Let me explain, there is a database table which has 1 XML column named audits and other common types of column.
so is this possible to deserialize below XML into class.
<?xml version="1.0"?>
<entity type="Order">
<id type="System.Int64">146</id>
<ordernumber type="System.String">OD555</ordernumber>
<audits type='System.String'>
<audit>
<item>
<create timestamp='2017-07-19 10:02:13' userid='23' />
</item>
<invoice>
<create timestamp='2017-07-19 10:03:37' userid='45' />
</invoice>
</audit>
</audits>
</entity>
Class:
public class Order
{
public long id { get; set; }
public string ordernumber { get; set; }
public string audits { get; set; }
}
Modifying your model with the attributes XmlType and XmlAnyElement (requires XmlElement as type)
[XmlType("entity")]
public class Order
{
public long id { get; set; }
public string ordernumber { get; set; }
[XmlAnyElement]
public XmlElement audits { get; set; }
}
allows to deserialize the complete XML string like
using (MemoryStream stream = new MemoryStream())
using (StreamWriter writer = new StreamWriter(stream))
{
writer.Write(xmlString);
writer.Flush();
stream.Position = 0;
XmlSerializer serializer = new XmlSerializer(typeof(Order));
Order o = (Order)serializer.Deserialize(stream);
}
Now you are able to get the audits as string like
string auditsString = o.audits.InnerXml;
You can also add a property to your model to simplify the access:
public string auditsString
{
get
{
return audits.InnerXml;
}
}
Try xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication68
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
Order order = doc.Descendants("entity").Select(x => new Order()
{
id = (long)x.Element("id"),
ordernumber = (string)x.Element("ordernumber"),
audits = x.Descendants("create").Select(y => (DateTime)y.Attribute("timestamp")).ToList()
}).FirstOrDefault();
}
}
public class Order
{
public long id { get; set; }
public string ordernumber { get; set; }
public List<DateTime> audits { get; set; }
}
}
You can try like this
const string xmlString = #"<columns><column><c1>100</c1><c2>200</c2><cn>300</cn></column><column><c1>111</c1><c2>222</c2><cn>333</cn></column> <column> <c1>MAX Newsletter</c1><c2>OLS Application</c2> <cn>Total funded accounts</cn> </column></columns>";
XDocument doc = XDocument.Parse(xmlString);
if (doc.Root != null)
{
List<Row> items = (from r in doc.Root.Elements("column")
select new Row
{
C1 = (string)r.Element ("C1"),
C2 = (string)r.Element("C2"),
}).ToList();
Related
I am trying to parse the xml into a list variable from its root tag. I have given below the xml file format. I want to get the entire content of the xml into a list variable excluding the first line
<?xml version="1.0" encoding="utf-8" ?>
<Root>
<Database>
Data Source
</Database>
<FromEmailDetails>
<UserName>
testuser
</UserName>
<Password>
myPassword
</Password>
<FromAddress>
test#gmail.com
</FromAddress>
<Server>
myserver
</Server>
<port>
80
</port>
</FromEmailDetails>
<FileFormat>
XLSX
</FileFormat>
<ExportFolder>
C:\NOTNEED\
</ExportFolder>
<Customer>
<SQL ID="GYSQL">
Select * from customer where code ='GYSQL'
</SQL>
<MailBody>
Please find attached Report
</MailBody>
<Address>customer1#mail.com</Address>
<Address>customer2#mail.com</Address>
</Customer>
<Customer>
<SQL ID="TSSQL">
Select * from customer where code ='TSSQL'
</SQL>
<MailBody>
Please find attached Report
</MailBody>
<Address>customer3#mail.com</Address>
<Address>customer4#mail.com</Address>
<Address>customer5#mail.com</Address>
</Customer>
</Root>
I am trying to parse the xml into a list
var doc = XDocument.Parse(textXML);
var contents = xml .ToList(); // Please help here how can I store the xml content as list
This should work:
foreach (var entry in doc.Descendants())
{
contents.Add(entry);
}
Using Xml Linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication176
