How to work with 'generic xml root' - c#

Some (external) genius decided to provide us with XML:
<message_X>
<header>
<foo>Foo</foo>
<bar>Bar</bar>
</header>
<body>
<blah>
<yadda1 />
<yadda2 />
<yadda3 />
<contentX>
<!-- message_X specific content -->
</contentX>
</blah>
</body>
</message_X>
However, there are also other messages (say, message_Y and message_Z). These all have the exact same basic structure besides what is in the content node and, the reason for this question, the differing root-nodes:
<message_Y>
<header>
<foo>Foo</foo>
<bar>Bar</bar>
</header>
<body>
<blah>
<yadda1 />
<yadda2 />
<yadda3 />
<contentY>
<!-- message_X specific content -->
</contentY>
</blah>
</body>
</message_Y>
Why the root node isn't just named <message>, as I would've done it baffles me. Who comes up with this?
I have created an abstract class Message accordingly:
public abstract class Message {
public Header Header { get; set; }
public Body Body { get; set; }
}
public class Header {
public string Foo { get; set; }
public string Bar { get; set; }
}
// Etc...
I was hoping I could then do this:
[XmlInclude(typeof(XMessage))]
[XmlInclude(typeof(YMessage))]
public abstract class Message {
// ...
}
[XmlRoot("message_X")]
public class XMessage : Message {
// ...
}
[XmlRoot("message_Y")]
public class YMessage : Message {
// ...
}
But that doesn't work: InvalidOperationException: <message_X xmlns=''> was not expected.. To deserialize I use:
var ser = new XmlSerializer(typeof(Message));
using (var sr = new StringReader(xmlString))
return (Message)ser.Deserialize(sr);
I have no control over the XML and I'm not looking forward to implement this message again and again for each X, Y and Z.
I'll sort the Content part out by probably making Message into Message<T> and inheriting with specifying T etc. but that'll be of later concern.
I have also tried specifying Message as Type and XMessage and YMessage as ExtraTypes of the XmlSerializer Constructor but that didn't help either. I have also tried to go the DataContractSerializer route with DataContract, KnownType etc. annotations but this didn't work either.
I would appreciate tips / pointers on how to solve this in a clean fashion.

With #steve16351's** ideas I wrote the following deserializer (I'm not interested in serializing, only deserializing):
public class XmlDeserializer<T>
where T : class
{
// "Globally" caches T => Dictionary<xmlelementnames, type>
private static readonly ConcurrentDictionary<Type, IDictionary<string, Type>> _typecache = new ConcurrentDictionary<Type, IDictionary<string, Type>>();
// We store instances of serializers per type T in this pool so we need not create a new one each time
private static readonly ConcurrentDictionary<Type, XmlSerializer> _serializers = new ConcurrentDictionary<Type, XmlSerializer>();
// And all serializers get the same instance of XmlReaderSettings which, again saves creating objects / garbage collecting.
private static readonly XmlReaderSettings _readersettings = new XmlReaderSettings() { IgnoreWhitespace = true };
// Lookup for current T, with this we keep a reference for the current T in the global cache so we need one less dictionary lookup
private readonly IDictionary<string, Type> _thistypedict;
public XmlDeserializer()
{
// Enumerate T's XmlInclude attributes
var includes = ((IEnumerable<XmlIncludeAttribute>)typeof(T).GetCustomAttributes(typeof(XmlIncludeAttribute), true));
// Get all the mappings
var mappings = includes.Select(a => new
{
a.Type,
((XmlRootAttribute)a.Type.GetCustomAttributes(typeof(XmlRootAttribute), true).FirstOrDefault())?.ElementName
}).Where(m => !string.IsNullOrEmpty(m.ElementName));
// Store all mappings in our current instance and at the same time store the mappings for T in our "global cache"
_thistypedict = _typecache.GetOrAdd(typeof(T), mappings.ToDictionary(v => v.ElementName, v => v.Type));
}
public T Deserialize(string input)
{
// Read our input
using (var stringReader = new StringReader(input))
using (var xmlReader = XmlReader.Create(stringReader, _readersettings))
{
xmlReader.MoveToContent();
// Make sure we know how to deserialize this element
if (!_thistypedict.TryGetValue(xmlReader.Name, out var type))
throw new InvalidOperationException($"Unable to deserialize type '{xmlReader.Name}'");
// Grab serializer from pool or create one if required
var serializer = _serializers.GetOrAdd(type, (t) => new XmlSerializer(t, new XmlRootAttribute(xmlReader.Name)));
// Finally, now deserialize...
return (T)serializer.Deserialize(xmlReader);
}
}
}
This deserializer uses the XmlInclude attributes to figure out which classes are to be mapped with what element-name using the XmlRoot attributes. Usage couldn't be simpler:
var ser = new XmlDeserializer<Message>();
ser.Deserialize("<message_X>...");
It does some internal 'caching' and 'pooling' of objects to keep it memory/GC-friendly and quite performant. So this solves my root-node-different-name-for-each-type problem. Now I need to figure out how I'm going to handle the different content-nodes...
** Who has since deleted his answer for some unknown reason...
The second part of the question, the 'generic content' was easily solved:
public class Blah {
public Yadda1 Yadda1 { get; set; }
public Yadda2 Yadda2 { get; set; }
public Yadda3 Yadda3 { get; set; }
[XmlElement("contentX", typeof(ContentX))]
[XmlElement("contentY", typeof(ContentY))]
[XmlChoiceIdentifier(nameof(PayloadType))]
public Payload Payload { get; set; }
public PayloadType PayloadType { get; set; }
}
public abstract class Payload { ... }
public class ContentX : Payload { ... }
public class ContentY : Payload { ... }
[XmlType]
public enum PayloadType
{
[XmlEnum("contentX")]
ContentX,
[XmlEnum("contentY")]
ContentY,
}
This only leaves me wondering if I could apply the same idea on the root node...

