I've always been really bad when it comes to using regular expressions but it is something I want to seriously understand because as we all know, it is quite useful.
This is for a personal project, to keep my folders organized and neat.
I have a bunch of folders with the following naming pattern XXXXXXXX.XXXXXXX.XXXXXX.SYY.EYY.SOMETHINGELSE
There can be any amount of X repeating separated by ".", but the SYY.EYY is always there. So what I want is a regular expression to retrieve all the text represented by XXX without the "." if possible up until the SYY.EYY pattern.
I managed to detect the pattern because YY are always numbers, so doing something like \d{2} will detect it but I'm wondering if its possible to also add the rest of the pattern to that \d{2}.
Any help is appreciate it :)
If the YY is as you stated 2 digits and you want to get the text except the . up until for example S11.E22 you could make use of the \G anchor and a capturing group to get the text without a dot.
The value is in the Match.Groups property.
\G(?!S[0-9]{2}\.E[0-9]{2})([^.]+)\.
In parts
\G Assert position at the end of previous match (start at the beginning)
(?! Negative lookahead, assert what is directly to the right is not
S[0-9]{2}\.E[0-9]{2} Math S, 2 digits, . E and 2 digits
) Close lookahead
( Capture group 1
[^.]+ Match 1+ times any char except a dot
) Close group 1
\. Match dot literal
Regex demo | C# demo
For example
string pattern = #"\G(?!S[0-9]{2}\.E[0-9]{2})([^.]+)\.";
string input = #"XXXXXXXX.XXXXXXX.XXXXXX.S11.E22.SOMETHINGELSE";
foreach (Match m in Regex.Matches(input, pattern))
{
Console.WriteLine(m.Groups[1].Value);
}
Output
XXXXXXXX
XXXXXXX
XXXXXX
You can "replace/cut" the "." with C#.
The regex to get up until the SYY.EYY can be like this:
.SYY.EYY$
Line ends with word -> Regex: ExampleWord$
I would do something like:
var leftPart = Regex.Match(x, "^.*?(?=SYY)").Captures.First().Value;
// this now has XXXXXXXX.XXXXXXX.XXXXXX.
// And we can:
var left = leftPart.Replace(".", " "); // or any other char
I have this regular expression pattern: .{2}\#.{2}\K|\..*(*SKIP)(?!)|.(?=.*\.)
It works perfectly to convert to replace the matches to get
trabc#abtrec.com.lo => ***bc#ab*****.com.lo
demomail#demodomain.com => ******il#de*********.com
But when I try to use it on C# the \K and the (*SKIP) and (*F) are not allowed.
what will be the c# version of this pattern? or do you know a simpler way to mask the email without the unsupported pattern entries?
Demo
UPDATE:
(*SKIP): this verb causes the match to fail at the current starting position in the subject if the rest of the pattern does not match
(*F): Forces a matching failure at the given position in the pattern (the same as (?!)
Try this regex:
\w(?=.{2,}#)|(?<=#[^\.]{2,})\w
Click for Demo
Explanation:
\w - matches a word character
(?=.{2,}#) - positive lookahead to find the position immediately followed by 2+ occurrences of any character followed by #
| - OR
(?<=#[^\.]{2,}) - positive lookbehind to find the position immediately preceded by # followed by 2+ occurrences of any character that is not a .
\w - matches a word character.
Replace each match with a *
You can achieve the same result with a regex that matches items in one block, and applying a custom match evaluator:
var res = Regex.Replace(
s
, #"^.*(?=.{2}\#.{2})|(?<=.{2}\#.{2}).*(?=.com.*$)"
, match => new string('*', match.ToString().Length)
);
The regex has two parts:
The one on the left ^.*(?=.{2}\#.{2}) matches the user name portion except the last two characters
The one on the right (?<=.{2}\#.{2}).*(?=.com.*$) matches the suffix of the domain up to the ".com..." ending.
Demo.
I have a string which looks like this :-
"$.ConfigSettings.DatabaseSettings.DatabaseConnections.SqlConnectionString.0.Id"
and I want the result to look like this :-
"$.ConfigSettings.DatabaseSettings.DatabaseConnections.SqlConnectionString[0].Id"
Basically wherever there is a single digit preceded and succeeded by a period I need to change it to [digit] followed by period ie [digit]. .I have seen tons of examples where people are only replacing the regex string.
How will I do this using Regex.Replace in C#
Regex.Replace(input, #"\.(\d)(?=\.)", "[$1]")
\. - capture a "."
(\d) - then a single digit in a capturing group ($1 in the replacement)
(?= - start a positive lookahead
\. - that matches a "."
) - end the lookahead
So, it means : (match a dot followed by a digit in a capturing group) only if it is followed by a dot
So we matched ".0" and captured "0". We replace the entire match with "[$1]", where $1 refers to the first captured group.
See "Grouping Constructs in Regular Expressions" : https://msdn.microsoft.com/en-us/library/bs2twtah(v=vs.110).aspx for information about the different grouping constructs that I use in this solution.
I'm trying to find a way to extract a word from a string only if it contains 3 or more digits/numbers in that word. It would also need to return the entire text like
TX-23443 or FUX3329442 etc...
From what I found
\w*\d\w*
won't return the any letters before the dash like the first example?
All the example I found online don't seem to be working for me. Any help is appreciated!
IF I understand your question correctly you wanted to find all the string which contains 3+ consequtive numbers in it such as TX-23443 or FUX3329442 so you wanted to extract TX-23443 and FUX3329442 even if it contains - in between the string. So here is the solution which might help you
string InpStr = "TX-23443 or FUX3329442";
MatchCollection ms = Regex.Matches(InpStr, #"[A-Za-z-]*\d{3,}");
foreach(Match m in ms)
{
Console.WriteLine(m);
}
This one should do the trick assuming your "words" have only the standard latin word characters: A-Z, a-z, 0-9 and _.
