C# How may i replace \" with " - c#

I am trying to replace \" in a string with ", how may i do that?
I've tried using replace but i could not find a way to do it.
Ex:
string line = "This is a \"sample\" "
string replaced = "This is a "sample" ".
Thanks.


Because quotes are used to start and end strings (they are a type of control character), you can't have a quote in the middle of a string because it would terminate the string
string replaced = "This is a "sample" ";
/*
You can see from the syntax highlighting (red) that the string is being
detected as <This is a > and <sample> is black meaning it is detected as
code (and will cause a syntax error)
*/
In order to put a quote in the middle of the string we escape it (escaping means to treat it as a character literal instead of a control character) using the escape character, which in C# is backslash.
string line = "This is a \"sample\"";
Console.WriteLine(line);
// Output: This is a "sample"
string literalLine = #"This is a ""sample""";
Console.WriteLine(literalLine);
// Output: This is a "sample"
The # symbol in C# means I want this to be a literal string (ignore control characters), however quotes still start and end strings so in order to print a quote in a literal string you write two of them "" (that's how the language is designed)


Case 1: If the value within the variable line is actually This is a \"sample\", then you could do line.Replace("\\\"", "\"").
If not:
\" is an escape sequence. it shows up as \" in the code, however when it compiles it would show up as " instead of the original \".
The reason for escaping quotes is because the compiler cannot identify whether the quote is within another quote or not. Let's see your example:
"This is a "sample" "
is this This is a as one group, then an unknown token sample, then another quote ? or This is a "sample" all within a quote? We can take a guess by looking at the context, but compiler cannot. Hence, we use escape sequence to tell the compiler "I used this double quote character as a character, not the closing/opening of a string literal."
See Also: https://en.wikipedia.org/wiki/Escape_sequences_in_C


You may try something like this:
String str = "This is a \"sample\" ";
Console.WriteLine("Original string: {0}", str);
Console.WriteLine("Replaced: {0}", str.Replace('\"', '"'));


Desired output : This is a sample
Given string : "This is a \"sample\""
The problem: you have escape characters protecting the double quotes from being interpreted. the \ escape character is an instruction to use a quotation mark literally instead of using it to indicate a break in the string. This means the actual string value is "This is a "sample"" when served as output.
The answer removing the \ may work, but it makes for smelly code because removing an escape character in this way can make it unclear what you intend and prevents you from escaping any character.
Removing the " might work, though it prevents use of any quotes and some IDEs might leave the escape character behind to ruin your day.
We want one specific target, the quotes around "sample".
string sample = "This is a \"sample\"";
List<string> sampleArray = sample.Split(' ').ToList(); // samplearray is now split into ["This", "is", "a", "\"sample\""]
var x = sampleArray.FirstOrDefault(t => t == "\"sample\""); //isolate our needed value
if (x != null) //prevent a null reference in case something went wrong and samplearray wasnt as expected
{
var index = sampleArray.IndexOf(x); //get the location of the value we just picked
x = x.Replace("\"", string.Empty); //replace chars
sampleArray[index] = x; //assign new value to the list
}
return String.Join(" ", sampleArray); //return the string joined together with spaces.


Try this:
string line="This is a \"sample\" " ;
replaced =line.Replace(#"\", "");

Related

Verbatim string replace

var a = "asdfgh\r";
Console.WriteLine(a.Contains(#"\r"));
var b = a.Replace(#"\r","").Replace(#"\n","");
var c = a.Replace("\r","").Replace("\n","");
Console.WriteLine(a);
Console.WriteLine(b);
Console.WriteLine(c);
"b" and "c" prints same string and "a" prints false,
I was trying to replace \r and \n to an empty char so first i tried below code, there's a backslash in "\r" and "\n" so i decided to use "#" before them ;
var b = a.Replace(#"\r","").Replace(#"\n","")
but this didn't work,
var c = a.Replace("\r","").Replace("\n","");
this works, so im confused when should i use "#" charachter ?