Related

xmlserialize argumentexception (ArgumentException: Could not cast or convert from System.String to System.Collections.Generic.List`1[System.String].)

Below piece of code is failing and throwing ArgumentException
static void Main(string[] args)
{
string xml = "<root><SourcePatient><Communication>HP:6055550120</Communication></SourcePatient></root>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
var serializedString = JsonConvert.SerializeXmlNode(doc, Newtonsoft.Json.Formatting.None,true);
var deserialise = serializedString.ToObject<SampleModel>();
}
Models are,
public class SampleModel
{
public SourcePatientModel SourcePatient { get; set; }
}
public class SourcePatientModel
{
public List<string> Communication { get; set; }
}
How to deserialize this? Sometimes Communication node from xml string will have multiple entries
Your current xml is only a single entry
<Communication>HP:6055550120</Communication>
Change your xml input
<Communication><Entry>HP:6055550120</Entry></Communication>
So later when you get multiple entries, they can be processed
<Communication><Entry>HP:6055550120</Entry><Entry>HP:xxxxxxxxx</Entry></Communication>
Your class needs tweaked a bit
if a string [] is acceptable
[XmlArray(ElementName = "Communication")]
[XmlArrayItem(ElementName = "Entry")]
public string[] comm_list // Whatever name you want here
{
get; set;
}
// if you want a list here
// also if your going to do this, realize it creates a new list every time you use it, not the best. (bad practice)
List<string> Communication
{
get => new List<string>(comm_list );
}
otherwise it gets a little complicated
[XmlRoot(ElementName="Communication")]
public class Communication // element name by def
{
[XmlElement(ElementName="Entry")]
public List<string> entry { get; set; }
}
Another possibility, not sure how your multiple entries come in.
If multiple entries look like the following
<Communication>HP:6055550120, HP:7055550120</Communication>
Then you cant have a direct list,
public class SourcePatientModel
{
public string Communication { get; set; }
// which again this creates a list everytime, its better to change your xml to match a tag name for each entry
[XmlIgnore]
public List<string> CommunicationValues { get => Communication.Split(',').ToList();
}
Also this is just typed up code, there may be some typos or compile errors
First I parsed xml to the valid model, then you can convert to json if needed
using (TextReader sr = new StringReader(xml))
{
XmlSerializer serializer = new XmlSerializer(typeof(SampleModel));
var schema = (SampleModel)serializer.Deserialize(sr);
}
[Serializable, XmlRoot("root")]
public class SampleModel
{
public SourcePatientModel SourcePatient { get; set; }
}
public class SourcePatientModel
{
[XmlElement("Communication")]
public List<string> Communication { get; set; }
}
I modified your classes to include some XML serialization attributes. (More on how to figure those out later - the short version is that you don't have to figure it out.)
[XmlRoot(ElementName = "SourcePatient")]
public class SourcePatientModel
{
[XmlElement(ElementName = "Communication")]
public List<string> Communication { get; set; }
}
[XmlRoot(ElementName = "root")]
public class SampleModel
{
[XmlElement(ElementName = "SourcePatient")]
public SourcePatientModel SourcePatientModel { get; set; }
}
...and this code deserializes it:
var serializer = new XmlSerializer(typeof(SampleModel));
using var stringReader = new StringReader(xmlString);
SampleModel deserialized = (SampleModel) serializer.Deserialize(stringReader);
Here's a unit test to make sure a test XML string is deserialized with a list of strings as expected. A unit test is a little easier to run and repeat than a console app. Using them makes writing code a lot easier.
[Test]
public void DeserializationTest()
{
string xmlString = #"
<root>
<SourcePatient>
<Communication>A</Communication>
<Communication>B</Communication>
</SourcePatient>
</root>";
var serializer = new XmlSerializer(typeof(SampleModel));
using var stringReader = new StringReader(xmlString);
SampleModel deserialized = (SampleModel) serializer.Deserialize(stringReader);
Assert.AreEqual(2, deserialized.SourcePatientModel.Communication.Count);
}
Here's a key takeaway: You don't need to memorize XML serialization attributes. I don't bother because I find them confusing. Instead, google "XML to Csharp" and you'll find sites like this one. I pasted your XML into that site and let it generate the classes for me. (Then I renamed them so that they matched your question.)
But be sure that you include enough sample data in your XML so that it can generate the classes for you. I made sure there were two Communication elements so it would create a List<string> in the generated class.
Sites like that might not work for extremely complicated XML, but they work for most scenarios, and it's much easier than figuring out how to write the classes ourselves.

