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Code unable to reference to local directory

The situation is like this:
I am modifying someone's code to download an image file from a shared path. So the person hardcoded the piece of code to be #"\\" + local_path
Since the call is expected to go and download from the shared path \\network\bla\bla\bla, it is fine to get hardcode in this way.
Now my problem come in, I actually need to modify some other parts and test it out in playback mode before I deliver this for actual use. However, my work guideline is not to delete away the #"\\" appended. Because, without the #"\\" the path would not link to the share directory and this changed .dll could not be used for actual activity.
Yet with this, if I were to use playback, the file path will now be \\C:\temp\Images, which will be wrong. My problem now is, how to maintain the ability of the code to link to share path and at the same time create a path local so that the code can reference to.

The UNC path \\localhost\C$\ will access the drive C: on your local computer.

The easiest solution is to simply provide a flag which indicates the type of path you want to create e.g.
public string BuildPath(bool isUnc, params string[] pathParts)
{
var path = Path.Combine(pathParts);
return isUnc ? #"\\" + path : path;
}
...
var uncPath = BuildPath(isUnc: true, "network", "bla", "bla", "bla");
var localPath = BuildPath(isUnc: false, #"C:\", "temp", "images");

How do i access and create txt files in the same directory as the program in c#

http://pastebin.com/DgpMx3Sx
Currently i have this, i need to find a way to make it so that as opposed to writing out the directory of the txt files, i want it to create them in the same location as the exe and access them.
basically i want to change these lines
string location = #"C:\Users\Ryan\Desktop\chaz\log.txt";
string location2 = #"C:\Users\Ryan\Desktop\chaz\loot.txt";
to something that can be moved around your computer without fear of it not working.

If you're saving the files in the same path as the executable file then you can get the directory using:
string appPath = System.IO.Path.GetDirectoryName(System.Reflection.Assembly.GetExecutingAssembly().Location);

Normally you wouldn't do that, mostly because the install path will be found in the Program Files folders, which require Administrative level access to be modified. You would want to store it in the Application Data folder. That way it is hidden, but commonly accessible through all the users.
You could accomplish such a feat by:
string path = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData);
string fullPath = Path.Combine(path, #"NameOfApplication");
With those first two lines you'll always have the proper path to a globally accessible location for the application.
Then when you do something you would simply combine the fullPath and the name of the file you attempt to manipulate with FileStream or StreamWriter.
If structured correctly it could be as simple as:
private static void WriteToLog(string file)
{
string path = Environment.GetFolderPath(Environment.SpecialFolder.ApplicationData);
string fullPath = Path.Combine(path, #"NameOfApplication");
// Validation Code should you need it.
var log = Path.Combine(fullPath, file);
using(StreamWriter writer = new StreamWriter(log))
{
// Data
}
}
You could obviously structure or make it better, this is just to provide an example. Hopefully this points you in the right direction, without more specifics then I can't be more help.
But this is how you can access data in a common area and write out to the file of your choice.

How to give path to an text file in Solution using XDocument?

I want to load a xml document Swedish.xml which exists in my solution. How can i give path for that file in Xamarin.android
I am using following code:
var text = File.ReadAllText("Languages/Swedish.txt");
Console.WriteLine("text: "+text);
But i am getting Exception message:
Could not find a part of the path "//Languages/swedish.txt".
I even tried following lines:
var text = File.ReadAllText("./Languages/Swedish.txt");
var text = File.ReadAllText("./MyProject/Languages/Swedish.txt");
var text = File.ReadAllText("MyProject/Languages/Swedish.txt");
But none of them worked. Same exception message is appearing. Build Action is also set as Content. Whats wrong with the path? Thanks in advance.

Just try with this
string startupPath = Path.Combine(Directory.GetParent(System.IO.Directory.GetCurrentDirectory()).Parent.Parent.FullName, "Languages", "Swedish.txt");
var text = File.ReadAllText(startupPath);

Try...
Environment.GetFolderPath (Environment.SpecialFolder.MyDocuments)+"/Languages/Swedish.txt"

If you mark a file as Content Type, it will be included in the app bundle with the path that you are using within your project file. You can inspect the IPA file (it's just a renamed zip) that is created to verify that this is happening.
var text = File.ReadAllText("Languages/Swedish.txt");
should work. The file path is relative to the root of your application. You need to be sure that you are using the exact same casing in your code that the actual file uses. In the simulator the casing will not matter, but on the device the file system is case sensitive, and mismatched casing will break the app.

I've looked into this before and never found any solution to access files in this way. All roads seem to indicate building them as "content" is a dead end. You can however place them in your "Assets" folder and use them this way. To do so switch the "Content" to "AndroidAsset".
After you have done this you can now access the file within your app by calling it via
var filename = "Sweedish.txt";
string data;
using
(var sr = new StreamReader(Context.Assets.Open(code)))
data = sr.ReadToEnd();
....

