Hello so I'm currently developing a program to help me automate the functionality of a python script, after a lot of research I found a way to launch and read the output of the python script to a C# console window but I want to implement a time-based condition for it to stop (close process after 5 minutes for example). My code for opening the process is as followed (credits to the original writer):
var process = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = "C:\\Python27\\python.exe",
Arguments = cmd,
UseShellExecute = false,
RedirectStandardOutput = true,
RedirectStandardError = true,
CreateNoWindow = true
},
EnableRaisingEvents = true
};
process.ErrorDataReceived += Process_OutputDataReceived;
process.OutputDataReceived += Process_OutputDataReceived;
process.Start();
process.BeginErrorReadLine();
process.BeginOutputReadLine();
process.WaitForExit();
Console.Read();
As you can see the process waits for it to be finished but the script can sometimes stall or not function correctly, I would like to add a time based condition to close the process if it's not completed after 5 minutes. I record the time by using the StopWatch class but having trouble targeting the process to close it, 5 different processes of the python script run at once so closing the python process would not be viable. I also use process.WaitForExit(); which waits until the process has finished but like I said above this isn't always the case so it's causing problems with processes never closing.
TL;DR: If process takes longer than 5 minutes to complete -> Force close
Any suggestions please?
Related
Trying to use Process class and it's async features. Couldn't figure out how to read all output from Process before the program exits. Please help!!
Here's my code,
void RunProcess()
{
Process process = new Process
{
StartInfo = new ProcessStartInfo
{
FileName = CmdName,
Arguments = CmdArgs,
CreateNoWindow = true,
WindowStyle = ProcessWindowStyle.Hidden,
RedirectStandardOutput = true,
RedirectStandardError = true,
UseShellExecute = false
}
};
using(process)
{
process.OutputDataReceived += Process_OutputDataReceived;
process.Start();
process.BeginOutputReadLine();
process.WaitForExit(); // Even waiting for exit here.
_logger.Debug("End of process");
}
} // void RunProcess()
void Process_OutputDataReceived(object sender, DataReceivedEventArgs e)
{
if (!String.IsNullOrEmpty(e.Data))
_logger.Debug($"\t{e.Data}");
}
I have a other code that runs for at least another 30 - 45 secs after RunProcess() method is called and done, but don't see the output from my process anywhere in the logs.
If I run the program synchronously, I get all the output. But see no output when run async. Does anyone know what I am doing wrong, please?
(Updating question to make it more clear!)
The code I posted above works, and is minimal ( stripped out validations, classes, etc). I am looking for suggestions on how to make my program stop until full output is captured in log files. Does anyone know if there is a way to make it happen with the combination of WaitForExit and event call like I have in code above, please? It seems the process is completing first and terminating the event handler before it could print the log lines.
Many Thanks in advance!!
You can organize your code a little better. Make some class to contain your process. Take a look at how to do async/await.
Remove the line below and read the output from the process its self instead of delegating it.
process.OutputDataReceived += Process_OutputDataReceived;
How and When to use `async` and `await`
I have created a management application that also allows to quickly access a remote desktop session to remote machines. I need to wait until the process ends, so I can close the VPN connection to the remote server. Everything works fine, except waiting for the process to end.
The following code is being used to start the MSTSC process and wait until it ends:
var process = new Process
{
StartInfo = new ProcessStartInfo("mstsc.exe"),
EnableRaisingEvents = true
};
process.Exited += (o, e) => Console.WriteLine("Process stopped.");
process.Start();
Console.ReadLine();
The Exited event is raised almost immediately after the program starts. When I replace mstsc.exe with notepad.exe everything works as expected. I thought that MSTSC might fork itself and abort the initial process.
But it is possible to wait for MSTSC to end using the following command (from the commandline):
start /wait mstsc.exe
This command doesn't return until I exit the remote desktop session. Given that information I replaced my code with this:
var process = new Process
{
StartInfo = new ProcessStartInfo("cmd.exe"),
Arguments = "/c start /wait mstsc.exe",
EnableRaisingEvents = true
};
process.Exited += (o, e) => Console.WriteLine("Process stopped.");
process.Start();
Console.ReadLine();
This would run CMD.exe and it will issue the start /wait mstsc.exe command. If that ends, the CMD process ends as well and I'm fine (with a nasty workaround, but okay). Unfortunately, this doesn't happen. The CMD process terminates immediately. Somebody knows what I am doing wrong?
process.WaitForExit();
Won't work because mstsc on start opens new copy of itself and closes original.
process.WaitForExit();
process = Process.GetProcessesByName(process.ProcessName).First();
process.WaitForExit();
Will work but it's awful workaround.
