This question already has answers here:
Why Async Method always blocking thread?
(4 answers)
Closed 1 year ago.
I am trying to call this async method from a console application. I was expecting the part "a" of my method to run asynchronously while the execution awaits for the ReturnsString() but that is not the case, everything seems to be executed synchronously. I am failing to understand why.
sorry for my bad english.
dotnet fiddler
output
public class AsyncAwaitExe3
{
public async Task<string> DoAsync()
{
string toReturn = "";
Console.WriteLine("I'm here A");
//a
for (int i = 0; i < 30; i++)
{
Console.WriteLine($"inside for {i}");
Thread.Sleep(1000);
}
//b
Console.WriteLine("I'm here B");
toReturn = await ReturnsString();
//c
Console.WriteLine("I'm here C");
return toReturn;
}
public async Task<string> ReturnsString()
{
Console.WriteLine("I'm here D");
await Task.Delay(2000);
Console.WriteLine("I'm here E");
return "sharp sword";
}
}
static void Main(string[] args)
{
AsyncAwaitExe3 exe3 = new AsyncAwaitExe3();
Console.WriteLine(exe3.DoAsync());
Console.ReadKey();
}
Section a is synchronous code-- there is nothing about it that returns a task while it continues to run. If you want it to be async, you can break it into a different, async method. Then wait for both to complete using Task.WhenAll.
Also, you have to using Task.Delay() instead of Thread.Sleep(). Task.Delay returns a task which you can await; Thread.Sleep just blocks the thread synchronously.
async Task RunSectionA()
{
Console.WriteLine("I'm here A");
for (int i = 0; i < 30; i++)
{
Console.WriteLine($"inside for {i}");
await Task.Delay(1000);
}
}
public async Task<string> DoAsync()
{
var taskA = RunSectionA();
var taskB = ReturnsString();
await Task.WhenAll(taskA, taskB);
return await taskB;
}
Related
This is a follow up question from this question: How do you run a variable number of concurrent parametrizable infinite loop type of threads in C#?
Say I have a value taskLimit (assume 20), of no of simultaneous Tasks "MyTask" which are created in the RunAsync method below:
protected override async Task RunAsync(CancellationToken cancellationToken)
{
var tasks = new List<Task>();
try
{
for (int i = 0; i < taskLimit; i++)
{
tasks.Add(MyTask(cancellationToken, i);
}
await Task.WhenAll(tasks);
}
catch (Exception e)
{
//Exception Handling
}
}
public async Task MyTask(CancellationToken cancellationToken, int a)
{
while (true)
{
cancellationToken.ThrowIfCancellationRequested();
try
{
//long running code, if possible check for cancellation using the token
//Do something useful here. Very Processor and IO heavy. Takes 5-10 minutes to complete.
//SomeHeavyTask can only concurrently run upto a limit of say 5. Implement a token system of sorts
while(freeTokens<1)
{
await Task.Delay(TimeSpan.FromMinutes(1), cancellationToken);
}
freeTokens = freeTokens-1;
SomeHeavyTask(cancellationToken);
freeTokens = freeTokens+1;
//sleep for an independently parameterizable period, then wake up and repeat
await Task.Delay(TimeSpan.FromHours(parametrizableTaskDelay[i]), cancellationToken);
}
catch (Exception e)
{
//Exception Handling
}
}
}
Is it possible to do such a thing? Is there a better more formal approach supported natively in C# to achieve the same thing? Please note the essence of this question is that there are substantially less freeTokens than the taskLimit. And that each MyTask spends only 10% time in SomeHeavyTask(), and most of the time is spent in await Task.Delay().
You should use Microsoft's Reactive Framework (aka Rx) - NuGet System.Reactive and add using System.Reactive.Linq; - then you can do this:
int taskLimit = 500;
int maxConcurrent = 5;
IObservable<Unit> query =
Observable
.Range(0, taskLimit)
.Select(x => Observable.FromAsync(ct => SomeHeavyTask(ct)))
.Merge(maxConcurrent);
await query;
That's a lot easier to work with in my book.