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement root = doc.Root;
DataBase db = new DataBase(root);
}
}
public class DataBase
{
public string database { get; set; }
public Email email { get; set; }
public string fileFormat { get; set; }
public string exportFolder { get; set; }
public List<Customer> customers { get; set; }
public DataBase(XElement root)
{
database = ((string)root.Element("Database")).Trim();
fileFormat = ((string)root.Element("FileFormat")).Trim();
exportFolder = ((string)root.Element("ExportFolder")).Trim();
email = new Email(root.Element("FromEmailDetails"));
customers = root.Elements("Customer").Select(x => new Customer(x)).ToList();
}
}
public class Email
{
public string username { get; set; }
public string password { get; set; }
public string fromAddress { get; set; }
public string server { get; set; }
public int port { get; set; }
public Email(XElement email)
{
username = ((string)email.Element("UserName")).Trim();
password = ((string)email.Element("Password")).Trim();
fromAddress = ((string)email.Element("FromAddress")).Trim();
server = ((string)email.Element("Server")).Trim();
port = (int)email.Element("port");
}
}
public class Customer
{
public string id { get; set; }
public string sql { get; set; }
public string mailBody { get; set; }
public List<string> addresses { get; set; }
public Customer(XElement customer)
{
id = ((string)customer.Element("SQL").Attribute("ID")).Trim();
sql = ((string)customer.Element("SQL")).Trim();
mailBody = ((string)customer.Element("SQL")).Trim();
addresses = customer.Elements("Address").Select(x => ((string)x).Trim()).ToList();
}
}
}
I am trying to find if an element value exists then get a element value below it. i.e.
<Reply>
<customer id="1223">
<group>A</group>
<class>
<custclass>AB</custclass>
<custval>1</custval>
</class>
<class>
<custclass>CD</custclass>
<custval>2</custval>
</class>
</customer>
</Reply>
I need to get the custval element value if the custclass = "CD". What is the best way to set this into a string in C# "2"? So I am looking for if custclass element value of "CD" exists then return the custval element value of 2.
Thanks for any info.
We can read the property value using various ways-
Method 1 - using XmlDocument
XmlDocument doc = new XmlDocument();
doc.Load(xmlFile);
XmlNodeList xnl = doc.SelectNodes("/Reply/customer/class");
foreach (XmlNode node in xnl)
{
if (node.ChildNodes[0].InnerText == "CD")
{
Console.WriteLine(node.ChildNodes[1].InnerText);
}
}
Method 2 - using XDcoument and LINQ
XDocument xml = XDocument.Load(xmlFile);
var result = xml.Root.DescendantsAndSelf("class")
.Where(r => (string)r.Element("custclass").Value == "CD")
.Select(s=> (string)s.Element("custval").Value).Single();
Console.WriteLine(result);
Method 3 - using XDocument and XPathSelectElement
var custval = xml.XPathSelectElement("Reply/customer/class[custclass='CD']/custval").Value;
Console.WriteLine(custval);
Method 4 - using XmlSerializer
Create C# classes using xmltocsharp & use Deserialize to convert the xml to object
[XmlRoot(ElementName = "class")]
public class Class
{
[XmlElement(ElementName = "custclass")]
public string Custclass { get; set; }
[XmlElement(ElementName = "custval")]
public string Custval { get; set; }
}
[XmlRoot(ElementName = "customer")]
public class Customer
{
[XmlElement(ElementName = "group")]
public string Group { get; set; }
[XmlElement(ElementName = "class")]
public List<Class> Class { get; set; }
[XmlAttribute(AttributeName = "id")]
public string Id { get; set; }
}
[XmlRoot(ElementName = "Reply")]
public class Reply
{
[XmlElement(ElementName = "customer")]
public Customer Customer { get; set; }
}
static async System.Threading.Tasks.Task Main(string[] args)
{
string xmlFile = #"xxxxxx.xml";
using (StreamReader r = new StreamReader(xmlFile))
