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Problem in cross platform (Convert 2 channel wav to mono wav in C#)

below code is only work in Window server.but i want its should also work in Linux server.Convert 2 channel wav to mono wav.please help
public static byte[] ConvertWavTo8000Hz16BitMonoWav(byte[] inArray)
{
using (var mem = new MemoryStream(inArray))
{
using (var reader = new WaveFileReader(mem))
{
using (var converter =
WaveFormatConversionStream.CreatePcmStream(reader))
{
using (var upsampler = new WaveFormatConversionStream(new
WaveFormat(8000, 16, 1), converter))
{
byte[] data;
using (var m = new MemoryStream())
{
upsampler.CopyTo(m);
data = m.ToArray();
}
using (var m = new MemoryStream())
{
// to create a propper WAV header (44 bytes),
//which begins with RIFF
var w = new WaveFileWriter(m, upsampler.WaveFormat);
// append WAV data body
w.Write(data,0,data.Length);
return m.ToArray();
}
}
}
}
}
}

About analysing the photo with tesseract

I wrote this code for analyzing the numbers included in picture. It does not give any error while starting but it can not read the numbers. When I start program, it shows an empty MessageBox.
I want to read pictures like this:
The code:
private string FotoAnaliz()
{
FileStream fs = new FileStream("D:\\program_goruntusu.jpg", FileMode.OpenOrCreate);
//string fotopath = #"D:\\program_goruntusu.jpg";
Bitmap images = new Bitmap(fs);
using (var engine = new TesseractEngine(#"./tessdata", "eng"))
{
engine.SetVariable("tessedit_char_whitelist", "0123456789");
// have to load Pix via a bitmap since Pix doesn't support loading a stream.
using (var image = new Bitmap(images))
{
using (var pix = PixConverter.ToPix(image))
{
using (var page = engine.Process(pix))
{
sayı = page.GetText();
MessageBox.Show(sayı);
fs.Close();
}
}
}
}
return sayı;
}

Try PSM 10: Treat the image as a single character.
https://github.com/tesseract-ocr/tesseract/blob/master/doc/tesseract.1.asc

Sevenzipsharp CompressStream throws Exception: Value cannot be null

I am trying out following code in order to compress and save a bitmap of a screenshot but get this error. I haven't tried using CompressFiles as I have to do it using memory stream.
public void CompressAndSaveBitmap(Bitmap bitmap)
{
using (MemoryStream memStream = new MemoryStream())
{
using (FileStream file = new FileStream("XYZ", FileMode.Create, System.IO.FileAccess.Write))
{
bitmap.Save(memStream, System.Drawing.Imaging.ImageFormat.Bmp);
// tried these but they don't work.
//memStream.Seek(0, 0);
//memStream.Position = 0;
this.compressor.CompressStream(memStream, file); // throws error here
// also tried the following to see if Bitmap contains the problem
//UnicodeEncoding uniEncoding = new UnicodeEncoding();
//byte[] firstString = uniEncoding.GetBytes("Invalid file path characters are: ");
//int count = 0;
//while (count < firstString.Length)
//memStream.WriteByte(firstString[count++]);
//memStream.Flush();
////memStream.Seek(0, 0);
//memStream.Position = 0;
//this.compressor.CompressStream(memStream, file);
}
}
}
Compressor initialization code:
public Compressor()
{
SevenZipCompressor.SetLibraryPath(#"D:\7z.dll");
this.compressor = new SevenZip.SevenZipCompressor();
compressor.CompressionLevel = CompressionLevel.Ultra;
compressor.CompressionMethod = CompressionMethod.Ppmd;
}
It's crashes on this line in the library:
var lockObject = (object) _files ?? _streams;
lock (lockObject) // here in ArchiveUpdateCallback.cs
I see that the file is created but it's corrupt.

I was able to successfully compress file using following code:
public void CompressAndSaveBitmap(Bitmap bitmap)
{
using (MemoryStream memStream = new MemoryStream())
{
using (FileStream file = new FileStream("XYZ", FileMode.Create, System.IO.FileAccess.Write))
{
bitmap.Save(memStream, System.Drawing.Imaging.ImageFormat.Bmp);
// tried these but they don't work.
//memStream.Seek(0, 0);
//memStream.Position = 0;
SevenZipCompressor compressor =
new SevenZipCompressor
{
CompressionLevel = CompressionLevel.Ultra,
CompressionMethod = CompressionMethod.Lzma
};
compressor.CompressStream(memStream, file); // throws error here
}
}
}
Following was the bitmap file:
Executed code:
Bitmap bmp = new Bitmap("Test.bmp");
res.CompressAndSaveBitmap(bmp);
After execution got following output:
Opened the file with WinRar and extracted file:
In folder found the extracted image:
UPDATE:
I think the only problem with OP's code is this.compressor is not initialized.

