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C# - Convert XML elements to key value pair in a concatenated string

I Have below XML as an input
<Details>
<PAY>
<Mode>xyz</Mode>
<REMARKS>no</REMARKS>
</PAY>
<data>
<Customer>
<Participant>
<Participant1FirstName>aaaa</Participant1FirstName>
<Participant1LastName>zzzz</Participant1LastName>
</Participant>
<Participant>
<Participant2FirstName>bbbb</Participant2FirstName>
<Participant2LastName>yyyy</Participant2LastName>
</Participant>
<Participant>
<Participant3FirstName>cccc</Participant3FirstName>
<Participant3LastName>xxxx</Participant3LastName>
</Participant>
</Customer>
</data>
</Details>
Desired output :
String strOutput = "|Participant1FirstName = aaaa|Participant1LastName = zzzz|; |Participant2FirstName = bbbb|Participant2LastName = yyyy|; |Participant3FirstName = cccc|Participant3LastName = xxxx|"
SO far, I have tried parsing XML string into XDocument, and thinking of using Linq to get the desired output, but don't know the way forward.
Input :
string strXML = "<Details> <PAY> <Mode>xyz</Mode> <REMARKS>no</REMARKS> </PAY> <data> <Customer> <Participant> <Participant1FirstName>aaaa</Participant1FirstName> <Participant1LastName>zzzz</Participant1LastName> </Participant> <Participant> <Participant2FirstName>bbbb</Participant2FirstName> <Participant2LastName>yyyy</Participant2LastName> </Participant> <Participant> <Participant3FirstName>cccc</Participant3FirstName> <Participant3LastName>xxxx</Participant3LastName> </Participant> </Customer> </data></Details>"
XDocument xdoc = new XDocument();
xdoc = XDocument.Parse(strXML);
Edit
Any way I can get desired output from below XML ?
<Details>
<PAY>
<Mode>xyz</Mode>
</PAY>
<data>
<Customer>
<Participant>
<Participant1>
<Participant1FirstName>aaaa</Participant1FirstName>
<Participant1LastName>zzzz</Participant1LastName>
</Participant1>
<Participant2>
<Participant2FirstName>bbbb</Participant2FirstName>
<Participant2LastName>yyyy</Participant2LastName>
</Participant2>
<Participant>
</Customer>
</data>
</Details>

You could do it like this
XDocument xdoc = new XDocument();
xdoc = XDocument.Parse(strXML);
var values = xdoc.Descendants("Participant").Elements()
.Select(x => x.Name + " = " + x.Value).ToList();
string result = string.Join("|", values);

Try following :
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
List<Particapant> participants = doc.Descendants("Participant").Select(x => new Particapant()
{
firstName = (string)x.Elements().FirstOrDefault(),
lastName = (string)x.Elements().LastOrDefault()
}).ToList();
string output = string.Join(";", participants
.Select(x => string.Format("|ParticipantFirstName = {0}|ParticipantLastName = {1}|", x.firstName, x.lastName)));
}
}
public class Particapant
{
public string firstName { get; set; }
public string lastName { get; set; }
}
}

