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How should i do to reference one file in my project, so when i publish the application, the file is generated in a specific folder?

the problem that i have with my application is about how to reference some files, when i load and image, etc, i use Path.GetFullPath(Path.Combine(AppContext.BaseDirectory, "..\\..\\..\\")); and this works fine for debugging and for some files, but doesn't work for some essential files, credentials.txt, config.ini, this files are searched in appdata when i run the published file and i don't know how i should reference them.
I try to generate some initial files so i am sure where they are and that they exists, but for folders that works great with
System.IO.Path.GetDirectoryName(
System.Reflection.Assembly.GetExecutingAssembly().Location);
with that i can make the folders where the app is run but you can't generate a file without load the content of the original file, and i don't know how to reference them.
Example:
Project.
Root of the project.
utils/key/credentials.txt
When the published file is executed i want to generate and store credentials.txt like this:
Executable (app.exe stored for example in "my documents")
"my documents"/utils/key/credentials.txt
how i do that? when i run the published application you just have the .exe, the dlls, and the resources are embebbed, so the uri doesn't works.

Assuming you have sufficient permissions, you could create a folder in the output folder of your compiled .exe at runtime using the Directory.CreateDirectory method.
If the utils/key/credentials.txt file is part of your deployment, you should set its Build Action to Content and the Copy to Output Directory property to Copy if newer in Visual Studio. This will add the utils and key folders to the output directory of the .exe, which is typically c:<project-folder\bin\Debug or \Release when you build from Visual Studio.
You can get the absolute path of the output directory like this:
string path = System.IO.Path.GetDirectoryName(
System.Diagnostics.Process.GetCurrentProcess().MainModule.FileName);
Depending on your requirements, you may then append the relative path of the file within your app to the absolute path.

C# get relative path of resources folder

I want to acess a .txt file, which I stored in the resources folder of my project, there where all the imported pictures are stored as well.
I want to use something like a relative path, since every user would have safed his programm somewehere else on his Pc, but there is always the resources folder at the same place, compared to the programm folder.
I tried to used this: displayText = System.IO.File.ReadAllText("Resources\\startmessages.txt"); but this isn't working.
I get this error message: System.IO.DirectoryNotFoundException:, it lists the unrelative path to the .txt there as well, so I don't get, why it cant read it.
Thanks for your Help.

What #ChetanRanpariya is trying to tell you is, that your programm is built in another folder than your folder Resources is sitting to. So you have explictly tell your file Resources\startmessages.txt to copy itself on build process, so it get copied to said another folder. Assuming that you are using Visual Studio, you have to right click on your file and set Copy To Output Directory to true. Its relative folder path (Resources\) will be taken over. You find your build folder somewhere in your bin folder depending on configuration and framework. :)

Current Path where your executable is
Directory.GetParent(System.IO.Directory.GetCurrentDirectory()).FullName
Path to Solution
If you are using Visual Studio and need to access the folders in the solution directory, you can use .Parent method,
Directory.GetParent(System.IO.Directory.GetCurrentDirectory()).Parent.Parent.FullName
Use of Path.Combine
and once you have the location of your Resource folder, use Path.Combine to get the location to read files / content etc
Path.Combine(Directory.GetParent(System.IO.Directory.GetCurrentDirectory()).Parent.Parent.FullName, "Resources\\startMessages.txt")

System.IO.Path.Combine(Environment.CurrentDirectory,"") takes me to wrong path

I am loading this file which is located in a folder i created, the same folder is also rendered in the bin/debug folder, but i need to locate the file in the folder i created, the thing is the method which should find the path of the file by its name gives me the path of the debug folder instead of the on i created.
I have harcoded the path to show you the real location.
var path2 = System.IO.Path.Combine(Environment.CurrentDirectory, "xulrunner");
var hardcodedPath= "C:\\Users\\Alan\\Desktop\\TabControl\\TabControl\\TabControl\\TabControl\\xulrunner";
This is the result of path2 variable:
C:\\Users\\Alan\\Desktop\\TabControl\\TabControl\\TabControl\\TabControl\\bin\\Debug\\xulrunner"
As you can see its pointing to different folder as hardcoded path.

When running from Visual Studio, the working directory is different from your project location, usually it is two folders up (from bin\Debug\). In your distributed application, the working directory might be the same as that of other files you want to access since you copy some other files to the working directory.
I would recommend to keep your code the same, and copy the files you require from your project to the output directory. You can do that by simply setting the Copy to Output Directory setting to Copy always or Copy if newer.
Changing the path to go two folders up is a bad idea, since this won't be true in production scenarios, and will thus break your code.

