Send Selected DropDownList value to HomeController ActionResult - c#

Hi I have a drop down list that is filled in from comma delimited values in the config. This works fine.
What I am trying to do is to send the selected value on button click to a ActionResult in the HomeController.
I created a Model, which is taking a string. When I hit the button I get error:
The view 'TestAction' or its master was not found or no view engine supports the searched locations.
This is what my Controller looks like:
[HttpPost]
[ActionName("TestAction")]
public ActionResult TestAction(SQL_Blocks_App.Models.DropdownList SelectedValue)
{
//System.Diagnostics.Debug.WriteLine(SelectedValue);
return View();
}
This is what my model looks like:
public class DropdownList
{
//
// GET: /DropdownList/
[Display(Name = "Servers")]
public string SelectedValue{ get; set; }
}
and this is what my Index View looks like:
<form id="SelectedValue" action="/Home/TestAction" method="post" style="margin: 0">
<div class="col-lg-5">
#{
ViewBag.Title = "Index";
}
#Html.DropDownList("YourElementName", (IEnumerable<SelectListItem>)ViewBag.DropdownVals, "--Choose Your Value--", new
{
//size = "5",
style = "width: 600px"
})
</div>
<div class="col-lg-5">
<input type="submit" value="Run Query" />
<input id="Button2" type="button" value="Clear" onclick="window.location.reload()" />
</div>
</form>
I want to clarify. My end goal is to use the selected value in a SQL query in the ActionResult and return the results back to the index so I can fill them in a table. ( You don't have to show me how to do the SQL part for now I just would like to see the selected value at least printed in the output.)

Redirect to index action, and pass the parameters along
[HttpPost]
[ActionName("TestAction")]
public ActionResult TestAction(SQL_Blocks_App.Models.DropdownList _selectedValue)
{
//System.Diagnostics.Debug.WriteLine(SelectedValue);
return RedirectToAction("Index", "[Controller]", new {#_selectedValue = _selectedValue });
}
and then your Index method should accept the parameter.
[HttpGet]
public ActionResult Index(SQL_Blocks_App.Models.DropdownList _selectedValue)
{
//use _selectedValue
}
I would recommend using another method other than your index, or make Dropdownlist nullable/set a default for it.

The default framework behavior of return View() is to return a view with the same name as the currently-executing action. Which is TestAction. The error is telling you that no such view was found.
You have a couple of options. You can either create the view, or you can return something else. For example, if you want to redirect back to the Index then you can return a redirect result:
return RedirectToAction("Index");
You could also specify the Index view in the response:
return View("Index");
However, keep in mind that the URL will still be for TestAction and not for Index, which could result in unexpected changes to behavior if you're not aware of this.
Edit: Based on comments on this answer, it sounds like what you actually want is to build a pair of actions which generally operate on the same view. This isn't particularly common for an index view, but is very common for edit views. The only difference is semantics, structurally the concept works anywhere.
Consider two actions:
public ActionResult Index()
{
// just show the page
return View();
}
[HttpPost]
public ActionResult Index(SQL_Blocks_App.Models.DropdownList SelectedValue)
{
// receive data from the page
// perform some operation
// and show the page again
return View();
}
Requests between these two actions would differ only by the HTTP verb (GET or POST), not by the action name on the URL. That name would always be "Index". But when the form on the index view is submitted via POST and has a "SelectedValue", the second action is invoked instead of the first.
In that second action you would perform your database interaction, gather whatever data you needed, and if necessary include a model or some additional data in the response.

You TestAction method is returning to a View. Make sure View TestAction.cshtml exists and is in the Home folder.

Related

How to retrieve input's value from a textbox

I'm learning to develop a webapp using .net and I'm having a problem in retrieving the value from an <input>
Size:
#using (Html.BeginForm("GetList", "User", FormMethod.Post))
{
#Html.TextBoxFor(Model => Model.PageSize)
<input type="submit" value="Invia" />
}
I want to retrieve the value posted and then use it as a parameter in the url but all I try isn't working and all this is frustrating me a lot, thanks for the help.
In your Post method in the Controller, define an input variable with the same datatype of the model that you are using in the view. Then you will be able to get the values that you have on the screen.
What happens is that when the submit button is pressed, all the input values will be submitted to Controller's post method.
Supposing that your model's datatype is "User", the Controller's Post method should look like the below:
[HttpPost]
public ActionResult GetList(User model)
{
int pageSize = model.PageSize;
...
return View();
}