How to extract data from SOAP response in C#

I have following SOAP response. Using my code I could only extract one element.
and then it throws null reference exception error.
How do I extract Item->key and Item->value in to my dictionary in the function in C#?
Following is a part of the function which i use to extract data from.
<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP- ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="urn:Magento" xmlns:ns2="http://xml.apache.org/xml-soap" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<SOAP-ENV:Body>
<ns1:callResponse>
<callReturn SOAP-ENC:arrayType="ns2:Map[2]" xsi:type="SOAP-ENC:Array">
<item xsi:type="ns2:Map">
<item>
<key xsi:type="xsd:string">state</key>
<value xsi:type="xsd:string">processing</value>
</item>
<item>
<key xsi:type="xsd:string">status</key>
<value xsi:type="xsd:string">processing</value>
</item>
<item>
<key xsi:type="xsd:string">protect_code</key>
<value xsi:type="xsd:string">ba8dd7</value>
</item>
<item>
<key xsi:type="xsd:string">shipping_firstname</key>
<value xsi:type="xsd:string">Roshan</value>
</item>
<item>
<key xsi:type="xsd:string">billing_name</key>
<value xsi:type="xsd:string">Roshan India</value>
</item>
<item>
<key xsi:type="xsd:string">shipping_name</key>
<value xsi:type="xsd:string">Roshan India</value>
</item>
<item>
<key xsi:type="xsd:string">order_id</key>
<value xsi:type="xsd:string">2</value>
</item>
</item>
</callReturn>
</ns1:callResponse>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>
The codes,
try
{
XmlDocument xdoc = new XmlDocument();//xml doc used for xml parsing
xdoc.LoadXml(content); // --------> THIS IS WHERE I PASS SOAP RESPONSE
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xdoc.NameTable);
nsmgr.AddNamespace("SOAP-ENV:encodingStyle", "http://schemas.xmlsoap.org/soap/encoding/");
XmlNodeList xNodelst = xdoc.DocumentElement.SelectNodes("//item");
int nodes = xNodelst.Count;
dynamic item;
Dictionary<string, string> items = new Dictionary<string, string>();
foreach (XmlNode xn in xNodelst)
{
XmlNode itemnode = xn["item"];
if (itemnode != null) {
string key = itemnode["key"].InnerText;
string value = itemnode["value"].InnerText;
items.Add(key, value);
}
}
var ss = items;
return "";
}
catch (Exception e) {
return e.Message;
}

The xml has two level of the tag item. So you have to make sure you treat each level of the item tag separately. I used xml linq to get data and put results into a dictionary.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
const string FILENAME = #"c:\temp\test.xml";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
XElement root = doc.Root;
XNamespace ns = root.GetDefaultNamespace();
XElement firstItem = doc.Descendants(ns + "item").FirstOrDefault();
Dictionary<string, string> dictItems = firstItem.Descendants(ns + "item")
.GroupBy(x => (string)x.Element("key"), y => (string)y.Element("value"))
.ToDictionary(x => x.Key, y => y.FirstOrDefault());
}
}
}

I finally managed to make this work. I added all the namespaces in namespace manager variable. And used xPath to navigate through the XML as below,
XmlNodeList xNodelst = xdoc.DocumentElement.SelectNodes("//item[#xsi:type]",nsmgr);
This helped me to resolve my problem. I'm posting this here in case if anyone having similar issue.
Cheers!
string soapString = #"<soapenv:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soapenv=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:urn=""urn:Magento""><soapenv:Header/><soapenv:Body><urn:call soapenv:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/""><sessionId xsi:type=""xsd:string"">"+ssid +#"</sessionId><resourcePath xsi:type=""xsd:string"">sales_order.list</resourcePath><args xsi:type=""xsd:anyType""></args></urn:call></soapenv:Body></soapenv:Envelope>";
HttpResponseMessage response = await PostXmlRequest("http://localhost/M1/api.php", soapString);
string content = await response.Content.ReadAsStringAsync();
XmlDocument xdoc = new XmlDocument();//xml doc used for xml parsing
xdoc.LoadXml(content);
XmlNamespaceManager nsmgr = new XmlNamespaceManager(xdoc.NameTable);
nsmgr.AddNamespace("ns1", "urn:Magento");
nsmgr.AddNamespace("ns2", "http://xml.apache.org/xml-soap");
nsmgr.AddNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");
nsmgr.AddNamespace("xsd", "http://www.w3.org/2001/XMLSchema");
nsmgr.AddNamespace("SOAP-ENV", "http://schemas.xmlsoap.org/soap/envelope/");
nsmgr.AddNamespace("encodingStyle", "http://schemas.xmlsoap.org/soap/encoding/");
XmlNodeList xNodelst = xdoc.DocumentElement.SelectNodes("//item[#xsi:type]",nsmgr);
int nodes = xNodelst.Count;
Dictionary<int, IDictionary> items = new Dictionary<int, IDictionary>();
int n = 0;
foreach (XmlNode xn in xNodelst)
{
XmlNode itemnode = xn;
Dictionary<string, string> itemData = new Dictionary<string, string>();
foreach (XmlNode xn1 in itemnode)
{
string key = xn1["key"].InnerText;
string value = xn1["value"].InnerText;
itemData.Add(key, value);
}
items.Add(n, itemData);
n++;
}
return items;

