C# - multiple thread start one thread - c#

I have 3 threads in 3 classes running in parallel. Each of them, increase Pos or Neg of the Fourthclass by "1". After 3 threads are done, if Fourclass.Pos > Fourclass.Neg, it will run Terminal4.
Q: How can i run the Terminal4 only 1 time. Because putting Fourthclass.Terminal4(); in each Terminal1-2-3 will run the Terminal4 3 times.
Here is what i have done:
public class Firstclass
{
static int Pos = 1;
static int Neg = 0;
public static void Terminal1()
{
if (Pos > Neg)
{
Fourthclass.Pos += 1;
// Fourthclass.Terminal4();
}
}
}
public class Secondclass
{
static int Pos = 1;
static int Neg = 0;
public static void Terminal2()
{
if (Pos > Neg)
{
Fourthclass.Pos += 1;
// Fourthclass.Terminal4();
}
}
}
public class Thirdclass
{
static int Pos = 1;
static int Neg = 0;
public static void Terminal3()
{
if (Pos > Neg)
{
Fourthclass.Neg += 1;
// Fourthclass.Terminal4();
}
}
}
public static class Fourthclass
{
public static int Pos = 0;
public static int Neg = 0;
public static void Terminal4()
{
if (Pos > Neg)
{
Console.WriteLine("Pos = {0} - Neg = {1}", Pos, Neg);
Console.WriteLine();
}
else { Console.WriteLine("fail"); }
}
}
class Program
{
static void Main(string[] args)
{
Thread obj1 = new Thread(new ThreadStart(Firstclass.Terminal1));
Thread obj2 = new Thread(new ThreadStart(Secondclass.Terminal2));
Thread obj3 = new Thread(new ThreadStart(Thirdclass.Terminal3));
obj1.Start();
obj2.Start();
obj3.Start();
}
}

Original Answer
By the by... these increments are not thread safe, they may suffer the ABA problem and that is ignoring thread visibility problems.
For that problem, please use Interloked. Interlocked.Increment and Interlocked.Decrement will take care of it.
Now, for making a code block run only once, keep an int variable that will be 1 if it did run, and 0 if it did not. Then use Interlocked.CompareExchange:
int didrun;
// ...
if (Interlocked.CompareExchange(ref didrun, 1, 0) == 0)
{
// code here will only run once, until you put didrun back to 0
}
There are other ways, of course. This one is just very versatile.
Addendum: Ok, what it does...
Interlocked.CompareExchange will look at the value of the passed variable (didrun) compare it to the second parameter (0) and if it matches, it will change the variable to the value of first parameter (1) [Since it may change the variable, you have to pass it by ref]. The return value is what it found in the variable.
Thus, if it returns 0, you know it found 0, which means that it did update the value to 1. Now, the next time this piece of code is called, the value of the variable is 1, so Interlocked.CompareExchange returns 1 and the thread does not enter the block.
Ok, why do not use a bool instead? Because of thread visibility. A thread may change the value of the variable, but this update could happen in CPU cache only, and not be visible to other threads... Interlocked gets around of that problem. Just use Interlocked. And MSDN is your friend.
That will work regardless if you are using ThreadPool, Task or async/await or just plain old Threads as you do. I mention that because I would like to suggest using those...
Sneaky link to Threading in C#.
Extended Answer
In comment, you ask about a different behavior:
The Terminal4 has cooldown until the next run
Well, if there is a cool down (which I understand as a period) you do not only need to store whatever or not the code did run, but also when was the last time it did.
Now, the conditional cannot be just "run only if it has not run yet" but instead "run if it has not run yet or if the period from the last time it ran to now is greater than the cool down".
We have to check multiple things, that is a problem. Now the check will no longer be atomic (from the Latin atomus which means indivisible, from a- "not" + tomos "a cutting, slice, volume, section").
That is relevant because if the check is not atomic, we are back to the ABA problem.