You declared string a to end with carriagereturn character:
var a = "asdfgh\r"; //it has a length of 7 when compiled
So you must replace the carriage return with nothing:
Replace("\r","")
If you had declared the string to end with "backslash r":
var a = #"asdfgh\r"; //it has a length of 8 when compiled
Then you would have succeeded in replacing "backslash r" with nothing:
Replace(#"\r","")
This would also work:
Replace("\\r","")
Because the double slash is turned into a single and then the r is a normal character so you're replacing "backslash r" and not carriagereturn
When compiling the C# compiler looks for \ in a string and converts the following character(s) according to some rule. Using # before the string turns this off. Mostly it's useful for paths. Remember that it's a compile time thing, not something you need to do to variables that hold data entered in runtime. Putting an # before a variable name means something different - allowing you to call a variable a reserved word, like string #for = "for" - deplorable practice; don't do it
Ultimately the problem is that you were inconsistent when declaring your strings - a was not a verbatim string so it really did have a single carriage return char, and then you were trying to replace using a verbatim string (and "backslash r" is a different string to "carriagereturn"

Replace Unicode character "�" with a space

I'm a doing an massive uploading of information from a .csv file and I need replace this character non ASCII "�" for a normal space, " ".
The character "�" corresponds to "\uFFFD" for C, C++, and Java, which it seems that it is called REPLACEMENT CHARACTER. There are others, such as spaces type like U+FEFF, U+205F, U+200B, U+180E, and U+202F in the C# official documentation.
I'm trying do the replace this way:
public string Errors = "";
public void test(){
string textFromCsvCell = "";
string validCharacters = "^[0-9A-Za-z().:%-/ ]+$";
textFromCsvCell = "This is my text from csv file"; //All spaces aren't normal space " "
string cleaned = textFromCsvCell.Replace("\uFFFD", "\"")
if (Regex.IsMatch(cleaned, validCharacters ))
//All code for insert
else
Errors=cleaned;
//print Errors
}
The test method shows me this text:
"This is my�texto from csv file"
I try some solutions too:
Trying solution 1: Using Trim
Regex.Replace(value.Trim(), #"[^\S\r\n]+", " ");
Try solution 2: Using Replace
System.Text.RegularExpressions.Regex.Replace(str, #"\s+", " ");
Try solution 3: Using Trim
String.Trim(new char[]{'\uFEFF', '\u200B'});
Try solution 4: Add [\S\r\n] to validCharacters
string validCharacters = "^[\S\r\n0-9A-Za-z().:%-/ ]+$";
Nothing works.
How can I replace it?
Sources:
Unicode Character 'REPLACEMENT CHARACTER' (U+FFFD)
Trying to replace all white space with a single space
Strip the byte order mark from string in C#
Remove extra whitespaces, but keep new lines using a regular expression in C#
EDITED
This is the original string:
"SYSTEM OF MONITORING CONTINUES OF GLUCOSE"
in 0x... notation
SYSTEM OF0xA0MONITORING CONTINUES OF GLUCOSE
Solution
Go to the Unicode code converter. Look at the conversions and do the replace.
In my case, I do a simple replace:
string value = "SYSTEM OF MONITORING CONTINUES OF GLUCOSE";
//value contains non-breaking whitespace
//value is "SYSTEM OF�MONITORING CONTINUES OF GLUCOSE"
string cleaned = "";
string pattern = #"[^\u0000-\u007F]+";
string replacement = " ";
Regex rgx = new Regex(pattern);
cleaned = rgx.Replace(value, replacement);
if (Regex.IsMatch(cleaned,"^[0-9A-Za-z().:<>%-/ ]+$"){
//all code for insert
else
//Error messages
This expression represents all possible spaces: space, tab, page break, line break and carriage return
[ \f\n\r\t\v​\u00a0\u1680​\u180e\u2000​\u2001\u2002​\u2003\u2004​\u2005\u2006​\u2007\u2008​\u2009\u200a​\u2028\u2029​​\u202f\u205f​\u3000]
References
Regular expressions (MDN)

