C# implementation of Ascii Minimum Delete Distance - c#

How do you implement the ASCII Minimum Delete Distance in C#?
See description here with a Python solution.
Deletion distance between 2 strings

I derived the C# solution from this Java solution.
https://leetcode.com/articles/minimum-ascii-delete-sum-for-two-strings/#
static void TestAscMinDelDist()
{
List<string[]> l = new List<string[]> {
new string[]{"cat", "at", "99"},
new string[]{"aunt","ant", "117"},
new string[]{"sea", "eat", "231"},
new string[]{"boat", "got", "298"},,
new string[]{"toradol", "tramadol", "317"},
new string[]{"tattoo","platoon", "562"},
new string[]{"delete", "leet", "403"},
new string[]{"flomax", "volmax", "436"},
new string[]{"clozapine", "olanzapine", "522"},
new string[]{"Sam", "Samantha", "524"},
new string[]{"kitten", "sitting", "531" },
new string[]{"sloughs", "thought", "674"}, };
foreach (string[] a in l) {
CalcPrint(a[0], a[1], a[2]);
CalcPrint(a[1], a[0], a[2]);
}
}
static int AsciiMinimumDeleteDistance(String s1, String s2) {
int s1Len = s1.Length, s2Len = s2.Length;
int[,] dp = new int[s1Len + 1, s2Len + 1];
for (int i = s1Len - 1; i >= 0; i--) {
dp[i, s2Len] = dp[i + 1, s2Len] + (int)s1[i]; }
for (int j = s2Len - 1; j >= 0; j--) {
dp[s1Len, j] = dp[s1Len, j+1] + (int)s2[j]; }
for (int i = s1Len - 1; i >= 0; i--) {
for (int j = s2Len - 1; j >= 0; j--) {
if (s1[i] == s2[j]) {
dp[i, j] = dp[i+1, j+1];
} else {
dp[i, j] = Math.Min(dp[i+1, j] + (int)s1[i],
dp[i, j+1] + (int)s2[j]);
}
}
}
return dp[0,0];
}
static void CalcPrint(string s1, string s2, string s3)
{
int cost = AsciiMinimumDeleteDistance(s1, s2);
string result = cost == int.Parse(s3) ? "Passed" : "Failed: Expected: " + s3;
Console.WriteLine($"{s1} -> {s2} {cost} \t {result}");
}

Related

How to append Int array to file horizontally?

I am trying to writ to a file horizontally the best i can do is write them to file vertically.
So Instead of printing to the file
1
2
They print to the file
1 2
Code
int[] test3 = new int[2];
Random randNum3 = new Random();
for (int i = 0; i < test3.Length; i++)
{
test3 = Enumerable.Range(1, 11).OrderBy(x => randNum3.NextDouble()).Take(2).ToArray();
}
int[] b = test3;
int u;
for (int i = 0; i < b.Length; i++)
{
// Console.Write(" " + b[i] + " ");
}
for (int j = 0; j <= b.Length - 2; j++)
{
for (int i = 0; i <= b.Length - 2; i++)
{
if (b[i] > b[i + 1])
{
u = b[i + 1];
b[i + 1] = b[i];
b[i] = u;
}
}
}
System.IO.File.AppendAllLines("C:\\Users\\Gandalf\\Desktop\\log.txt", b.Select(i => i.ToString()).ToArray());
Ok, this will append the text "horizontally", instead of using AppendAllLines, we need to use AppendAllText, and the IEnumerable should be transformed to a string
int[] test3 = new int[11];
Random randNum3 = new Random();
for (int i = 0; i < test3.Length; i++)
{
test3 = Enumerable.Range(1, 11).OrderBy(x =>
randNum3.NextDouble()).Take(2).ToArray();
}
int[] b = test3;
int u;
for (int i = 0; i < b.Length; i++)
{
// Console.Write(" " + b[i] + " ");
}
for (int j = 0; j <= b.Length - 2; j++)
{
for (int i = 0; i <= b.Length - 2; i++)
{
if (b[i] > b[i + 1])
{
u = b[i + 1];
b[i + 1] = b[i];
b[i] = u;
}
}
}
var write = $" {String.Join(" ", b.Select(x => x.ToString()))}";
File.AppendAllText("lines.txt", write);
You need to insert a newline between each value. So
So use this to convert an array to a string:
String.Join(Environment.NewLine, a);