Protobuf-net deserializing after defining inheritance

I'm using protobuf-net version 2.0.0.640 to serialize some data as shown below.
[ProtoContract(ImplicitFields = ImplicitFields.AllFields)]
public interface ITestMessage
{
}
[ProtoContract(ImplicitFields = ImplicitFields.AllFields)]
public class MyOrder : ITestMessage
{
public int Amount { get; set; }
}
[ProtoContract(ImplicitFields = ImplicitFields.AllFields)]
public class MyOrderWrapper
{
public MyOrder Order { get; set; }
}
[TestMethod]
public void TestOrderSerialize()
{
var order = new MyOrder() {Amount = 10};
var orderWrapper = new MyOrderWrapper() { Order = order };
using (var file = File.Create("C:\\temp\\order.bin"))
{
Serializer.Serialize<MyOrderWrapper>(file, orderWrapper);
}
}
Now, If I declare an inheritance dependency between 'ITestMessage' & 'MyOrder' via code using:
RuntimeTypeModel.Default[typeof(ITestMessage)].AddSubType(2, typeof(MyOrder));
I get the following error when trying to deserialize my prevously saved data.
"No parameterless constructor found for ITestMessage".
[TestMethod]
public void TestOrderDeserialize()
{
RuntimeTypeModel.Default[typeof(ITestMessage)].AddSubType(2, typeof(MyOrder));
MyOrderWrapper orderWrapper;
using (var file = File.OpenRead("C:\\temp\\order.bin"))
{
orderWrapper = Serializer.Deserialize<MyOrderWrapper>(file);
}
}
Can someone please explain why this would happen when 'MyOrderWrapper' does not reference anything higher than 'MyOrder' in the inheritance hirarchy.
Also, why it works when I explictly include '[ProtoInclude(2, typeof(MyOrder))]' on 'ITestMessage'
Thanks
Basically, that is a breaking change as far as the serializer is concerned - at the wire layer, neither "classes" nor "interfaces" exist, so in terms of storage, this is akin to changing the base-type of the class; when serializing, the root type was MyOrder - and during deserialization the root type is ITestMessage. This will not make it happy.
Basically: you can't do that.