I will use this case to explain the ABA problem. If we encode the following:
1. Check if the operation has not run (if it has not go to 4)
2. Get the last time it ran
3. Compute the difference from the last run to now (exit if less than cool down)
4. Update the last run time to now
5. Run code
Two threads may do the following:
|
t Thread1: Check if the operation has not run (it has)
i Thread2: Check if the operation has not run (it has)
m Thread2: Get the last time it ran
e Thread1: Get the last time it ran
| Thread1: Compute the difference from the last run to now (more than cool down)
v Thread2: Compute the difference from the last run to now (more than cool down)
Thread2: Update the last run time to now
Thread2: Run code
Thread1: Update the last run time to now
Thread1: Run code
As you see, they both Run code.
What we need is a way to check and update in a single atomic operation, that way the act of checking will alter the result of the other thread. That is what we get with Interlocked.
How Interlocked manages to do that is beyond the scope of the question. Suffice to say that there are some special CPU instructions for that.
The new pattern I suggest is the following (pseudocode):
bool canRun = false;
DateTime lastRunCopy;
DateTime now = DateTime.Now;
if (try to set lastRun to now if lastRun is not set, copy lastRun to lastRunCopy)
{
// We set lastRun
canRun = true;
}
else
{
if ((now - lastRunCopy) < cooldown)
{
if (try to set lastRun to now if lastRun = lastRunCopy, copy lastRun to lastRunCopy)
{
// we updated it
canRun = true;
}
}
else
{
// Another thread got in
}
}
if (canRun)
{
// code here will only run once per cool down
}
Notice I have expressed the operations in terms of "try to set X to Y if X is Z, copy X to W" which is how Interlocked.CompareExchange works.
There is a reason I left that in pseudo code, and that is that DateTime is not an atomic type.
In order to make the code work we will have to use DateTime.Ticks. For an unset value we will use 0 (00:00:00.0000000 UTC, January 1, 0001), which is something you have to worry about for a cool down greater than a couple of millennia.
In addition, of course, we will use the overload of Interlocked.CompareExchange that takes long because DateTime.Ticks is of that type.
Note: Ah, we will use TimeSpan.Ticks for the cool down.
The code is as follows:
long lastRun = 0;
long cooldown = TimeSpan.FromSeconds(1).Ticks; // Or whatever, I do not know.
// ...
bool canRun = false;
long lastRunCopy = 0;
long now = DateTime.Now.Ticks;
lastRunCopy = Interlocked.CompareExchange(ref lastRun, now, 0);
if (lastRunCopy == 0)
{
// We set lastRun
canRun = true;
}
else
{
if ((now - lastRunCopy) < cooldown)
{
if (Interlocked.CompareExchange(ref lastRun, now, lastRunCopy) == lastRunCopy)
{
// we updated it
canRun = true;
}
else
{
// Another thread got in
}
}
}
if (canRun)
{
// code here will only run once per cooldown
}
Alternatively, if you want to boil it down to a single conditional:
long lastRun = 0;
long cooldown = TimeSpan.FromSeconds(1).Ticks; // Or whatever, I do not know.
// ...
long lastRunCopy;
var now = DateTime.Now.Ticks;
if
(
(lastRunCopy = Interlocked.CompareExchange(ref lastRun, now, 0)) == 0
|| now - lastRunCopy < cooldown
&& Interlocked.CompareExchange(ref lastRun, now, lastRunCopy) == lastRunCopy
)
{
// code here will only run once per cooldown
}
As I said, Interlocked.CompareExchange is versatile. Although, as you can see, you still need to think around the requirements.

Related

How do I reduce integer A when integer B increments?

I am generally pretty new to C# and coding in general.
Basically, this is what I have.
public bool TimeLeft;
public void Process()
{
int B = (int)Game.LocalPlayer.Character.TravelDistanceTo(spawnPoint) * 3; // An integer based on the distance of the character to a Vector3(spawnPoint).
while (TimeLeft)
{
int A = Game.GameTime / 1000; //GameTime is time lapsed in game in milliseconds.
}
}
But this is where my brain fries. Let's assume int B is 150.
How would I go about do reduce int B by 1 every time int A increases by 1? This happens within a loop.
I declare int B outside of the loop, and A inside because it needs to update every tick. TimeLeft is set somewhere else.