Byte array getting corrupted when passed to another method

I have a bunch of Jpg images in byte array form. I want to add these to a zip file, turn the zip file into a byte array, and pass it to somewhere else. In a method, I have this code:
var response = //some response object that will hold a byte array
using (var ms = new MemoryStream())
{
using (var zipArchive = new ZipArchive(ms, ZipArchiveMode.Create, true))
{
var i = 1;
foreach (var image in images) // some collection that holds byte arrays.
{
var entry = zipArchive.CreateEntry(i + ".jpg");
using (var entryStream = entry.Open())
using (var compressStream = new MemoryStream(photo.ImageOriginal))
{
compressStream.CopyTo(entryStream);
}
i++;
}
response.ZipFile = ms.ToArray();
}
using (var fs = new FileStream(#"C:\Users\MyName\Desktop\image.zip", FileMode.Create))
{
ms.Position = 0;
ms.CopyTo(fs);
}
}
return response;
Now, I've added a filestream near the bottom to write it to a zipfile right away for testing purposes. This works, I get a zip file with 1 or more images in it on my desktop. However: response.ZipFile can not be made into a valid zipfile in the same way. I have tried this:
using (var ms2 = new MemoryStream(response.ZipFile))
using (var fs = new FileStream(#"C:\Users\Bara\Desktop\image.zip", FileMode.Create))
{
ms2.Position = 0;
ms2.CopyTo(fs);
}
But that creates a zipfile that can not be opened.
What I'm trying to do: turn response.ZipFileinto an array that can be turned into a working zipfile again. What am I doing wrong in this code?

How do you know that ZipArchive's Dispose doesn't write more to the underlying stream?
You should move this line to be after disposing the ZipArchive:
response.ZipFile = ms.ToArray();
Full code:
var response = //some response object that will hold a byte array
using (var ms = new MemoryStream())
{
using (var zipArchive = new ZipArchive(ms, ZipArchiveMode.Create, true))
{
var i = 1;
foreach (var image in images) // some collection that holds byte arrays.
{
var entry = zipArchive.CreateEntry(i + ".jpg");
using (var entryStream = entry.Open())
using (var compressStream = new MemoryStream(photo.ImageOriginal))
{
compressStream.CopyTo(entryStream);
}
i++;
}
}
response.ZipFile = ms.ToArray();
}
return response;

Zip package with Unicode chars in file name can't be uncompressed with System.IO.Packaging.Package?

Have some troubles with file package manipulation.
Here is short description of issue:
If a package contains a file with Unicode characters in it, compressing of it works well(can open package and be uncompressed it in windows) but if try to use this Package.Open(.., FileMode.Open), it results in error "File contains corrupted data".
Question: What am i doing wrong? Can't figure this out. Please advise.
Here is code for compressing and uncompromising binary data in-memory that i use:
public virtual byte[] UnZipFile(byte[] data, string packageFileName)
{
using (var inputStream = new MemoryStream(data))
{
using (var package = Package.Open(inputStream, FileMode.Open))
{
var fileUri = PackUriHelper.CreatePartUri(new Uri(#"/" + packageFileName, UriKind.Relative));
using (var outputStream = new MemoryStream())
{
using (var partStream = package.GetPart(fileUri).GetStream())
{
partStream.CopyTo(outputStream);
}
return outputStream.ToArray();
}
}
}
}
public virtual byte[] ZipFile(byte[] data, string packageFileName)
{
using (var outMs = new MemoryStream())
{
using (var package = Package.Open(outMs, FileMode.Create))
{
var fileUri = PackUriHelper.CreatePartUri(new Uri(#"/" + packageFileName, UriKind.Relative));
var contentType = #"data/" + packageFileName.Substring(packageFileName.LastIndexOf(".", StringComparison.Ordinal) + 1);
using (var zipStream = package.CreatePart(fileUri, contentType, CompressionOption.Normal).GetStream())
{
using (var ms = new MemoryStream(data))
{
ms.CopyTo(zipStream);
}
}
}
return outMs.ToArray();
}
}

solved by using newer lib, System.IO.Compression, thanks for pointing out this #Hans Passant