Serialize list of interface types with ServiceStack.Text

I'm looking at ways to introduce something other than BinaryFormatter serialization into my app to eventually work with Redis. ServiceStack JSON is what I would like to use, but can it do what I need with interfaces?
It can serialize (by inserting custom __type attribute)
public IAsset Content;
but not
public List<IAsset> Contents;
- the list comes up empty in serialized data. Is there any way to do this - serialize a list of interface types?
The app is big and old and the shape of objects it uses is probably not going to be allowed to change.
Thanks
Quoting from http://www.servicestack.net/docs/framework/release-notes
You probably don't have to do much :)
The JSON and JSV Text serializers now support serializing and
deserializing DTOs with Interface / Abstract or object types. Amongst
other things, this allows you to have an IInterface property which
when serialized will include its concrete type information in a __type
property field (similar to other JSON serializers) which when
serialized populates an instance of that concrete type (provided it
exists).
[...]
Note: This feature is automatically added to all
Abstract/Interface/Object types, i.e. you don't need to include any
[KnownType] attributes to take advantage of it.
By not much:
public interface IAsset
{
string Bling { get; set; }
}
public class AAsset : IAsset
{
public string Bling { get; set; }
public override string ToString()
{
return "A" + Bling;
}
}
public class BAsset : IAsset
{
public string Bling { get; set; }
public override string ToString()
{
return "B" + Bling;
}
}
public class AssetBag
{
[JsonProperty(TypeNameHandling = TypeNameHandling.None)]
public List<IAsset> Assets { get; set; }
}
class Program
{
static void Main(string[] args)
{
try
{
var bag = new AssetBag
{
Assets = new List<IAsset> {new AAsset {Bling = "Oho"}, new BAsset() {Bling = "Aha"}}
};
string json = JsonConvert.SerializeObject(bag, new JsonSerializerSettings()
{
TypeNameHandling = TypeNameHandling.Auto
});
var anotherBag = JsonConvert.DeserializeObject<AssetBag>(json, new JsonSerializerSettings()
{
TypeNameHandling = TypeNameHandling.Auto
});