You have to keep track of the value of A. When you poll A anew you store the value in another variable. Then you can compute the difference and decrease B by this difference. Pseudocode:
int A = ...
int B = ...
while(...)
{
int A_new = ...
B -= A_new - A;
}
You need to define the values outside of the loop, inside the loop should only be the processing taking place. (Like Adok has mentioned)
I'd also say that while (true) is not a good practise of a general processing loop, unless you're making sure the whole program is defined within that loop.
Some game studios have a certain "Init" function, and an "Update" function, the init will happen when the game starts up the first time, and update will always be repeated like a loop after the init has been triggered. The benefit of using Update over a personal while loop is that it won't miss out out on other looping functions like Drawing
With understanding the difference between initialising and updating, It would be easier to understand a countdown like this:
In Init:
//defining 2 values to count down, one that decreases, and one that sets the value back to default.
int A = 150;
int Amax = A;
In Update:
if (A > 0)
{
A -= 1; //decrease the value if it's not at 0
}
else
{
//trigger an activity that happens when A reaches 0
//reset the timer
A = Amax;
}

How come this algorithm in Ruby runs faster than in Parallel'd C#?

The following ruby code runs in ~15s. It barely uses any CPU/Memory (about 25% of one CPU):
def collatz(num)
num.even? ? num/2 : 3*num + 1
end
start_time = Time.now
max_chain_count = 0
max_starter_num = 0
(1..1000000).each do |i|
count = 0
current = i
current = collatz(current) and count += 1 until (current == 1)
max_chain_count = count and max_starter_num = i if (count > max_chain_count)
end
puts "Max starter num: #{max_starter_num} -> chain of #{max_chain_count} elements. Found in: #{Time.now - start_time}s"
And the following TPL C# puts all my 4 cores to 100% usage and is orders of magnitude slower than the ruby version:
static void Euler14Test()
{
Stopwatch sw = new Stopwatch();
sw.Start();
int max_chain_count = 0;
int max_starter_num = 0;
object locker = new object();
Parallel.For(1, 1000000, i =>
{
int count = 0;
int current = i;
while (current != 1)
{
current = collatz(current);
count++;
}
if (count > max_chain_count)
{
lock (locker)
{
max_chain_count = count;
max_starter_num = i;
}
}
if (i % 1000 == 0)
Console.WriteLine(i);
});
sw.Stop();
Console.WriteLine("Max starter i: {0} -> chain of {1} elements. Found in: {2}s", max_starter_num, max_chain_count, sw.Elapsed.ToString());
}
static int collatz(int num)
{
return num % 2 == 0 ? num / 2 : 3 * num + 1;
}
How come ruby runs faster than C#? I've been told that Ruby is slow. Is that not true when it comes to algorithms?
Perf AFTER correction:
Ruby (Non parallel): 14.62s
C# (Non parallel): 2.22s
C# (With TPL): 0.64s
Actually, the bug is quite subtle, and has nothing to do with threading. The reason that your C# version takes so long is that the intermediate values computed by the collatz method eventually start to overflow the int type, resulting in negative numbers which may then take ages to converge.
This first happens when i is 134,379, for which the 129th term (assuming one-based counting) is 2,482,111,348. This exceeds the maximum value of 2,147,483,647 and therefore gets stored as -1,812,855,948.
To get good performance (and correct results) on the C# version, just change:
int current = i;
…to:
long current = i;
…and:
static int collatz(int num)
…to:
static long collatz(long num)
That will bring down your performance to a respectable 1.5 seconds.
Edit: CodesInChaos raises a very valid point about enabling overflow checking when debugging math-oriented applications. Doing so would have allowed the bug to be immediately identified, since the runtime would throw an OverflowException.
Should be:
Parallel.For(1L, 1000000L, i =>
{
Otherwise, you have integer overfill and start checking negative values. The same collatz method should operate with long values.
I experienced something like that. And I figured out that's because each of your loop iterations need to start other thread and this takes some time, and in this case it's comparable (I think it's more time) than the operations you acctualy do in the loop body.
