For example I have a UserControl like this:
<UserControl x:Class="SMPlayer.ScrollingTextBlock">
<ScrollViewer
x:Name="TextScrollViewer"
HorizontalScrollBarVisibility="Hidden"
PointerEntered="TextScrollViewer_PointerEntered"
VerticalScrollBarVisibility="Disabled">
<StackPanel>
<TextBlock x:Name="NormalTextBlock" />
<TextBlock x:Name="PointerOverTextBlock" Visibility="Collapsed" />
</StackPanel>
</ScrollViewer>
</UserControl>
I want this UserControl still to be treated as a normal TextBlock. For example <ScrollingTextBlock Text="Something"/>. It is just a TextBlock with more functionalities, or in other words, another control that inherits from TextBlock. Because there are a lot of properties, I don't want to do this manually by adding DependencyProperty and do things like public string Text { get; set; }. It is just too much work.
How can I achieve that? I think this question might have been asked but I am not sure how to properly paraphrase it.
If you want to implement <ScrollingTextBlock Text="Something"/> in UserControl, you still need to add DependencyProperty to achieve it.
If you want your control to "be treated as a normal TextBlock", then you don't have any other choice than inheriting from TextBlock. This is what inheritance is for.
Otherwise you indeed have to add properties to your UserControl and bind them by yourself, even though this is a lot of work this is due to the poor flexibility of the UserControl. You cannot have a Text property on an object unless it inherits from a TextBlock or you add it yourself.
Alternatively you can use templating to re-template a ContentControl like this:
public class ScrollingContent : ContentControl { }
<Window.Resources>
<Style TargetType="local:ScrollingContent">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="local:ScrollingContent">
<ScrollViewer
x:Name="TextScrollViewer"
HorizontalScrollBarVisibility="Hidden"
VerticalScrollBarVisibility="Disabled">
<StackPanel>
<TextBlock x:Name="NormalTextBlock" />
<ContentPresenter></ContentPresenter>
</StackPanel>
</ScrollViewer>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
<Grid>
<local:ScrollingContent>
<TextBlock Text="Whatever control I want" Foreground="Red"></TextBlock>
</local:ScrollingContent>
</Grid>
But then again, your control is not really a TextBlock.
Related
Given I have a control from somewhere called SomeControl
In MyUserControl.xaml I use SomeControl like so:
<Grid.Resources>
<Window.Resources>
<Style TargetType="local:SomeControl">
<Setter Property="ToolTip">
<Setter.Value>
<ToolTip>
<TextBlock Text="FOO"/>
</ToolTip>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
</Grid.Resources>
<Grid>
<!-- Others controls in here -->
<local:SomeControl />
</Grid>
In Window.xaml:
<Window.Resources>
<Style TargetType="local:SomeControl">
<Setter Property="ToolTip">
<Setter.Value>
<ToolTip>
<TextBlock Text="BAR"/>
</ToolTip>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
<Grid>
<local:MyUserControl />
</Grid>
The result is it will display Foo when I want it to display Bar.
If I delete the ToolTip from the UserControl, the Window's style is used and it displays Bar like I expect.
Why is the Window style not overriding the UserControl explicit ToolTip property when present, but does when removed?
For the record, I've also tried changing MyUserControl to use a DynamicResource of the same x:Key names and had no affect.
Changing both to ToolTipService.ToolTip also had the same results.
EDIT: I fixed the example to demonstrate that even if the ToolTip is not set on a local level, it still doesn't override the style.
Unless someone can answer how to do override the children's style for the tooltip, I ended up making ToolTip object a dependency property on MyUserControl and passing it down to SomeControl.
