I have a XML file which looks like:
<?xml version="1.0" encoding="UTF-8" standalone="no" ?>
<UFCC xmlns="http://actel.com/sweng/afi">
<Region name="Region_0_0">
<content>
<static_data>
<fixed>
<value>11111111111111111111111111111111</value>
<type>HEX</type>
</fixed>
</static_data>
</content>
<region_start_word>0</region_start_word>
<number_of_word>16</number_of_word>
<simulation_value>
<value>11111111111111111111111111111111</value>
<type>HEX</type>
</simulation_value>
</Region>
<Region name="Region_1_0">
<content>
<static_data>
<fixed>
<value>BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB</value>
<type>HEX</type>
</fixed>
</static_data>
</content>
<region_start_word>16</region_start_word>
<number_of_word>16</number_of_word>
<simulation_value>
<value>BBBBBBBBBBBBBBBBBBBBBBBBBBBBBBBB</value>
<type>HEX</type>
</simulation_value>
</Region>
<Program_Pages/>
</UFCC>
I'm trying to change value fields "11111111111111111111111111111111" to "A...A". I have tried this with Xml.Linq and using examples found online, from which none seem to work.
How can I modify these fields?
Sorry about the formatting, I'm not that familiar with proper XML formatting and the source file is written in single line.
You need to use the namespace :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement root = doc.Root;
XNamespace ns = root.GetDefaultNamespace();
List<XElement> values1s = doc.Descendants(ns + "value").Where(x => (string)x == "11111111111111111111111111111111").ToList();
foreach (XElement x in values1s)
{
x.SetValue(((string)x).Replace("1", "A"));
}
}
}
}
Related
string content = ....
I have some XML content stored in a string as shown in the variable above. The content stored is similar to below ,
<?xml version="1.0"?>
<model xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Items>
<ItemModel xsi:type="TypeKeep">
<Name>Name01</Name>
</ItemModel>
<ItemModel xsi:type="TypeDelete">
<Name>Name02</Name>
</ItemModel>
<ItemModel xsi:type="TypeDelete">
<Name>Name03</Name>
</ItemModel>
</Items>
</model>
In here I want to remove all the elements which have the type="TypeDelete" . In the sense I am trying to alter the content variable by removing the elments of TypeDelete
Any idea how I can achieve this ?
Using xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
using System.IO;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
string xml = File.ReadAllText(FILENAME);
XDocument doc = XDocument.Parse(xml);
XNamespace xsiNs = doc.Root.GetNamespaceOfPrefix("xsi");
List<XElement> removeNodes = doc.Descendants("ItemModel").Where(x => (string)x.Attribute(xsiNs + "type") == "TypeDelete").ToList();
for (int i = removeNodes.Count - 1; i >= 0; i--)
{
removeNodes[i].Remove();
}
}
}
}
If you want to remove a specific XML node from an XML file directly you can go through this link and try this
I have this XML:
<?xml version="1.0" encoding="UTF-8"?>
<LayerDefinition version="1.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="LayerDefinition-1.0.0.xsd">
<VectorLayerDefinition>
<ResourceId>ddddd</ResourceId>
<FeatureName>SHP_Schema:HydrographicPolygons</FeatureName>
<FeatureNameType>FeatureClass</FeatureNameType>
<Geometry>SHPGEOM</Geometry>
<VectorScaleRange>
<AreaTypeStyle>
<AreaRule>
<LegendLabel/>
<AreaSymbolization2D>
<Fill>
<FillPattern>Solid</FillPattern>
<ForegroundColor>FFABC7E9</ForegroundColor>
<BackgroundColor>FF000000</BackgroundColor>
</Fill>
<Stroke>
<LineStyle>Solid</LineStyle>
<Thickness>0</Thickness>
<Color>FFABC7E9</Color>
<Unit>Inches</Unit>
</Stroke>
</AreaSymbolization2D>
</AreaRule>
</AreaTypeStyle>
</VectorScaleRange>
</VectorLayerDefinition>
</LayerDefinition>
I need to change this element:
<BackgroundColor>FF000000</BackgroundColor>
To this:
<BackgroundColor>FFFFAAAA</BackgroundColor>
Here is the way I try to do it:
XmlDocument doc = new XmlDocument();
doc.LoadXml(layoutXml);
XmlNodeList objNodeList = doc.SelectNodes("VectorLayerDefinition/VectorScaleRange/BackgroundColor");
objNodeList.InnerXml = "FFFFAAAA";
But the code above dosent works.What I do wrong here why the attitude not works?