Update 1:
It seems that mstsc closes original process but NOT it's output stream!
So you can wait for process StandardOutput to close.
var process = new Process
{
StartInfo = new ProcessStartInfo("mstsc.exe") { UseShellExecute = false, RedirectStandardOutput = true }
};
process.Start();
process.StandardOutput.ReadToEnd(); //This will wait for stream to close.
Or if you don't want to block current thread:
var process = new Process
{
StartInfo = new ProcessStartInfo("mstsc.exe") { UseShellExecute = false, RedirectStandardOutput = true }
};
process.Start();
var outputResultPromise = process.StandardOutput.ReadToEndAsync();
outputResultPromise.ContinueWith(o=> Console.WriteLine("Stream closed"));
Console.ReadLine();
Here is the link at MSDN about starting mstsc,
It might be answer to your problem with mstsc closing immediately after running (raising Exited event). Try changing in Visual Studio target platform to AnyCPU.
Let's say your machine is 64bit Windows, your app is 32bit. The app runs 32bit mstsc. 32bit mstsc detects that Windows is 64bit, tries to close itself and run 64bit mstsc (Exited event is raised at that moment even though mstsc starts GUI window).
Changing target platform solved my issue.
There are multiple MSTSC processes running, so it's difficult to wait for one. What I don't understand is that CMD.EXE can do it when I use the start /wait command.
this worked with me:
process.Start();
Thread.Sleep(2000);
while(getNumProcesses() > 0)
process.WaitForExit();
private static int getNumProcesses()
{
Process[] myProcesses = Process.GetProcessesByName("mstsc");
return myProcesses.Length;
}
You cannot wait for mstsc.exe process. Say exactly, you cannot simply wait for end of remote desktop. When I observed mstsc.exe process by Process Monitor, mstsc passed his work to svchost, mstsc.exe ended, but remote desktop was still run.
But I wrote script for remoting application.
Script remoteCmd.cmd starts remoteApplication, remote machine creates a temp file ( \\tsclient\c..\temp\xxx) and remoteCmd.cmd waits until temp file exists.
See
https://github.com/turzik/WindowsScripts/tree/master/remoteApp
You need to call WaitForExit() after you call Start():
process.Start();
process.WaitForExit();
This overload causes the current thread to wait indefinitely to wait until the process exits. There's also an overload that allows you to specify the number of milliseconds you'd like to wait.
I see several questions about how to launch processes and push data into stdin, but not how to control where their output goes.
First here is my current code, run from a console mode C# application:
// Prepare the process to run
ProcessStartInfo start = new ProcessStartInfo();
// Enter in the command line arguments, everything you would enter after the executable name itself
start.Arguments = " -";
// Enter the executable to run, including the complete path
start.FileName = "doxygen.exe";
// Do you want to show a console window?
start.WindowStyle = ProcessWindowStyle.Normal;
start.CreateNoWindow = false;
start.RedirectStandardInput = true;
start.UseShellExecute = false;
// Run the external process & wait for it to finish
using (Process proc = Process.Start(start))
{
//doxygenProperties is just a dictionary
foreach (string key in doxygenProperties.Keys)
proc.StandardInput.WriteLine(key+" = "+doxygenProperties[key]);
proc.StandardInput.Close();
proc.WaitForExit();
// Retrieve the app's exit code
int exitCode = proc.ExitCode;
}
What happens when I run this is I do not see any new window (though I think I should) and all of doxygen.exe's stdout is printed to my app's console window.
What I would like to happen is one of two things:
Doxygen is launched in a visible window, and I can see its stdout in that window, not in my app's window.
Doxygen is launched in a hidden window, and it's stdout is written to a log file.
How can I achieve these?
In addition, why am I not getting a separate window for the spawned process, and why is the spawned process writing output to my window not its own?
One thing that you can do is use RedirectStandardOutput and instead of using WaitForExit you can use ReadToEnd
ProcessStartInfo start = new ProcessStartInfo();
start.RedirectStandardOutput = true;
//make other adjustments to start
Process p = new Process();
p.StartInfo = start;
p.Start();
string output = p.StandardOutput.ReadToEnd();
and then you can use string output at your leisure
If you want to get output in real-time the p.StandardOutput property has methods that allow you to get the output asynchronously. I don't know all the details to it offhand, I've only used it once before, but there's plenty of literature out there if you search for it.