Read XML NodeList

I am trying to parse an XML response from a REST call. I can read the XML just fine with my stream reader but when I try to select the first node, it brings back nothing. Here is my XML:
<?xml version="1.0" encoding="UTF-8" standalone="true"?>
<slot_meta_data xmlns:ns2="http://www.w3.org/2005/Atom">
<product id="MDP">
<name>MDP</name>
</product>
<product id="CTxP">
<name>CTxP</name>
</product>
<product id="STR">
<name>STR</name>
</product>
<product id="ApP">
<name>ApP</name>
<slot>
<agent_id>-1111</agent_id>
<agent_name>ApP</agent_name>
<index_id>-1</index_id>
<alias>App Alias</slot_alias>
</slot>
</product>
<product id="TxP">
<name>TxP</name>
<slot>
<agent_id>2222</agent_id>
<agent_name>App2</agent_name>
<index_id>-1</index_id>
<alias>App2 Alias</slot_alias>
</slot>
</product>
</slot_meta_data>
Here is my code
string newURL = "RESTURL";
HttpWebRequest request = WebRequest.Create(newURL) as HttpWebRequest;
HttpWebResponse response = request.GetResponse() as HttpWebResponse;
StreamReader reader = new StreamReader(response.GetResponseStream());
XmlDocument xdoc = new XmlDocument();
xdoc.Load(response.GetResponseStream());
XmlNodeList list = xdoc.SelectNodes("/slot_meta_data[#*]");
foreach (XmlNode node in list)
{
XmlNode product = node.SelectSingleNode("product");
string name = product["name"].InnerText;
string id = product["id"].InnerText;
Console.WriteLine(name);
Console.WriteLine(id);
Console.ReadLine();
}
When I debug list, it has a count of 0.

Using xml linq
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication22
{
class Program
{
const string FILENAME = #"c:\TEMP\TEST.XML";
static void Main(string[] args)
{
XDocument doc = XDocument.Load(FILENAME);
var results = doc.Descendants("product").Select(x => new {
name = (string)x.Element("name"),
slot = x.Elements("slot").Select(y => new {
agent_id = (int)y.Element("agent_id"),
agent_name = (string)y.Element("agent_name"),
index_id = (int)y.Element("index_id"),
slot_alias = (string)y.Element("slot_alias")
}).FirstOrDefault()
}).ToList();
}
}
}

How to group XML nodes based on their values in C#

I have my XML as:
<root>
    <element>
        <id>1</id>
        <group>first</group>
    </element>
    <element>
        <id>2</id>
        <group>second</group>
    </element>
    <element>
        <id>3</id>
        <group>first</group>
    </element>
</root>
Is there anyway we can group the nodes with same values like this:
<root>
    <groups name="first">
<element>
        <id>1</id>
        <group>first</group>
     </element>
<element>
        <id>3</id>
        <group>first</group>
    </element>
</groups>
   <groups name="second"><element>
       <id>2</id>
        <group>second</group>
    </element>
</groups>
</root>
Is there a way to group it based on same node values?

I just tested the code below and it matches your results.
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string xml =
"<root>" +
"<element>" +
"<id>1</id>" +
"<group>first</group>" +
"</element>" +
"<element>" +
"<id>2</id>" +
"<group>second</group>" +
"</element>" +
"<element>" +
"<id>3</id>" +
"<group>first</group>" +
"</element>" +
"</root>";
XDocument doc = XDocument.Parse(xml);
var groups = doc.Descendants("element")
.GroupBy(x => (string)x.Element("group"))
.ToList();
XElement newXml = new XElement("root");
foreach(var group in groups)
{
newXml.Add(new XElement("groups", new object[] {
new XAttribute("name", group.Key),
group
}));
}
}
}
}

XPath approach
string val= "first";
XmlDocument doc = new XmlDocument();
doc.Load(Server.MapPath("./Xml/YourXML.xml"));
string text = string.Empty;
XmlNodeList xnl = doc.SelectNodes("/root/groups ");
foreach (XmlNode node in xnl)
{
text = node.Attributes["name"].InnerText;
if (text == val)
{
XmlNodeList xnl = doc.SelectNodes(string.Format("/root/groups [#name='{0}']/element", val));
foreach (XmlNode node2 in xnl )
{
text = text + "<br>" + node2["id"].InnerText;
text = text + "<br>" + node2["group"].InnerText;
}
}
Response.Write(text);
}
or
var nodes = (from n in xml.Descendants("element").
Where(r => r.Parent.Attribute("name").Value == "first")
select new
{
id = (string)n.Element("id").Value,
group = (string)n.Element("group").Value
}).ToList();