ASP MVC and changing url of posted form

I have an MVC 4 app and I am using a RESTful methodology for my URLs. I have the following routes registered in my app (along with others that are not relevant to my question:
//EDIT
routes.MapRoute(alias + "_EDIT", alias + "/{id}/edit",
new { controller = controllerName, action = "edit" },
new { httpMethod = new RestfulHttpMethodConstraint(HttpVerbs.Get) });
//PUT (update)
routes.MapRoute(alias + "_PUT", alias + "/{id}",
new { controller = controllerName, action = "update" },
new { httpMethod = new RestfulHttpMethodConstraint(HttpVerbs.Put) });
I have the following methos in my controller mapping to these routes:
public override ActionResult Edit(int id)
{...}
public override ActionResult Update(RequestEditViewModel userModel)
{
if (!ModelState.IsValid)
{
//do some stuff to ensure lookups are populated
...
return View("Edit", userModel);
}
}
In my app when I perform a request to edit a request my URL looks like:
http://server/request/1/edit
it correctly calls the Edit method on my controller.
My Edit.cshtml uses the followng to ensure the Update method is called on PUT:
#using (Html.BeginForm("Update", "Request"))
{
#Html.HttpMethodOverride(HttpVerbs.Put);
...
}
My form is generated as follows:
<form action="/requests/71" method="post" autocomplete="off" novalidate="novalidate">
<input name="X-HTTP-Method-Override" type="hidden" value="PUT"/>
...
</form>
When I click the submit button it correctly calls my Update method.
OK...Now for the issue. If my model is NOT valid I want to return back the Edit model. As you can see in the above code but, the URL is the one called from the submit button:
http://server/request/1
not
http://server/requests/1/edit
I have tried an reviewed two other options but both of these redirect the request back through the Edit method again which adds additional overhead and also puts all the model values in the querystring which I do NOT want:
return RedirectToAction("Edit", userModel);
return RedirectToRoute("requests_Edit", userModel);
So, is there a way to just return the View as I have in my code but, ensure the URL changes back and include the "/edit"?
The only alternative I have come up with is to perform an AJAX call and put the update that way the URL never changes, but I was trying to avoid that for this form.
Conceptually, you want to be doing something like a Server.Transfer (that is, making on URL appear to be another.) This discussion may be of use to you:
How to simulate Server.Transfer in ASP.NET MVC?

MVC Maintaining Model through multi view form submits

So I am working on a MVC which is basically three steps.
Create a view for each step i.e.
StepOne
StepTwo
StepThree
On step one and two I ask the users to enter some details.
All the values for the multiple step I store in one Model.
And getting from StepOne to StepTwo is fine. Certain values in my model are being set and maintained.
But on StepTwo when I do my second httppost and pass the model, it seems to just create a new instance of the model and values from stepone are not maintained.
<% using (Html.BeginForm("StepTwo", "Home", FormMethod.Post, new { id = "restrictionForm" })) { %>
<%: Html.AntiForgeryToken() %>
<div id="wrapping" class="clearfix">
<h3>Postcode Restriction Type : </h3>
<%= Html.DropDownListFor(x => x.SelectedRestriction, Model.RestrictionTypes,"Select Restriction...", new { #class = "selmenu required" }) %>
<h3>Restriction Description : </h3>
<%= Html.TextBoxFor(m => m.RestrictionDescription, new { #class = "txtblock required" }) %>
</div>
<section id="buttons">
<input type="submit" value="Submit" id="submitBtn" />
</section>
And in my controller
On Page Load my Model is still intact and still maintains values from previous step.
[Authorize]
public ActionResult StepTwo(PostcodesModel model)
{
var summaryMessage = "";
model.SummaryMessage = summaryMessage;
model.RestrictionTypes = _Provider.GetRestrictionTypes();
return View(model);
}
But at the Httppost, the model has lost values and seems to have created new instance of model.
[Authorize]
[HttpPost]
[ActionName("StepTwo")]
[ValidateAntiForgeryToken]
public ActionResult StepTwoPost(PostcodesModel model)
{
return View(model);
}
Any idea how I can maintain model between Http Posts ?
It seems from your question that you believe models persist across requests. This is not true.
You either pass information to the view via your model from the controller, or submit values from your view to your controller and MVC handles this by binding html form inputs to your View Model.
If you want to persist your View Model across each step you need to take the values accepted and copy them into a new model (or directly inject it) when calling your new view.
Something like this (I just typed this up off my head so its not clean but should give you an idea):
[HttpGet]
public ActionResult StepOne()
{
var model = new MyNewModel();
return View(model);
}
/* NOTE THE MODEL PASSED BACK HERE IS NOT THE EXACT SAME OBJECT
AS THE ONE CREATED IN THE GET ACTION ABOVE, MODEL BINDING HAS OCCURRED
TO READ YOUR FORM INPUTS AND MATCH THEM TO A NEW MODEL WHICH IS EXPECTED */
[HttpPost]
public ActionResult StepOne(MyNewModel model)
{
if (ModelState.IsValid)
{
// Do something here
// pass model to new view
TempData["model"] = model;
return RedirectToAction("StepTwo");
}
return View(model);
}
[HttpGet]
public ActionResult StepTwo()
{
MyNewModel model;
if (TempData["model"] != null)
{
model = (MyNewModel) TempData["model"];
// make some changes if necessary
model.MyProperty = 2;
return View(model);
}
return RedirectToAction("StepOne");
}
I think you can also keep your model in Session ( per application ) or in a ViewState ( per page ).
Every time you make a post you upgrade the session. It's also optimal because on the client side you receive only a session identifier.
Some differences between Session and Viewstate:
Session is per application, while ViewState is per page
Session sends to the client side only a session identifier, while ViewState sends an ecrypted text