Regex word_with_3_digits = new Regex(#"(?#!cs word_with_3_digits Rev:20161129_0600)
# Match word having at least three digits.
\b # Anchor to word boundary.
(?: # Loop to find three digits.
[A-Za-z_]* # Zero or more non-digit word chars.
\d # Match one digit at a time.
){3} # End loop to find three digits.
\w* # Match remainder of word.
\b # Anchor to word boundary.
", RegexOptions.IgnorePatternWhitespace);
In javascript I would write a regex like this:
\S*\d{3,}\S*
I've prepared an online test.
Try this:
string strToCount = "Asd343DSFg534434";
int count = Regex.Matches(strToCount,"[0-9]").Count;
This one seems to be working for me even if there is a dash at the end as well.
[-]\w[-]\d{3,}[-]\w*[-]\w
i have the following string
Fat mass loss was 2121,323.222 greater for GPLC (2–2.4kg vs. 0.5kg)
i want to capture
212,323.222
2-2.24
0.5
i.e. i want the above three results from the string,
can any one help me with this regex
I noticed that your hyphen in 2–2.4kg is not really hyphen, its a unicode 0x2013 "DASH".
So, here is another regex in C#
#"[0-9]+([,.\u2013-][0-9]+)*"
Test
MatchCollection matches = Regex.Matches("Fat mass loss was 2121,323.222 greater for GPLC (2–2.4kg vs. 0.5kg)", #"[0-9]+([,.\u2013-][0-9]+)*");
foreach (Match m in matches) {
Console.WriteLine(m.Groups[0]);
}
Here is the results, my console does not support printing unicode char 2013, so its "?" but its properly matched.
2121,323.222
2?2.4
0.5
Okay I didn't notice the C# tag until now. I will leave the answer but I know that's not what you expected, see if you can do something with it. Perhaps the title should have mentioned the programming language?
Sure:
Fat mass loss was (.*) greater for GPLC \((.*) vs. (.*)kg\)
Find your substrings in \1, \2 and \3.
If for Emacs, swap all parentheses and escaped parentheses.
How about something like this:
^.*((?:\d+,)*\d+(?:\.\d+)?).*(\d+(?:\.\d+)?(?:-\d+(?:\.\d+))?).*(\d+(?:\.\d+)).*$
A little more general, I think. I'm a little concerned about .* being greedy.
Fat mass loss was 2121,323.222 greater
for GPLC (2–2.4kg vs. 0.5kg)
a generalized extractor:
/\D+?([\d\,\.\-]+)/g
explanation:
/ # start pattern
\D+ # 1 or more non-digits
( # capture group 1
[\d,.-]+ # character class, 1 or more of digits, comma, period, hyphen
) # end capture group 1
/g # trailing regex g modifier (make regex continue after last match)
sorry I don't know c# well enough for a full writeup, but the pattern should plug right in.
see: http://www.radsoftware.com.au/articles/regexsyntaxadvanced.aspx for some implementation examples.
I came out with something like this atrocity:
-?\d(?:,?\d)*(?:\.(?:\d(?:,?\d)*\d|\d))?(?:[–-]-?\d(?:,?\d)*(?:\.(?:\d(?:,?\d)*\d|\d))?)?
Out of witch -?\d(?:,?\d)*(?:\.(?:\d(?:,?\d)*\d|\d))? is repeated twice, with – in the middle (note that this is a long hyphen).
This should take care of dots and commas outside of numbers, eg: hello,23,45.2-7world - will capture 23,45.2-7.
It looks like you're trying to find all numbers in the string (possibly with commas inside the number), and all ranges of numbers such as "2-2.4". Here is a regex that should work:
\d+(?:[,.-]\d+)*
From C# 3, you can use it like this:
var input = "Fat mass loss was 2121,323.222 greater for GPLC (2-2.4kg vs. 0.5kg)";
var pattern = #"\d+(?:[,.-]\d+)*";
var matches = Regex.Matches(input, pattern);
foreach ( var match in matches )
Console.WriteLine(match.Value);
Hmm, this is a tricky question, especially because the input string contains unicode character – (EN DASH) instead of - (HYPHEN-MINUS). Therefore the correct regex to match the numbers in the original string would be:
\d+(?:[\u2013,.]\d+)*
If you want a more generic approach would be:
\d+(?:[\p{Pd}\p{Pc}\p{Po}]\d+)*
which matches dash punctuation, connecter punctuation and other punctuation. See here for more information about those.
An implementation in C# would look like this:
string input = "Fat mass loss was 2121,323.222 greater for GPLC (2–2.4kg vs. 0.5kg)";
try {
Regex rx = new Regex(#"\d+(?:[\p{Pd}\p{Pc}\p{Po}\p{C}]\d+)*", RegexOptions.IgnoreCase | RegexOptions.Multiline);
Match match = rx.Match(input);
while (match.Success) {
// matched text: match.Value
// match start: match.Index
// match length: match.Length
match = match.NextMatch();
}
} catch (ArgumentException ex) {
// Syntax error in the regular expression
}
Let's try this one :
(?=\d)([0-9,.-]+)(?<=\d)
It captures all expressions containing only :
"[0-9,.-]" characters,
must start with a digit "(?=\d)",
must finish with a digit "(?<=\d)"
It works with a single digit expression and does not include beginning or trailing [.,-].
Hope this helps.
I got the solution to my problem.
The following is the Regex that gave my desired result:
(([0-9]+)([–.,-]*))+