Group the elements and build up a new document placing each group in a new <groups> element.
var newDoc = new XDocument(
new XElement("root",
from e in doc.Descendants("element")
group e by (string)e.Element("group") into g
select new XElement("groups",
new XAttribute("name", g.Key),
g
)
)
);

I had to try this in VB. My Group By skills need a lot of practice.
Using this test data
Dim myXML As XElement
myXML = <root>
<element>
<id>1</id>
<group>first</group>
</element>
<element>
<id>2</id>
<group>second</group>
</element>
<element>
<id>3</id>
<group>first</group>
</element>
</root>
this seems to work
Dim newXML As XElement = <root></root>
newXML.Add(From el In myXML.Elements
Order By el.<group>.Value
Group By gn = el.<group>.Value Into g = Group
Select New XElement("Groups", New XAttribute("name", gn), g))
newXML =
<root>
<Groups name="first">
<element>
<id>1</id>
<group>first</group>
</element>
<element>
<id>3</id>
<group>first</group>
</element>
</Groups>
<Groups name="second">
<element>
<id>2</id>
<group>second</group>
</element>
</Groups>
</root>
Similar to other answers.

C# XML Document Error (2,2) deserialize xml and storing to array

Aim:
- Deserialize data from an xml document and storing it as an array.
- Avoiding manually assigning the data to different strings.
- The xml document will be manually generated
public void DeserializeObject(string filename)
{
try
{
XmlSerializer deserializer = new XmlSerializer(typeof(string[]));
FileStream fs = new FileStream(filename, FileMode.Open);
string[] XmlData = (string[])deserializer.Deserialize(fs);
foreach (string p in XmlData)
{
Console.WriteLine(p);
}
}
catch (Exception e)
{
Console.WriteLine(e.Message);
}
}
The XML document is as follows
<?xml version="1.0" encoding="utf-8"?>
<Mapping xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<Products>
<Product>
<software>Seiko</software>
</Product>
<Product>
<hardware>Martina</hardware>
</Product>
</Products>
</Mapping>

Thank you, found this solution
<?xml version="1.0" encoding="utf-8" ?>
<Locations>
<Location Name="Location1" IP="127.0.0.1"></Location>
<Location Name="Location2" IP="127.0.0.1"></Location>
<Location Name="Location3" IP="127.0.0.1"></Location>
<Location Name="Location4" IP="127.0.0.1"></Location>
<Location Name="Location5" IP="127.0.0.1"></Location>
</Locations>
using System.Xml.Linq;
class Program
{
static void Main(string[] args)
{
string[] strarr = GetStringArray("Locations.xml");
foreach (string str in strarr)
{
Console.WriteLine(str);
}
}
public static string[] GetStringArray(string url)
{
XDocument doc = XDocument.Load(url);
var locations = from l in doc.Descendants("Location")
select (string)l.Attribute("Name");
return locations.ToArray();
}
}

Try this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication38
{
class Program
{
static void Main(string[] args)
{
string input =
"<?xml version=\"1.0\" encoding=\"utf-8\"?>" +
"<Mapping xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\">" +
"<Products>" +
"<Product>" +
"<software>Seiko</software>" +
"</Product>" +
"<Product>" +
"<hardware>Martina</hardware>" +
"</Product>" +
"</Products>" +
"</Mapping>";
XDocument doc = XDocument.Parse(input);
var results = doc.Descendants("Product").Select(x =>
x.Elements().Select(y => new { type = y.Name, value = (string)y }).ToList()
).SelectMany(z => z).ToList();
var groups = results.GroupBy(x => x.type).ToList();
}
}
}

You need to generate a class from your sample XML.
You can use the xsd.exe to generate a .xsd and from that create a .cs file.
The you need to add this type to your XmlSerializer
See this answer: Generate C# class from XML
XmlSerializer deserializer = new XmlSerializer(typeof(Mapping)); <- Created class type here.

If all you want to do is get the data form the XML-document as an array of strings, you can use XmlDocument to load in the data
XmlDocument doc = new XmlDocument();
doc.Load("file.xml");
Then you can find the nodes you need using an xPath expression:
XmlNodeList nodelist = doc.SelectNodes(...);