It's BitConverter.ToString(blabla) same with blabla.toString?
Example:
int values = 1500;
byte[] bytes = BitConverter.GetBytes(values);
byte[] bits = new byte[2];
bits.SetValue(bytes[0], 0);
bits.SetValue(bytes[1], 1);
string hex = BitConverter.ToString(bits);
string hexHub1 = hex.Substring(0, hex.IndexOf("-"));
string hexHub2 = hex.Substring(hex.IndexOf("-") +1,2);
And get "DC-05"
How can i implement anything like this in kotlin?
byteArray.toString() is used to convert ByteArray to String. On the other hand, contentToString() will result elements in the array.
val byteArray = "Hello".toByteArray(Charsets.UTF_8)
println(byteArray.contentToString()) // this will print numbers
println(byteArray.toString(Charsets.UTF_8))
Related
I have bytes array of decimal values like [0, 4, 20, 141] and I want that to be converted as [0x00, 0x04, 0x14, 0x8D] which I need to use this array as bytes to add in a buffer
Current data:
byte[] packet = new byte[4];
packet[0] = 0;
packet[1] = 4;
packet[2] = 20;
packet[3] = 141;
and expected data to send to the serial port is as below:
byte[] mBuffer = new byte[4];
mBuffer[0] = 0x02;
mBuffer[1] = 0x04;
mBuffer[2] = 0x14;
mBuffer[3] = 0x8D;
Tried:
Convert.ToByte(string.Format("{0:X}", packet[0]));
But throwing an exception:
Input string was not in a correct format.
You're getting the exception because you're trying to substitute a variable in the string without the "$" prefix. Try this:
// Converts integer 141 to string "8D"
String parsed = String.Format($"{0:X}", packet[3]);
Then, you should be able to convert to a byte using this:
// Parses string "8D" as a hex number, resulting in byte 0x8D (which is 141 in decimal)
Byte asByte = Byte.Parse(parsed, NumberStyles.HexNumber);
How do I further encrypt a MD5 hash by XOR'ing it with a string of variable size (not bigger than 32 characters) ?
I would like the result of the XOR to be a 32 character string as well.
What i have tried so far is:
convert the md5 string to binary
convert second string to binary
pad second binary with 0's (to the left) until both binaries are of equal length
iterate the binary representations and XOR them
convert the XOR'ed result to a string
The approach may be wrong, im not sure how to do it. My problem is, when converting the result of the XOR, it is not a 32 character long string, as I would like it to be.
Sample code (equal length strings in this case):
class Program
{
static void Main(string[] args)
{
var md51 = ToBinary(ConvertToByteArray(CalculateMD5Hash("Maaa"), Encoding.ASCII));
var md52 = ToBinary(ConvertToByteArray(CalculateMD5Hash("Moo"), Encoding.ASCII));
List<int> xoredResult = new List<int>();
for (int i = 0; i < md51.Length; i++)
{
var string1 = md51[i];
var string2 = md52[i];
var xor = string1 ^ string2;
xoredResult.Add(xor);
}
var resultingString = string.Join("", xoredResult);
Console.WriteLine(resultingString.Length);
var data = GetBytesFromBinaryString(resultingString);
var text = Encoding.ASCII.GetString(data);
}
public static byte[] ConvertToByteArray(string str, Encoding encoding)
{
return encoding.GetBytes(str);
}
public static String ToBinary(Byte[] data)
{
return string.Join("", data.Select(byt => Convert.ToString(byt, 2).PadLeft(8, '0')));
}
public static Byte[] GetBytesFromBinaryString(String binary)
{
var list = new List<Byte>();
for (int i = 0; i < binary.Length; i += 8)
{
String t = binary.Substring(i, 8);
list.Add(Convert.ToByte(t, 2));
}
return list.ToArray();
}
public static string CalculateMD5Hash(string input)
{
// step 1, calculate MD5 hash from input
MD5 md5 = System.Security.Cryptography.MD5.Create();
byte[] inputBytes = System.Text.Encoding.ASCII.GetBytes(input);
byte[] hash = md5.ComputeHash(inputBytes);
// step 2, convert byte array to hex string
StringBuilder sb = new StringBuilder();
for (int i = 0; i < hash.Length; i++)
{
sb.Append(hash[i].ToString("X2"));
}
return sb.ToString();
}
}
xoring a string with what is essentially random bytes is not guaranteed to give you a valid string as a output. Your var text = Encoding.ASCII.GetString(data); is likely failing because you are passing it a non valid string in byte form. You must use something like var text = Convert.ToBase64String(data) to be able to represent the random data without loss of information in the process.