Using Web API to deserialize into class with abstract property

I'm attempting to write a set of classes to represent a particularly complex object, and in one of those classes, I have a property that is set as the base (abstract) class of three possible derived classes. I'm setting up an ASP.NET Web API to handle the serialization and deserialization, which means that, by default, it uses Json.NET for JSON. How can I get the Web API to properly deserialize JSON sent via POST or PUT into the proper derived class?
The class with the abstract member looks like this (I'm including the Xml decorators for clarity and because they work perfectly well for deserializing xml using the XmlSerializer)
[Serializable]
public class FormulaStructure {
[XmlElement("column", typeof(ColumnStructure))]
[XmlElement("function", typeof(FunctionStructure))]
[XmlElement("operand", typeof(OperandStructure))]
public AFormulaItemStructure FormulaItem;
}
The abstract class is pretty basic:
[Serializable]
public abstract class AFormulaItemStructure { }
And there are three derivatives of the abstract class:
[Serializable]
public class ColumnStructure: AFormulaItemStructure {
[XmlAttribute("type")]
public string Type;
[XmlAttribute("field")]
public string Field;
[XmlAttribute("display")]
public string Display;
}
[Serializable]
public class FunctionStructure: AFormulaItemStructure {
[XmlAttribute("type")]
public string Type;
[XmlAttribute("name")]
public string Name;
[XmlElement("parameters")]
public string Parameters;
}
[Serializable]
public class OperandStructure: AFormulaItemStructure {
[XmlAttribute("type")]
public string Type;
[XmlElement("left")]
public string Left;
[XmlElement("right")]
public string Right;
}
At present, using [DataContract] attributes, the Json.NET formatter fails to populate the derived class, leaving the property null.
Questions
Can I mix XmlSerializer attributes with DataContractSerializer attributes on the same class? I use the XmlSerializer because I use xml attributes in the xml I designed, but that can be changed if necessary since I am developing the xml schema myself.
What is the equivalent in Json.NET to [KnownType()] ? Json.NET doesn't appear to respect the DataContractSerializer version of KnownType. Will I need to roll my own JsonConverter to determine the proper type?
How would I decorate the classes so that DataContractSerializer or DataContractJsonSerializer will properly deserialize the objects in both Xml and Json? My goal is to put this into an ASP.NET Web API, so I want the flexibility to generate Xml or Json, as appropriate to the requested type. Is there an alternative formatter that I need to use to work with this complex class, if Json.NET won't work?
I need the ability to generate an object on the client side without necessarily including the .NET class names into the object.
Testing and Refinement
In my testing of the Web API, the default serialization sends down to the client:
{"FormulaItem":{"type":"int","field":"my_field","display":"My Field"}}
which is ideal for my purposes. Getting this to go back to the API and deserialize into the proper derived types, though, isn't working (it's generating null for the property).
Testing Tommy Grovnes answer below, the DataContractSerializer he used for testing generates:
{"FormulaItem":{"__type":"column:#ExpressionStructureExperimentation.Models","display":"My Field","field":"my_field","type":"int"}}
which doesn't work for me, or for code maintainability (refactoring becomes a PITA if I hard-code the entire namespace into the JavaScript for generating these objects).
You can mix as mentioned already but I don't think you need to, haven't used WEB api myself but WCF Rest produces xml and json from DataContracts (without Xml.. tags), tag your classes like this:
[DataContract]
public class FormulaStructure
{
[DataMember]
public AFormulaItemStructure FormulaItem;
}
[DataContract]
[KnownType(typeof(ColumnStructure))]
[KnownType(typeof(FunctionStructure))]
[KnownType(typeof(OperandStructure))]
public abstract class AFormulaItemStructure { }
[DataContract(Name="column")]
public class ColumnStructure : AFormulaItemStructure
{
[DataMember(Name="type")]
public string Type;
[DataMember(Name = "field")]
public string Field;
[DataMember(Name = "display")]
public string Display;
}
[DataContract(Name="function")]
public class FunctionStructure : AFormulaItemStructure
{
[DataMember(Name = "type")]
public string Type;
[DataMember(Name = "name")]
public string Name;
[DataMember(Name = "parameters")]
public string Parameters;
}
[DataContract(Name = "operand")]
public class OperandStructure : AFormulaItemStructure
{
[DataMember(Name = "type")]
public string Type;
[DataMember(Name = "left")]
public string Left;
