I have a image uploader that stores my images on that project location:
C:\Users\example\source\Workspaces\project\projectsample\Content\Files
When I try to access this images with the following URL and code it breaks:
var fileURL = "~/Content/Files/image.png";
byte[] file = File.ReadAllBytes(fileURL);
Cannot find a part of the path
What I'm missing?
EDIT
Solved with the following: How to read existing text files without defining path using AXMIM solution.
You are on windows and not unix, so your fileURL is wrong. See naming files, paths, and namespaces for more info.
It should look like this:
var fileURL = #".\Content\Files\image.png";
EDIT: before its unclear, the ~ is the wrong character here, / or \ does not matter in that regard.
Related
I want to provide links to files uploaded on the server in iTextSharp documents.
The problem I'm facing is the string containing my file path is getting mangled en-route from my code onto the page.
Let's say the full path for the file, I'm trying to link is "C:\site uploads\some_file.txt".
I'm trying to create the link using the "Anchor" object, like so:
string path = "C:\site uploads\some_file.txt";
string name = "some_file.txt";
Anchor anchor = new Anchor(name, new Font(Font.FontFamily.UNDEFINED, 12));
anchor.Reference = path;
pdfDoc.Add(anchor);
ASP.NET C# will double up those backslashes in "path", as it does, but iTextSharp will further alter the string to something like C%5%20site%HCuploads%20some%34file.txt, which does not work as a clickable link in my document. FYI, I know I didn't get my % codes just right; those are offered for example only.
I'm not trying to launch any external applications from my document, I just want to enable the user to download this file. Any advice would be appreciated.
Why do you link to a local file? If someone else downloads that PDF on their machine, it won't have that directory.
The backslashes and colon are escaped.
Use https:// links. If you do want to link to local files, use a file:// link.
I'm building a webapp using ASP.NET.
On my physical hard drive:
The path for my text file is: D:\Users\(MyName)\Documents\Visual Studio 2013\Projects\(ProjectName)\(ProjectName)\Data\TextFiles\someFile.txt
The .cs file is located in: D:\Users\(MyName)\Documents\Visual Studio 2013\Projects\(ProjectName)\(ProjectName)\Account\someCSFile.cs
In my code, I have the followings:
string fileName= Server.MapPath("TextFile/someFile.txt");
The code throws an exception saying that Could not find a part of the path 'D:\Users\(MyName)\Documents\Visual Studio 2013\Projects\(ProjectName)\(ProjectName)\Account\TextFile\someCSFile.cs
How am I going to use Server.MapPath to make it "go up one level", then find the "Data" folder > "TextFiles" > finally the "someFile.txt" WITHOUT hardcoding the entire file path?
This should do the trick
string fileName= Server.MapPath(#"..\Data\TextFile\someFile.txt");
take a look at this:
StackOverflow Post about Server.MapPath
You can use .. to go up one level:
string fileName= Server.MapPath("../Data/TextFile/someFile.txt");
You can also start from the application root by starting the path with a slash:
string fileName= Server.MapPath("/Data/TextFile/someFile.txt");
I want to load a xml document Swedish.xml which exists in my solution. How can i give path for that file in Xamarin.android
I am using following code:
var text = File.ReadAllText("Languages/Swedish.txt");
Console.WriteLine("text: "+text);
But i am getting Exception message:
Could not find a part of the path "//Languages/swedish.txt".
I even tried following lines:
var text = File.ReadAllText("./Languages/Swedish.txt");
var text = File.ReadAllText("./MyProject/Languages/Swedish.txt");
var text = File.ReadAllText("MyProject/Languages/Swedish.txt");
But none of them worked. Same exception message is appearing. Build Action is also set as Content. Whats wrong with the path? Thanks in advance.
Just try with this
string startupPath = Path.Combine(Directory.GetParent(System.IO.Directory.GetCurrentDirectory()).Parent.Parent.FullName, "Languages", "Swedish.txt");
var text = File.ReadAllText(startupPath);
Try...
Environment.GetFolderPath (Environment.SpecialFolder.MyDocuments)+"/Languages/Swedish.txt"
If you mark a file as Content Type, it will be included in the app bundle with the path that you are using within your project file. You can inspect the IPA file (it's just a renamed zip) that is created to verify that this is happening.
var text = File.ReadAllText("Languages/Swedish.txt");
should work. The file path is relative to the root of your application. You need to be sure that you are using the exact same casing in your code that the actual file uses. In the simulator the casing will not matter, but on the device the file system is case sensitive, and mismatched casing will break the app.
I've looked into this before and never found any solution to access files in this way. All roads seem to indicate building them as "content" is a dead end. You can however place them in your "Assets" folder and use them this way. To do so switch the "Content" to "AndroidAsset".
After you have done this you can now access the file within your app by calling it via
var filename = "Sweedish.txt";
string data;
using
(var sr = new StreamReader(Context.Assets.Open(code)))
data = sr.ReadToEnd();
....
In my app I have a WebBrowser element.
I would like to load a local file in it.
I have some questions:
Where to place the HTML file (so that it will also be installed if a user executes the setup)
how to reference the file? (e.g. my guess is the user's installation folder would not always be the same)
EDIT
I've added the HTML file to my project.
And I have set it up so that it gets copied to output folder.
When I check it it is present when run: \bin\Debug\Documentation\index.html
However when I do the following I get a 'Page cannot be displayed' error in the webbrowser element.
I use the following code to try to display the HTML file in the Webbrowser.
webBrowser1.Navigate(#".\Documentation\index.html");
Do a right click->properties on the file in Visual Studio.
