I'm looking to write a regex (C#) that will match words that aren't surrounded by quotes. An example input string would be:
dbo.test line_length "quoted words" notquoted
And this needs to match
dbo.test
line_length
nonquoted
So 3 separate matches and "quoted words" is not matched. The quoted phrase could be anywhere in the input...beginning, middle, end, etc.
I haven't been able to come up with a regex that matches words not in quotes where there could be a space in the quotes...I've been able to match something like: hello "world" and only get hello.
Is there a way to write the regex I'm trying to?
There are two ways to tackle this, depending on what you want to do with the output.
First, match (but don't capture) any text within quotation marks. (This is specifically matching the stuff that you DON'T want.)
Using the | pipe, use capture groups to select everything that you DO want to keep.
Example:
".*?"|(\b\S+\b)
You can see an example of that here.
The other option, using look-arounds, is to specifically look backward from the beginning of the words to ensure that the " doesn't appear there:
(?<!")(\b\S+\b)(?!")
You can see that here.
This may have a problem when you start using multiple words, but this should get you on the right track, and you can indicate whether one of these methods works better for you than the other.
Related
I'm using the following regex in c# to match some input cases:
^
(?<entry>[#])?
(?(entry)(?<id>\w+))
(?<value>.*)
$
The options are ignoring pattern whitespaces.
My input looks as follows:
hello
#world
[xxx]
This all can be tested here: DEMO
My problem is that this regex will not match the last line. Why?
What I'm trying to do is to check for an entry character. If it's there I force an identifier by \w+. The rest of the input should be captured in the last group.
This is a simplyfied regex and simplyfied input.
The problem can be fixed if I change the id regex to something like (?(entry)(?<id>\w+)|), (?(entry)(?<id>\w+))? or (?(entry)(?<id>\w+)?).
I try to understand why the conditional group doesn't match as stated in original regex.
I'm firm in regex and know that the regex can be simplyfied to ^(\#(?<id>\w+))?(?<value>.*)$ to match my needs. But the real regex contains two more optional groups:
^
(?<entry>[#])?
(\?\:)?
(\(\?(?:\w+(?:-\w+)?|-\w+)\))?
(?(entry)(?<id>\w+))
(?<value>.*)
$
That's the reason why I'm trying to use a conditional match.
UPDATE 10/12/2018
I tested a little arround it. I found the following regex that should match on every input, even an empty one - but it doesn't:
(?(a)a).*
DEMO
I'm of the opinion that this is a bug in .net regex and reported it to microsoft: See here for more information
There is no error in the regex parser, but in one's usage of the . wildcard specifier. The . specifier will consume all characters, wait for it, except the linefeed character \n. (See Character Classes in Regular Expressions "the any character" .])
If you want your regex to work you need to consume all characters including the linefeed and that can be done by specify the option SingleLine. Which to paraphrase what is said
Singline tells the parser to handle the . to match all characters including the \n.
Why does it still fail when not in singleline mode for the other lines are consumed? That is because the final match actually places the current position at the \n and the only option (as specified is use) is the [.*]; which as we mentioned cannot consume it, hence stops the parser. Also the $ will lock in the operations at this point.
Let me demonstrate what is happening by a tool I have created which illustrates the issue. In the tool the upper left corner is what we see of the example text. Below that is what the parser sees with \r\n characters represented by ↵¶ respectively. Included in that pane is what happens to be matched at the time in yellow boxes enclosing the match. The middle box is the actual pattern and the final right side box shows the match results in detail by listening out the return structures and also showing the white space as mentioned.
Notice the second match (as index 1) has world in group capture id and value as ↵.
I surmise your token processor isn't getting what you want in the proper groups and because one doesn't actually see the successful match of value as the \r, it is overlooked.
Let us turn on Singline and see what happens.
Now everything is consumed, but there is a different problem. :-)
I want to export a View as a HTML-Document to the User on my ASP.NET page. I want to give the option to only get a part of the view.