Field methods in C# in the namespace

So the goal of my code is to pick two points in a grid of numbers and figure out with point gets the highest value of numbers when counting every other point in the grid closest to the two points. While typing this code I was trying to use private field variables to hold the current position of both pointers however I receive errors for the field variables I have and any calls that I make into this grid built.
namespace Program
{
private int xMe;
private int yMe;
private int zMe;
private int xEn;
private int yEn;
private int zEn;
private int dif = 0;
public class Castles
{
public static string Process(uint[,] grid)
{
int taxX = 0;
int taxY = 0;
for (int i = 0; i < grid.GetLength; i++)
{
for(int j = 0; j < grid[i]; j++)
{
for(int k = 0; k < grid.GetLength; k++)
{
for(int l = 0; l < grid[k]; l++)
{
if (distance(i, j, k, l) > 3)
{
if (grid[i, j] != 0 && grid[k, l] != 0)
{
for (int m = 0; grid.GetLength; m++)
{
for (int n = 0; grid[m]; n++)
{
if (grid[i, j] != grid[m, n] || grid[k, l] != grid[m, n])
{
if(distance(i,j,m,n) > distance(m, n, k, l))
{
taxX = taxX + distance[m, n];
}
else if(distance(i,j,m,n)< distance(m, n, k, l))
{
taxY = taxY + distance[m, n];
}
else
{
}
}
}
}
if(taxX - taxY > dif)
{
xMe = i;
yMe = j;
xEn = k;
yEn = l;
zMe = taxX;
zEn = taxY;
dif = taxX - taxY;
}
}
}
}
}
}
}
return "Your castle at (" + xMe + "," + yMe + ") earns " + zMe + ". Your nemesis' castle at (" + xEn + "," + yEn + ") earns " + zEn + ".";
}
public int distance(int x, int y, int a, int b)
{
int c = a - x;
int d = b - y;
return Math.Sqrt(c ^ 2 + d ^ 2);
}
static void Main(string[] args)
{
System.Console.WriteLine("");
}
}
}
This is my first exploration into c# so this could be a simple fix but any help would be useful
Just move the definitions of the fields to the inside of the class definition...
namespace Program
{
public class Castles
{
private int xMe;
private int yMe;
private int zMe;
private int xEn;
private int yEn;
private int zEn;
private int dif = 0;
public static string Process(uint[,] grid)
{
int taxX = 0;
int taxY = 0;
for (int i = 0; i < grid.GetLength; i++)
{
for(int j = 0; j < grid[i]; j++)
{
for(int k = 0; k < grid.GetLength; k++)
{
for(int l = 0; l < grid[k]; l++)
{
if (distance(i, j, k, l) > 3)
{
if (grid[i, j] != 0 && grid[k, l] != 0)
{
for (int m = 0; grid.GetLength; m++)
{
for (int n = 0; grid[m]; n++)
{
if (grid[i, j] != grid[m, n] || grid[k, l] != grid[m, n])
{
if(distance(i,j,m,n) > distance(m, n, k, l))
{
taxX = taxX + distance[m, n];
}
else if(distance(i,j,m,n)< distance(m, n, k, l))
{
taxY = taxY + distance[m, n];
}
else
{
}
}
}
}
if(taxX - taxY > dif)
{
xMe = i;
yMe = j;
xEn = k;
yEn = l;
zMe = taxX;
zEn = taxY;
dif = taxX - taxY;
}
}
}
}
}
}
}
return "Your castle at (" + xMe + "," + yMe + ") earns " + zMe + ". Your nemesis' castle at (" + xEn + "," + yEn + ") earns " + zEn + ".";
}
public int distance(int x, int y, int a, int b)
{
int c = a - x;
int d = b - y;
return Math.Sqrt(c ^ 2 + d ^ 2);
}
static void Main(string[] args)
{
System.Console.WriteLine("");
}
}