this is my problem: i need to convert bytes array to int in c#, on xamarin pcl.
But i have tryed this:
byte[] fromBoardSerial = new byte[3];
fromBoardSerial[0] = 0x04
fromBoardSerial[1] = 0x93
fromBoardSerial[2] = 0xe0
result = BitConverter.ToInt32(fromBoardSerial, 0);
Solution:
Array.Reverse(fromBoardSerial); //call before conversion
but the result is: -527236096...Instead..the correct result should be: 300000
how do conversion from array bytes in Int ?
Thanks
It looks like you have two problems here:
Number of bytes. You must have 4 bytes for conversion to Int32.
Byte order. It looks like you try to calculate your number "backwards".
Look at this code:
byte[] fromBoardSerial = new byte[4];
fromBoardSerial[0] = 0xe0;
fromBoardSerial[1] = 0x93;
fromBoardSerial[2] = 0x04;
fromBoardSerial[3] = 0x00;
var result = BitConverter.ToInt32(fromBoardSerial, 0); // result = 300000
I have a random integer value which I need to represent in String as a Byte array. For example:
int value = 32;
String strValue = getStringByteArray(value);
Console.WriteLine(strValue); // should write: " \0\0\0"
If value = 11 then getStringByteArray(value) shuld return "\v\0\0\0".
If value = 13 then getStringByteArray(value) shuld return "\r\0\0\0".
And so on.
Any idea on how to implement the method getStringByteArray(int value) in C#?
UPDATE
This is the code that receives the data from the C# NamedPipe Server:
bool CFilePipe::ReadString(int m_handle, string &value)
{
//--- check for data
if(WaitForRead(sizeof(int)))
{
ResetLastError();
int size=FileReadInteger(m_handle);
if(GetLastError()==0)
{
//--- check for data
if(WaitForRead(size))
{
value=FileReadString(m_handle,size);
return(size==StringLen(value));
}
}
}
//--- failure
return(false);
}
Don't take this approach at all. You should be writing to a binary stream of some description - and write the binary data for the length of the packet/message, followed by the message itself. For example:
BinaryWriter writer = new BinaryWriter(stream);
byte[] data = Encoding.UTF8.GetBytes(text);
writer.Write(data.Length);
writer.Write(data);
Then at the other end, you'd use:
BinaryReader reader = new BinaryReader(stream);
int length = reader.ReadInt32();
byte[] data = reader.ReadBytes(length);
string text = Encoding.UTF8.GetString(data);
No need to treat binary data as text at all.
Well. First of all you should get bytes from integer. You can do it with BitConverter:
var bytes = BitConverter.GetBytes(value);
Next, here is three variants. First - if you want to get result in binary format. Just take all your bytes and write as it is:
var str = string.Concat(bytes.Select(b => Convert.ToString(b, 2)));
Second variant. If you want convert your byte array to hexadecimal string:
var hex = BitConverter.ToString(array).Replace("-","");
Third variant. Your representation ("\v\0\0\0") - it is simple converting byte to char. Use this:
var s = bytes.Aggregate(string.Empty, (current, t) => current + Convert.ToChar(t));
This should help with that.
class Program
{
static void Main(string[] args)
{
Random rand = new Random();
int number = rand.Next(1, 1000);
byte[] intBytes = BitConverter.GetBytes(number);
string answer = "";
for (int i = 0; i < intBytes.Length; i++)
{
answer += intBytes[i] + #"\";
}
Console.WriteLine(answer);
Console.WriteLine(number);
Console.ReadKey();
}
}
Obviously, you should implement two steps to achieve the goal:
Extract bytes from the integer in the appropriate order (little-endian or big-endian, it's up to you to decide), using bit arithmetics.