Another option:
var block = new ActionBlock<int>(x => SomeHeavyTask(cancellationToken, x),
new ExecutionDataflowBlockOptions()
{
MaxDegreeOfParallelism = 20,
CancellationToken = cancellationToken
});
for (int i = 0; i < 100; i++)
await block.SendAsync(i, cancellationToken);
block.Complete();
await block.Completion;
You could use a SemaphoreSlim to limit the number of tasks that are working concurrently (you will still have taskLimit Tasks active, but only a limited number of those will be doing the heavy work simultaneously; I assume this is what you want).
This is best demonstrated with a sample console app. If you run this you'll see from the output that a maximum of 5 "heavy tasks" are active simultaneously.
using System;
using System.Collections.Generic;
using System.Threading;
using System.Threading.Tasks;
namespace Demo
{
class Program
{
static async Task Main()
{
Console.WriteLine("Starting");
// Cancel after 30 seconds for demo purposes.
using var source = new CancellationTokenSource(TimeSpan.FromSeconds(30));
await RunAsync(source.Token);
Console.WriteLine("Stopped.");
Console.ReadLine();
}
public static async Task RunAsync(CancellationToken cancellationToken)
{
int taskLimit = 20;
int concurrencyLimit = 5;
var sem = new SemaphoreSlim(concurrencyLimit);
var tasks = new List<Task>();
try
{
for (int i = 0; i < taskLimit; i++)
{
int p = i; // Prevent modified closure.
tasks.Add(Task.Run(() => MyTask(cancellationToken, p, sem)));
}
await Task.WhenAll(tasks);
}
catch (OperationCanceledException)
{
Console.WriteLine("Task(s) were cancelled.");
}
catch (Exception e)
{
// Exception Handling
}
}
public static async Task MyTask(CancellationToken cancellationToken, int a, SemaphoreSlim sem)
{
while (true)
{
cancellationToken.ThrowIfCancellationRequested();
try
{
await sem.WaitAsync(cancellationToken);
try
{
someHeavyTask(cancellationToken, a);
}
finally
{
sem.Release();
}
}
catch (OperationCanceledException)
{
Console.WriteLine("Task was cancelled.");
return;
}
catch (Exception e)
{
//Exception Handling
}
}
}
static int heavyTaskCount;
static void someHeavyTask(CancellationToken cancel, int a)
{
int n = Interlocked.Increment(ref heavyTaskCount);
Console.WriteLine("Starting heavy task. Number of simultaneous heavy tasks = " + n);
// Simulate work. Make the work for each task take varying time by using 'a' for the sleep.
for (int i = 0; i < 20 && !cancel.IsCancellationRequested; ++i)
{
Thread.Sleep(100 + a*10);
}
n = Interlocked.Decrement(ref heavyTaskCount);
Console.WriteLine("Finishing heavy task. Number of simultaneous heavy tasks = " + n);
}
}
}
The core of this is controlled by the semaphore in the code here:
await sem.WaitAsync(cancellationToken);
try
{
someHeavyTask(cancellationToken, a);
}
finally
{
sem.Release();
}
Like #mjwills said, you can use a C# semaphore to manage concurrent access to resources. (random example)
I do recommend looking at existing solutions first though. For example, Hangfire.
You can store its state inside SF if needed.
This question already has answers here:
How to delay 'hot' tasks so they can processed in a set order
(2 answers)
Closed 4 years ago.
I need to first create new task then do some remaining work and then start the task that works with its result.