{
string xmlString = r.ReadToEnd();
XmlSerializer ser = new XmlSerializer(typeof(Reply));
using (TextReader reader = new StringReader(xmlString))
{
var result = (Reply)ser.Deserialize(reader);
var custvalue = result.Customer.Class.Where(i => i.Custclass == "CD").Select(a => a.Custval).Single();
Console.WriteLine(custvalue);
}
}
}
I'm trying to read a xml file from a c# application. so far no luck at all. This is the XML file
<?xml version="1.0" encoding="utf-8"?>
<ExportJobs xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<JobList>
<Job Id="555555">
<Comments></Comments>
<DueDate>2017-11-17</DueDate>
<FormattedDueDate>17-Nov-2017 12:00</FormattedDueDate>
<TargetDueDate>2017-11-17</TargetDueDate>
<ServiceTypeId>3</ServiceTypeId>
<ServiceType>Service</ServiceType>
<TenantName>Miss Ash</TenantName>
<Uprn>testUpr</Uprn>
<HouseName></HouseName>
</Job>
<Job Id="666666">
<Comments></Comments>
<DueDate>2018-03-15</DueDate>
<FormattedDueDate>15-Mar-2018 12:00</FormattedDueDate>
<TargetDueDate>2018-03-15</TargetDueDate>
<ServiceTypeId>3</ServiceTypeId>
<ServiceType>Service</ServiceType>
<TenantName>Mr Howard</TenantName>
<Uprn>testUpr2</Uprn>
</Job>
</JobList>
</ExportJobs>
I'm trying to get the job Id and the Uprn from the joblist node and pass the values in to Sql Server DB. I tried this, but I can't get the values,
string costCode;
string uprn;
//File path where the xml is located
string filepath = "C:\\ExportJobs.xml";
XmlDocument xmlDoc = new XmlDocument();
xmlDoc.Load(filepath);
foreach (XmlNode node in xmlDoc.DocumentElement.ChildNodes)
{
costCode = node.Attributes["Id"].InnerText;
uprn = node.Attributes["Uprn"].InnerText;
}
I really appreciate any help. Thanks
XmlSerializer is your friend:
using System;
using System.Collections.Generic;
using System.IO;
using System.Xml.Serialization;
public class ExportJobs
{
public List<Job> JobList { get; } = new List<Job>();
}
public class Job
{
[XmlAttribute]
public int Id { get; set; }
public string Comments { get; set; }
public DateTime DueDate { get; set; }
public string FormattedDueDate { get; set; }
public DateTime TargetDueDate{ get; set; }
public int ServiceTypeId { get; set; }
public string ServiceType { get; set; }
public string TenantName { get; set; }
public string Uprn { get; set; }
public string HouseName { get; set; }
}
static class P
{
static void Main()
{
var ser = new XmlSerializer(typeof(ExportJobs));
ExportJobs jobs;
using (var sr = new StringReader(xml))
{
jobs = (ExportJobs) ser.Deserialize(sr);
}
foreach(var job in jobs.JobList)
{
Console.WriteLine($"{job.Id} / {job.Uprn}: {job.DueDate}");
}
}
const string xml = #"<?xml version=""1.0"" encoding=""utf-8""?>
<ExportJobs xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"">
<JobList>
<Job Id=""555555"">
<Comments></Comments>
<DueDate>2017-11-17</DueDate>
<FormattedDueDate>17-Nov-2017 12:00</FormattedDueDate>
<TargetDueDate>2017-11-17</TargetDueDate>
<ServiceTypeId>3</ServiceTypeId>
<ServiceType>Service</ServiceType>
<TenantName>Miss Ash</TenantName>
<Uprn>testUpr</Uprn>
<HouseName></HouseName>
</Job>
<Job Id=""666666"">
<Comments></Comments>
<DueDate>2018-03-15</DueDate>
<FormattedDueDate>15-Mar-2018 12:00</FormattedDueDate>
<TargetDueDate>2018-03-15</TargetDueDate>
<ServiceTypeId>3</ServiceTypeId>
<ServiceType>Service</ServiceType>
<TenantName>Mr Howard</TenantName>
<Uprn>testUpr2</Uprn>
</Job>
</JobList>
</ExportJobs>";
}
You are accessing ChildNodes of root element, which contains only Jobs element, which in order does not contains attributes Id and Uprn.
The usual practice is to use XPath query as following:
foreach (XmlNode node in xmlDoc.DocumentElement.SelectNodes("Jobs/Job"))
{
costCode = node.Attributes["Id"].InnerText;
uprn = node.SelectSingleNode("Uprn").InnerText;
}
Note that Uprn is the node and not the node attribute.