Transfer Model Data in View to the Controller

I have a model that I am using in my view that is full of data. This data is then edited in the view. I need to figure out a way to resubmit this data back over to the controller.
Here is what I have so far.
VIEW:
#using (Html.BeginForm("DownloadCSV", "Respondents", FormMethod.Post))
{
#Html.HiddenFor(m => m.FilterSet)
<div class="btn btn-default pull-right" id="dispoCSV" onclick="$('#csvFormSubmit').click()">
<i class="icon-file-alt"></i> Disposition Report
</div>
<input id="csvFormSubmit" type="submit" style="display:none;" />
}
CONTROLLER:
[HttpPost]
public ActionResult DownloadCSV(RespondentsFilterSet model)
{
string csv = "Charlie, Test";
return File(new System.Text.UTF8Encoding().GetBytes(csv), "text/csv", "DispositionReport.csv");
}
MODEL:
public class RespondentsFilterSet : ColdListFilterSet
{
public List<int> OwningRecruiters { get; set; }
public List<int> RecruitingGroups { get; set; }
public override bool HasAtLeastOneFilter()
{
return base.HasAtLeastOneFilter() || OwningRecruiters.IsNotNullOrEmpty() || RecruitingGroups.IsNotNullOrEmpty();
}
public override ExpressionBase ToExpression()
{
var expr = base.ToExpression();
var expressions = expr == null ? new List<ExpressionBase>() : new List<ExpressionBase> { expr };
if (OwningRecruiters.IsNotNullOrEmpty())
{
expressions.Add(new InExpression<int> { Field = Create.Name<Respondent>(r => r.RecruitedBy), Values = OwningRecruiters });
}
if (RecruitingGroups.IsNotNullOrEmpty())
{
expressions.Add(new InExpression<int> { Field = Create.Name<Respondent>(r => r.RecruitingGroupId), Values = RecruitingGroups });
}
return expressions.Count == 0 ? null : BuildAndExpressionFromList(expressions);
}
}
I realize that my controller is not not finalized. I just have displaying some static csv. But I can't figure out why my model from my view is always null when returned to the controller.
Just look at your form. There's not a single input element (except the submit button). You cannot expect to get anything back on the server in this case.
Please read about HTML and how forms work in HTML. In HTML forms you have input fields. Things like text fields, hidden fields, checkboxes, radio buttons, ... - fields that the user interacts with get submitted to the server.
The fact that you have made your HttpPost controller action take some model as parameter doesn't mean at all that this parameter will be initialized. In ASP.NET MVC you have a default model binder. This model binder looks at what gets sent to the server as values when the form is submitted and uses the names of the fields to bind to the corresponding properties. Without input fields in the form, nothing gets sent to the server. Just use the debugging tools built into your web browser to inspect what exactly gets sent to the server.
Contrary to classic ASP.NET WebForms, ASP.NET MVC is stateless. There's no ViewState to remember your model.
So all this rambling is to say that you should read more about HTML forms first and understand the stateless nature of the web before getting into ASP.NET MVC. As far as your particular problem is concerned, well, assuming the user is not supposed to modify any values of the view model in your view throughout some input fields, you could simply include a hidden field containing the id of your model in the form. This id will then be sent to your POST controller action as parameter and you could use it to retrieve your original model from wherever it is stored (I guess a database or something).

Load View again by passing updated parameter to the same Controller MVC 3

I want to load the same view again by passing updated parameter from text input on the link click. I tried to use something like <a href="#Url.Action("Index", "Home", new {id = "txtCount".value }). Not sure if there is even a way to do this. I know I could use partial but I want to reload the whole page with updated parameter. Thanks in advance for any help.
Controller
[HttpGet]
public ActionResult Index(int id)
{
return View(id);
}
View
#model int
#using (#Html.BeginForm())
{
<input id="txtCount" value="1" />
Update
for (int i = 0; i < Model; i++)
{
<div>#i </div>
}
}
Maybe something like this
Go!
and binding with jquery
$("#mylink").click(function(){
document.location.href = '#Url.Content("~/Controller/Action")' + $("#mytxt").val();
return false;
});
Obviously with the proper validations if the textbox is empty and all that stuff.
You cannot add the id value to the #Url.Action because it is processed before on the server side, before the page is rendered

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