The dependency property I made is called ExampleToolTip
MyUserControl.xaml:
<UserControl x:Name='MainControl'>
<UserControl.Resources>
<ToolTip x:Key="DefaultSomeControlToolTip">
<TextBlock Text="FOO"/>
<ToolTip>
</UserControl.Resources>
<Grid>
<local:SomeControl ToolTip="{Binding ExampleToolTip, ElementName=MainControl, TargetNullValue={StaticResource DefaultSomeControlToolTip}}"/>
</Grid>
</UserControl>
Window.xaml:
<Grid>
<local:MyUserControl>
<local:MyUserControl.ExampleToolTip>
<ToolTip>
<TextBlock Text="BAR"/>
</ToolTip>
</local:MyUserControl.ExampleToolTip>
</local:MyUserControl>
</Grid>
Now I can use MyUserControl with it's special "FOO" tooltip on SomeControl and Window has its "BAR" tooltip overriding it.
I have a ContentControl which will not display any XAML from its DataTemplate, and I feel certain that the problem I'm facing will be obvious for those with better WPF codemancy than myself. I have substituted "Object" for my object name where appropriate for confidentiality reasons.
In my MainWindow.xaml I have this:
<ContentControl x:Name="ObjectDetailView"
Margin="20,20,20,20" Grid.Row="2" Grid.Column="1"
DataContext="{Binding SelectedItem, ElementName=ObjectListView}"
Template="{DynamicResource DetailControlTemplate}"
ContentTemplate="{DynamicResource DetailDataTemplate}"/>
I keep my templates in separate files to keep code readable. The template is in a DataResources.xaml file that is being successfully used for the ListView. The code for the content/template in question is:
<ControlTemplate x:Key="DetailControlTemplate">
<Border Style="{StaticResource ObjectDetailBorderStyle}">
<ContentPresenter/>
</Border>
</ControlTemplate>
<DataTemplate x:Key="DetailDataTemplate" DataType="{x:Type model:Object}">
<!-- Valid XAML -->
</DataTemplate>
In my Designer (both in VS and Blend) The border/background gradient displays, but nothing further. Same for the running program.
If I move the <!-- Valid XAML --> into the Control Template, it displays fine, but I don't believe that's kosher, and I also don't believe that the data-binding will work that way. Please correct me if I'm wrong.
ObjectListView is a ListView populated dynamically from my VM, and I'm using MVVM. That all works just fine. I'd prefer this ContentControl only appears once there is a valid selected object in the list view, but that's UX sugar at this point, thus my only concern is to get this content control displaying my model's data.
I'm also fairly new to StackOverflow, so if I missed anything or made an error in posting this question, please let me know. I've not had luck with searching for this issue over the last few hours, as I don't want to waste your time.
Two things. You did not set the actual Content of the ContentControl, but only its DataContext. You should instead write this:
<ContentControl ...
Content="{Binding SelectedItem, ElementName=ObjectListView}"
Template="{DynamicResource DetailControlTemplate}"
ContentTemplate="{DynamicResource DetailDataTemplate}"/>
And your ControlTemplate is missing a TargetType:
<ControlTemplate x:Key="DetailControlTemplate" TargetType="ContentControl">
<Border Style="{StaticResource ObjectDetailBorderStyle}">
<ContentPresenter/>
</Border>
</ControlTemplate>
Without the TargetType, the ContentPresenter's properties aren't set by default, and you would have to set them explicitly like
<ControlTemplate x:Key="DetailControlTemplate">
<Border Style="{StaticResource ObjectDetailBorderStyle}">
<ContentPresenter
Content="{Binding Content,
RelativeSource={RelativeSource TemplatedParent}}"
ContentTemplate="{Binding ContentTemplate,
RelativeSource={RelativeSource TemplatedParent}}"/>
</Border>
</ControlTemplate>
I'm a bit beginner in WPF, so I ask this..
Let's say I have a window, and inside the window I want to have something like container, could be just border or maybe panel (in winform terms). The content of container is binded to the selected option (e.g:button). So, for instance, when user selects OPTION 1, the container shows chart; when user selects OPTION 2, the container shows listview filled with data; when user selects OPTION 3, the container shows another things, and so on.
What is the best/nicest (or easiest maybe) approach to do this? I'm thinking about using user control for the content of the container, but don't know if this is nice solution neither the performance for using user control to show little bit complex things and maybe some calculations. Any other idea guys?