[DataMember(Name = "right")]
public string Right;
}
If you need more control over the XML/JSON generated you might have to tweak this further. I used this code to test:
public static string Serialize(FormulaStructure structure)
{
using (MemoryStream memoryStream = new MemoryStream())
using (StreamReader reader = new StreamReader(memoryStream))
{
var serializer = new DataContractSerializer(typeof(FormulaStructure));
serializer.WriteObject(memoryStream, structure);
memoryStream.Position = 0;
return reader.ReadToEnd();
}
}
public static FormulaStructure Deserialize(string xml)
{
using (Stream stream = new MemoryStream())
{
byte[] data = System.Text.Encoding.UTF8.GetBytes(xml);
stream.Write(data, 0, data.Length);
stream.Position = 0;
var deserializer = new DataContractSerializer(typeof(FormulaStructure));
return (FormulaStructure)deserializer.ReadObject(stream);
}
}
After we ran into some issues much further down the line with my previous answer, I discovered the SerializationBinder class that JSON can use for serializing/deserializing namespaces.
Code First
I generated a class to inherit the SerializationBinder:
public class KnownTypesBinder : System.Runtime.Serialization.SerializationBinder {
public KnownTypesBinder() {
KnownTypes = new List<Type>();
AliasedTypes = new Dictionary<string, Type>();
}
public IList<Type> KnownTypes { get; set; }
public IDictionary<string, Type> AliasedTypes { get; set; }
public override Type BindToType(string assemblyName, string typeName) {
if (AliasedTypes.ContainsKey(typeName)) { return AliasedTypes[typeName]; }
var type = KnownTypes.SingleOrDefault(t => t.Name == typeName);
if (type == null) {
type = Type.GetType(Assembly.CreateQualifiedName(assemblyName, typeName));
if (type == null) {
throw new InvalidCastException("Unknown type encountered while deserializing JSON. This can happen if class names have changed but the database or the JavaScript references the old class name.");
}
}
return type;
}
public override void BindToName(Type serializedType, out string assemblyName, out string typeName) {
assemblyName = null;
typeName = serializedType.Name;
}
}
How it works
Let's say I have a set of classes defined thus:
public class Class1 {
public string Text { get; set; }
}
public class Class2 {
public int Value { get; set; }
}
public class MyClass {
public Class1 Text { get; set; }
public Class2 Value { get; set; }
}
Aliased Types
What this does is allows me to generate my own names for classes that will be serialized/deserialized. In my global.asax file, I apply the binder as such:
KnownTypesBinder binder = new KnownTypesBinder()
binder.AliasedTypes["Class1"] = typeof(Project1.Class1);
binder.AliasedTypes["WhateverStringIWant"] = typeof(Project1.Class2);
var json = GlobalConfiguration.Configuration.Formatters.JsonFormatter;
json.SerializerSettings.Binder = binder;
Now, whenever I serialize, say, MyClass as JSON, I get the following:
{
item: {
$type: "Project1.MyClass",
Text: {
$type: "Class1",
Text: "some value"
},
Value: {
$type: "WhateverStringIWant",
Value: 88
}
}
}
Known Types
I can also choose to strip off the assembly information and strictly use the class name by adding information to the KnownTypesBinder:
KnownTypesBinder binder = new KnownTypesBinder()
binder.KnownTypes.Add(typeof(Project1.Class1));
binder.KnownTypes.Add(typeof(Project1.Class1));
In the two examples given, Class1 is referenced the same way. However, if I refactor Class1 to, say, NewClass1, then this second example will start sending a different name. That may or may not be a big deal, depending on whether you are using the types or not.
Final Thoughts
The advantage of the AliasedTypes is that I can give it any string that I want, and it doesn't matter how much I refactor the code, the communication between the .NET and the JavaScript (or whatever consumer is out there) is unbroken.
Be careful not to mix AliasedTypes and KnownTypes that have the exact same class name, because the code is written that the AliasType will win out over KnownType. When the binder doesn't recognize a type (aliased or known), it will provide the full assembly name of the type.
In the end, I broke down and added the .NET class information to the module in string variables to make refactoring easier.
module.net = {};
module.net.classes = {};
module.net.classes['column'] = "ColumnStructure";
module.net.classes['function'] = "FunctionStructure";
module.net.classes['operand'] = "OperandStructure";
module.net.getAssembly = function (className) {
return "MyNamespace.Models." + module.net.classes[className] + ", MyAssembly";
}
and generated the JSON as
{
"FormulaItem": {
"$type": module.net.getAssembly('column'),
"type": "int",
"field": "my_field",
"display": "My Field"
}
}

