The static property NodaTime.LocalDate.MinIsoValue has the value 9999-01-01 whereas I'd have expected it to have the same value as default(LocalDate) which is 0001-01-01. Is there a reason for this value or is it a bug?
I'm using NodaTime version 2.4.4.
Formatting local date using pattern "yy" or "yyyy" outputs years of era not the year which is -9998 in this case. LocalDate.MinIsoValue is from BCE era. The format you have used didn't include era in it. You can use "g" or "gg" in your custom format to include the era.
var def = default(LocalDate);
var min = LocalDate.MinIsoValue;
Console.WriteLine("def: " + def.ToString("yyyy-MM-dd", CultureInfo.InvariantCulture));
Console.WriteLine("def with era: " + def.ToString("yyyy-MM-dd gg", CultureInfo.InvariantCulture));
Console.WriteLine("def.Year: " + def.Year);
Console.WriteLine("def.YearOfEra: " + def.YearOfEra);
Console.WriteLine("min: " + min.ToString("yyyy-MM-dd", CultureInfo.InvariantCulture));
Console.WriteLine("min with era: " + min.ToString("yyyy-MM-dd gg", CultureInfo.InvariantCulture));
Console.WriteLine("min.Year: " + min.Year);
Console.WriteLine("min.YearOfEra: " + min.YearOfEra);
Console.WriteLine("min < def: " + (min < def));
def: 0001-01-01
def with era: 0001-01-01 A.D.
def.Year: 1
def.YearOfEra: 1
min: 9999-01-01
min with era: 9999-01-01 B.C.
min.Year: -9998
min.YearOfEra: 9999
min < def: True
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************** Exception Text **************
System.FormatException: String was not recognized as a valid DateTime.
at System.DateTimeParse.Parse(String s, DateTimeFormatInfo dtfi, DateTimeStyles styles)
at System.Convert.ToDateTime(String value)
at ExtraTutoManager.Dashcont.CulcPay(DateTime dateAf) in D:\coure du soire gestion\visual studio project\ExtraTutoManager\ExtraTutoManage
declaration global
public DateTime rendVous;
public DateTime temp;
I want to covert string to datetime by ToDateTime() , in my project VS running without any problem but in another pc this String was not recognized as a valid DateTime
temp = Convert.ToDateTime("" + dateAf.Date.Day + "/" + (DateTime.Now.Month + 1) + "/" + DateTime.Now.Year);
this is my method
//Culcs
public DateTime Culcdate(DateTime dateAf)
{
int mont = DateTime.Now.Month - dateAf.Date.Month;
if (DateTime.Now.Month == dateAf.Date.Month)
{
temp = Convert.ToDateTime("" + dateAf.Date.Day + "/" + (DateTime.Now.Month + 1) + "/" + DateTime.Now.Year);
}
else if (mont - (mont - 1) >= 1 && DateTime.Now.Day >= dateAf.Date.Day)
{
temp = Convert.ToDateTime("" + dateAf.Date.Day + "/" + (DateTime.Now.Month + 1) + "/" + DateTime.Now.Year);
}
else if (mont - (mont - 1) >= 1)
{
temp = Convert.ToDateTime("" + dateAf.Date.Day + "/" + DateTime.Now.Month + "/" + DateTime.Now.Year);
}
return rendVous = temp;
}
The reason is failed in other computers is likely to be they have different Cultures, one computer could be trying to parse in American format MM/dd/yyyy and the other one is in dd/MM/yyyy.
You can use DateTime.ParseExact() and specify the format and culture you are trying to parse.
https://learn.microsoft.com/en-us/dotnet/api/system.datetime.parseexact?view=net-6.0
DateTime.ParseExact(temp, "dd/MM/yyyy", CultureInfo.InvariantCulture)
Convert.ToDateTime will take into account the current systems Culture and thus expects the string to be in a certain format.
See more info here:
https://learn.microsoft.com/en-us/dotnet/api/system.convert.todatetime?view=net-6.0#System_Convert_ToDateTime_System_String_System_IFormatProvider_
To make this code work on the other system, you could change the system language used, but a better solution is to make sure that the input value is in the current cultures format, or use the second parameter for Convert.ToDateTime() which is an IFormatProvider to tell the system which culture to use. That way it will not matter anymore what system runs the code.