Using String.Replace:
Use a simple String.Replace().
I've assumed that the only characters you want to remove are the ones you've mentioned in the question: � and you want to replace them by a normal space.
string text = "imp�ortant";
string cleaned = text.Replace('\u00ef', ' ')
.Replace('\u00bf', ' ')
.Replace('\u00bd', ' ');
// Returns 'imp ortant'
Or using Regex.Replace:
string cleaned = Regex.Replace(text, "[\u00ef\u00bf\u00bd]", " ");
// Returns 'imp ortant'
Try it out: Dotnet Fiddle

Define a range of ASCII characters, and replace anything that is not within that range.
We want to find only Unicode characters, so we will match on a Unicode character and replace.
Regex.Replace("This is my te\uFFFDxt from csv file", #"[^\u0000-\u007F]+", " ")
The above pattern will match anything that is not ^ in the set [ ] of this range \u0000-\u007F (ASCII characters (everything past \u007F is Unicode)) and replace it with a space.
Result
This is my te xt from csv file
You can adjust the range provided \u0000-\u007F as needed to expand the range of allowed characters to suit your needs.

If you just want ASCII then try the following:
var ascii = new ASCIIEncoding();
byte[] encodedBytes = ascii.GetBytes(text);
var cleaned = ascii.GetString(encodedBytes).Replace("?", " ");

conversion of special character string

i am using a web service and result is coming like this
" methew wade watto"
then I've tried with string.replace():
jsona = jsona.Replace(#"", "");
but the problem is i am unable to replace special character's like " this in my replace statement, How can I replace " from the input string? and what are the other options of replacing the string other then this?

In c#, The # symbol means to read that string literally, and don't
interpret control characters otherwise. whereas \ followed by a
character that is not recognized as an escaped character, matches that
character.
So you have to use \" to represent " in .Replace() instead for #
I think you have to try something like this:
string jsonInput = "\"methew wade watto\""; // be the input
string replacedQuotes = jsonInput.Replace("\"", "");
Working example

You need to escape the " with \ , right now, you are just saying to replace empty string with empty string:
jsona= jsona.Replace("\"","");
Now this will replace the " sign in your string with empty string.
Output:
methew wade watto

Use a backslash to determine special character
string = string.Replace("\"", "");

How do I find and remove any rule or newline in an output? [duplicate]

How can I replace Line Breaks within a string in C#?

Use replace with Environment.NewLine
myString = myString.Replace(System.Environment.NewLine, "replacement text"); //add a line terminating ;
As mentioned in other posts, if the string comes from another environment (OS) then you'd need to replace that particular environments implementation of new line control characters.

The solutions posted so far either only replace Environment.NewLine or they fail if the replacement string contains line breaks because they call string.Replace multiple times.
Here's a solution that uses a regular expression to make all three replacements in just one pass over the string. This means that the replacement string can safely contain line breaks.
string result = Regex.Replace(input, #"\r\n?|\n", replacementString);

To extend The.Anyi.9's answer, you should also be aware of the different types of line break in general use. Dependent on where your file originated, you may want to look at making sure you catch all the alternatives...
string replaceWith = "";
string removedBreaks = Line.Replace("\r\n", replaceWith).Replace("\n", replaceWith).Replace("\r", replaceWith);
should get you going...

I would use Environment.Newline when I wanted to insert a newline for a string, but not to remove all newlines from a string.
Depending on your platform you can have different types of newlines, but even inside the same platform often different types of newlines are used. In particular when dealing with file formats and protocols.
string ReplaceNewlines(string blockOfText, string replaceWith)
{
return blockOfText.Replace("\r\n", replaceWith).Replace("\n", replaceWith).Replace("\r", replaceWith);
}

If your code is supposed to run in different environments, I would consider using the Environment.NewLine constant, since it is specifically the newline used in the specific environment.
line = line.Replace(Environment.NewLine, "newLineReplacement");
However, if you get the text from a file originating on another system, this might not be the correct answer, and you should replace with whatever newline constant is used on the other system. It will typically be \n or \r\n.