Here is tested code. You need the namespace. See code below which is using xml linq
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication67
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement exportJobs = doc.Root;
XNamespace ns = exportJobs.GetDefaultNamespace();
var results = exportJobs.Descendants(ns + "Job").Select(x => new {
id = (string)x.Attribute(ns + "Id"),
comment = (string)x.Element(ns + "Comments"),
dueDate = (DateTime)x.Element(ns + "DueDate"),
formattedDueDate = (DateTime)x.Element(ns + "FormattedDueDate"),
targetDueDate = (DateTime)x.Element(ns + "TargetDueDate"),
serviceTypeId = (int)x.Element(ns + "ServiceTypeId"),
serviceType = (string)x.Element(ns + "ServiceType"),
tenantName = (string)x.Element(ns + "TenantName"),
uprn = (string)x.Element(ns + "Uprn"),
houseName = (string)x.Element(ns + "HouseName")
}).ToList();
}
}
}
I think the best way to solve your problem is XDocument class.
XDocument xDoc = XDocument.Load(#"D:\1.xml");
foreach(var node in xDoc.Descendants("Job"))
{
id = node.Attribute("Id");
foreach(var subnode in node.Descendants("Uprn"))
{
uprn = subnode.Value;
}
//or like that. but check it for null before
uprn = node.Descendants("Uprn")?.First().Value
}
I have a set of data xml node list, i want to filter with a particular attributes inner text, I tried with this but nothing worked. My code here and also posting the xml data
string baseName = categoryName.Split(':').Last();
int categoryId = 0;
string xmlFile = File.ReadAllText(Application.StartupPath + #"\EbayCategories\EbayCategories.xml");
XmlDocument xmldoc = new XmlDocument();
xmldoc.LoadXml(xmlFile);
XmlNodeList nodeList = xmldoc.SelectNodes("/CategoryArray/Category[CategoryName='" + baseName + "']");
if (nodeList.Count > 0)
{
var memberNames = nodeList.Cast<XmlNode>().Where(node => node.Attributes["CategoryID"].InnerText == "58193").ToList();
categoryId = int.Parse(nodeList[0]["CategoryID"].InnerText);
}
Here is my xml Data. I want to filter CategoryParentID = My Value.
<CategoryArray>
<Category>
<BestOfferEnabled>true</BestOfferEnabled>
<AutoPayEnabled>true</AutoPayEnabled>
<CategoryID>20081</CategoryID>
<CategoryLevel>1</CategoryLevel>
<CategoryName>Antiques</CategoryName>
<CategoryParentID>20081</CategoryParentID>
</Category>
<Category>
<BestOfferEnabled>true</BestOfferEnabled>
<AutoPayEnabled>true</AutoPayEnabled>
<CategoryID>37903</CategoryID>
<CategoryLevel>2</CategoryLevel>
<CategoryName>Antiquities</CategoryName>
<CategoryParentID>20081</CategoryParentID>
</Category>
<Category>
<BestOfferEnabled>true</BestOfferEnabled>
<AutoPayEnabled>true</AutoPayEnabled>
<CategoryID>37908</CategoryID>
<CategoryLevel>3</CategoryLevel>
<CategoryName>The Americas</CategoryName>
<CategoryParentID>37903</CategoryParentID>
<LeafCategory>true</LeafCategory>
</Category>
<Category>
<BestOfferEnabled>true</BestOfferEnabled>
<AutoPayEnabled>true</AutoPayEnabled>
<CategoryID>162922</CategoryID>
<CategoryLevel>3</CategoryLevel>
<CategoryName>Byzantine</CategoryName>
<CategoryParentID>37903</CategoryParentID>
<LeafCategory>true</LeafCategory>
</Category>
I have done with small changes Removed Attributes
var node = nodeList.Cast<XmlNode>().Where(n => n["CategoryParentID"].InnerText == "58193").Select(x => x["CategoryID"].InnerText).SingleOrDefault();
Perfectly worked!!!
