I am trying to use JavaScriptSerializer and I have got good results when I want to serialize a list of objects of a class like
public class employee
{
public string id; //unique id of the employee
public string displayName;
public int displayFlag;
public employee(string i, string dN, int dF)
{
id = i;
displayName = dN;
displayFlag = dF;
}
}
public class data2
{
public List<employee> detail;
}
When I do the following
var json = new JavaScriptSerializer();
string jsonData = json.Serialize(data2);
(and data2 is an object of class data2)
However when I try to do the same for something a little more complicated such as
public class Ccanister
{
string identifier;
public Ccanister(string c)
{
identifier = c;
}
}
public class medicine
{
public string id; //unique id
public string displayName;
//and here an array of canisters
public List<Ccanister> canister;
}
public class dataMedicine
{
public List<medicine> detail; //Change this
}
and I do this
string jsonMedi = json.Serialize(dataM);
I got wrong results.
dataM has correct results (I debugged it) but when jsonMedi gets its results, the canister list 'canister' is always empty. (It was not empty in dataM)
I wonder what I am doing wrong here
Related
I have this class that contains a static list
public class TypeList
{
public string Name;
public string NameTag;
public TypeList(string Name, string NameTag)
{
this.Name = Name;
this.NameTag = NameTag;
}
public static List<TypeList> DataType = new List<TypeList>() {
new TypeList("DataType","-1"),
new TypeList("OpOne","1"),
new TypeList("OpTwo","2"),
};
}
I then put the static list called DataType into a combobox:
public void RefreshList()
{
List<TypeList> data = new List<TypeList>();
data = TypeList.DataType;
typeCB.DataSource = data;
typeCB.DisplayMember = "Name";
typeCB.ValueMember = "NameTag";
typeCB.SelectedValue = -1;
typeCB.SelectedText = "Select DataType";
}
However, when I run it, all I get are the classnames in my combobox. Is something wrong with my code? I tried to do
data.Select(x=>x.Name).ToList()
But that just gives me the name portion.
I might be wrong, but based on the Documentation and Example it might be that this Feature only works with public property getters, not public fields:
Gets or sets the property to display for this ListControl.
public class USState
{
private string myShortName;
private string myLongName;
public USState(string strLongName, string strShortName)
{
this.myShortName = strShortName;
this.myLongName = strLongName;
}
public string ShortName
{
get
{
return myShortName;
}
}
public string LongName
{
get
{
return myLongName;
}
}
}
Of course I would also advise against making the list a part of the Type class. A simple Programm scope static would be better. If that is the case and as autoproties have have become a thing by now, this should be enough of a fix:
public class Type
{
public string Name { private set; get } ;
public string NameTag {private set; get };
public TypeList(string Name, string NameTag)
{
this.Name = Name;
this.NameTag = NameTag;
}
}
//use in the class of main, the form or some similar central point
static List<Type> TypeList = new List<Type>();
I am trying to get an object to deserialize into itself. I have tride the following:-
public class JobID
{
public string jobname;
public string first;
public string second;
public string third;
public string clientName;
public string workflow;
}
public void load(string fname)
{
string s = File.ReadAllText(fname);
this = JsonConvert.DeserializeObject<JobID>(s);
}
But the word this is 'read only' according to the error I get.
I have used 'this.jobname = "X";' before so clearly 'this' is not read only.
I am using Newtonsof.Json.
Why not use static method to load the object. Such as :
public class JobID
{
public string jobname;
public string first;
public string second;
public string third;
public string clientName;
public string workflow;
public static JobId Load(string fname){
string s = File.ReadAllText(fname);
return JsonConvert.DeserializeObject<JobID>(s);
}
}
Although you can assign a value to a property of 'this', you can't change the object to which 'this' refers to.
The 'this' keyword refers to the current object instance in the context (https://learn.microsoft.com/en-us/dotnet/csharp/language-reference/keywords/this).
Assuming the Load function is inside another object (or static), you could do something like:
public class JobID
{
public string jobname;
public string first;
public string second;
public string third;
public string clientName;
public string workflow;
}
public class JobReader
{
// Property to store deserialized object
public JobID Job { get; set; }
public void load(string fname)
{
string s = File.ReadAllText(fname);
// Assign object to property.
this.JobID = JsonConvert.DeserializeObject<JobID>(s);
}
}
You can use the static method as suggested by Xbotter to create a new instance. But for some reason if you want to deserialize the file content into current object only, then easiest way would be:
public class JobID
{
public string jobname;
public string first;
public string second;
public string third;
public string clientName;
public string workflow;
public void load(string fname)
{
string s = File.ReadAllText(fname);
JobID tmp = JsonConvert.DeserializeObject<JobID>(s);
copy(tmp);
}
public void copy(JobID tmp)
{
this.jobname = tmp.jobname;
// do the same for other properties that you want to copy
}
}
If you want to do this without a static method, you can use the JsonSerializer.Populate method. Example code:
public class JobID
{
public string jobname;
public string first;
public string second;
public string third;
public string clientName;
public string workflow;
public void load(string fname)
{
string s = File.ReadAllText(fname);
new JsonSerializer().Populate(new JsonTextReader(new StringReader(s)), this);
}
}
Anssssss provided the answer I've been looking for years. Thank you!