if you want to "clean" the new lines, flamebaud comment using regex #"[\r\n]+" is the best choice.
using System;
using System.Text.RegularExpressions;
class MainClass {
public static void Main (string[] args) {
string str = "AAA\r\nBBB\r\n\r\n\r\nCCC\r\r\rDDD\n\n\nEEE";
Console.WriteLine (str.Replace(System.Environment.NewLine, "-"));
/* Result:
AAA
-BBB
-
-
-CCC
DDD---EEE
*/
Console.WriteLine (Regex.Replace(str, #"\r\n?|\n", "-"));
// Result:
// AAA-BBB---CCC---DDD---EEE
Console.WriteLine (Regex.Replace(str, #"[\r\n]+", "-"));
// Result:
// AAA-BBB-CCC-DDD-EEE
}
}

Use new in .NET 6 method
myString = myString.ReplaceLineEndings();
Replaces ALL newline sequences in the current string.
Documentation:
ReplaceLineEndings

Don't forget that replace doesn't do the replacement in the string, but returns a new string with the characters replaced. The following will remove line breaks (not replace them). I'd use #Brian R. Bondy's method if replacing them with something else, perhaps wrapped as an extension method. Remember to check for null values first before calling Replace or the extension methods provided.
string line = ...
line = line.Replace( "\r", "").Replace( "\n", "" );
As extension methods:
public static class StringExtensions
{
public static string RemoveLineBreaks( this string lines )
{
return lines.Replace( "\r", "").Replace( "\n", "" );
}
public static string ReplaceLineBreaks( this string lines, string replacement )
{
return lines.Replace( "\r\n", replacement )
.Replace( "\r", replacement )
.Replace( "\n", replacement );
}
}

To make sure all possible ways of line breaks (Windows, Mac and Unix) are replaced you should use:
string.Replace("\r\n", "\n").Replace('\r', '\n').Replace('\n', 'replacement');
and in this order, to not to make extra line breaks, when you find some combination of line ending chars.

Why not both?
string ReplacementString = "";
Regex.Replace(strin.Replace(System.Environment.NewLine, ReplacementString), #"(\r\n?|\n)", ReplacementString);
Note: Replace strin with the name of your input string.

I needed to replace the \r\n with an actual carriage return and line feed and replace \t with an actual tab. So I came up with the following:
public string Transform(string data)
{
string result = data;
char cr = (char)13;
char lf = (char)10;
char tab = (char)9;
result = result.Replace("\\r", cr.ToString());
result = result.Replace("\\n", lf.ToString());
result = result.Replace("\\t", tab.ToString());
return result;
}

var answer = Regex.Replace(value, "(\n|\r)+", replacementString);

As new line can be delimited by \n, \r and \r\n, first we’ll replace \r and \r\n with \n, and only then split data string.
The following lines should go to the parseCSV method:
function parseCSV(data) {
//alert(data);
//replace UNIX new lines
data = data.replace(/\r\n/g, "\n");
//replace MAC new lines
data = data.replace(/\r/g, "\n");
//split into rows
var rows = data.split("\n");
}

Use the .Replace() method
Line.Replace("\n", "whatever you want to replace with");

Best way to replace linebreaks safely is
yourString.Replace("\r\n","\n") //handling windows linebreaks
.Replace("\r","\n") //handling mac linebreaks
that should produce a string with only \n (eg linefeed) as linebreaks.
this code is usefull to fix mixed linebreaks too.

Another option is to create a StringReader over the string in question. On the reader, do .ReadLine() in a loop. Then you have the lines separated, no matter what (consistent or inconsistent) separators they had. With that, you can proceed as you wish; one possibility is to use a StringBuilder and call .AppendLine on it.
The advantage is, you let the framework decide what constitutes a "line break".

string s = Regex.Replace(source_string, "\n", "\r\n");
or
string s = Regex.Replace(source_string, "\r\n", "\n");
depending on which way you want to go.
Hopes it helps.