To elaborate on #Sheridan's answer, here is a simple TabControl XAML that does what you need:
<TabControl TabStripPlacement="Left">
<TabItem Header="Option 1">
<Grid Background="DarkGray">
<TextBlock Foreground="AliceBlue" VerticalAlignment="Center" HorizontalAlignment="Center" FontSize="20" Text="View 1"/>
</Grid>
</TabItem>
<TabItem Header="Option 2">
<Grid Background="DarkBlue">
<TextBlock Foreground="AliceBlue" VerticalAlignment="Center" HorizontalAlignment="Center" FontSize="20" Text="View 2"/>
</Grid>
</TabItem>
<TabItem Header="Option 3">
<Grid Background="DarkSlateBlue">
<TextBlock Foreground="AliceBlue" VerticalAlignment="Center" HorizontalAlignment="Center" FontSize="20" Text="View 3"/>
</Grid>
</TabItem>
</TabControl>
Result:
You can customize it a little bit by adding this simple Style To your Window.Resources:
<Window.Resources>
<Style TargetType="TabItem">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate TargetType="TabItem">
<RadioButton Content="{TemplateBinding Header}" Margin="2"
IsChecked="{Binding IsSelected, RelativeSource={RelativeSource TemplatedParent}, Mode=TwoWay}"/>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</Window.Resources>
Which then results in:
The "WPF Mentality" makes you think the UI controls in terms of their functionality, not their appearance, this is a TabControl =)
I solved this with a ContentControl
MainWindow:
(Define the views you wish to visualize as resources)
<Window.Resources>
<DataTemplate DataType="{x:Type viewModels:SystemPCViewModel}">
<controls:SystemPCControl/>
</DataTemplate>
<DataTemplate DataType="{x:Type viewModels:ChipPCViewModel}">
<controls:ChipPCControl/>
</DataTemplate>
</ResourceDictionary>
</Window.Resources>
<Grid>
<ContentControl Content="{Binding CurrentView}"/>
</Grid>
ViewModel: (can't get much simpler)
public ViewModelBase CurrentView
{
get { return currentView; }
set { Set(() => CurrentView, ref currentView, value); }
}
And there you go, you can change your views by setting the view model for the controls you defined in your MainWindow
private void OnCommandExecuted()
{
CurrentView = someViewModel;
}
private void OnAnotherCommandExecuted()
{
CurrentView = anotherViewModel;
}
HTH!
What you are describing sounds pretty close to a standard TabControl, but with a ControlTemplate that puts the tabs on the left side instead of above the content panel. Using this method would mean having a UserControl in each TabItem, eg. multiple controls. You can find out more about the TabControl from the TabControl Class page at MSDN.
Is there some way to apply styles to the first (or last or nth) child of a container (anything that contains children)? I am trying to customize the look of tab items so that the first one has different border radius than the others.
This is what I have now:
<ControlTemplate TargetType="{x:Type TabItem}">
<Grid>
<Border Name="Border" BorderBrush="#666" BorderThickness="1,1,1,0" CornerRadius="8,8,0,0" Margin="0,0,0,-1">
<TextBlock x:Name="TabItemText" Foreground="#444" Padding="6 2" TextOptions.TextFormattingMode="Display">
<ContentPresenter x:Name="ContentSite" VerticalAlignment="Center" HorizontalAlignment="Center" ContentSource="Header" Margin="12,2,12,2"/>
</TextBlock>
</Border>
</Grid>
</ControlTemplate>
For ItemsControl derived classes (such as TabControl), you can use the ItemContainerStyleSelector dependency property. When this dependency property is set, ItemsControl will call StyleSelector.SelectStyle() for each item in the control. This will allow you to use different styles for different items.
The following example changes the last tab item in a TabControl so its text is bold and a bit larger than the other tabs.