This is how I used it:
bool bOk = false;
StreamReader myFileStream = null;
Newtonsoft.Json.JsonSerializer mySerializer = new Newtonsoft.Json.JsonSerializer();
try
{
myFileStream = File.OpenText(sFilePath);
mySerializer.Populate(myFileStream, this);
bOk = true;
}
catch (Exception e)
{
string sException = e.ToString();
CHelper.ThrowException(new Exception(sException + "\n\n" + sFilePath));
}
finally
{
if (myFileStream != null)
{
myFileStream.Close();
}
}
return bOk;
Currently I am just returning the json string to corresponding file from where Test1() is called and Deserializing there as ResponseClass r = JsonConvert.DeserializeObject(response_json)
Send part I forget to make a class [Serializable].Its working fine now.
Part1:
public class Movie
{
public string Name { get; set; }
public string Description { get; set; }
public string Classification { get; set; }
public string Studio { get; set; }
public DateTime? ReleaseDate { get; set; }
public List<string> Genres{ get; set; }
}
public class ResponseClass
{
public string SuccessStatus{ get; set; }
public string next_link { get; set; }
}
private void Test1<T,Q>()
{
string json = #"{
'Name': 'Bad Boys',
'ReleaseDate': '1995-4-7T00:00:00',
'Genres': [
'Action',
'Comedy'
]
}";
//Here making network call with above json and getting correct response_josn
Q response_obj = JsonConvert.DeserializeObject<Q>(reponse_json);
print(response_obj);
}
I am calling Test1() as follows on button click:
Test1<Movie, ResponseClass>();
For the above example I am getting print log as ClassName+Movie (T FullName).
I want to deserialize the string into that class. How to achieve that?
Part2 : If I have class as:
[Serializable]
public class Movie
{
public string Name;
public string Description;
public string Classification;
public string Studio;
public DateTime ReleaseDate;
public SubClass subClass;
public List<SubClass> lsubclass;
}
[Serializable] //This was the mistake.
public class SubClass
{
public string a;
public string b;
public List<string> ReleaseCountries;
}
private Movie createValidMovieJson()
{
Movie m = new Movie();
SubClass sc = new SubClass();
sc.a = "aaa";
sc.b = "bbb";
sc.ReleaseCountries = new List<string>();
sc.ReleaseCountries.Add("Japan");
sc.ReleaseCountries.Add("India");
List<SubClass> lsC = new List<SubClass>();
lsC.Add(sc);
lsC.Add(sc);
m.Name = "Bad Boys";
m.Studio = "Pixa";
m.subClass = sc;
m.lsubclass = lsC;
Debug.Log(JsonUtility.ToJson(m)); // value n log = {"Name":"Bad Boys","Description":"","Classification":"","Studio":"Pixa"}
return m;
}
JsonUtility is returning empty value in place of subclass after using ToJson() as shown in above function.
Based on the screenshot you added I think you are expecting to be able to treat the deserialized type as a Movie. This is the way to achieve that:
var movie = JsonConvert.DeserializeObject<Movie>(json);
Currently your deserialized object is being treated as type T - which could be anything since you have no generic type constraints on your method.
Like I said in the comment section, JsonUtility should do it.
I just replaced T m = JsonConvert.DeserializeObject(json); with T
m = JsonUtility.FromJson(json); it gives an error
ArgumentException: JSON parse error: Missing a name for object member.
Your json is invalid for JsonUtility. I believe you are using ' instead of ". This is why you are getting this error.
Use the function below to generate a valid json:
void createValidMovieJson()
{
Movie m = new Movie();
m.Name = "Bad Boys";
m.ReleaseCountries = new List<string>();
m.ReleaseCountries.Add("Japan");
m.Studio = "Pixa";
Debug.Log(JsonUtility.ToJson(m));
}
You will get:
{"Name":"Bad Boys","Description":"","Classification":"","Studio":"Pixa","ReleaseCountries":["Japan"]}
When ecaped for testing, you will get:
{\"Name\":\"Bad Boys\",\"Description\":\"\",\"Classification\":\"\",\"Studio\":\"Pixa\",\"ReleaseCountries\":[\"Japan\"]}
For JsonUtility to work, you must add [Serializable] to the class and remove { get; set; } from them class variables.