Simplified example:
static int value;
static async Task work1()
{
do
{
int i;
for (i = 0; i < 10000000; i++) {} // some calculations
Console.WriteLine("result1: " + value + " i: " + i);
await Task.Delay(2000).ConfigureAwait(false);
} while (condition);
}
static async Task work2()
{
do
{
int i;
for (i = 0; i < 10000000; i++) {} // some calculations
Console.WriteLine("result2: " + value + " i: " + i);
await Task.Delay(2000).ConfigureAwait(false);
} while (condition);
}
static void Main(string[] args)
{
Task task;
int tempvalue = 100;
if (condition1)
{
tempvalue *= 10;
task = new Task(() => work1());
} else
{
tempvalue -= 5;
task = new Task(() => work2());
}
if (tempvalue > 100)
{
value = 5;
} else
{
value = tempvalue;
}
task.Start();
// immediately do remaining work
}
this code does exactly what I need but compiler shows following warning:
Warning CS4014 Because this call is not awaited, execution of the current method continues before the call is completed. Consider applying the 'await' operator to the result of the call.
on line:
Task task = new Task(() => work());
should I rather use it like so? Is there any difference?
Task task = new Task(async () => await work());
This is not a duplicate of How to delay 'hot' tasks so they can processed in a set order because after task.Start(); it should do remaining work immediately.
Func<Task> f = () => work();
// do stuff
f(); // blocks thread until work1() or work2() hits await
// do remaining work
The async keyword means that the task within your task is asynchronous and using await will mean that you want to wait for the method work to finish.
You could also use Task.Wait() in order to wait for the method to finish it's execution.
But using async await is the better way to do it because it's not blocking the main thread.
I am trying to see how CPU is being utilized when I spawn a lot of tasks using the following code:
static void Main(string[] args)
{
Stopwatch sw = new Stopwatch();
sw.Start();
Console.WriteLine("Main Started");
MainChild(sw).Wait();
Console.WriteLine("Main ended: "+sw.Elapsed);
}
static async Task MainChild(Stopwatch sw)
{
Task[] tasks = new Task[100];
for (int i = 0; i < 100; i++)
{
tasks[i] = Task.Factory.StartNew(new Action(async()=> {
await Task.Delay(1000);
Console.WriteLine("Task1 completed: " + sw.Elapsed);
}));
}
await Task.WhenAll(tasks);
}
I noticed that the main thread executes the :"Main Ended: " even before the tasks are executed. Why is this?
The Task.Factory.StartNew method is outdated and almost never used this days, also it doesn't understand async delegates.
Another thing is that the Action delegate returns void and async void is a fire-and-forget type of action. This operation doesn't return Task and is not awaited.
Change Action:
tasks[i] = Task.Factory.StartNew(new Action(async () =>
{
await Task.Delay(1000);
Console.WriteLine("Task1 completed: " + sw.Elapsed);
}));
To Func<Task> and Task.Run:
tasks[i] = Task.Run(new Func<Task>(async () =>
{
await Task.Delay(1000);
Console.WriteLine("Task1 completed: " + sw.Elapsed);
}));
As delegate type is inferred by compiler we can shorten it to:
tasks[i] = Task.Run(async () => ...
Now it is working as expected and waits for all tasks to finish execution
I have a console application with have two threads as:
public static async void Thread1()
{
for (int i = 0; i < 100; i++)
{
Debug.WriteLine("Thread1 " + i);
await MyFunc();
}
}
public static async void Thread2()
{
for (int i = 0; i < 100; i++)
{
Debug.WriteLine("Thread2 " + i);
await MyFunc();
}
}
public static void Main(string[] args)
{
MainAsync(args).GetAwaiter().GetResult();
}
private static async Task MainAsync(string[] args)
{
Console.WriteLine("Before start thread");
Thread tid1 = new Thread(Thread1);
Thread tid2 = new Thread(Thread2);
tid1.Start();
tid2.Start();
}
public static async Task MyFunc()
{
//do something
}
However, when the application run and terminates, it seems that only each thread is run just once as I see only below things in output:
Before start thread
Thread1 0
Thread2 0
//some thing from MyFunc
I expect or rather wannt to run each thread till the for loop.It seems to me that the for loop continues to run despite the await.