Because of that I want to split the output with Regex.Split(). I wrote a Regex that matches the part I want to cut out. After splitting I put the 2 output parts together again.
The problem is that I get a list of 3 parts, of which the second contains " ". How can I change the code that the output contains only 2 strings?
My Code:
textParts = Regex.Split(text, #"<!--Graphic2-->(.|\n)*<!--EndDiscarded-->");
text = textParts[0] + textParts[1];
text contains HTML, CSS and jQuery Code. I wrote comments like <!--Graphic2--> around the blocks I want to cut out.
EDIT
I got it working now by using the Regex.Replace() Method. But I still don't know why Split isn't working how I expected.
You should consider parsing HTML with the proper tools, like HtmlAgilityPack.
The current question is about why Regex.Split returned 3 values. That is due to the presence of a capturing group in your pattern. Regex.Split returns the chunks between start/end of string and the matched chunks, and all captured substrings:
If capturing parentheses are used in a Regex.Split expression, any captured text is included in the resulting string array. For example, if you split the string "plum-pear" on a hyphen placed within capturing parentheses, the returned array includes a string element that contains the hyphen.
So, Regex.Split(text, #"<!--Graphic2-->(.|\n)*<!--EndDiscarded-->") matches <!--Graphic2--> substring, then matches and captures into Group 1 any 0+ occurrences of any char, as many as possible, and then matches <!--EndDiscarded-->") - these matches are removed and substrings that are not matched are returned, but the last char captured into the repeated capturing group is also returned.
So, if you plan to use regex for this task, you should consider re-writing it to #"(?s)<!--Graphic2-->.*?<!--EndDiscarded-->" or #"<!--Graphic2-->[^<]*(?:<(?!!--EndDiscarded)[^<]*)*<!--EndDiscarded-->" that will be much more efficient, or even #"<!--Graphic2-->[^<]*(?:<(?!!--(?:EndDiscarded|Graphic2))[^<]*)*<!--EndDiscarded-->" that will ensure no nested Graphic2 comments are matched.
See, the complexity of the regexps rises when you want to make sure your patterns work more efficiently and safer. However, even these longer versions do not guarantee 100% safety.
I have a case I'm trying to match using regular expressions.
My current expression will match a string in a certain format with or without dashes. I would like to add it to match only if the string has not been matched before, with or without the dashes. For example, take the following cases:
1. 1234-56-789-5555
2. 1234567895555
3. 0000-99-888-3333
4. 1111223334444
If the four examples above appeared in this same order in a list, document, whatever, I would want to only capture (1, 3, 4). I want to skip #2 since it was already captured by #1, but with the dashes. If #2 had of come first, I would have wanted to similarly skip #1.
Here's the current expression I'm using:
\d\d\d\d-*\d\d-*\d\d\d-*\d\d\d\d
I tried to read up on look behinds (I'm fairly inexperienced with Regex) but I only really understand that a look behind only checks if certain text is matched previously. I'm not sure if what I want can be combined with this; I only see how to check for specific text, not for the current value with/without dashes.
I'm currently doing this with C# logic, but am trying to see if it can be done purely in Regex. If it can't be done, that's fine; I'm just trying to beef up my Regex knowledge in this case.
Is this possible -- how can I accomplish this?
If you want to obtain just the first occurrence of each number (answering I want to skip #2 since it was already captured by #1, but with the dashes), you need a negative look-behind with a RegexOptions.RightToLeft and RegexOptions.Singleline options:
(?<!\b\1-?\2-?\3-?\4\b.*)\b(\d{4})-?(\d{2})-?(\d{3})-?(\d{4})\b
The \b(\d{4})-?(\d{2})-?(\d{3})-?(\d{4})\b subpattern is the number with capture groups to check for their presence regardless of the hyphens earlier in the string.
The (?<!\b\1-?\2-?\3-?\4\b.*) subpattern look-behind is checking if we have no other occurrences of the same string.