To get exactly what you are looking for, you could do the following:
var path2 = System.IO.Path.GetFullPath(System.IO.Path.Combine(Environment.CurrentDirectory, "..\\..\\xulrunner"));
However, please be aware that Environment.CurrentDirectory can change as your program runs. I have found that using the %PROGRAMDATA% environment variable works well for creating a location where you save data. It allows for a more consistent solution for using paths.
Additionally, the code snippet provided will only really be useful when you are running through the IDE's debugger. When you deploy, it will likely not give you what you are expecting.
It would help to know what is the overall functional result you are hoping for.

avoid hard coding path in ReadAllText

My exact file path is as follows. This .txt file is not supposed to be deployed to bin/debug
string str = File.ReadAllText(#"C:\development\slnfolder\projfolder\myfile.txt");
How can I write the code so that I do not have to hard code full path to get to the file
I am trying to avoid hard coding path in the above line of code as follows:
string file = #"myfile.txt";
string str = Path.GetFullPath(file);
but the str ends up being as follows and is not able to find the file.
C:\development\slnfolder\projfolder\bin\debug\myfile.txt

You can include myfile.txt in your Visual Studio solution and go to its properties and set the Build action to Copy always (or Copy if newer if you want to avoid copying the file if it didn't change since the previous build...).
This way you're going to have the whole file in the target directory (i.e. bin\debug).

That's where it should map, because that's where your executable is running from. I'd highly suggest you ensure that the text file is moved to the bin/debug folder (there's a VS option to copy it down in properties) rather than trying to read two levels up. It will be much easier once you end up deploying your app instead of running it from visual studio.

If you're using Visual studio, than add the txt file to your project
right click on properties
set build action to none
and set copy to output directory to copy if newer
this will ensure that the txt file is always in the same folder as your executable

To avoid hard-coding something, you should:
"Soft-code" it (i.e. make it part of your product's configuration). You can use Configuration Settings APIs for that.
Take it as a parameter on the command line (read the directory location from one of the args passed to the Main method), or
Make a convention as to where it should be located, for example, in the data directory, which is a subdirectory of your current running directory (read from #"..\data\myfile.txt").
You can always define a combination of these methods, for example, use the "by convention" location when the configuration / command line option has not been specified.

C# console app: reference file without ..\..\filename

I need to read data from a file in a c# console application.
What works: new StreamReader(#"..\\..\myData.csv");
Problem:
the ..\\..\ work because my exe file is in the bin/Debug directory
When I deploy my project the path doesn't work any longer
Question:
How can I reference myData.csv regardless of the location of the exe file?
I had hoped to find a method that returns the 'root' of my console application
So far I tried the following:
Process.GetCurrentProcess().MainModule.FileName
Path.GetDirectoryName(Assembly.GetEntryAssembly().Location
Path.GetFullPath("bp.csv")
AppDomain.CurrentDomain.BaseDirectory
Directory.GetCurrentDirectory()
All of these expressions lead me to the directory of the exe file not the root.
I just started to read about isolated storage but it would be nice to have something simpler. Any suggestions / recommendations?

The simplest option is probably to add your CSV file to the solution and right-click it in VS and set the build action to "Copy if newer", which will output it together with the .exe (to the Debug or Release folder) when you build.
In the code, you can get the current location of the executing assembly like this:
string folder = Path.GetDirectoryName(Assembly.GetExecutingAssembly().Location);
And then you can combine the path with the CSV file name:
string filePath = Path.Combine(folder, "myData.csv");

Where your myData.csv will be stored ? You should have an absolute location of this file.
there are couple of options
You can place this file at the same directory where your exe is placed so you will only need to do
new StreamReader("myData.csv");
you can define file location in the App.Conig file and read that location.
you can set a path variable an read the PATH variable.

You should change your code to
new StreamReader("myData.csv");
This will ensure that the data is always read from the same folder the .exe is run from.
After that, you can create a post build step to copy the file to the deployment folder (or a subfolder) so that even in your debug environment the file will be in the correct place. The property "Copy to Output Folder" on the data file will do this as well if you just need the file to be in the output path for a project.
If you need more control, n the post build steps you can use macros like $(ProjectPath) to reference where the project files are located and $(TargetDir) to reference where the output directory will be.