There is an alternative for that: You can get how many CPU cores you have and than use a parallelism loop with the same number of iterations you have cores, each loop will evaluate part of the acctual loop you want, it's done by making an inner for loop that depends on the parallel loop.
EDIT: EXAMPLE
int start = 1, end = 1000000;
Parallel.For(0, N_CORES, n =>
{
int s = start + (end - start) * n / N_CORES;
int e = n == N_CORES - 1 ? end : start + (end - start) * (n + 1) / N_CORES;
for (int i = s; i < e; i++)
{
// Your code
}
});
You should try this code, I'm pretty sure this will do the job faster.
EDIT: ELUCIDATION
Well, quite a long time since I answered this question, but I faced the problem again and finally understood what's going on.
I've been using AForge implementation of Parallel for loop, and it seems like, it fires a thread for each iteration of the loop, so, that's why if the loop takes relatively a small amount of time to execute, you end up with a inefficient parallelism.
So, as some of you pointed out, System.Threading.Tasks.Parallel methods are based on Tasks, which are kind of a higher level of abstraction of a Thread:
"Behind the scenes, tasks are queued to the ThreadPool, which has been enhanced with algorithms that determine and adjust to the number of threads and that provide load balancing to maximize throughput. This makes tasks relatively lightweight, and you can create many of them to enable fine-grained parallelism."
So yeah, if you use the default library's implementation, you won't need to use this kind of "bogus".

Messagebox If Loop

I have a simple message box pop up when a variable is achieved. It spirals into infinity since I have no stopper. Perhaps it's just my inability to figure out where the stopper is to be placed, but it doesn't seem to halt no matter my solution.
if (number == 10)
{
MessageBox.Show("Woot!");
}
Without more code, you can either use a break (as it sounds like you are using a loop), or set your number to something other than 10
while(switchstatement)
{
...logic...
if(number == 10)
{
MessageBox.Show("woot");
break;
}
...more logic...
}
Or, you can set the switch that kills your loop
while(switchstatement)
{
...logic...
if(number == 10)
{
MessageBox.Show("woot");
switchstatement = false;
}
...more logic...
}
That is based off of limited code...so you may have to provide more code if this is not correct.
You are using a variable but i don't see where you set the value so i assume that you never change it in the loop. Hence you are in an infinite loop.
You could use a for-loop instead
for(int number = 0; number < 10; number++)
{
MessageBox.Show("Woot!");
}
or in a while
int number = 0;
while(number++ < 10)
{
MessageBox.Show("Woot!");
}
C# Increment Int
++ Operator (C# Reference)

Change the priority in a custom priority queue

I followed the directions given in this question (the answer by Jason) in order to write my PriorityQueue<T> using a SortedList. I understand that the count field within this class is used to ensure unique priorities and to preserve the enqueue order among the same priority.
However, when count reaches its maximum value and I sum 1 to it, the latter will starts again from 0, so the priority of the subsequent items would be higher than the priority of the previous items. Using this approach I could need for a way to "securely" reset the counter count... In fact, suppose to have the following queue state (in the format priority | count | item):
0 | 123 | A
0 | 345 | B
1 | 234 | C
2 | 200 | D
Now suppose the counter limit has reached, so I have to reset it to 0: as a consequence, the next inserted item will have counter 0: for example, if I insert an element with priority equal to 1, it will be wrongly inserted before 1 | 234 | D
0 | 123 | A
0 | 345 | B
1 | 000 | new element
1 | 234 | C
2 | 200 | D
The problem of the priority can be solved by implementing an heap: I created an Heap class, then I used Heap<KeyValuePair<TPriority, TElement> and a custom PriorityComparer in order to sort elements by TPriority.
Given TPriority as an int and TElement as a string, the PriorityComparer is as follows:
public class MyComparer : IComparer<KeyValuePair<int, string>>
{
public int Compare(KeyValuePair<int, string> x, KeyValuePair<int, string> y)
{
return x.Key.CompareTo(y.Key);
}
}
...
int capacity = 10;
Heap<KeyValuePair<int, string>> queue;
queue = new Heap<KeyValuePair<int, string>>(capacity, new PriorityComparer());
...
UPDATE
In this way (using the PriorityComparer), I have succeeded to implement a priority queue.