If your goal is to convert any json to any data type then you have to return generic type then use Convert.ChangeType to convert it to that type.
It should look something like this:
// Use this for initialization
void Start()
{
string json = "{\"Name\":\"Bad Boys\",\"Description\":\"\",\"Classification\":\"\",\"Studio\":\"Pixa\",\"ReleaseCountries\":[\"Japan\"]}";
Movie movie = Load<Movie>(json);
print(movie.Name);
}
[Serializable]
public class Movie
{
public string Name;
public string Description;
public string Classification;
public string Studio;
public DateTime? ReleaseDate;
public List<string> ReleaseCountries;
}
private T Load<T>(string json)
{
object resultValue = JsonUtility.FromJson<T>(json);
return (T)Convert.ChangeType(resultValue, typeof(T));
}
I have something like:
class ABC
{
public int id { get; set; }
public string name { get; set; }
public int value { get; set; }
}
And json like {"name":"John","value":123}
I want to parse this json and create an ABC for a specified id value. I wondered if I have to do this in two steps or can pass the id in somehow? Ideally these fields would be readonly but I'm not sure if JSON.net allows that.
e.g. a method like ABC getABC(int id, string json)
It's a bit code-golfy, but you want to make the members of ABC readonly, then deserialize JSON into an instance of ABC while passing in a specified id using just one line of code, you can do:
var abc = new JObject(new[] { new JProperty("id", id) }.Concat(JObject.Parse(json).Properties())).ToObject<ABC>();
Using the class:
class ABC
{
readonly int m_id;
readonly string m_name;
readonly int m_value;
public ABC(int id, string name, int value)
{
this.m_id = id;
this.m_name = name;
this.m_value = value;
}
public int id { get { return m_id; } }
public string name { get { return m_name; } }
public int value { get { return m_value; } }
}
This takes advantage of the fact that, if an object has a single public parameterized constructor, Json.NET will invoke it to construct the object, matching argument names to JSON property names. Thus you can pass the id in by parsing the JSON to a JObject, merging in the id, then deserializing to your final class.
A less code-golfy solution would be to do:
var abc = JObject.Parse(json).WithProperty("id", id).ToObject<ABC>();
Using the fluent extension method:
public static class JsonExtensions
{
public static JObject WithProperty(this JObject obj, string name, JToken value)
{
obj = obj ?? new JObject();
obj[name] = value;
return obj;
}
}
I am serializing with xml, and I had it working with just a simple class, but when I made a secondary class, of which the simple class was just a component, the serialization stopped working. It fails with an "Error reflecting type" error at the serialization stage. The code is as follows:
public class CustomField
{
[XmlAttribute("FieldID")]
public string FieldID;
[XmlAttribute("FieldValue")]
public string FieldValue;
public CustomField() { }
public CustomField(string fieldID, string fieldValue)
{
this.FieldID = fieldID;
this.FieldValue = fieldValue;
}
}
[XmlType("Entry")]
public class CustomEntry
{
[XmlAttribute("Author")]
public string Author;
[XmlAttribute("Title")]
public string Title;
[XmlAttribute("Trial")]
public string Trial;
[XmlAttribute("Responses")]
public List<CustomField> Responses;
public CustomEntry() { }
}
public static class EntrySerializer
{
public static void SerializeObject(this CustomEntry entry, string file)
{
var serializer = new XmlSerializer(typeof(CustomEntry));
using (var stream = File.OpenWrite(file))
{
serializer.Serialize(stream, entry);
}
}
}
Is it a labeling issue with the Xml markers, or is it something else?
Try defining your serializer like this:
var serializer = new XmlSerializer(typeof(CustomEntry), new Type[] { typeof(CustomField) });
You need to inform the serializer of the additional types it is expecting to serialize.
I usually tag with XMLRoot (two places). I need to see sample of XML to give better answer.
[XmlRoot("CustomField")]
public class CustomField
{
[XmlAttribute("FieldID")]
public string FieldID;
[XmlAttribute("FieldValue")]
public string FieldValue;
public CustomField() { }
public CustomField(string fieldID, string fieldValue)
{
this.FieldID = fieldID;
this.FieldValue = fieldValue;
}
}
[XmlRoot("Entry")]
public class CustomEntry
{
[XmlAttribute("Author")]
public string Author;
[XmlAttribute("Title")]
public string Title;
[XmlAttribute("Trial")]
public string Trial;
[XmlAttribute("Responses")]
public List<CustomField> Responses;
public CustomEntry() { }
}