Using xml linq :
using System;
using System.Collections.Generic;
using System.Collections;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication75
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XNamespace ns = doc.Root.GetDefaultNamespace();
XElement backgrounColor = doc.Descendants(ns + "BackgroundColor").FirstOrDefault();
backgrounColor.SetValue("FFFFAAAA");
}
}
}
I don't think you are going far enough down in your nodes. I think you need something more like this.
XmlNodeList objNodeList = doc.SelectNodes("VectorLayerDefinition/VectorScaleRange/AreaTypeStyle/AreaRule/AreaSymbolization2D/Fill");
objNodeList.selectSingleNode("BackgroundColor").innerXml= "FFFFAAAA";
Other wise your are trying to get a node inside VectorScaleRange that does not exist. Also you need the selectSingleNode() fucntion to grab the BackGroundColor node out of the list of nodes inside Fill.
Edited with the answer to your problem
XmlDocument doc = new XmlDocument();
doc.Load("texto.xml");
XmlNodeList objNodeList = doc.SelectNodes("/LayerDefinition/VectorLayerDefinition/VectorScaleRange/AreaTypeStyle/AreaRule/AreaSymbolization2D/Fill");
objNodeList.Item(0).SelectSingleNode("BackgroundColor").InnerXml = "FFFFAAAA";
doc.Save("texto.xml");
I have made a web api with C# and an ssms table. The result is an xml with only elements.
//This is only an example
<?xml version="1.0" encoding="UTF-8"?>
<note>
<to>Tove</to>
<from>Jani</from>
<heading>Reminder</heading>
<body>Don't forget me this weekend!</body>
</note>
How can I format my xml as nested like this and add an optional different header from ssms table element??:
<?xml version="1.0" encoding="UTF-8"?>
<note>
<to>Tove</to>
<example>
<from>Jani
<heading>Reminder</heading>
</from>
<body>Don't forget me this weekend!</body>
</example>
</note>
Use xml linq :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication78
{
class Program
{
static void Main(string[] args)
{
string xml =
"<?xml version=\"1.0\" encoding=\"UTF-8\"?>" +
"<note>" +
"<to>Tove</to>" +
"<from>Jani</from>" +
"<heading>Reminder</heading>" +
"<body>Don't forget me this weekend!</body>" +
"</note>";
XDocument doc = XDocument.Parse(xml);
XElement from = doc.Descendants("from").FirstOrDefault();
XElement heading = doc.Descendants("heading").FirstOrDefault();
XElement body = doc.Descendants("body").FirstOrDefault();
from.Add(heading);
XElement example = new XElement("example", new object[] {from,body});
heading.Remove();
body.Remove();
from.ReplaceWith(example);
}
}
}
If you are creating from scratch
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Data;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication78
{
class Program
{
static void Main(string[] args)
{
string ident = "<?xml version=\"1.0\" encoding=\"UTF-8\"?><note></note>";
XDocument doc = XDocument.Parse(ident);
XElement note = doc.Root;
note.Add(new XElement("to", "Tove"),
new XElement("example", new object[] {
new XElement("from", new object[] {
"Jani", new XElement("heading", "Reminder")
}),
new XElement("body","Don't forget me this weekend!")
})
);
}
}
}
I am developing an application in which I am accessing the word document xml from Microsoft Dynamics CRM and want to replace the fields which were added through XML Mapping pane.
Below is the XML which is retrieved through the OpenXML.