Using Linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.Text.RegularExpressions;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
Category.categories = doc.Descendants("Category").Select(x => new Category() {
BestOfferEnabled = (Boolean)x.Element("BestOfferEnabled"),
AutoPayEnabled = (Boolean)x.Element("BestOfferEnabled"),
CategoryID = (int)x.Element("CategoryID"),
CategoryLevel = (int)x.Element("CategoryLevel"),
CategoryName = (string)x.Element("CategoryName"),
CategoryParentID = (int)x.Element("CategoryParentID"),
}).ToList();
int id = 37903;
Category categoryId = Category.categories.Where(x => x.CategoryParentID == id).FirstOrDefault();
}
}
public class Category
{
public static List<Category> categories { get; set; }
public Boolean BestOfferEnabled { get; set; }
public Boolean AutoPayEnabled { get; set; }
public int CategoryID { get; set; }
public int CategoryLevel { get; set; }
public string CategoryName { get; set; }
public int CategoryParentID { get; set; }
}
}
I am creating XML to send data. The data contains multiple datatypes as string, integer and decimal. My XML format and c# code to create it as follows.
<root>
<data>
<struct>
<PartnerCD></PartnerCD>
<UserName> </UserName>
<Password> </Password>
<Action> </Action>
<OfficeCD></OfficeCD>
<ChannelCD></ChannelCD>
<Token></Token>
<Notes> </Notes>
<Products>
<Product>
<ProductID></ProductID>
<SVA></SVA>
<Amount></Amount>
</Product>
</Products>
</struct>
</data>
</root>
And my c# code is
public static string CreateRequestXML(string partnerCd, string userName, string password, string action, string productId, string token, string sva, string amount)
{
XmlDocument doc = new XmlDocument();
XmlElement elemRoot = doc.CreateElement("root");
XmlElement elemData = doc.CreateElement("data");
XmlElement elemStruct = doc.CreateElement("struct");
XmlElement elemProducts = doc.CreateElement("Products");
XmlElement elemProduct = doc.CreateElement("Product");
doc.AppendChild(elemRoot);
elemRoot.AppendChild(elemData);
elemData.AppendChild(elemStruct);
//Insert data here
InsertDataNode(doc, elemStruct, "PartnerCD", partnerCd);
InsertDataNode(doc, elemStruct, "UserName", userName);
InsertDataNode(doc, elemStruct, "Password", password);
InsertDataNode(doc, elemStruct, "Action", action);
InsertDataNode(doc, elemStruct, "Token", token);
elemStruct.AppendChild(elemProducts);
elemProducts.AppendChild(elemProduct);
InsertDataNode(doc, elemProduct, "ProductID", productId);
InsertDataNode(doc, elemProduct, "SVA", sva);
InsertDataNode(doc, elemProduct, "Amount", amount);
return doc.OuterXml;
}
private static void InsertDataNode(XmlDocument doc, XmlElement parentElem, string nodeName, string nodeValue)
{
XmlElement elem = doc.CreateElement(nodeName);
elem.InnerText = nodeValue;
parentElem.AppendChild(elem);
}
and am getting the result as
<root>
<data>
<struct>
<PartnerCD>123</PartnerCD>
<UserName>api</UserName>
<Password>pass</Password>
<Action>token</Action>
<Token>4847898</Token>
<Products>
<Product>
<ProductID>123</ProductID>
<SVA>e8a8227c-bba3-4f32-a2cd-15e8f246344b</SVA>
<Amount>700</Amount>
</Product>
</Products>
</struct>
</data>
</root>
I want the PartnerCD and ProductId elements as integer and Amount element as decimal. I have tried XMLNodeType but no use.
Well the data type is irrelevant in the XML as such, it's all defined in the schema it uses, that's where the declaration of expected data types are stored.
So if you have a XSD that says that /root/data/struct/PartnerCD is of type xs:int then you will get validation errors upon validating the file. The XML itself is just a container of all data, it doesn't include the meta information. You CAN define it manually, but the Point is beyond me in about 99.99% of the cases, and it's more or less a bastard of XML, like MSXML that will understand what you're up to.
Xml has no concept of "data type" natively, the XmlNodeType you refer to is what type of Node it is (such as element, attribute etc), not what type of data is contained within it.