In your case you could also write:
temp = new DateTime(DateTime.Now.Year, DateTime.Now.Month + 1, dateAf.Date.Day)
instead of
temp = Convert.ToDateTime("" + dateAf.Date.Day + "/" + (DateTime.Now.Month + 1) + "/" + DateTime.Now.Year);
to avoid the date parsing all together. Make sure to not do this when the month is december as that would still result in an invalid datetime.
If you are simply trying to achieve getting the current DateTime + 1 month you could do this:
temp = DateTime.Now.AddMonths(1);
which will also work when the current date is in december, and will result in a date in januari the next year.
I want to make a year as 1 April to 31 March with c#. If a Person input his DOB, the year changes if cross 31 March.`
//Display Window Period
DateTime winst21 = new DateTime(DateTime.Now.Year, dob.Month, dob.Day);
DateTime wind21 = winst21.AddYears(1);
Label2.Text = "Your Current IPPT Window is " + " " + winst21.ToString("dd/MM/yyy") + " " + "-" + " " + wind21.ToString("dd/MM/yyy");
I guess you just an offset of +9 or -3 months:
//Display Window Period
DateTime winst21 = new DateTime(dob.AddMonths(9).Year, dob.Month, dob.Day);
DateTime wind21 = winst21.AddYears(1);
My code parses a raw data and turns it into a datetime string format such as below
string birthday = "20" + year + "-" + month + "-" + day + " " + hour + ":" + minutes + ":" + second;
So birthday is a string and then I converted it to datetime format such as below
DateTime bdaylater= Convert.ToDateTime(birthday);
The result became like the one below
7/8/2015 5:02:05 AM
in which I wanted to convert to something like the one below
2015/07/08 05:02:05.000
How can I achieve such result.
Thanks.
You should format your date variable before printing the same
string birthday = "2015" + "-" + "07" + "-" + "08" + " " + "05" + ":" + "02" + ":" + "05";
DateTime bdaylater= Convert.ToDateTime(birthday);
Console.WriteLine(bdaylater.ToString("yyyy/MM/dd hh:mm:ss.mmm"));
this will give the o/p 2015/07/08 05:02:05.02
Fiddle example
If you want only 000 in millisecond the string will be "yyyy/MM/dd hh:mm:ss.000"
Would you like to convert it to string format? With 3 zeros padded on it? Maybe this could help:
int year = 15;
int month = 7;
int day = 8;
int hour = 5;
int minutes = 2;
int second = 5;
string birthday = "20" + year + "-" + month + "-" + day + " " + hour + ":" + minutes + ":" + second;
DateTime bdaylater = Convert.ToDateTime(birthday);
Console.WriteLine(bdaylater);
Console.WriteLine(bdaylater.ToString("yyyy/MM/dd hh:mm:ss.000")); //2015/07/08 05:02:05.000
Console.ReadLine();
Try this:
DateTime.Parse(birthday).ToString("yyyy/MM/dd hh:mm:ss.fff")
I want all people that there age is 27
how i calc the start and the end date?
ss.startAge = (DateTime.Now.Year - startAge).ToString() +
"-" + DateTime.Now.ToString("MM") + "-" + DateTime.Now.ToString("dd");
ss.endAge = (DateTime.Now.Year - (endAge-1)).ToString() +
"-" + DateTime.Now.ToString("MM") + "-" + DateTime.Now.ToString("dd");
i know that i need to sub 1 day but if the end age is need to be
1999-12-31 because the calc is above is give 2000-01-01 how i need to
write the code that the end age will be correct
how i calc the end date correctly?
I am trying to add ticks to a DateTime (c#), but I can't figure out why is this not working:
DateTime end = StartTime.AddTicks(timer.Interval);
Console.WriteLine(StartTime.ToLocalTime() + " + " + timer.Interval + " = " + end.ToLocalTime());
This is giving me the following output :
24/05/2014 20:47:27 + 60000 = 24/05/2014 20:47:27
So, why is end the same value than StartTime ?
FYI, I declared my variables like this :
private DateTime StartTime;
private Timer timer = new Timer();
10.000 ticks make 1ms, 60.000 ticks make 6ms, you don't display millisecond part so there is no difference in output, but values are different.
If you change your output formatting to the following (display millisecond part), then you can see the difference.
Console.WriteLine(StartTime.ToLocalTime().ToString("dd/MM/yyyy HH:mm:ss.fff") + " + " + timer.Interval + " = " + end.ToLocalTime().ToString("dd/MM/yyyy HH:mm:ss.fff"));
More about ticks: DateTime.Ticks