C# Xml serialization, collection and root element

My app serializes objects in streams.
Here is a sample of what I need :
<links>
<link href="/users" rel="users" />
<link href="/features" rel="features" />
</links>
In this case, the object is a collection of 'links' object.
-----------First version
At first I used the DataContractSerializer, however you cannot serialize members as attributes (source)
Here is the object :
[DataContract(Name="link")]
public class LinkV1
{
[DataMember(Name="href")]
public string Url { get; set; }
[DataMember(Name="rel")]
public string Relationship { get; set; }
}
And here is the result :
<ArrayOflink xmlns:i="...." xmlns="...">
<link>
<href>/users</href>
<rel>users</rel>
</link>
<link>
<href>/features</href>
<rel>features</rel>
</link>
</ArrayOflink>
----------- Second version
Ok, not quiet what I want, so I tried the classic XmlSerializer, but... oh nooo, you cannot specify the name of the root element & of the collection's elements if the root element is a collection...
Here is the code :
[XmlRoot("link")]
public class LinkV2
{
[XmlAttribute("href")]
public string Url { get; set; }
[XmlAttribute("rel")]
public string Relationship { get; set; }
}
Here is the result :
<ArrayOfLinkV2>
<LinkV2 href="/users" rel="users" />
<LinkV2 href="/features" rel="features" />
<LinkV2 href="/features/user/{keyUser}" rel="featuresByUser" />
</ArrayOfLinkV2>
----------- Third version
using XmlSerializer + a root element :
[XmlRoot("trick")]
public class TotallyUselessClass
{
[XmlArray("links"), XmlArrayItem("link")]
public List<LinkV2> Links { get; set; }
}
And its result :
<trick>
<links>
<link href="/users" rel="users" />
<link href="/features" rel="features" />
<link href="/features/user/{keyUser}" rel="featuresByUser" />
</links>
</trick>
Nice, but I don't want that root node !!
I want my collection to be the root node.
Here are the contraints :
the serialization code is generic, it works with anything serializable
the inverse operation (deserialization) have to work too
I don't want to regex the result (I serialize directly in an output stream)
What are my solutions now :
Coding my own XmlSerializer
Trick XmlSerializer when it works with a collection (I tried, having it find a XmlRootElement and plurialize it to generate its own XmlRootAttribute, but that causes problem when deserializing + the items name still keeps the class name)
Any idea ?
What really bother me in that issue, is that what I want seems to be really really really simple...
Ok, here is my final solution (hope it helps someone), that can serialize a plain array, List<>, HashSet<>, ...
To achieve this, we'll need to tell the serializer what root node to use, and it's kind of tricky...
1) Use 'XmlType' on the serializable object
[XmlType("link")]
public class LinkFinalVersion
{
[XmlAttribute("href")]
public string Url { get; set; }
[XmlAttribute("rel")]
public string Relationship { get; set; }
}
2) Code a 'smart-root-detector-for-collection' method, that will return a XmlRootAttribute
private XmlRootAttribute XmlRootForCollection(Type type)
{
XmlRootAttribute result = null;
Type typeInner = null;
if(type.IsGenericType)
{
var typeGeneric = type.GetGenericArguments()[0];
var typeCollection = typeof (ICollection<>).MakeGenericType(typeGeneric);
if(typeCollection.IsAssignableFrom(type))
typeInner = typeGeneric;
}
else if(typeof (ICollection).IsAssignableFrom(type)
&& type.HasElementType)
{
typeInner = type.GetElementType();
}
// yeepeeh ! if we are working with a collection
if(typeInner != null)
{
var attributes = typeInner.GetCustomAttributes(typeof (XmlTypeAttribute), true);
if((attributes != null)
&& (attributes.Length > 0))
{
var typeName = (attributes[0] as XmlTypeAttribute).TypeName + 's';
result = new XmlRootAttribute(typeName);
}
}
return result;
}
3) Push that XmlRootAttribute into the serializer
// hack : get the XmlRootAttribute if the item is a collection
var root = XmlRootForCollection(type);
// create the serializer
var serializer = new XmlSerializer(type, root);
I told you it was tricky ;)
To improve this, you can :
A) Create a XmlTypeInCollectionAttribute to specify a custom root name (If the basic pluralization does not fit your need)
[XmlType("link")]
[XmlTypeInCollection("links")]
public class LinkFinalVersion
{
}
B) If possible, cache your XmlSerializer (in a static Dictionary for example).
In my testing, instanciating a XmlSerializer without the XmlRootAttributes takes 3ms.
If you specify an XmlRootAttribute, it takes around 80ms (Just to have a custom root node name !)
XmlSerializer should be able to do what you need, but it is highly dependent on the initial structure and setup. I use it in my own code to generate remarkably similar things.
public class Links<Link> : BaseArrayClass<Link> //use whatever base collection extension you actually need here
{
//...stuff...//
}
public class Link
{
[XmlAttribute("href")]
public string Url { get; set; }
[XmlAttribute("rel")]
public string Relationship { get; set; }
}
now, serializing the Links class should generate exactly what you are looking for.
The problem with XmlSerializer is when you give it generics, it responds with generics. List implemets Array somewhere in there and the serialized result will nearly always be ArrayOf<X>. To get around that you can name the property, or the class root. The closes to what you need is probably the Second Version from your examples. Im assuming you attempted direct serialization of an object List Links. That wouldn't work because you didn't specify the root node. Now, a similar approach can be found here. In this one they specify the XmlRootAttribute when declaring the serializer. yours would look like this:
XmlSerializer xs = new XmlSerializer(typeof(List<Link>), new XmlRootAttribute("Links"));
Here you go...
class Program
{
static void Main(string[] args)
{
Links ls = new Links();
ls.Link.Add(new Link() { Name = "Mike", Url = "www.xml.com" });
ls.Link.Add(new Link() { Name = "Jim", Url = "www.xml.com" });
ls.Link.Add(new Link() { Name = "Peter", Url = "www.xml.com" });
XmlSerializer xmlSerializer = new XmlSerializer(typeof(Links));
StringWriter stringWriter = new StringWriter();
xmlSerializer.Serialize(stringWriter, ls);
string serializedXML = stringWriter.ToString();
Console.WriteLine(serializedXML);
Console.ReadLine();
}
}
[XmlRoot("Links")]
public class Links
{
public Links()
{
Link = new List<Link>();
}
[XmlElement]
public List<Link> Link { get; set; }
}
[XmlType("Link")]
public class Link
{
[XmlAttribute("Name")]
public string Name { get; set; }
[XmlAttribute("Href")]
public string Url { get; set; }
}

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