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Reference - What does this regex mean?
(1 answer)
Learning Regular Expressions [closed]
(1 answer)
Closed 2 years ago.
Actually i am just beginer to learn regex but now i have a problem.
Can somebody help me to create regex for the follwing condtions:
Text lenght should be 6
1st character should be in Caps
2nd character should be in lower
3rd character should be numeric
4th character should be in lower again
5th character should be in Caps again
6th character should be in numeric again
But shouldn't contain any special character
You can do it pretty easily.
([A-Z][a-z]\d{1}[a-z][A-Z]\d{1})
Related
This question already has answers here:
Reference - What does this regex mean?
(1 answer)
What do ^ and $ mean in a regular expression?
(2 answers)
Closed 3 years ago.
I've already read this here and I still have got some questions. I will be very grateful if you can help me to solve them. I'm trying to compose a RegEx to verify that a string contains only letters, numbers, underscores and hyphens. Firstly, when I tried to do it (without Google-search) I did this #"[A-Za-z0-9_-]". After I made some research I found that it should be #"^[a-zA-Z0-9_-]$" where:
^ asserts position at start of a line
$ asserts position at the end of a line
My question is why we should insert these symbols? And my other question is why the string "jeffbutt" (with yellow in the screenshot) doesn't match?
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C# Regex Match whole word, with special characters
(2 answers)
Regex whitespace word boundary
(3 answers)
Closed 4 years ago.
I am trying to search 100$ through the RegEx. But unable to find its pattern is as above.
\b100\$\b
However, if the text contains 100$1 then it displays properly.
But I want to do exact search.
Word boundaries only work with word characters, not $. Try using this regex:
\b100\$(?=\s|\$)
This will match 100$, where what follows the $ is either whitespace or the end of the line.
Demo
This question already has answers here:
Regular expression to match characters at beginning of line only
(8 answers)
Closed 7 years ago.
I have a string of type "12.43 some non important stuff", I want to get the number 12.43, but only if it is at exact position, which is 0 in this case.
"\d+" will return 12.43, but it will return it even in case of "hello world 12.43 some non important stuff".
Is there an easy way (maybe not regex even) to get the decimal only if it's on desired position?
You can use ^ (start anchor)
^\d+
If you know a specific position, (say 5th) you can do the following:
^.{4}(\d+)
This question already has answers here:
Strong password regex [duplicate]
(4 answers)
Closed 8 years ago.
How do I write a regular expression for the following
at least 6 characters
at least 1 uppercase
at least 1 lowercase
at least 1 number
at least 1 special character ("#¤%&/( æøå etc.)
I tried the below regex but it isn't working.
^(?=.*\d)(?=.*[a-z])(?=.*[A-Z])(?=.*[#+-?$!]).{8,}$
Below regex would satisfy all of your conditions,
^(?=.{6,})(?=.*?[A-Z])(?=.*?[a-z])(?=.*?\d)(?=.*?\W).*$
DEMO
(?=.{6,}) at least 6 characters
(?=.*?[A-Z]) at least 1 uppercase
(?=.*?[a-z]) at least 1 lowercase
(?=.*?\d) at least 1 number
(?=.*?\W) at least 1 non-word character
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Is it possible to pad integers with zeros using regular expressions?
(2 answers)
Closed 9 years ago.
I am trying to display a code like ABC/DEF/00012 or ABC/EDF/01234 or ABC/DEF/00009
I use RegEx mask \w{3}/\w{3}/?????
The question mark is hard part that I could not figure it out.
Basically, I try to display the code with characters and numbers. I want to automatically add leading zeros on the number.
Byron
Seems that you're trying to match 5 digits at the end:
\w{3}/\w{3}/\d{5}