Now I'd like to add support to modify its behavior at runtime, ie switch from FIFO to priority sorting and vice-versa. Since my implementation of priority queue has an IComparer field, I think it is sufficient to add a Comparer property to edit this field, like as follows:
public IComparer
{
set
{
this._comparer = value;
}
}
In the meantime I thought I'd take a different approach: instead of using a binary heap to manage priorities, I could wrap different queues (each queue refers to a given priority) as follows.
public class PriorityQueue<T, int>
{
private Queue<T> _defaultQueue;
private bool _priority;
private SortedList<int, Queue<T>> _priorityQueues;
public PriorityQueue(int capacity)
{
this._defaultQueue = new Queue<T>(capacity);
this._priority = false;
this._priorityQueues = new SortedList<int, Queue<T>>(0);
}
public void PriorityEnable()
{
this._priority = true;
}
public void PriorityDisable()
{
this._priority = false;
}
public void Enqueue(T item)
{
if (this._priority)
{
// enqueue to one of the queues
// with associated priority
// ...
}
else this._defaultQueue.Enqueue(item);
}
public T Dequeue()
{
if (this._priority)
{
// dequeue from one of the queues
// with associated priority and
// return
// ...
}
return this._defaultQueue.Dequeue();
}
}
How to manage the transition from FIFO mode to priority mode when there are still elements in the default queue? I could copy them in the priority queues based on the item priority... Other better solutions?
How to manage the transition from priority mode to FIFO mode? In this case, I would have several priority queues, which may contain elements, but no longer have to manage them according to priority and not even know the original order of arrival...
How can I manage the capacity of the different queues?
What about the performances of the above two solutions? Which does use more memory?
You could "cheat" and use BigInteger so you never "run out of numbers". This of course leads to gradual deterioration of performance over time, but probably not significant enough to matter.
Combine that with a heap-based priority queue and you are set!
Don't try to "switch from FIFO to priority sorting and vice-versa" - simply put elements in both data structures appropriate for the task (Queue and priority queue).
Using both Queue and Priority Queue is what I would do.
But if you must...
Instead of one key use 2 keys for an element.
The first key priority will be the priority.
The second key time will be a counter that will be like a timestamp.
For the regular behavior use the priority key.
When the heap is full, HEAPIFY it by the time key.
Then remove n needed elements.
Now HEAPIFY it again with the prioritykey to return to the regular behavior.
EDIT: You have kind of changed what you are asking with your edits. You went from asking one question to doing a new approach and asking a new question. Should probably open a new question for your new approach, as this one is now confusing as to what answer/response is to what question/comment. I believe your original question about sorting equal priorities has been answered.
You could use a long to allow for more values. You will always reach an end eventually, so you would need to use a new pattern for unique values or 'recount' the items when the max is reached (loop through each and reset the unique count value).
Maybe use a GUID for each item instead?
Guid.NewGuid()
EDIT:
To add after your edit: If you want the new 1 to be placed after the existing, In the Compare override, return a greater than result (1) when the values are equal. That way the following will happen:
1 > 0, return greater (1), continue
1 > 0, return greater (1), continue
1 == 1, return greater (1), continue
1 < 2, return less than (-1), insert
EDIT 2:
If the second parameter is only meant to be a unique value, you could always use a string and set the value as numeric strings instead. That way you will never reach a cap, would just have to parse the string accordingly. You can use leading alpha values that represent a new set.
I have not tested this code, just an idea as to what you could do.
static string leadingStr = "";
static char currentChar = 'a';
static Int32 currentId = Int32.MinValue;
static string getNextId()
{
if (currentId >= Int32.MaxValue)
{
currentId = Int32.MinValue;
if (currentChar >= 'z')
{
currentChar = 'a';
leadingStr = leadingStr.Insert(0, "X");
}
else
currentChar++;
}
else
currentId++;
return String.Format("{0}{1}-{2}", leadingStr, currentChar, currentId);
}
EDIT 3: Reset Values
static Int64 currentValue = Int64.MinValue;
static void AddItem(object item)
{
if (currentValue == Int64.MaxValue)
RecountItems();
item.counter = currentValue++;
SortedList.Add(item);
}
static void RecountItems()
{
currentValue = 0;
foreach (var item in SortedList)
{
item.counter = currentValue++;
}
}
Edit 4: For your second question:
You could use a FIFO stack as you normally would, but also have a priority List that only stores the unique ID of the items. However you would then need to remove the item from the list every time you remove from the FIFO stack.
