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Getting values of both attribute and element in an xml

I have the following xml
<lists>
<list Group="3">More_lists_go_here</list>
</lists>
What I want is both the list element value which is More_lists_go_here and the Group attribute value which is 3.
What I have tried so far is
XmlDocument doc = new XmlDocument();
doc.LoadXml("<list Group=\"3\">More_lists_go_here</list>");
XmlElement root = doc.DocumentElement;
string value = root.Descendants("lists").Elements("list").Select(x => (string)x.Attribute("Group")).ToList();
what that gets me is
value = 3
what I want is both 3 and More_lists_go_here for string value

Use xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication40
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
string input = "<lists><list Group=\"3\">More_lists_go_here</list></lists>";
XDocument doc = XDocument.Parse(input);
var results = doc.Descendants("list").Select(x => new { group = (string)x.Attribute("Group"), value = (string)x }).ToList();
}
}
}

C# Xdocument Xml get Element

I have a xml file that looks like this:
<s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/">
<s:Body>
<GetAllArticlesResponse xmlns="http://www.borger.dk/2009/WSArticleExport/v1">
<GetAllArticlesResult xmlns:a="http://www.borger.dk/2009/WSArticleExport/v1/types" xmlns:i="http://www.w3.org/2001/XMLSchema-instance">
<a:ArticleDescription>Test 1</a:ArticleDescription>
<a:ArticleDescription>Test 2</a:ArticleDescription>
</GetAllArticlesResult>
</GetAllArticlesResponse>
</s:Body>
</s:Envelope>
I'm trying to get all the articles, but can't get it to work.
XDocument doc = XDocument.Parse(soapResult);
IEnumerable<XElement> articles = doc.Root.Descendants("a:ArticleDescription");
This has work before, but because the element name as a : then it fails..
Any idea how to fix this.
Thanks for all the inputs.
I ended with::
XNamespace a = "http://www.borger.dk/2009/WSArticleExport/v1/types";
XDocument doc = XDocument.Parse(soapResult);
IEnumerable<XElement> articles = doc.Root.Descendants(a + "ArticleDescription");
List<Article> article = articles.Select(m => new Article()
{
ArticleID = m.Element(a + "ArticleID").Value.ToString(),
ArticleTitle = m.Element(a + "ArticleTitle").Value.ToString(),
ArticleUrl = m.Element(a + "ArticleUrl").Value.ToString(),
LastUpdated = m.Element(a + "LastUpdated").Value.ToString(),
PublishingDate = m.Element(a + "PublishingDate").Value.ToString()
}).ToList();
json = JsonConvert.SerializeObject(article);

Here's an alterante way:
var doc = XDocument.Load(xml);
XNamespace ns1 = "http://schemas.xmlsoap.org/soap/envelope/";
XNamespace ns2 = "http://www.borger.dk/2009/WSArticleExport/v1";
XNamespace ns3 = "http://www.borger.dk/2009/WSArticleExport/v1/types";
var result = doc.Element(ns1 + "Envelope")
.Element(ns1 + "Body")
.Element(ns2 + "GetAllArticlesResponse")
.Element(ns2 + "GetAllArticlesResult")
.Elements(ns3 + "ArticleDescription")
.Select(x => x.Value);
Or
var doc = XDocument.Load(xml);
var envelope = doc.Root;
var body = (XElement)envelope.FirstNode;
var getAllArticlesResponse = (XElement)body.FirstNode;
var getAllArticlesResult = (XElement)getAllArticlesResponse.FirstNode;
var articleDescriptions = getAllArticlesResult.Nodes().Cast<XElement>();
var result = articleDescriptions.Select(x => x.Value);

Here is easiest way using Xml Linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication137
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
string[] description = doc.Descendants().Where(x => x.Name.LocalName == "ArticleDescription").Select(x => (string)x).ToArray();
}
}
}

The prefix a: is a short-for of the namespace name "http://www.borger.dk/2009/WSArticleExport/v1/types", you can see that where the prefix is declared.
You can use namespace-aware XName's when querying:
var descriptions = doc.Root.Descendants(
XName.Get("ArticleDescription", "http://www.borger.dk/2009/WSArticleExport/v1/types"));
Of course you could store the namespaces you want in variables, you don't have to type them out every time.
You can also just look at the local names, if you're not worried about collisions.
var descriptions = doc.Root.Descendants().Where(x => x.Name.LocalName == "ArticleDescription");

c# - Select node in xmlDocument

I have an XML with this structure:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ns2:Dossiers xmlns:ns2="http://www.dat.de/vxs" source="SD3" type="completeEvaluation">
<ns2:Dossier>
<ns2:Vehicle>
<ns2:VehicleIdentNumber>aaaaaaaaaa</ns2:VehicleIdentNumber>
<ns2:Equipment>
<ns2:OriginalEquipmentValueGross origin="dat">16206.00</ns2:OriginalEquipmentValueGross>
<ns2:SeriesEquipment>
<ns2:EquipmentPosition>
<ns2:DatEquipmentId>15201</ns2:DatEquipmentId>
<ns2:Description>lorem ipsum</ns2:Description>
</ns2:EquipmentPosition>
<ns2:EquipmentPosition>
<ns2:DatEquipmentId>17602</ns2:DatEquipmentId>
<ns2:Description>lorem ipsum</ns2:Description>
</ns2:EquipmentPosition>
...
</ns2:SeriesEquipment>
</ns2:Vehicle>
<ns2:Vehicle>
....
</ns2:Vehicle>
</ns2:Dossier>
</ns2:Dossiers>
With this code I have obtained the ns2:VehicleIdentNumber value:
XmlDocument xml = new XmlDocument();
xml.LoadXml(xmlFileContent);
var xmlNodeList = xml.GetElementsByTagName("ns2:Vehicle");
foreach (XmlElement xmlElement in xmlNodeList)
{
var telaio = xmlElement["ns2:VehicleIdentNumber"];
}
but how can I get ns2:OriginalEquipmentValueGross value and ns2:Description value?