Tested at regexhero.net and in Expresso:
You can easily do this without using regex.. but if you still want to use regex for this purpose.. you can use the following to match:
(?<=((\d{4})-(\d{2})-(\d{3})-(\d{4})).*?)\2\3\4\5
And replace with '' (empty string)
Explanation:
This will match all those digits without dashes which are already captured by digits with dashes
So, in your 1,2,3 and 4.. instead of matching 1,3 and 4 types it matches type 2.. and you can replace it with '' (nothing) and you remain with 1,3, and 4
See demo here
You can use the following regex to do exactly what you want..
((?<=((\d{4})-(\d{2})-(\d{3})-(\d{4})).*?)(?!\3\4\5\6)\d{13})|(((?<=((\d{4})(\d{2})(\d{3})(\d{4})).*?)(?!\10-\11-\12-\13)((\d{4})-(\d{2})-(\d{3})-(\d{4}))))
Explanation:
((?<=((\d{4})-(\d{2})-(\d{3})-(\d{4})).*?)(?!\3\4\5\6)\d{13}) match all those \d{13} which are not previously occurred with dashes in between them (this excludes strings of type 2 in your case)
((\d{4})-(\d{2})-(\d{3})-(\d{4})) and match all of this pattern
Matches 1, 3 and 4 in your case.
See DEMO
I'm looking to write a regex (C#) that will match words that aren't surrounded by quotes. An example input string would be:
dbo.test line_length "quoted words" notquoted
And this needs to match
dbo.test
line_length
nonquoted
So 3 separate matches and "quoted words" is not matched. The quoted phrase could be anywhere in the input...beginning, middle, end, etc.
I haven't been able to come up with a regex that matches words not in quotes where there could be a space in the quotes...I've been able to match something like: hello "world" and only get hello.
Is there a way to write the regex I'm trying to?
There are two ways to tackle this, depending on what you want to do with the output.
First, match (but don't capture) any text within quotation marks. (This is specifically matching the stuff that you DON'T want.)
Using the | pipe, use capture groups to select everything that you DO want to keep.
Example:
".*?"|(\b\S+\b)
You can see an example of that here.
The other option, using look-arounds, is to specifically look backward from the beginning of the words to ensure that the " doesn't appear there:
(?<!")(\b\S+\b)(?!")
You can see that here.
This may have a problem when you start using multiple words, but this should get you on the right track, and you can indicate whether one of these methods works better for you than the other.
If I have the string hello world , how can I modify the regex world|wo|w so that it will match all of "world", "wo" and "w" rather than just the single first match of "world" that it comes to ?
If this is not possible directly, is there a good workaround ? I'm using C# if it makes a difference:
Regex testRegex = new Regex("world|wo|w");
MatchCollection theMatches = testRegex.Matches("hello world");
foreach (Match thisMatch in theMatches)
{
...
}
I think you're going to need to use three separate regexs and match on each of them. When you specify alternatives it considers each one a successful match and stops looking after matching one of them. The only way I can see to do it is to repeat the search with each of your alternatives in a separate regex. You can create an array or list of Match items and have each search add to the list if you want to be able to iterate through them later.
If you're trying to match (the beginning of) the word world three times, you'll need to use three separate Regex objects; a single Regex cannot match the same character twice.
As SLaks wrote, a regex can't match the same text more than once.
You could "fake it" like this:
\b(w)((?<=w)o)?((?<=wo)rld)?
will match the w, the o only if preceded by w*, and rld only if preceded by wo.
Of course, only parts of the word will actually be matched, but you'll see whether only the first one, the first two or all the parts did match by looking at the captured groups.
So in the word want, the w will match (the rest is optional, so the regex reports overall success.
In work, the wo will match; \1 will contain w, and \2 will contain o. The rld will fail, but since it's optional, the regex still reports success.
I have added a word boundary anchor \b to the start of the regex to avoid matches in the middle of words like reword; if don't want to exclude those matches, drop the \b.
* The (?<=w) is not actually needed here, but I kept it in for consistency.