This question already has answers here:
Escape double quotes in a string
(9 answers)
Closed 5 years ago.
I am trying to get the text inside "" in:
_["Some text to get"]
So I tried the following in C#:
Regex pattern = new Regex(#"_\["(.*?)\"]");
This does not compile because of the " inside the regex expression.
The regex expression seems to work: https://regexr.com/3h076
How to fix this?
Why not just append the inside of the regex to make a larger string
_["Some text to get"]
Regex p = new Regex(#"_\[" + " (.*?)" + "\"]");
Related
This question already has answers here:
Regex for numbers after a certain string part
(2 answers)
Closed 4 years ago.
I want to extract a character after a particular string, example:
Sentence: "Develop1 Tester2 BA3"
String: Develop
Expected result: "1"
I tried the Regex as following but still not get result as my expectation, please consult me, thank in advance.
RegEx: /[DEVELOP\d]\[+-]?\d+(?:\.\d*)?/
You don't really need a regex for this.
Something like this should do the trick:
var input = "Develop1 Tester2 BA3";
var search = "Develop";
if (input.StartsWith(search) && input.Length > search.Length) {
var result = input[search.Length];
Console.Write("Result: " + result);
}
This question already has answers here:
mask all digits except first 6 and last 4 digits of a string( length varies )
(13 answers)
Closed 4 years ago.
I'm using C# to create a pattern in order to replace all the occurrences in a string from
RX123456789 into RX*********
I have tried various patterns without success. I'm kinda new regarding Regular Expression.
I appreciate your help.
Use this Regex:-
string data = "RX123456789";
var resultString = Regex.Replace(data, #"[0-9]", "*");
If you need * of number only When RX is present then use this logic:-
string data = "RX123456789";
var resultString="";
if (new Regex("RX([0-9]+)").IsMatch(data))
{
resultString = Regex.Replace(data, #"[0-9]", "*");
}
This question already has answers here:
What special characters must be escaped in regular expressions?
(13 answers)
How to globally replace pipe symbol "|" in string
(5 answers)
Closed 4 years ago.
string query = "A|B";
The output of the next 2 lines are equal to "%A%|%B%" whereas "A%B" is expected!
query = Regex.Replace(query, "|", "%");
query = Regex.Replace(query, #"|", "%");
Why?
The | is a special character of regexes, it means "or". You have to escape it.
query = Regex.Replace(query, #"\|", "%");
This question already has answers here:
RegEx Starts with [ and ending with ]
(4 answers)
Closed 6 years ago.
How to replace a set of characters where I only know the first and the last one, in between is a variable that is not constant.
All I know is that this string will always start with & and it will end with ;
string str = "Hello &145126451; mate!";
How to get rid of &145126451; ?
So the desired result is:
string result = "Hello mate!"
The most easiest way is to use Regex:
Regex yourRegex = new Regex(#"&.*;");
string result = yourRegex.Replace("Hello &145126451; mate!", String.Empty);
Console.WriteLine(result);
Here is a fiddle with example.
This question already has answers here:
Closed 14 years ago.
I would like to take a pascal-cased string like "CountOfWidgets" and convert it into something more user-friendly like "Count of Widgets" in C#. Multiple adjacent uppercase characters should be left intact. What is the most efficient way to do this?
NOTE: Duplicate of .NET - How can you split a "caps" delimited string into an array?
Don't know about efficient but at least it's terse:
Regex r = new Regex("([A-Z]+[a-z]+)");
string result = r.Replace("CountOfWidgets", m => (m.Value.Length > 3 ? m.Value : m.Value.ToLower()) + " ");