Set the Copy to Output Directory to Copy always.
Then you will be able to reference your files by using a path such as #".\my_html.html"
Copy to Output Directory will put the file in the same folder as your binary dlls when the project is built. This works with any content file, even if its in a sub folder.
If you use a sub folder, that too will be copied in to the bin folder so your path would then be #".\my_subfolder\my_html.html"
In order to create a URI you can use locally (instead of served via the web), you'll need to use the file protocol, using the base directory of your binary - note: this will only work if you set the Copy to Ouptut Directory as above or the path will not be correct.
This is what you need:
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Url = new Uri(String.Format("file:///{0}/my_html.html", curDir));
You'll have to change the variables and names of course.
quite late but it's the first hit i found from google
Instead of using the current directory or getting the assembly, just use the Application.ExecutablePath property:
//using System.IO;
string applicationDirectory = Path.GetDirectoryName(Application.ExecutablePath);
string myFile = Path.Combine(applicationDirectory, "Sample.html");
webMain.Url = new Uri("file:///" + myFile);
Note that the file:/// scheme does not work on the compact framework, at least it doesn't with 5.0.
You will need to use the following:
string appDir = Path.GetDirectoryName(
Assembly.GetExecutingAssembly().GetName().CodeBase);
webBrowser1.Url = new Uri(Path.Combine(appDir, #"Documentation\index.html"));
Place it in the Applications setup folder or in a separte folder beneath
Reference it relative to the current directory when your app runs.
Somewhere, nearby the assembly you're going to run.
Use reflection to get path to your executing assembly, then do some magic to locate your HTML file.
Like this:
var myAssembly = System.Reflection.Assembly.GetEntryAssembly();
var myAssemblyLocation = System.IO.Path.GetDirectoryName(a.Location);
var myHtmlPath = Path.Combine(myAssemblyLocation, "my.html");
What worked for me was
<WebBrowser Source="pack://siteoforigin:,,,/StartPage.html" />
from here. I copied StartPage.html to the same output directory as the xaml-file and it loaded it from that relative path.
Windows 10 uwp application.
Try this:
webview.Navigate(new Uri("ms-appx-web:///index.html"));
Update on #ghostJago answer above
for me it worked as the following lines in VS2017
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Navigate(new Uri(String.Format("file:///{0}/my_html.html", curDir)));
I have been trying different answers from here, but managed to derive something working, here it is:
1- Added the page in a folder i created at project level named WebPagesHelper
2- To have the page printed by webBrowser Control,
string curDirectory = Path.GetDirectoryName(Assembly.GetExecutingAssembly().GetName().CodeBase);
var uri = new Uri(curDirectory);
string myFile = Path.Combine(uri.AbsolutePath, #"WebPagesHelper\index.html");
Uri new_uri = new Uri(myFile);
i had to get the assembly path, create a first uri to get an absolute path without the 'file://' attached, next i combined this absolute path with a relative path to the page in its folder, then made another URI from the result.
Then pass this to webBrowser URL property webBrowser.URL = new_uri;
There is a text file that I have created in my project root folder. Now, I am trying to use Process.Start() method to externally launch that text file.
The problem I have got here is that the file path is incorrect and Process.Start() can't find this text file. My code is as follows:
Process.Start("Textfile.txt");
So how should I correctly reference to that text file? Can I use the relative path instead of the absolute path? Thanks.
Edit:
If I change above code to this, would it work?
string path = Assembly.GetExecutingAssembly().Location;
Process.Start(path + "/ReadMe.txt");
Windows needs to know where to find the file, so you need somehow specify that:
Either using absolute path:
Process.Start("C:\\1.txt");
Or set current directory:
Environment.CurrentDirectory = "C:\\";
Process.Start("1.txt");
Normally CurrentDirectory is set to the location of the executable.
[Edit]
If the file is in the same directory where executable is you can use the code like this:
var directory = Path.GetDirectoryName(Assembly.GetEntryAssembly().Location);
var file = Path.Combine(directory, "1.txt");
Process.Start(file);
The way you are doing this is fine. This will find the text file that is in the same directory as your exe and it will open it with the default application (probably notepad.exe). Here are more examples of how to do this:
http://www.dotnetperls.com/process-start
However, if you want to put a path in, you have to use the full path. You can build the full path while only caring about the relative path using the method listed in this post:
http://social.msdn.microsoft.com/Forums/en-US/vbgeneral/thread/e763ae8c-1284-43fe-9e55-4b36f8780f1c
It would look something like this:
string pathPrefix;
if(System.Diagnostics.Debugger.IsAttached())
{
pathPrefix = System.IO.Path.GetFullPath(Application.StartupPath + "\..\..\resources\");
}
else
{
pathPrefix = Application.StartupPath + "\resources\";
}
Process.Start(pathPrefix + "Textfile.txt");
This is for opening a file in a folder you add to your project called resources. If you want it in your project root, just drop off the resources folder in the above two strings and you will be good to go.
You'll need to know the current directory if you want to use a relative path.
System.Envrionment.CurrentDirectory
You could append that to your path with Path
System.IO.Path.Combine(System.Envrionment.CurrentDirectory, "Textfile.txt")
Try using Application.StartupPath path as default path may point to current directory.
This scenario has been explained on following links..
Environment.CurrentDirectory in C#.NET
http://start-coding.blogspot.com/2008/12/applicationstartuppath.html
On a windows box:
Start notepad with the file's location immediately following it. WIN
process.start("notepad C:\Full\Directory\To\File\FileName.txt");