Counting Sort Implementation in C#

I am implementing counting sort But some thing is wrong with my code
I am new in Programming Please help me to find an error.
I am implenting it step by step .
namespace ConsoleApplication1
{
class Program
{
public static int[] a = { 0,0,0,5,4,8,9,9,7,3, 3, 2, 1 };
public static void Sorting()
{
int j = 0, i = 0, smallestvalue = 0, largestvalue = 0, n = a.Length, lengthof_B = 0, temp = 0, anothersmallestvalue;
smallestvalue = largestvalue = a[0];
for (i = 0; i < n; i++)
{
if (smallestvalue > a[i])
{
smallestvalue = a[i];
}
else if (largestvalue < a[i])
{
largestvalue = a[i];
}
}
int x = anothersmallestvalue = smallestvalue;
lengthof_B = largestvalue - smallestvalue + 1;
int[] b = new int[lengthof_B];
for (i = 0; i < lengthof_B && smallestvalue <= largestvalue; i++)
{
for (j = 0; j < n; j++)
{
if (smallestvalue == a[j])
{
b[i] = b[i] + 1;
}
}
b[i] = temp + b[i];
temp = b[i];
smallestvalue++;
}
int[] c = new int[a.Length];
// I think error here
for (i = n - 1; i >= 0; i--)
{
anothersmallestvalue = x;
for (j = 0; j <= lengthof_B ; j++)
{
if (a[i] == anothersmallestvalue)
{
temp = b[j];
c[temp - 1] = anothersmallestvalue;
b[j] = b[j];
}
anothersmallestvalue++;
}
}
for (i = 0; i < c.Length; i++)
{
Console.WriteLine("c[i] : " + c[i]);
}
}
}
class Demo
{
static void Main(string[] args)
{
Program.Sorting();
Console.ReadLine();
}
}
}
Desired Output is
000123457899
But output of my program is
000120457809
This Is Your Code Here I found a mistake.
And your Code is too complex Please Go through your code Once more.
for (i = n - 1; i >= 0; i--)
{
anothersmallestvalue = x;
for (j = 0; j <= lengthof_B ; j++)
{
if (a[i] == anothersmallestvalue)
{
temp = b[j];
c[temp - 1] = anothersmallestvalue;
b[j] = b[j] -1 ;// Possible Mistake I think here
}
anothersmallestvalue++;
}
}
the very simple and stylish way is described and shown here.
en.wikipedia.org/wiki/Counting_sort#The_algorithm
Normal sorting your two loops should look like this
for (i = 0; i < lengthof_B - 1; i++)
{
for (j = i + 1; j < lengthof_B; j++)
{
}
}​