Also be careful when redirecting both StandardOutput and StandardError at the same time, If they're long enough, it is possible for that to cause deadlocks.
You need to do two things:
1) Indicate that you want the standard output of the process to be directed to your app by setting the RedirectStandardOuput property to true in the process.
2) BEFORE the call to WaitForExit, start capturing the output:
string sOutput = p.StandardOutput.ReadToEnd();
If you do not start reading the output before calling wait for exit, you can encounter a deadlock.
However, it is important to know that standard output will only capture output information, not anything written to the standard error stream of the app.
In order to capture both streams of information, you can hook the process's OutputDataReceived and ErrorDataReceived events and write the event data directly into a log file or store it in a class property for use after the process has completed.
This problem is bizarre. I have never encountered anything like it before.
I am trying to make my program extract a file using 7zip. I have done this before in other programs and it was never too difficult. So I copy and pasted my code in:
Process process = new Process
{
StartInfo =
{
CreateNoWindow = true,
WindowStyle = ProcessWindowStyle.Hidden,
FileName = "7za.exe",
UseShellExecute = false,
ErrorDialog = false,
Arguments = "x -y -o\"" + outputPath +"\" \""+ inputFile +"\"",
RedirectStandardOutput = false,
}
};
process.Start();
Immediately after this code has run my application terminates. It just disappears. It's certainly not meant to! I used the step into function and ran it. As soon as process.Start(); had finished the program closed and returned me into Visual C#. It didn't run any Application.Exit(); or anything, it just went away. There was no error awaiting me in Visual C#.
So I tried adding a MessageBox.Show("Test"); to the end. Ran it in step mode. Did process.Start(); fine, as soon as it executed the MessageBox code it disappeared again. I didn't even click ok in the message box (which showed up for about 0.2 seconds before the application terminated)
Well if this code is in Main() then it will finish when your code is done executing. Can you post the full code where this snippet is contained?
You can wait for the process to finish by including
process.WaitForExit();
Checking the ExitCode might tell you if your process succeeded. And you can always redirect the StandardError to check the output of that too.
process.StartInfo.RedirectStandardError = true;
string error = process.StandardError.ReadToEnd();
Try process.WaitForExit() after process.Start() ...
I'm trying to put together a wrapper around a console application using StandardInput and StandardOutput. I'm getting stuck where the console application would prompt for input such as a password.
I'd like to read from StandardOutput, prompt the user using the read text, and write the user's input back to the console application using its StandardInput. Seems easy enough, here's what I have currently:
Process process = new Process()
{
StartInfo =
{
FileName = "bin\\vpnc.exe",
Arguments = "--no-detach --debug 0",
CreateNoWindow = true,
UseShellExecute = false,
RedirectStandardInput = true,
RedirectStandardOutput = true,
}
};
process.OutputDataReceived += (s, args) =>
{
textBlock1.Dispatcher.Invoke(new Action(() =>
{
textBlock1.Text += args.Data;
}));
};
process.Start();
process.BeginOutputReadLine();
The problem is that BeginOutputReadLine() is doing just that...waiting for a line ending. In this case it just sits, and sits, and sits because there is no line to read...the console application has written out text with no line ending and is waiting for input. Coincidentally, when I manually kill the process the event fires and I get the text.
Is there a way to tell that the process is waiting for StandardInput? Or am I missing a completely obvious way to accomplish the goal?
Unless you need something asynchronous you probably want ReadToEnd.
Here is a list of all StreamReader Methods
process.StandardOutput.BaseStream.BeginRead(...) is a potential substitute for your readline, and that will not wait for a line ending however you'd need to know what terminates the output to figure out when not to start wait for the next chunk of data
As Rune said, you can access directly to the output stream of the process (process.StandardOutput) and read from there (if you don't want to wait until a line break is entered into the console app), but this means that you need to check periodically for new data.
To interact with the application, you can just write to the StandardInput of the process (create a StreamWriter that writes to the process.StandardInput).
A nice sample of writing to it is on the MSDN documentation (http://msdn.microsoft.com/en-us/library/system.diagnostics.process.beginoutputreadline.aspx).
Hope this helps
You need to use the synchronous read method and handle any necessary threading yourself. The below code won't tell you that input is expected, but you will be able to detect that a prompt is displayed.
char[] b = new char[1024];
while (!process.HasExited) {
int c = process.StandardOutput.Read(b, 0, b.Length);
context.Response.Write(b, 0, c);
Thread.Sleep(100);
}