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<w:document xmlns:wpc="http://schemas.microsoft.com/office/word/2010/wordprocessingCanvas" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:o="urn:schemas-microsoft-com:office:office" xmlns:r="http://schemas.openxmlformats.org/officeDocument/2006/relationships" xmlns:m="http://schemas.openxmlformats.org/officeDocument/2006/math" xmlns:v="urn:schemas-microsoft-com:vml" xmlns:wp14="http://schemas.microsoft.com/office/word/2010/wordprocessingDrawing" xmlns:wp="http://schemas.openxmlformats.org/drawingml/2006/wordprocessingDrawing" xmlns:w10="urn:schemas-microsoft-com:office:word" xmlns:w="http://schemas.openxmlformats.org/wordprocessingml/2006/main" xmlns:w14="http://schemas.microsoft.com/office/word/2010/wordml" xmlns:w15="http://schemas.microsoft.com/office/word/2012/wordml" xmlns:wpg="http://schemas.microsoft.com/office/word/2010/wordprocessingGroup" xmlns:wpi="http://schemas.microsoft.com/office/word/2010/wordprocessingInk" xmlns:wne="http://schemas.microsoft.com/office/word/2006/wordml" xmlns:wps="http://schemas.microsoft.com/office/word/2010/wordprocessingShape" mc:Ignorable="w14 w15 wp14"><w:body><w:sdt><w:sdtPr><w:id w:val="1519887787"/><w:placeholder><w:docPart w:val="DefaultPlaceholder_1081868574"/></w:placeholder><w:dataBinding w:prefixMappings="xmlns:ns0='urn:microsoft-crm/document-template/new_candidate/10006/' " w:xpath="/ns0:DocumentTemplate[1]/new_candidate[1]/new_candidatename[1]" w:storeItemID="{2D909ED6-F428-47C5-93D4-89B5709D4B5C}"/><w:text/></w:sdtPr><w:sdtContent><w:p w:rsidR="0055490F" w:rsidRDefault="00F5486B"><w:r><w:t>new_candidatename</w:t></w:r></w:p></w:sdtContent></w:sdt><w:bookmarkStart w:id="0" w:name="_GoBack" w:displacedByCustomXml="prev"/><w:bookmarkEnd w:id="0" w:displacedByCustomXml="prev"/><w:sectPr w:rsidR="0055490F"><w:pgSz w:w="11906" w:h="16838"/><w:pgMar w:top="1701" w:right="1134" w:bottom="1701" w:left="1134" w:header="708" w:footer="708" w:gutter="0"/><w:cols w:space="708"/><w:docGrid w:linePitch="360"/></w:sectPr></w:body></w:document>
In the above XML, there is one field called new_candidatename, which I want to replace with my custom value.
Can anyone please suggest me how do I replace the value using OpenXML?
If you are using c# there is no reason to use openxml. You can use xml linq library.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement t = doc.Descendants().Where(x => x.Name.LocalName == "t").FirstOrDefault();
t.Value = "New Value";
doc.Save(FILENAME);
}
}
}
Assuming I have the following XML files:
Sample1.xml
<?xml version="1.0" encoding="utf-8"?>
<Root>
<NodeA>
<Node1>test1</Node1>
<Node1>test2</Node1>
</NodeA>
</Root>
Sample2.xml
<?xml version="1.0" encoding="utf-8"?>
<Root>
<NodeB>
<Node1>test1</Node1>
<Node1>test2</Node1>
</NodeB>
</Root>
My goal is to deserialize those 2 xml files using one factory method.
For that I have the following generic code:
public static T get<T>() where T : class // class = all reference types
{
string Ttype = typeof(T).Name;
using (var streamReader1 = new StreamReader(directoryPath + #"\Sample1.xml"))
using (var streamReader2 = new StreamReader(directoryPath + #"\Sample2.xml"))
using (var xmlReader ??? = XmlReader.Create(streamReader))
{
...
}
}
Built both xml files with the same root element.
My question is, since the xmlReader create function accepts only 1 stream reader.
How in the name of *, do i read with the xml reader from 2 xmls?
Do I combine 2 streams into 1 and read from 1st bit to the last 1, if so, how?
Thanks in advance,
Montana.
I would do it like this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME1 = #"c:\temp\test.xml";
const string FILENAME2 = #"c:\temp\test2.xml";
static void Main(string[] args)
{
XDocument doc1 = XDocument.Load(FILENAME1);
XElement root1 = (XElement)doc1.FirstNode;
XDocument doc2 = XDocument.Load(FILENAME2);
XElement root2 = (XElement)doc2.FirstNode;
root1.Add(root2.Elements());
}
}
}