static Object RemoveNextFIFO()
{
if (fifoList.Count > 0)
{
var removedItem = fifoList[0];
fifoList.RemoveAt(0);
RemoveItemFromPriority(removedItem);
return removedItem;
}
}
static void RemoveItemFromPriority(Object itemToRemove)
{
foreach (var counter in priorityQueue)
{
if (counter == itemToRemove.counter)
{
priorityQueue.remove(item);
break;
}
}
}
static Object RemoveFromFIFO(int itemCounter)
{
foreach (var item in fifoList)
{
if (item.counter == itemCounter)
{
fifoList.Remove(item);
return item;
}
}
}
static Object RemoveNextPriority()
{
if (priorityQueue.Count > 0)
{
var counter = priorityQueue.Pop();
return RemoveFromFIFO(counter);
}
}

Can a C# blocking FIFO queue leak messages?

I'm working on an academic open source project and now I need to create a fast blocking FIFO queue in C#. My first implementation simply wrapped a synchronized queue (w/dynamic expansion) within a reader's semaphore, then I decided to re-implement in the following (theorically faster) way
public class FastFifoQueue<T>
{
private T[] _array;
private int _head, _tail, _count;
private readonly int _capacity;
private readonly Semaphore _readSema, _writeSema;
/// <summary>
/// Initializes FastFifoQueue with the specified capacity
/// </summary>
/// <param name="size">Maximum number of elements to store</param>
public FastFifoQueue(int size)
{
//Check if size is power of 2
//Credit: http://stackoverflow.com/questions/600293/how-to-check-if-a-number-is-a-power-of-2
if ((size & (size - 1)) != 0)
throw new ArgumentOutOfRangeException("size", "Size must be a power of 2 for this queue to work");
_capacity = size;
_array = new T[size];
_count = 0;
_head = int.MinValue; //0 is the same!
_tail = int.MinValue;
_readSema = new Semaphore(0, _capacity);
_writeSema = new Semaphore(_capacity, _capacity);
}
public void Enqueue(T item)
{
_writeSema.WaitOne();
int index = Interlocked.Increment(ref _head);
index %= _capacity;
if (index < 0) index += _capacity;
//_array[index] = item;
Interlocked.Exchange(ref _array[index], item);
Interlocked.Increment(ref _count);
_readSema.Release();
}
public T Dequeue()
{
_readSema.WaitOne();
int index = Interlocked.Increment(ref _tail);
index %= _capacity;
if (index < 0) index += _capacity;
T ret = Interlocked.Exchange(ref _array[index], null);
Interlocked.Decrement(ref _count);
_writeSema.Release();
return ret;
}
public int Count
{
get
{
return _count;
}
}
}
This is the classic FIFO queue implementation with static array we find on textbooks. It is designed to atomically increment pointers, and since I can't make the pointer go back to zero when reached (capacity-1), I compute modulo apart. In theory, using Interlocked is the same as locking before doing the increment, and since there are semaphores, multiple producers/consumers may enter the queue but only one at a time is able to modify the queue pointers.
First, because Interlocked.Increment first increments, then returns, I already understand that I am limited to use the post-increment value and start store items from position 1 in the array. It's not a problem, I'll go back to 0 when I reach a certain value
What's the problem with it?
