
using (var iterator = source.GetEnumerator())
{
if (!iterator.MoveNext())
{
yield break;
}
else
{
int current = iterator.Current;
List<int> group = new List<int> { current };
while (iterator.MoveNext())
{
int next = iterator.Current;
if (next < current || current + 1 < next)
{
yield return group;
group = new List<int>();
}
current = next;
group.Add(current);
}
if (group.Any())
yield return group;
}
}
}
Usage is simple:
var listOfInt = new List<int> { 1, 2, 3, 4, 7, 8, 12, 13, 14 };
var groups = listOfInt.ToConsecutiveGroups();
Result:
[
[ 1, 2, 3, 4 ],
[ 7, 8 ],
[ 12, 13, 14 ]
]
UPDATE: Here is generic version of this extension method, which accepts predicate for verifying if two values should be considered consecutive:
public static IEnumerable<List<T>> ToConsecutiveGroups<T>(
this IEnumerable<T> source, Func<T,T, bool> isConsequtive)
{
using (var iterator = source.GetEnumerator())
{
if (!iterator.MoveNext())
{
yield break;
}
else
{
T current = iterator.Current;
List<T> group = new List<T> { current };
while (iterator.MoveNext())
{
T next = iterator.Current;
if (!isConsequtive(current, next))
{
yield return group;
group = new List<T>();
}
current = next;
group.Add(current);
}
if (group.Any())
yield return group;
}
}
}
Usage is simple:
var result = listOfInt.ToConsecutiveGroups((x,y) => (x == y) || (x == y - 1));

This works for both sorted and unsorted lists:
var listOfInt = new List<int> { 1, 2, 3, 4, 7, 8, 12, 13 };
int index = 0;
var result = listOfInt.Zip(listOfInt
.Concat(listOfInt.Reverse<int>().Take(1))
.Skip(1),
(v1, v2) =>
new
{
V = v1,
G = (v2 - v1) != 1 ? index++ : index
})
.GroupBy(x => x.G, x => x.V, (k, l) => l.ToList())
.ToList();
External index is building an index of consecutive groups that have value difference of 1. Then you can simply GroupBy with respect to this index.
To clarify solution, here is how this collection looks without grouping (GroupBy commented):

Assuming your input is in order, the following will work:
var grouped = input.Select((n, i) => new { n, d = n - i }).GroupBy(p => p.d, p => p.n);
It won't work if your input is e.g. { 1, 2, 3, 999, 5, 6, 7 }.
You'd get { { 1, 2, 3, 5, 6, 7 }, { 999 } }.

This works:
var results =
listOfInt
.Skip(1)
.Aggregate(
new List<List<int>>(new [] { listOfInt.Take(1).ToList() }),
(a, x) =>
{
if (a.Last().Last() + 1 == x)
{
a.Last().Add(x);
}
else
{
a.Add(new List<int>(new [] { x }));
}
return a;
});
I get this result:

LINQ: Separating single list to multiple lists

I have a single array with these entries:
{1, 1, 2, 2, 3,3,3, 4}
and i want to transform them to ( 3 lists in this case ):
{1,2,3,4}
{1,2,3}
{3}
Is there any way to do this with LINQ or SQL? I guess there's a mathematical term for this operation, which I don't know unfortunately...
Or do I have to do it with loops?
=======
EDIT: I can't really describe the logic, so here are more examples.. It more or less loops multiple times over the array and takes every number once ( but every number only once per round ) until there are no numbers left
{1, 1, 2, 2, 3,3,3, 4, 5}
would be
{1,2,3,4,5}
{1,2,3}
{3}
or
{1, 1, 2, 2,2, 3,3,3, 4, 5}
would be
{1,2,3,4,5}
{1,2,3}
{2,3}

private IEnumerable<List<int>> FooSplit(IEnumerable<int> items)
{
List<int> source = new List<int>(items);
while (source.Any())
{
var result = source.Distinct().ToList();
yield return result;
result.ForEach(item => source.Remove(item));
}
}
Usage:
int[] items = { 1, 1, 2, 2, 3, 3, 3, 4 };
foreach(var subList in FooSplit(items))
{
// here you have your three sublists
}
Here is another solution, which is less readable but it will have better performance:
private IEnumerable<IEnumerable<int>> FooSplit(IEnumerable<int> items)
{
var groups = items.GroupBy(i => i).Select(g => g.ToList()).ToList();
while (groups.Count > 0)
{
yield return groups.Select( g =>
{ var i = g[0]; g.RemoveAt(g.Count - 1); return i; });
groups.RemoveAll(g => g.Count == 0);
}
}

this does the job:
static void Main(string[] args)
{
int[] numbers = {1, 1, 2, 2, 3, 3, 3, 3, 4, 5, 5};
List<int> nums = new List<int>(numbers.Length);
nums.AddRange(numbers);
while (nums.Count > 0)
{
int[] n = nums.Distinct().ToArray();
for (int i = 0; i < n.Count(); i++)
{
Console.Write("{0}\t", n[i]);
nums.Remove(n[i]);
}
Console.WriteLine();
}
Console.Read();
}