Personally I would create an object and Serialize\Deserialize to\from XML like so.....
using System;
using System.Xml.Serialization;
using System.Collections.Generic;
using System.IO;
namespace _37321906
{
class Program
{
static void Main(string[] args)
{
Root root = new Root();
root.Data.Struct.PartnerCD = 123;
root.Data.Struct.UserName = "api";
root.Data.Struct.Password = "pass";
root.Data.Struct.Action = "token";
root.Data.Struct.Token = 4847898;
root.Data.Struct.Products.Product.Add(new Product { ProductID = 123, SVA = "e8a8227c-bba3-4f32-a2cd-15e8f246344b", Amount = 700.0001 });
// Serialize the root object to XML
Serialize<Root>(root);
// Deserialize from XML
Root DeserializeRoot = Deserialize<Root>();
}
private static void Serialize<T>(T data)
{
// Use a file stream here.
using (TextWriter WriteFileStream = new StreamWriter("test.xml"))
{
// Construct a SoapFormatter and use it
// to serialize the data to the stream.
XmlSerializer SerializerObj = new XmlSerializer(typeof(T));
try
{
// Serialize EmployeeList to the file stream
SerializerObj.Serialize(WriteFileStream, data);
}
catch (Exception ex)
{
Console.WriteLine(string.Format("Failed to serialize. Reason: {0}", ex.Message));
}
}
}
private static T Deserialize<T>() where T : new()
{
//List<Employee> EmployeeList2 = new List<Employee>();
// Create an instance of T
T ReturnListOfT = CreateInstance<T>();
// Create a new file stream for reading the XML file
using (FileStream ReadFileStream = new FileStream("test.xml", FileMode.Open, FileAccess.Read, FileShare.Read))
{
// Construct a XmlSerializer and use it
// to serialize the data from the stream.
XmlSerializer SerializerObj = new XmlSerializer(typeof(T));
try
{
// Deserialize the hashtable from the file
ReturnListOfT = (T)SerializerObj.Deserialize(ReadFileStream);
}
catch (Exception ex)
{
Console.WriteLine(string.Format("Failed to serialize. Reason: {0}", ex.Message));
}
}
// return the Deserialized data.
return ReturnListOfT;
}
// function to create instance of T
public static T CreateInstance<T>() where T : new()
{
return (T)Activator.CreateInstance(typeof(T));
}
}
[XmlRoot(ElementName = "Product")]
public class Product
{
[XmlElement(ElementName = "ProductID")]
public int ProductID { get; set; }
[XmlElement(ElementName = "SVA")]
public string SVA { get; set; }
[XmlElement(ElementName = "Amount")]
public double Amount { get; set; }
}
[XmlRoot(ElementName = "Products")]
public class Products
{
public Products()
{
this.Product = new List<Product>();
}
[XmlElement(ElementName = "Product")]
public List<Product> Product { get; set; }
}
[XmlRoot(ElementName = "struct")]
public class Struct
{
public Struct()
{
this.Products = new Products();
}
[XmlElement(ElementName = "PartnerCD")]
public int PartnerCD { get; set; }
[XmlElement(ElementName = "UserName")]
public string UserName { get; set; }
[XmlElement(ElementName = "Password")]
public string Password { get; set; }
[XmlElement(ElementName = "Action")]
public string Action { get; set; }
[XmlElement(ElementName = "OfficeCD")]
public string OfficeCD { get; set; }
[XmlElement(ElementName = "ChannelCD")]
public string ChannelCD { get; set; }
[XmlElement(ElementName = "Token")]
public int Token { get; set; }
[XmlElement(ElementName = "Notes")]
public string Notes { get; set; }
[XmlElement(ElementName = "Products")]
public Products Products { get; set; }
}
[XmlRoot(ElementName = "data")]
public class Data
{
public Data()
{
this.Struct = new Struct();
}
[XmlElement(ElementName = "struct")]
public Struct Struct { get; set; }
}
[XmlRoot(ElementName = "root")]
public class Root
{
public Root()
{
this.Data = new Data();
}
[XmlElement(ElementName = "data")]
public Data Data { get; set; }
}
}
find your XML in the build folder called test.xml