how can i find lcs length between two large strings

I've written the following code in C# for obtaining the length of longest common subsequence of two texts given by use, but it doesn't work with large strings. Could you please help me. I'm really confused.
public Form1()
{
InitializeComponent();
}
public int lcs(char[] s1, char[] s2, int s1size, int s2size)
{
if (s1size == 0 || s2size == 0)
{
return 0;
}
else
{
if (s1[s1size - 1] == s2[s2size - 1])
{
return (lcs(s1, s2, s1size - 1, s2size - 1) + 1);
}
else
{
int x = lcs(s1, s2, s1size, s2size - 1);
int y = lcs(s1, s2, s1size - 1, s2size);
if (x > y)
{
return x;
}
else
return y;
}
}
}
private void button1_Click(object sender, EventArgs e)
{
string st1 = textBox2.Text.Trim(' ');
string st2 = textBox3.Text.Trim(' ');
char[] a = st1.ToCharArray();
char[] b = st2.ToCharArray();
int s1 = a.Length;
int s2 = b.Length;
textBox1.Text = lcs(a, b, s1, s2).ToString();
}
Here you are using the Recursion method. So it leads the program to occur performance problems as you mentioned.
Instead of recursion, use the dynamic programming approach.
Here is the C# Code.
public static void LCS(char[] str1, char[] str2)
{
int[,] l = new int[str1.Length, str2.Length];
int lcs = -1;
string substr = string.Empty;
int end = -1;
for (int i = 0; i < str1.Length; i++)
{
for (int j = 0; j < str2.Length; j++)
{
if (str1[i] == str2[j])
{
if (i == 0 || j == 0)
{
l[i, j] = 1;
}
else
l[i, j] = l[i - 1, j - 1] + 1;
if (l[i, j] > lcs)
{
lcs = l[i, j];
end = i;
}
}
else
l[i, j] = 0;
}
}
for (int i = end - lcs + 1; i <= end; i++)
{
substr += str1[i];
}
Console.WriteLine("Longest Common SubString Length = {0}, Longest Common Substring = {1}", lcs, substr);
}
Here is a solution how to find the longest common substring in C#:
public static string GetLongestCommonSubstring(params string[] strings)
{
var commonSubstrings = new HashSet<string>(strings[0].GetSubstrings());
foreach (string str in strings.Skip(1))
{
commonSubstrings.IntersectWith(str.GetSubstrings());
if (commonSubstrings.Count == 0)
return string.Empty;
}
return commonSubstrings.OrderByDescending(s => s.Length).DefaultIfEmpty(string.Empty).First();
}
private static IEnumerable<string> GetSubstrings(this string str)
{
for (int c = 0; c < str.Length - 1; c++)
{
for (int cc = 1; c + cc <= str.Length; cc++)
{
yield return str.Substring(c, cc);
}
}
}
I found it here: http://www.snippetsource.net/Snippet/75/longest-common-substring
Just for fun, here is one example using Queue<T>:
string LongestCommonSubstring(params string[] strings)
{
return LongestCommonSubstring(strings[0], new Queue<string>(strings.Skip(1)));
}
string LongestCommonSubstring(string x, Queue<string> strings)
{
if (!strings.TryDequeue(out var y))
{
return x;
}
var output = string.Empty;
for (int i = 0; i < x.Length; i++)
{
for (int j = x.Length - i; j > -1; j--)
{
string common = x.Substring(i, j);
if (y.IndexOf(common) > -1 && common.Length > output.Length) output = common;
}
}
return LongestCommonSubstring(output, strings);
}
It's still using recursion though, but it's a nice example of Queue<T>.
I refactored the C++ code from Ashutosh Singh at https://iq.opengenus.org/longest-common-substring-using-rolling-hash/ to create a rolling hash approach in C# - this will find the substring in O(N * log(N)^2) time and O(N) space
using System;
using System.Collections.Generic;
public class RollingHash
{
private class RollingHashPowers
{
// _mod = prime modulus of polynomial hashing
// any prime number over a billion should suffice
internal const int _mod = (int)1e9 + 123;
// _hashBase = base (point of hashing)
// this should be a prime number larger than the number of characters used
// in my use case I am only interested in ASCII (256) characters
// for strings in languages using non-latin characters, this should be much larger
internal const long _hashBase = 257;
// _pow1 = powers of base modulo mod
internal readonly List<int> _pow1 = new List<int> { 1 };
// _pow2 = powers of base modulo 2^64
internal readonly List<long> _pow2 = new List<long> { 1L };
internal void EnsureLength(int length)
{
if (_pow1.Capacity < length)
{
_pow1.Capacity = _pow2.Capacity = length;
}
for (int currentIndx = _pow1.Count - 1; currentIndx < length; ++currentIndx)
{
_pow1.Add((int)(_pow1[currentIndx] * _hashBase % _mod));
_pow2.Add(_pow2[currentIndx] * _hashBase);
}
}
}
private class RollingHashedString
{
readonly RollingHashPowers _pows;
readonly int[] _pref1; // Hash on prefix modulo mod
readonly long[] _pref2; // Hash on prefix modulo 2^64
// Constructor from string:
internal RollingHashedString(RollingHashPowers pows, string s, bool caseInsensitive = false)
{
_pows = pows;
_pref1 = new int[s.Length + 1];
_pref2 = new long[s.Length + 1];
const long capAVal = 'A';
const long capZVal = 'Z';
const long aADif = 'a' - 'A';
unsafe
{
fixed (char* c = s)
{
// Fill arrays with polynomial hashes on prefix
for (int i = 0; i < s.Length; ++i)
{
long v = c[i];
if (caseInsensitive && capAVal <= v && v <= capZVal)
{
v += aADif;
}
_pref1[i + 1] = (int)((_pref1[i] + v * _pows._pow1[i]) % RollingHashPowers._mod);
_pref2[i + 1] = _pref2[i] + v * _pows._pow2[i];
}
}
}
}
// Rollingnomial hash of subsequence [pos, pos+len)
// If mxPow != 0, value automatically multiply on base in needed power.
// Finally base ^ mxPow
internal Tuple<int, long> Apply(int pos, int len, int mxPow = 0)
{
int hash1 = _pref1[pos + len] - _pref1[pos];
long hash2 = _pref2[pos + len] - _pref2[pos];
if (hash1 < 0)
{
hash1 += RollingHashPowers._mod;
}
if (mxPow != 0)
{
hash1 = (int)((long)hash1 * _pows._pow1[mxPow - (pos + len - 1)] % RollingHashPowers._mod);
hash2 *= _pows._pow2[mxPow - (pos + len - 1)];
}
return Tuple.Create(hash1, hash2);
}
}
private readonly RollingHashPowers _rhp;
public RollingHash(int longestLength = 0)
{
_rhp = new RollingHashPowers();
if (longestLength > 0)
{
_rhp.EnsureLength(longestLength);
}
}
public string FindCommonSubstring(string a, string b, bool caseInsensitive = false)
{
// Calculate max neede power of base:
int mxPow = Math.Max(a.Length, b.Length);
_rhp.EnsureLength(mxPow);
// Create hashing objects from strings:
RollingHashedString hash_a = new RollingHashedString(_rhp, a, caseInsensitive);
RollingHashedString hash_b = new RollingHashedString(_rhp, b, caseInsensitive);
// Binary search by length of same subsequence:
int pos = -1;
int low = 0;
int minLen = Math.Min(a.Length, b.Length);
int high = minLen + 1;
var tupleCompare = Comparer<Tuple<int, long>>.Default;
while (high - low > 1)
{
int mid = (low + high) / 2;
List<Tuple<int, long>> hashes = new List<Tuple<int, long>>(a.Length - mid + 1);
for (int i = 0; i + mid <= a.Length; ++i)
{
hashes.Add(hash_a.Apply(i, mid, mxPow));
}
hashes.Sort(tupleCompare);
int p = -1;
for (int i = 0; i + mid <= b.Length; ++i)
{
if (hashes.BinarySearch(hash_b.Apply(i, mid, mxPow), tupleCompare) >= 0)
{
p = i;
break;
}
}
if (p >= 0)
{
low = mid;
pos = p;
}
else
{
high = mid;
}
}
// Output answer:
return pos >= 0
? b.Substring(pos, low)
: string.Empty;
}
}

