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I want to create a regular expression to check the following string pattern, I tried following these tutorials but it's still confusing. Any help is appreciated.
Type: In Folder
(T or t)ype(spaces or no space):(spaces or no space)(i or I)n(spaces or multiple space)(f or F)older
So following your desired pattern at the end of your question:
(t|T)ype\s*:\s*(i|I)n\s*(f|F)older
The above pattern should match your string. Mind you, \s* is zero to unlimited spaces, which means it would match on the string you provided even if there were no spaces present; if there will always be at least one space present, you can replace them with \s+
Hope this helps!
(T|t)ype\s*:\s*(I|i)n\s*(f|F)older
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What would be a regex for matching "[d-n]", where n is any number?
i.e.
Test_4_[d-123] - returns ideally only 123
or, if I can return [d-123] I could make some string formatting.
(?<=\[d-)\d+(?=\]) will return 123 from Test_4_[d-123].
You give very little information as to how you want stuff matched.
A very simple solution could be:
\[d-(\d+)\]
From left to right:
\[ will match the literal character [
d- will match just d-
(\d+) will match any digit one or more times. It is in parenthesis, which makes it a capture/match group. This should mean that if you are using a regex tool/library, you should be able to retrieve the "first match group" and you should retrieve just 123.
\] will match the literal character ]
I can only suggest using a website like https://regex101.com/ which can help in creating regular expressions.
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What is the regex for matching a date starting at the 4th position? I want it to return just the date and not the whole match. This is what I have.
^.{4}[2-9][0-9]{3}[0-1][0-9][0-9]{2}
DCSG20170406090204-FQI-046.TOT 04-FIC-046 00060Y000815050.562500G
DCS120170406090204-FQI-045.TOT 04-FIC-045 00060Y000878279.312500G
DCS120170406090204-FQI-046.TOT 04-FIC-046 00060Y000815050.562500G
http://regexr.com/3g0d5
You probably want a non-capturing group:
^(?:.{4})([2-9][0-9]{3}[0-1][0-9][0-9]{2})(?:.*)$
(mouse over the text at: http://regexr.com/3g0db and it will show just one group)
I don't know C#, but from my Perl perspective, I don't see any need for a regular expression. If you just want "the date" and don't need to validate it or separate it into components, just get the substring starting at position 4 (0 based) and 8 characters long.
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I'm trying to use Regex to change my URL from this:
http://localhost:51577/Item/92MM+BLACK+CASE+FAN+W%2f+3+PIN+CONNECTOR+-+Cool+%26+Quiet/222069843383
Into a URL that would look like this:
http://localhost:51577/Item/92MM-BLACK-CASE-FAN-W-2f-3-PIN-CONNECTOR-Cool-26-Quiet/222069843383
Any %, + or +-+ sign would be replaced with - sign using regex. I think regex is the best solution for this, but I'm not so familiar with writing regex expressions... Can someone help me out with this?
Edit: Guys I have an even better idea... I have the Title name in controller in following format:
92MM BLACK CASE FAN W/ 3 PIN CONNECTOR - Cool & Quiet
How could I write an regex to replace white spaces and remove any extra white space (if there are any) in the string array...
Edit 2: Basically replacing any special character with a - sign... Any ideas?
https://msdn.microsoft.com/en-us/library/e7f5w83z(v=vs.110).aspx
Regex.Replace(YOUR_STRING, "[^0-9a-zA-Z]+", "-");
Try that
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I would like to exclude a specific string when it is contained in an expression:
Example:
myurl.htm = exclude
myurl = include
I tried this one : ([a-z0-9]+)(?!.htm)
But looks like it doesn't work.
Try the following:
([a-z0-9]+)(?!^\.htm)
You had two errors in your expression:
You have to escape the dot . with a backslash because it means "matches any character (except newline)" unescaped.
You have to add a ^ to prevent cutting of the last character.
You can test your expression on this website: https://regex101.com/
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I need one white space only in my regular expressen.
How should I create the code that validate if one white space is availabe in the string value?
I'm not sure exactly what you mean but I'm guessing you want to check for exactly one whitespace, but any number of non-whitespace characters:
#"^\S*\s\S*$"
Example code:
Regex regex = new Regex(#"^\S*\s\S*$");
Console.WriteLine(regex.IsMatch("Hello, world!"));
Console.WriteLine(regex.IsMatch("This contains three spaces."));
Console.WriteLine(regex.IsMatch("Two\nlines."));
Output:
True
False
True
Other variations
To check if the string contains exactly one whitespace only (no other characters):
#"^\s$"
To check if the string contains at least one whitespace:
#"\s"