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Regex to get digits from a string when there is no separator between digits

I have a string like Acc:123-456-789 and another string like -1234567, I need your help to write an expression to match digits in case there is no separator between the digits.
-*(?!\d*(?:\d*-)$)\d*$
Input strings:
Acc:123-456-789 -12323232 7894596
Desired result:
group 1 12323232
group 2 7894596

I think this ought to work:
(?<=^|\s|\s-)(\d+)(?=\s|$)
Breaking it down:
(?<=^|\s|\s-) - A positive lookbehind that matches the start of the string, whitespace, or whitespace followed by a -.
(\d+) - Matches and captures number sequences.
(?=\s|$) - A positive lookahead that matches whitespace or the end of the string.
** Note: If you need to capture negative number sequences, replace (\d+) with (\-?\d+).
Try it online
Regex reference
Remember for use in C# that you need to escape backslashes or use the # prefix to a string literal (#" ").

Regex - Replace specific zeros in a string before a period

sorry for such a direct question but i've spent a little too long trying to find a suitable RegEx that can alter the following strings:
01.10
10.01
setting them as:
1.10
10.1
So basically always remove the first '0' in the complete sequence before each period, or in the last sequence.
Is this possible with RegEx as currently it doesn't seem so?

Try this:
find: (^|\.)0+
replace: $1
See here a demo
Note: if the expression is not at the beginning of the string, you should not use ^, but the word boundary \b, like this:
(\b|\.)0+
eventually, double escape it:
(\\b|\.)0+
See other demo

Perhaps you could try it using this regex. This will not match the zero in 0.0 or 0.1 but only when there are digits after the leading zero(s).
\b0+(?=\d\.\d+\b)|(?<=\b\d+\.)0+(?=\d+\b)
\b word boundary
0+(?=\d\.\d+\b) match a zero and use a positive lookahead to assert that the zero is followed by a digit, dot, one or more digits and a word boundary
| Or
(?<=\b\d+\.)0+(?=\d+\b) Positive lookbehind that asserts that what is on the left is a wordboundary, one or more digits and a dot. Then match one or more zeroes and assert that what follows id one or more digits and a wordboundary.

C# Regular Expression for x number of groups of A-Z separated by hyphen

I am trying to match the following pattern.
A minimum of 3 'groups' of alphanumeric characters separated by a hyphen.
Eg: ABC1-AB-B5-ABC1
Each group can be any number of characters long.
I have tried the following:
^(\w*(-)){3,}?$
This gives me what I want to an extent.
ABC1-AB-B5-0001 fails, and ABC1-AB-B5-0001- passes.
I don't want the trailing hyphen to be a requirement.
I can't figure out how to modify the expression.

Your ^(\w*(-)){3,}?$ pattern even allows a string like ----- because the only required pattern here is a hyphen: \w* may match 0 word chars. The - may be both leading and trailing because of that.
You may use
\A\w+(?:-\w+){2,}\z
Details:
\A - start of string
\w+ - 1+ word chars (that is, letters, digits or _ symbols)
(?:-\w+){2,} - 2 or more sequences of:
- - a single hyphen
\w+ - 1 or more word chars
\z - the very end of string.
See the regex demo.
Or, if you do not want to allow _:
\A[^\W_]+(?:-[^\W_]+){2,}\z
or to only allow ASCII letters and digits:
\A[A-Za-z0-9]+(?:-[A-Za-z0-9]+){2,}\z

It can be like this:
^\w+-\w+-\w+(-\w+)*$

^(\w+-){2,}(\w+)-?$
Matches 2+ groups separated by a hyphen, then a single group possibly terminated by a hyphen.

((?:-?\w+){3,})
Matches minimum 3 groups, optionally starting with a hyphen, thus ignoring the trailing hyphen.
Note that the \w word character also select the underscore char _ as well as 0-9 and a-z
link to demo

RegExp multiply matches in text

I want to write a regexp to get multiple matches of the first character and next three digits. Some valid examples:
A123,
V322,
R333.
I try something like that
[a-aA-Z](1)\d3
but it gets me just the first match!
Could you possibly show me, how to rewrite this regexp to get multiple results?Thank you so much and Have a nice day!

Your regex does not work because it matches:
[a-aA-Z] - an ASCII letter, then
(1) - a 1 digit (and puts into a capture)
\d - any 1 digit
3 - a 3 digit.
So, it matches Y193, E103, etc., even in longer phrases, where Y and E are not first letters.
You need to use a word boundary and fix your pattern as
\b[a-aA-Z][0-9]{3}
NOTE: if you need to match it as a whole word, add \b at the end: \b[a-aA-Z][0-9]{3}\b.
See the regex demo.
Details:
\b - leading word boundary
[a-aA-Z] - an ASCII letter
[0-9]{3} - 3 digits.
C# code:
var results = Regex.Matches(s, #"\b[a-aA-Z][0-9]{3}")
.Cast<Match>()
.Select(m => m.Value)
.ToList();

Regex to detect numbers only between special characters

I need Regex to detect numbers only between special characters.
Pattern ;\d+=\d+?
String 0014;5010730101000033347=4510120173?AA
My objective is to get this string
;5010730101000033347=4510120173?

The \d+? at the end of the pattern matches 1 digit, no more, due to the +? lazy quantifier matching 1 or more occurrences, but as few as necessary to return a valid match.
You may use
;\d+=\d+\?
^^
C# declaration:
string pattern = #";\d+=\d+\?";
See the regex demo
Details:
; - a semi-colon
\d+ - 1 or more digits
= - an equal sign
\d+ - 1 or more digits
\? - a literal ? char