Compare string similarity

What is the best way to compare two strings to see how similar they are?
Examples:
My String
My String With Extra Words
Or
My String
My Slightly Different String
What I am looking for is to determine how similar the first and second string in each pair is. I would like to score the comparison and if the strings are similar enough, I would consider them a matching pair.
Is there a good way to do this in C#?
static class LevenshteinDistance
{
public static int Compute(string s, string t)
{
if (string.IsNullOrEmpty(s))
{
if (string.IsNullOrEmpty(t))
return 0;
return t.Length;
}
if (string.IsNullOrEmpty(t))
{
return s.Length;
}
int n = s.Length;
int m = t.Length;
int[,] d = new int[n + 1, m + 1];
// initialize the top and right of the table to 0, 1, 2, ...
for (int i = 0; i <= n; d[i, 0] = i++);
for (int j = 1; j <= m; d[0, j] = j++);
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= m; j++)
{
int cost = (t[j - 1] == s[i - 1]) ? 0 : 1;
int min1 = d[i - 1, j] + 1;
int min2 = d[i, j - 1] + 1;
int min3 = d[i - 1, j - 1] + cost;
d[i, j] = Math.Min(Math.Min(min1, min2), min3);
}
}
return d[n, m];
}
}
If anyone was wondering what the C# equivalent of what #FrankSchwieterman posted is:
public static int GetDamerauLevenshteinDistance(string s, string t)
{
if (string.IsNullOrEmpty(s))
{
throw new ArgumentNullException(s, "String Cannot Be Null Or Empty");
}
if (string.IsNullOrEmpty(t))
{
throw new ArgumentNullException(t, "String Cannot Be Null Or Empty");
}
int n = s.Length; // length of s
int m = t.Length; // length of t
if (n == 0)
{
return m;
}
if (m == 0)
{
return n;
}
int[] p = new int[n + 1]; //'previous' cost array, horizontally
int[] d = new int[n + 1]; // cost array, horizontally
// indexes into strings s and t
int i; // iterates through s
int j; // iterates through t
for (i = 0; i <= n; i++)
{
p[i] = i;
}
for (j = 1; j <= m; j++)
{
char tJ = t[j - 1]; // jth character of t
d[0] = j;
for (i = 1; i <= n; i++)
{
int cost = s[i - 1] == tJ ? 0 : 1; // cost
// minimum of cell to the left+1, to the top+1, diagonally left and up +cost
d[i] = Math.Min(Math.Min(d[i - 1] + 1, p[i] + 1), p[i - 1] + cost);
}
// copy current distance counts to 'previous row' distance counts
int[] dPlaceholder = p; //placeholder to assist in swapping p and d
p = d;
d = dPlaceholder;
}
// our last action in the above loop was to switch d and p, so p now
// actually has the most recent cost counts
return p[n];
}
I am comparing two sentences like this
string[] vs = string1.Split(new char[] { ' ', '-', '/', '(', ')' },StringSplitOptions.RemoveEmptyEntries);
string[] vs1 = string2.Split(new char[] { ' ', '-', '/', '(', ')' }, StringSplitOptions.RemoveEmptyEntries);
vs.Intersect(vs1, StringComparer.OrdinalIgnoreCase).Count();
Intersect gives you a set of identical word lists , I continue by looking at the count and saying if it is more than 1, these two sentences contain similar words.

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