If you want to replace only the newlines:
var input = #"sdfhlu \r\n sdkuidfs\r\ndfgdgfd";
var match = #"[\\ ]+";
var replaceWith = " ";
Console.WriteLine("input: " + input);
var x = Regex.Replace(input.Replace(#"\n", replaceWith).Replace(#"\r", replaceWith), match, replaceWith);
Console.WriteLine("output: " + x);
If you want to replace newlines, tabs and white spaces:
var input = #"sdfhlusdkuidfs\r\ndfgdgfd";
var match = #"[\\s]+";
var replaceWith = "";
Console.WriteLine("input: " + input);
var x = Regex.Replace(input, match, replaceWith);
Console.WriteLine("output: " + x);

This is a very long winded one-liner solution but it is the only one that I had found to work if you cannot use the the special character escapes like "\r" and "\n" and \x0d and \u000D as well as System.Environment.NewLine as parameters to thereplace() method
MyStr.replace( System.String.Concat( System.Char.ConvertFromUtf32(13).ToString(), System.Char.ConvertFromUtf32(10).ToString() ), ReplacementString );
This is somewhat offtopic but to get it to work inside Visual Studio's XML .props files, which invoke .NET via the XML properties, I had to dress it up like it is shown below.
The Visual Studio XML --> .NET environment just would not accept the special character escapes like "\r" and "\n" and \x0d and \u000D as well as System.Environment.NewLine as parameters to thereplace() method.
$([System.IO.File]::ReadAllText('MyFile.txt').replace( $([System.String]::Concat($([System.Char]::ConvertFromUtf32(13).ToString()),$([System.Char]::ConvertFromUtf32(10).ToString()))),$([System.String]::Concat('^',$([System.Char]::ConvertFromUtf32(13).ToString()),$([System.Char]::ConvertFromUtf32(10).ToString())))))

Based on #mark-bayers answer and for cleaner output:
string result = Regex.Replace(ex.Message, #"(\r\n?|\r?\n)+", "replacement text");
It removes \r\n , \n and \r while perefer longer one and simplify multiple occurances to one.

String Manipulation using C#

Using C# we can do string check like if string.contains() method, e.g.:
string test = "Microsoft";
if (test.Contains("i"))
test = test.Replace("i","a");
This is fine. But what if I want to replace a string which contains " symbol to be replaced.
I want to achieve this:
"<html><head>
I want to remove the " symbol present in check so that the result would be:
<html><head>

The " character can also be replaced, just like any other:
test = test.Replace("\"","");
Also, note that you don't have to test if the character exists : your test.Contains("i") could be removed since the .Replace() method won't do anything (no replace, no error thrown) if the character doesn't exist inside the string.

To include a quote symbol in a string, you need to escape it, using a backslash. In your example, you want to use something lik this:
if (test.Contains("\""))

There are two ways to include a '"' character in a string literal. All the answers so far have used the c-style way:
var quotation = "Parting is such sweet sorrow";
var howSweetIsIt = quotation + " that I shall say \"good-night\" till it be morrow.";
In some contexts (especially for users experienced with Visual Basic), the verbatim string literal may be easier to read. A verbatim string literal begins with an # sign, and the only character that requires escaping is the quotation mark -- all other characters are included verbatim (hence the name). Significantly, the method of escaping the quotation mark is different: rather than preceding it with a backslash, it must be doubled:
var howSweetIsIt = quotation + " that I shall say ""good-night"" till it be morrow.";

string SymbolString = "Micro\"so\"ft";
The string above use scape char \ to insert " between the characters
string Result = SymbolString.Replace("\"", string.Empty);
With the following replace I replace the character "" for empty.
This is what you try to achieve?

if (check.Contains("\"")
output = check.Replace("\"", "");

output = check.Replace("\"", "");
Just remember to use "\"" for the quote sign as the backslash is an escape character.

if (str.Contains("\""))
{
str = str.Replace("\"", "");
}

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