Merge extracted bytes into string using the format you need.
Possible implementation:
using System;
using System.Text;
public class Test
{
public static void Main()
{
Int32 value = 5152;
byte[] bytes = new byte[4];
for (int i = 0; i < 4; i++)
{
bytes[i] = (byte)((value >> i * 8) & 0xFF);
}
StringBuilder result = new StringBuilder();
for (int i = 0; i < 4; i++)
{
result.Append("\\" + bytes[i].ToString("X2"));
}
Console.WriteLine(result);
}
}
Ideone snippet: http://ideone.com/wLloo1
I think you are saying that you want to convert each byte into a character literal, using escape sequences for the non printable characters.
After converting the integer to 4 bytes, cast to char. Then use Char.IsControl() to identify the non-printing characters. Use the printable char directly, and use a lookup table to find the corresponding escape sequence for each non-printable char.
Hi i was able to convert a ASCII string to binary using a binarywriter .. as 10101011 . im required back to convert Binary ---> ASCII string .. any idea how to do it ?
This should do the trick... or at least get you started...
public Byte[] GetBytesFromBinaryString(String binary)
{
var list = new List<Byte>();
for (int i = 0; i < binary.Length; i += 8)
{
String t = binary.Substring(i, 8);
list.Add(Convert.ToByte(t, 2));
}
return list.ToArray();
}
Once the binary string has been converted to a byte array, finish off with
Encoding.ASCII.GetString(data);
So...
var data = GetBytesFromBinaryString("010000010100001001000011");
var text = Encoding.ASCII.GetString(data);
If you have ASCII charters only you could use Encoding.ASCII.GetBytes and Encoding.ASCII.GetString.
var text = "Test";
var bytes = Encoding.ASCII.GetBytes(text);
var newText = Encoding.ASCII.GetString(bytes);
Here is complete code for your answer
FileStream iFile = new FileStream(#"c:\test\binary.dat",
FileMode.Open);
long lengthInBytes = iFile.Length;
BinaryReader bin = new BinaryReader(aFile);
byte[] byteArray = bin.ReadBytes((int)lengthInBytes);
System.Text.Encoding encEncoder = System.Text.ASCIIEncoding.ASCII;
string str = encEncoder.GetString(byteArray);
Take this as a simple example:
public void ByteToString()
{
Byte[] arrByte = { 0, 1, 1, 0, 1, 0, 1, 0, 1, 0, 1, 0 };
string x = Convert.ToBase64String(arrByte);
}
This linked answer has interesting details about this kind of conversion:
binary file to string
Sometimes instead of using the built in tools it's better to use "custom" code.. try this function:
public string BinaryToString(string binary)
{
if (string.IsNullOrEmpty(binary))
throw new ArgumentNullException("binary");
if ((binary.Length % 8) != 0)
throw new ArgumentException("Binary string invalid (must divide by 8)", "binary");
StringBuilder builder = new StringBuilder();
for (int i = 0; i < binary.Length; i += 8)
{
string section = binary.Substring(i, 8);
int ascii = 0;
try
{
ascii = Convert.ToInt32(section, 2);
}
catch
{
throw new ArgumentException("Binary string contains invalid section: " + section, "binary");
}
builder.Append((char)ascii);
}
return builder.ToString();
}
Tested with 010000010100001001000011 it returned ABC using the "raw" ASCII values.