First, the new StyleSelector class:
class LastItemStyleSelector : StyleSelector
{
public override Style SelectStyle(object item, DependencyObject container)
{
var itemsControl = ItemsControl.ItemsControlFromItemContainer(container);
var index = itemsControl.ItemContainerGenerator.IndexFromContainer(container);
if (index == itemsControl.Items.Count - 1)
{
return (Style)itemsControl.FindResource("LastItemStyle");
}
return base.SelectStyle(item, container);
}
}
This style selector will return the style with the key "LastItemStyle" but only for the last item in the control. The other items will use the default style. (Note, that this function only uses members from ItemsControl. It could also be used for other ItemsControl derived classes.) Next, in your XAML, you first need to create two resources. The first resource will be to this LastItemStyleSelector and the second resource is the style.
<Window.Resources>
<local:LastItemStyleSelector x:Key="LastItemStyleSelector" />
<Style x:Key="LastItemStyle" TargetType="TabItem">
<Setter Property="FontWeight" Value="Bold" />
<Setter Property="FontSize" Value="16" />
</Style>
</Window.Resources>
Then finally your TabControl:
<TabControl ItemContainerStyleSelector="{StaticResource LastItemStyleSelector}">
<TabItem Header="First" />
<TabItem Header="Second" />
<TabItem Header="Third" />
</TabControl>
For more information see the MSDN documentation:
ItemsControl.ItemContainerStyleSelector Property
StyleSelector Class
Unlike HTML and CSS, there's not a simple way to determine and trigger that type of change.
You could potentially write a trigger and use a value converter to do something like that using this forum post as inspiration potentially.
Much simpler would be to apply a custom style to the tabitem that you want to look different. Have you tried that?
<TabItem Header="TabItem" Style="{DynamicResource FirstTabStyle}">
<Grid Background="#FFE5E5E5"/>
</TabItem>
I'm trying to have a custom control that requires 2 or more areas of the XAML to be defined by a child control - that inherits from this control. I'm wondering if there's a way to define multiple contentpresenters and one which acts as the default content presenter
<MyControl>
<MyControl.MyContentPresenter2>
<Button Content="I am inside the second content presenter!"/>
</MyControl.MyContentPresenter2>
<Button Content="I am inside default content presenter" />
</MyControl>
Is this possible, how do I define this in the custom control's template?
The template can just bind the separate ContentPresenter instances like this (I've only set one property here but you'll likely want to set others):
<ContentPresenter Content="{TemplateBinding Content1}"/>
<ContentPresenter Content="{TemplateBinding Content2}"/>
The control itself should expose two properties for content and set the default using the ContentPropertyAttribute:
[ContentProperty("Content1")]
public class MyControl : Control
{
// dependency properties for Content1 and Content2
// you might also want Content1Template, Content2Template, Content1TemplateSelector, Content2TemplateSelector
}
You can use an "ItemsControl" with a custom template.
<ItemsControl>
<ItemsControl.Style>
<Style TargetType="ItemsControl">
<Setter Property="Template">
<Setter.Value>
<ControlTemplate>
<StackPanel Orientation="Horizontal">
<ContentControl Content="{Binding RelativeSource={RelativeSource TemplatedParent}, Path=Items[0]}"/>
<ContentControl Content="{Binding RelativeSource={RelativeSource TemplatedParent}, Path=Items[1]}"/>
<ContentControl Content="{Binding RelativeSource={RelativeSource TemplatedParent}, Path=Items[2]}"/>
</StackPanel>
</ControlTemplate>
</Setter.Value>
</Setter>
</Style>
</ItemsControl.Style>
<TextBlock Text="Item 1"/>
<TextBlock Text="Item 2"/>
<TextBlock Text="Item 3"/>
</ItemsControl>
Here's another option that doesn't require making a custom control and is more typesafe than doing the ItemsControl thing (if type safety is something you want..perhaps not):
...Use an attached property!
Create an attached property of the appropriate type. We happened to need a text control so I did a string TextContent attached property. Then create a TemplateBinding to it from the template, and when instantiating in Xaml set it there as well. Works nicely.