Using Xml Linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement root = doc.Root;
XNamespace ns2 = root.GetNamespaceOfPrefix("ns2");
var results = doc.Descendants(ns2 + "Vehicle").Select(x => new
{
vehicleIdentNumber = (string)x.Element(ns2 + "VehicleIdentNumber"),
originalEquipmentValueGross = (string)x.Descendants(ns2 + "OriginalEquipmentValueGross").FirstOrDefault()
}).ToList();
}
}
}

It should be more or less the same of what you already have:
var xmlNodeList = xml.GetElementsByTagName("ns2:Vehicle");
foreach (XmlElement xmlElement in xmlNodeList)
{
var telaio = xmlElement["ns2:VehicleIdentNumber"];
var equipment = xmlElement["ns2:Equipment"];
var originalEquipmentValueGross = equipment["ns2:OriginalEquipmentValueGross"].InnerText;
foreach (XmlElement equipmentPosition in equipment["ns2:SeriesEquipment"].GetElementsByTagName("ns2:EquipmentPosition"))
{
var description = equipmentPosition["ns2:Description"].InnerText;
}
}

Grab xml value using XmlDocument

I want to grab UPC value from the following XML example node, but the current doc.SelectNodes fails to grab that value. I am using XmlDocument to process my XML. Can you fix my code to grab UPC value? What am I doing wrong here?
C# Code:
string responseStr = new StreamReader(responseStream).ReadToEnd();
responseStream.Flush();
responseStream.Close();
XmlDocument doc = new XmlDocument();
doc.LoadXml(responseStr);
if (doc.GetElementsByTagName("Ack").Item(0).InnerText != "Failure")
{
string UPC = doc.SelectNodes("Item").Item(0).SelectNodes("UPC").Item(0).InnerText;
}
XML Sample:
<?xml version="1.0" encoding="UTF-8"?>
<GetItemResponse xmlns="urn:ebay:apis:eBLBaseComponents">
<Timestamp>2018-07-28T08:18:10.048Z</Timestamp>
<Ack>Success</Ack>
<Version>1069</Version>
<Build>E1069_CORE_API_18748854_R1</Build>
<Item>
<ProductListingDetails>
<ISBN>Not Applicable</ISBN>
<UPC>853365007036</UPC>
<EAN>0853365007036</EAN>
<BrandMPN>
<Brand>UpCart</Brand>
<MPN>MPCB-1DX</MPN>
</BrandMPN>
<IncludeeBayProductDetails>true</IncludeeBayProductDetails>
</ProductListingDetails>
</Item>
</GetItemResponse>

You have a namespace that must be used to get values. Here is the easy way using xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XNamespace ns = doc.Root.GetDefaultNamespace();
string UPC = (string)doc.Descendants(ns + "UPC").FirstOrDefault();
}
}
}
If you have nulls use this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XNamespace ns = doc.Root.GetDefaultNamespace();
var upcs = doc.Descendants(ns + "UPC");
if (upcs != null)
{
string upc = (string)upcs.FirstOrDefault();
}
}
}
}

Get value from simple XML document

I have the following XML
<User
xmlns:i="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://schemas.datacontract.org/2004/07/GaryLeaderboardsAPI.Models">
<Game_ID>3</Game_ID>
<UserGUID>e00d3560-4133-4ba6-8bba-e6c8659468b4</UserGUID>
<UserName>tony2</UserName>
<User_ID>16</User_ID>
</User>
Using C# I am loading this into an XMLDocument, How do I retrieve the UserGUID value?

Leveraging System.Xml.Linq you could do
string xml = "..."; // your inline XML
var doc = System.Xml.Linq.XDocument.Parse(xml);
or
string xmlFile = "..."; // your XML filename
var doc = System.Xml.Linq.XDocument.Load(xmlFile);
and then, to get the UserGUID
var userGuid = doc.Descendants().Where(x=>x.Name.LocalName == "UserGUID").First().Value;

This will work for you.
string xml = "<User xmlns:i=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns=\"http://schemas.datacontract.org/2004/07/GaryLeaderboardsAPI.Models\">" +
"<Game_ID>3</Game_ID>" +
"<UserGUID>e00d3560-4133-4ba6-8bba-e6c8659468b4</UserGUID>" +
"<UserName>tony2</UserName>" +
"<User_ID>16</User_ID>" +
"</User>";
XmlDocument doc = new XmlDocument();
doc.LoadXml(xml);
var id = doc.GetElementsByTagName("UserGUID")[0].InnerText;

You need to use the namespace. I often use mipnw approach (probably stole idea from one of my postings). See code below :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement user = doc.Root;
XNamespace ns = user.GetDefaultNamespace();
string UserGUID = (string)user.Element(ns + "UserGUID");
}
}
}