You wouldn't believe that, running on heavy loads, sometimes the queue returns a NULL value. I am SURE, repeat, I AM SURE, that no method enqueues null into the queue. This is definitely true because I tried to put a null check in Enqueue to be sure, and no error was thrown. I created a test case for that with Visual Studio (by the way, I use a dual core CPU like maaaaaaaany people)
private int _errors;
[TestMethod()]
public void ConcurrencyTest()
{
const int size = 3; //Perform more tests changing it
_errors = 0;
IFifoQueue<object> queue = new FastFifoQueue<object>(2048);
Thread.CurrentThread.Priority = ThreadPriority.AboveNormal;
Thread[] producers = new Thread[size], consumers = new Thread[size];
for (int i = 0; i < size; i++)
{
producers[i] = new Thread(LoopProducer) { Priority = ThreadPriority.BelowNormal };
consumers[i] = new Thread(LoopConsumer) { Priority = ThreadPriority.BelowNormal };
producers[i].Start(queue);
consumers[i].Start(queue);
}
Thread.Sleep(new TimeSpan(0, 0, 1, 0));
for (int i = 0; i < size; i++)
{
producers[i].Abort();
consumers[i].Abort();
}
Assert.AreEqual(0, _errors);
}
private void LoopProducer(object queue)
{
try
{
IFifoQueue<object> q = (IFifoQueue<object>)queue;
while (true)
{
try
{
q.Enqueue(new object());
}
catch
{ }
}
}
catch (ThreadAbortException)
{ }
}
private void LoopConsumer(object queue)
{
try
{
IFifoQueue<object> q = (IFifoQueue<object>)queue;
while (true)
{
object item = q.Dequeue();
if (item == null) Interlocked.Increment(ref _errors);
}
}
catch (ThreadAbortException)
{ }
}
Once a null is got by the consumer thread, an error is counted.
When performing the test with 1 producer and 1 consumer, it succeeds. When performing the test with 2 producers and 2 consumers, or more, a disaster happens: even 2000 leaks are detected. I found that the problem can be in the Enqueue method. By design contract, a producer can write only into a cell that is empty (null), but modifying my code with some diagnostics I found that sometimes a producer is trying to write on a non-empty cell, which is then occupied by "good" data.
public void Enqueue(T item)
{
_writeSema.WaitOne();
int index = Interlocked.Increment(ref _head);
index %= _capacity;
if (index < 0) index += _capacity;
//_array[index] = item;
T leak = Interlocked.Exchange(ref _array[index], item);
//Diagnostic code
if (leak != null)
{
throw new InvalidOperationException("Too bad...");
}
Interlocked.Increment(ref _count);
_readSema.Release();
}
The "too bad" exception happens then often. But it's too strange that a conflict raises from concurrent writes, because increments are atomic and writer's semaphore allows only as many writers as the free array cells.
Can somebody help me with that? I would really appreciate if you share your skills and experience with me.
Thank you.
I must say, this struck me as a very clever idea, and I thought about it for a while before I started to realize where (I think) the bug is here. So, on one hand, kudos on coming up with such a clever design! But, at the same time, shame on you for demonstrating "Kernighan's Law":
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
The issue is basically this: you are assuming that the WaitOne and Release calls effectively serialize all of your Enqueue and Dequeue operations; but that isn't quite what is going on here. Remember that the Semaphore class is used to restrict the number of threads accessing a resource, not to ensure a particular order of events. What happens between each WaitOne and Release is not guaranteed to occur in the same "thread-order" as the WaitOne and Release calls themselves.
This is tricky to explain in words, so let me try to provide a visual illustration.
Let's say your queue has a capacity of 8 and looks like this (let 0 represent null and x represent an object):
[ x x x x x x x x ]
So Enqueue has been called 8 times and the queue is full. Therefore your _writeSema semaphore will block on WaitOne, and your _readSema semaphore will return immediately on WaitOne.
Now let's suppose Dequeue is called more or less concurrently on 3 different threads. Let's call these T1, T2, and T3.
Before proceeding let me apply some labels to your Dequeue implementation, for reference:
public T Dequeue()
{
_readSema.WaitOne(); // A
int index = Interlocked.Increment(ref _tail); // B
index %= _capacity;
if (index < 0) index += _capacity;
T ret = Interlocked.Exchange(ref _array[index], null); // C
Interlocked.Decrement(ref _count);
_writeSema.Release(); // D
return ret;
}
OK, so T1, T2, and T3 have all gotten past point A. Then for simplicity let's suppose they each reach line B "in order", so that T1 has an index of 0, T2 has an index of 1, and T3 has an index of 2.
