This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 2 years ago.
for (double i = 0; i < 0.05; i+= 0.001)
{
//do something
}
In this for loop,
I thought the count would go as follows: 0, 0.001, 0.002, 0.003, etc., but it becomes 0.0090000000000000011 instead of 0.009.
Why is such conversion possible?
The resolution of the double/float is not infinite.
See here
Because some numbers cannot be represented exactly as fractional binary values, floating-point numbers can only approximate real numbers.
Related
This question already has answers here:
Why does integer division in C# return an integer and not a float?
(8 answers)
Closed 3 years ago.
I'm making a simple calculator in c# and and everything works well until I try dividing numbers that should give decimal places. How to display 2 decimal places in these cases?
I've tried putting #.## after .ToString.
{label1.Text = (divide / Convert.ToInt64(label1.Text)).ToString("#.##");}
I expect the output of 5/4 to be 1.25, but it is 1.
convert the number to float instead of int,
{label1.Text = ((float)divide / float.Parse(label1.Text)).ToString("n2");}
This question already has answers here:
Rounding a variable to two decimal places C# [duplicate]
(8 answers)
How do you round a number to two decimal places in C#?
(15 answers)
Closed 5 years ago.
I have a decimal number decimal n = 0.111111111m; and I want to change it to 0.112. How could I do this ?
You can use:
Math.Round(n, 3);
To always round up, you can use:
Math.Ceiling(n * 1000) / 1000;
According to this link
https://msdn.microsoft.com/en-us/library/6be1edhb(v=vs.110).aspx
You'll need to do something like Decimal.Round(n, 3);
However your initial approximation is not accurate
This question already has answers here:
Is floating point math broken?
(31 answers)
Closed 5 years ago.
when divide in c# Answer is different and when i divide from calculator answer is different kindly solve it.
c#
double div=(double)100000/30/9;
Answer 370.37037037037038
370.37037037037038*9*30 //100000.0000000000026
in calculator
Answer 370.3703703703704
370.3703703703704*9*30 //100000
i need exact answer like a calculator.
The difference is simply one of rounding. That is not a rational number, it has a repeating sequence, and cannot be perfectly expressed in binary code. It cannot even be expressed with a finite number of digits in decimal. The only difference there is that your calculator displays fewer digits than the C# double.
The final '04' is simply your calculator rounding '038' upward.
This question already has answers here:
Why is floating point arithmetic in C# imprecise?
(3 answers)
decimal vs double! - Which one should I use and when? [duplicate]
(7 answers)
Closed 6 years ago.
double sth = 250 - 249.99;
Console.WriteLine(sth);
Why does this return sth like 0.009994507, instead of 0.01?
Floating point numbers (in this case doubles) cannot represent decimal values exactly. For more info, see this page here
If you need a more accurate representation, use decimal instead.
because when you print the double you print the all double value not just the first x after point digits.
you can use String.Format to print only the first 2 numbers.
double sth = 250.00d - 249.99d;
string sthString = String.Format("{0:0.00}", sth);
Console.WriteLine(sthString);
There are a lot of decimals that have infinite binary representation. What you're experiencing is exactly this case.
For more on this topic see: http://www.exploringbinary.com/why-0-point-1-does-not-exist-in-floating-point/
This question already has answers here:
Truncate Two decimal places without rounding
(24 answers)
Closed 8 years ago.
I have this Number
double Nb=4.9584763251
how can I make get only two digits after the comma without rounding the number :
Nb=`4.95` and not `4.96`
using the Math.Round(Nb,2) will return 4.96
is there any way to fix this ?
You may use Math.Truncate(Nb * 100) / 100m
double x = ((int)(Nb*100))/100.0