Here's an alternative console app:
class Program
{
class Freq
{
public int Num { get; set; }
public int Count { get; set; }
}
static void Main(string[] args)
{
var nums = new[] { 1, 1, 2, 2, 3, 3, 3, 4 };
var groups = nums.GroupBy(i => i).Select(g => new Freq { Num = g.Key, Count = g.Count() }).ToList();
while (groups.Any(g => g.Count > 0))
{
var list = groups.Where(g => g.Count > 0).Select(g => g.Num).ToList();
list.ForEach(li => groups.First(g => g.Num == li).Count--);
Console.WriteLine(String.Join(",", list));
}
Console.ReadKey();
}
}

How do you transpose dimensions in a 2D collection using LINQ?

Consider the following structure:
IEnumerable<IEnumerable<int>> collection = new[] {
new [] {1, 2, 3},
new [] {4, 5, 6},
new [] {7, 8, 9}
};
How can I enumerate this collection so that I obtain IEnumerable<int> collections made up of the first items, second items, etc.?
That is, {1, 4, 7}, {2, 5, 8}, ...
(Though the implementation I've chosen is int[] objects, assume you only have IEnumerable<int> functionality. Thanks.)

Here's an approach that uses a generator instead of recursion. There's less array construction too, so it might be faster, but that's totally conjecture.
public static IEnumerable<IEnumerable<T>> Transpose<T>(
this IEnumerable<IEnumerable<T>> #this)
{
var enumerators = #this.Select(t => t.GetEnumerator())
.Where(e => e.MoveNext());
while (enumerators.Any()) {
yield return enumerators.Select(e => e.Current);
enumerators = enumerators.Where(e => e.MoveNext());
}
}

Just my 2 cents
In pure linq:
var transpond = collection.First().Select((frow,i)=>collection.Select(row=>row.ElementAt(i)));
Or with some inpurity:
var r1 = collection.First().Select((frow, i) => collection.Select(row => row.ToArray()[i]));

Code credit goes here (untested but looks fine).
public static class LinqExtensions
{
public static IEnumerable<IEnumerable<T>> Transpose<T>(this IEnumerable<IEnumerable<T>> values)
{
if (!values.Any())
return values;
if (!values.First().Any())
return Transpose(values.Skip(1));
var x = values.First().First();
var xs = values.First().Skip(1);
var xss = values.Skip(1);
return
new[] {new[] {x}
.Concat(xss.Select(ht => ht.First()))}
.Concat(new[] { xs }
.Concat(xss.Select(ht => ht.Skip(1)))
.Transpose());
}
}
//Input: transpose [[1,2,3],[4,5,6],[7,8,9]]
//Output: [[1,4,7],[2,5,8],[3,6,9]]
var result = new[] {new[] {1, 2, 3}, new[] {4, 5, 6}, new[] {7, 8, 9}}.Transpose();

Assuming all the sequences are of the same length.
static void Main(string[] args)
{
IEnumerable<IEnumerable<int>> collection =
new[]
{
new [] {1, 2, 3},
new [] {4, 5, 6 },
new [] {7, 8, 9}
};
Console.WriteLine("\tInitial");
Print(collection);
var transposed =
Enumerable.Range(0, collection.First().Count())
.Select(i => collection.Select(j => j.ElementAt(i)));
Console.WriteLine("\tTransposed");
Print(transposed);
}
static void Print<T>(IEnumerable<IEnumerable<T>> collection)=>
Console.WriteLine(string.Join(Environment.NewLine, collection.Select(i => string.Join(" ", i))));
Gives:
Initial
1 2 3
4 5 6
7 8 9
Transposed
1 4 7
2 5 8
3 6 9

If all elements are guaranteed to be the same length, you could do this:
IEnumerable<IEnumerable<int>> Transpose(IEnumerable<IEnumerable<int>> collection)
{
var width = collection.First().Count();
var flattened = collection.SelectMany(c => c).ToArray();
var height = flattened.Length / width;
var result = new int[width][];
for (int i = 0; i < width; i++)
{
result[i] = new int[height];
for (int j = i, k = 0; j < flattened.Length; j += width, k++)
result[i][k] = flattened[j];
}
return result;
}