So far so good. But here's the gotcha: there is no guarantee that from here, T1, T2, and T3 are going to get to line D in any specified order. Suppose T3 actually gets ahead of T1 and T2, moving past line C (and thus setting _array[2] to null) and all the way to line D.
After this point, _writeSema will be signaled, meaning you have one slot available in your queue to write to, right? But your queue now looks like this!
[ x x 0 x x x x x ]
So if another thread has come along in the meantime with a call to Enqueue, it will actually get past _writeSema.WaitOne, increment _head, and get an index of 0, even though slot 0 is not empty. The result of this will be that the item in slot 0 could actually be overwritten, before T1 (remember him?) reads it.
To understand where your null values are coming from, you need only to visualize the reverse of the process I just described. That is, suppose your queue looks like this:
[ 0 0 0 0 0 0 0 0 ]
Three threads, T1, T2, and T3, all call Enqueue nearly simultaneously. T3 increments _head last but inserts its item (at _array[2]) and calls _readSema.Release first, resulting in a signaled _readSema but a queue looking like:
[ 0 0 x 0 0 0 0 0 ]
So if another thread has come along in the meantime with a call to Dequeue (before T1 and T2 are finished doing their thing), it will get past _readSema.WaitOne, increment _tail, and get an index of 0, even though slot 0 is empty.
So there's your problem. As for a solution, I don't have any suggestions at the moment. Give me some time to think it over... (I'm posting this answer now because it's fresh in my mind and I feel it might help you.)
(+1 to Dan Tao who I vote has the answer)
The enqueue would be changed to something like this...
while (Interlocked.CompareExchange(ref _array[index], item, null) != null)
;
The dequeue would be changed to something like this...
while( (ret = Interlocked.Exchange(ref _array[index], null)) == null)
;
This builds upon Dan Tao's excellent analysis. Because the indexes are atomically obtained, then (assuming that no threads die or terminate in the enqueue or dequeue methods) a reader is guaranteed to eventually have his cell filled in, or the writer is guaranteed to eventually have his cell freed (null).
Thank you Dan Tao and Les,
I really appreciated your help a lot. Dan, you opened my mind: it's not important how many producers/consumers are inside the critical section, the important is that the locks are released in order. Les, you found the solution to the problem.
Now it's time to finally answer my own question with the final code I made thanks to the help of both of you. Well, it's not much but it's a little enhancement from Les's code
Enqueue:
while (Interlocked.CompareExchange(ref _array[index], item, null) != null)
Thread.Sleep(0);
Dequeue:
while ((ret = Interlocked.Exchange(ref _array[index], null)) == null)
Thread.Sleep(0);
Why Thread.Sleep(0)? When we find that an element cannot be retrieved/stored, why immediately checking again? I need to force context switch to allow other threads to read/write. Obviously, the next thread that will be scheduled could be another thread unable to operate, but at least we force it. Source: http://progfeatures.blogspot.com/2009/05/how-to-force-thread-to-perform-context.html
I also tested the code of the previous test case to get proof of my claims:
without sleep(0)
Read 6164150 elements
Wrote 6322541 elements
Read 5885192 elements
Wrote 5785144 elements
Wrote 6439924 elements
Read 6497471 elements
with sleep(0)
Wrote 7135907 elements
Read 6361996 elements
Wrote 6761158 elements
Read 6203202 elements
Wrote 5257581 elements
Read 6587568 elements
I know this is not a "great" discover and I will wiln no Turing prize for these numbers. Performance increment is not dramatical, but is greater than zero. Forcing context switch allows more RW operations to be performed (=higher throughput).
To be clear: in my test, I merely evaluate the performance of the queue, not simulate a producer/consumer problem, so don't care if at the end of the test after a minute there are still elements in queue. But I just demonstrated my approach works, thanks to you all.
Code available open source as MS-RL: http://logbus-ng.svn.sourceforge.net/viewvc/logbus-ng/trunk/logbus-core/It.Unina.Dis.Logbus/Utils/FastFifoQueue.cs?revision=461&view=markup

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