Load local HTML file in a C# WebBrowser

In my app I have a WebBrowser element.
I would like to load a local file in it.
I have some questions:
Where to place the HTML file (so that it will also be installed if a user executes the setup)
how to reference the file? (e.g. my guess is the user's installation folder would not always be the same)
EDIT
I've added the HTML file to my project.
And I have set it up so that it gets copied to output folder.
When I check it it is present when run: \bin\Debug\Documentation\index.html
However when I do the following I get a 'Page cannot be displayed' error in the webbrowser element.
I use the following code to try to display the HTML file in the Webbrowser.
webBrowser1.Navigate(#".\Documentation\index.html");

Do a right click->properties on the file in Visual Studio.
Set the Copy to Output Directory to Copy always.
Then you will be able to reference your files by using a path such as #".\my_html.html"
Copy to Output Directory will put the file in the same folder as your binary dlls when the project is built. This works with any content file, even if its in a sub folder.
If you use a sub folder, that too will be copied in to the bin folder so your path would then be #".\my_subfolder\my_html.html"
In order to create a URI you can use locally (instead of served via the web), you'll need to use the file protocol, using the base directory of your binary - note: this will only work if you set the Copy to Ouptut Directory as above or the path will not be correct.
This is what you need:
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Url = new Uri(String.Format("file:///{0}/my_html.html", curDir));
You'll have to change the variables and names of course.

quite late but it's the first hit i found from google
Instead of using the current directory or getting the assembly, just use the Application.ExecutablePath property:
//using System.IO;
string applicationDirectory = Path.GetDirectoryName(Application.ExecutablePath);
string myFile = Path.Combine(applicationDirectory, "Sample.html");
webMain.Url = new Uri("file:///" + myFile);

Note that the file:/// scheme does not work on the compact framework, at least it doesn't with 5.0.
You will need to use the following:
string appDir = Path.GetDirectoryName(
Assembly.GetExecutingAssembly().GetName().CodeBase);
webBrowser1.Url = new Uri(Path.Combine(appDir, #"Documentation\index.html"));

Place it in the Applications setup folder or in a separte folder beneath
Reference it relative to the current directory when your app runs.

Somewhere, nearby the assembly you're going to run.
Use reflection to get path to your executing assembly, then do some magic to locate your HTML file.
Like this:
var myAssembly = System.Reflection.Assembly.GetEntryAssembly();
var myAssemblyLocation = System.IO.Path.GetDirectoryName(a.Location);
var myHtmlPath = Path.Combine(myAssemblyLocation, "my.html");

What worked for me was
<WebBrowser Source="pack://siteoforigin:,,,/StartPage.html" />
from here. I copied StartPage.html to the same output directory as the xaml-file and it loaded it from that relative path.

Windows 10 uwp application.
Try this:
webview.Navigate(new Uri("ms-appx-web:///index.html"));

Update on #ghostJago answer above
for me it worked as the following lines in VS2017
string curDir = Directory.GetCurrentDirectory();
this.webBrowser1.Navigate(new Uri(String.Format("file:///{0}/my_html.html", curDir)));

I have been trying different answers from here, but managed to derive something working, here it is:
1- Added the page in a folder i created at project level named WebPagesHelper
2- To have the page printed by webBrowser Control,
string curDirectory = Path.GetDirectoryName(Assembly.GetExecutingAssembly().GetName().CodeBase);
var uri = new Uri(curDirectory);
string myFile = Path.Combine(uri.AbsolutePath, #"WebPagesHelper\index.html");
Uri new_uri = new Uri(myFile);
i had to get the assembly path, create a first uri to get an absolute path without the 'file://' attached, next i combined this absolute path with a relative path to the page in its folder, then made another URI from the result.
Then pass this to webBrowser URL property webBrowser.URL = new_uri;

Open a text file with WPF

There is a text file that I have created in my project root folder. Now, I am trying to use Process.Start() method to externally launch that text file.
The problem I have got here is that the file path is incorrect and Process.Start() can't find this text file. My code is as follows:
Process.Start("Textfile.txt");
So how should I correctly reference to that text file? Can I use the relative path instead of the absolute path? Thanks.
Edit:
If I change above code to this, would it work?
string path = Assembly.GetExecutingAssembly().Location;
Process.Start(path + "/ReadMe.txt");

Windows needs to know where to find the file, so you need somehow specify that:
Either using absolute path:
Process.Start("C:\\1.txt");
Or set current directory:
Environment.CurrentDirectory = "C:\\";
Process.Start("1.txt");
Normally CurrentDirectory is set to the location of the executable.
[Edit]
If the file is in the same directory where executable is you can use the code like this:
var directory = Path.GetDirectoryName(Assembly.GetEntryAssembly().Location);
var file = Path.Combine(directory, "1.txt");
Process.Start(file);

The way you are doing this is fine. This will find the text file that is in the same directory as your exe and it will open it with the default application (probably notepad.exe). Here are more examples of how to do this:
http://www.dotnetperls.com/process-start
However, if you want to put a path in, you have to use the full path. You can build the full path while only caring about the relative path using the method listed in this post:
http://social.msdn.microsoft.com/Forums/en-US/vbgeneral/thread/e763ae8c-1284-43fe-9e55-4b36f8780f1c
It would look something like this:
string pathPrefix;
if(System.Diagnostics.Debugger.IsAttached())
{
pathPrefix = System.IO.Path.GetFullPath(Application.StartupPath + "\..\..\resources\");
}
else
{
pathPrefix = Application.StartupPath + "\resources\";
}
Process.Start(pathPrefix + "Textfile.txt");
This is for opening a file in a folder you add to your project called resources. If you want it in your project root, just drop off the resources folder in the above two strings and you will be good to go.

You'll need to know the current directory if you want to use a relative path.
System.Envrionment.CurrentDirectory
You could append that to your path with Path
System.IO.Path.Combine(System.Envrionment.CurrentDirectory, "Textfile.txt")

Try using Application.StartupPath path as default path may point to current directory.
This scenario has been explained on following links..
Environment.CurrentDirectory in C#.NET
http://start-coding.blogspot.com/2008/12/applicationstartuppath.html

On a windows box:
Start notepad with the file's location immediately following it. WIN
process.start("notepad C:\Full\Directory\To\File\FileName.txt");