If yes, what could be other probable approach.
Any leads would be helpful.
You aren't doing anything to wait for the threads. The main routine will just continue on until it returns to the O/S, which will kill the process and any child threads. Since you aren't doing anything else, this happens almost immediately, cutting both threads' lives short.
If you want to wait for the threads to finish, you can refer to this answer and write some variation of
while (thread1.IsAlive || thread2.IsAlive)
{
//Do something to wait
}
...before exiting.
That being said, you should probably using Tasks instead of threads, e.g.
public static async Task Task1()
{
for (int i = 0; i < 100; i++)
{
Debug.WriteLine("Task1 " + i);
await MyFunc();
}
}
public static async Task Task2()
{
for (int i = 0; i < 100; i++)
{
Debug.WriteLine("Task2 " + i);
await MyFunc();
}
}
And then to execute and wait for both of them:
Task.WaitAll
(
new[]
{
Task1(),
Task2()
}
);
See this code in action on DotNetFiddle
See also What is the difference between tasks and threads?
You seem to have a lot of confusion about the role of threads and tasks, so it's a good idea to read up about it. Steven Cleary has a nice write-up about this. "There Is No Thread"
From the comments, it seems that your actual intention here is to run two async tasks in parallel, then to wait until they are both finished.
If you want to wait for two async tasks to complete in parallel, make sure your async methods actually return Task then:
Task task1 = DoSomethingAsync(); //don't await
Task task2 = DoSomethingElseAsync(); //don't await
then you can wait asynchronously for Task.WhenAll:
await Task.WhenAll(task1,task2);
You really don't need to be involving Thread at all.
Use async Task instead of async void
private static async Task MainAsync(string[] args)
{
Console.WriteLine("Before start thread");
var task1 = Thread1();
var task2 = Thread2();
var taskList = new [] { task1, task2 };
Task.WaitAll(taskList);
}
Previously, when making a looping task it would run perfectly the first time and fall apart because of the timing problems, such as the functions of one individual task would start running faster than another, even though it was programmed to come before that task.
So my idea to figure out a way to repeat the events of a task once the delays(times) have ended, in my head it would go something like this:
private async Task programCore()
{
int n = 1000;
for (int i = 0; i < n; )
{
FirstThing();
await Task.Delay(2100);
SecondThing();
await Task.Delay(2200);
ThirdThing();
await Task.Delay(2300);
}
////////////////////////////////////////////////////////////////////////////
else if (programCore.TasksHaveAllTimedOut) // Idealistic code.
{
programCore.Restart();
}
}
Is something like this possible? If not, is there a better way to do it?
How about this:
private async Task programCore()
{
int n = 1000;
for (int i = 0; i < n; )
{
await FirstThing();
await SecondThing();
await ThirdThing();
}
}
private async Task FirstThing()
{
// Do something here
}
private async Task SecondThing()
{
// Do something here
}
private async Task ThirdThing()
{
// Do something here
}
This has the effect that it runs FirstThing, waits for it to finish, then runs SecondThing, waits for it to finish, then finally runs ThirdThing and waits for it to finish before repeating the loop.
I believe #CodingGorilla has the right idea. Your code should look something like this (using CancellationTokens for timeouts):
private async Task programCore()
{
int n = 1000;
for (int i = 0; i < n; ++i)
{
var timeout1 = new CancellationTokenSource(2100);
await FirstThingAsync(timeout1.Token);
var timeout2 = new CancellationTokenSource(2200);
await SecondThingAsync(timeout2.Token);
var timeout2 = new CancellationTokenSource(2300);
await ThirdThingAsync(timeout3.Token);
}
}
The code above will raise an exception if any task exceeds its timeout, which may not be exactly what you want. You can catch the OperationCanceledException if you wish to handle this differently.