This question already has answers here:
RegEx match open tags except XHTML self-contained tags
(35 answers)
Closed 3 years ago.
I have a string where i want to replace some chars by empty chars inside a string.
For eg my string is :
"<anyKey>2018-10-08T00.00000-07:00</anyKey>"
The regex i use is :
return System.Text.RegularExpressions.Regex.Replace(sb.ToString(), "<{1}[0-9a-zA-Z]*Key>{1}[0-9]{4}-[0-9]{2}-[0-9]{2}(?<timeandzone>T[0-9]{2}.[0-9]{5}-[0-9]{2}:[0-9]{2})</{1}[0-9a-zA-Z]*Key>{1}", "");
So the output i get is empty. It means that my regex is correct and it is replacing it with empty string, but i just want output like :
"<anyKey>2018-10-08</anyKey>"
I just want to find something that starts with "T" inside the tag where "Key" word is there and replace it with "".
Can you tell me what should i change here ?
Update :
I have an XML which is 1000 lines, but it is stored in a String, so in some cases i need to replace this thing.
I usually bury RegEx in the bottom of my toolbox, preferring other more purpose-built tools whenever possible.
With that in mind I would use the DateTime class to accomplish this.
anykeyNode.InnerText = DateTime.Parse(anykeyNode.InnerText).ToShortDateString();
Related
This question already has answers here:
Can I use variables in pattern in Regex (C#)
(2 answers)
Closed 3 years ago.
Is it possible to place a string variable inside a Regex? If so.. how?
I've been playing with regex for 4 hours now and i need just one more thing to finish.
return (new Regex(#"\bA=(\d+[/]\d+)").Match(From).Groups[1].Value.Trim()).ToString();
This line basically gets any fractional number like 42/13 only if it's after "A=" from a string and extracts it.
So here's my question - Is it possible to do something like that:
string variable;
Regex(#"\b"variable"=(\d+[/]\d+)").Match(From).Groups[1].Value.Trim()).ToString();
The idea is to make it so whatever is in variable becomes the regex and for example if in the variable we input D it's now D= now A=.
Thanks in advance.
This is string interpolation. You use the $ operator on your strings to use it. Example
string variable = "hello";
Regex regex = new Regex($#"\b{Regex.Escape(variable)}=(\d+[/]\d+)");
You need to concatenate your strings as usual (+) and prepend # to each string if using backslashes without escaping them. You also don't need to encase / in the character class as [/]. Alternatively, as mentioned by Josh in his answer and Ron Beyer in his comment below your question, you can use interpolation.
#"\b" + variable + #"=(\d+/\d+)"
Additionally, you should use the method Regex.Escape() against your variable to ensure any special characters are escaped (this will prevent your pattern from failing or making incorrect matches) - sanitizing your variable.
This question already has answers here:
Can I use variables in pattern in Regex (C#)
(2 answers)
Closed 3 years ago.
Is it possible to place a string variable inside a Regex? If so.. how?
I've been playing with regex for 4 hours now and i need just one more thing to finish.
return (new Regex(#"\bA=(\d+[/]\d+)").Match(From).Groups[1].Value.Trim()).ToString();
This line basically gets any fractional number like 42/13 only if it's after "A=" from a string and extracts it.
So here's my question - Is it possible to do something like that:
string variable;
Regex(#"\b"variable"=(\d+[/]\d+)").Match(From).Groups[1].Value.Trim()).ToString();
The idea is to make it so whatever is in variable becomes the regex and for example if in the variable we input D it's now D= now A=.
Thanks in advance.
This is string interpolation. You use the $ operator on your strings to use it. Example
string variable = "hello";
Regex regex = new Regex($#"\b{Regex.Escape(variable)}=(\d+[/]\d+)");
You need to concatenate your strings as usual (+) and prepend # to each string if using backslashes without escaping them. You also don't need to encase / in the character class as [/]. Alternatively, as mentioned by Josh in his answer and Ron Beyer in his comment below your question, you can use interpolation.
#"\b" + variable + #"=(\d+/\d+)"
Additionally, you should use the method Regex.Escape() against your variable to ensure any special characters are escaped (this will prevent your pattern from failing or making incorrect matches) - sanitizing your variable.
This question already has answers here:
Regex Match all characters between two strings
(16 answers)
Closed 5 years ago.
I'm trying to parse a text looking for data inside this pattern:
{{([^]+)}}
i.e. any sequence of characters between {{ and }} .
But, when I try to build a Regex object:
Regex _regex = new Regex("{{([^]+)}}", RegexOptions.Compiled);
I got this error:
analysis of "{{([^]+)}}" - Set of [] not terminated....
whatever it means...
Someone has an hint?
The purpose of [^...] is to negate character classes present in the specified list. After the ^ symbol, in order to define a correct regular expression, you should include a set of characters to exclude like, for example [^a]+ (this matches one or more characters that don't include the literal a).
The regex you are attempting to define is probably:
{{\s*([\w]+)\s*}}
Visit this link for trying a working demo.
This is because [^] is not a valid regex, because you need to specify at least one symbol that you wish to exclude.
In order to capture the string up to the closing }} change the expression to this:
{{((?:[^}]|}[^}])*)}}
Demo.
This question already has answers here:
Regex to pick characters outside of pair of quotes
(6 answers)
Closed 7 years ago.
I am new in writing regular expression and I have the following Scenario.
I have a string, like :
string line = "if (true){var data = string.Format(\"something {0} {1}.\", \"is\", \"wrong\");}";
now I need to write a regular expression that just pick the closing curly braces which are not in the double quote
so far I tried this:
"(^(\"[^\"]*\")(}))+"
^(\"[^\"]*\") : I want to Ignore any substring which is inside double quote, AND
(}) : I want to take }
+: for at least 1 occurrence.
But it seems I Did something wrong. Could any one please guide me to sort out where I did the wrong?
Thank you.
You just need these parts of your regex:
(?:\"[^\"]*\")|(})
Regex live here.
This question already has answers here:
Parsing CSV files in C#, with header
(19 answers)
Closed 7 years ago.
i have a semicolon separates string, that contains values of every type. string and date values are in quotations.
Now i have an evil string, where an inner string contains s semicolon, that i need to remove (replace by nothing).
eg:
"Value1";0;"Value2";4711;"Evil; Value";"2015-09-03"
in C#:
string value = "\"Value1\";0;\"Value2\";4711;\"Evil; Value\";\"2015-09-03\""
So how to replace all semicolons, that are in quotations? can anybody help?
Regex is awful at handling delimited strings. It can do it, but it's not often as good of a choice as it first appears. This is one of several reasons why.
Instead, you should use a dedicated delimited string parser. There are (at least) three built into the .Net framework. The TextFieldParser type is one of those, and it will handle this correctly.
You should try this i.e to match only those semicolons which is not preceded by : :
(?<=[^"]);
Here is demo