How to send pdf file to telegram bot using c# - c#

i'm new to c# .i tried following code but not worked.Someone please help me to solve this.
i want send pdf using c# post method. Thank You
using System.Net.Http;
HttpClient client = new HttpClient();
var chat_id = xxxxxx;
var text = "This is my default text";
var token = "xxxxxxxxxxxxxxxxxxxx";
Byte[] bytes = File.ReadAllBytes(#"C:\xxx.pdf");
var file = Convert.ToBase64String(bytes);
var values = new Dictionary<string, string>
{
};
var urlstring = "https://api.telegram.org/bot{0}/sendDocument?chat_id={1}&document={2}";
urlstring = String.Format(urlstring, token, chat_id,file);
var content = new FormUrlEncodedContent(values);
var response = await client.PostAsync(urlstring, content);
var responseString = await response.Content.ReadAsStringAsync();

Related

How to CREATE POST IN C# to an endpoint on BMC REMEDY API to create a ticket with files submited in form-data?

I have this problem. i have to submit a file (or not) to an endpoint on an API of bmc.
the KEY:entry with the VALUE:data_entry.txt is the json to send with the values, as the same of the body.
The attach-z2AF_WIAttachment1 is the file i want to submit. I'm it's always throuwing some error, or headers invalid, or filetype not valid, but in postman is working.
I cant convert to C#.
this is my code so far, or now.
try
{
//authentication
var dict = new Dictionary<string, string>();
dict.Add("username", "applicationUsernameJonDoe");
dict.Add("password", "applicationPassowrdXPTO");
var clientLogin = new HttpClient();
var req = new HttpRequestMessage(HttpMethod.Post, Endpoint_loginITSM) { Content = new FormUrlEncodedContent(dict) };
var res = clientLogin.SendAsync(req); //.Result.ToString();
var body = res.GetAwaiter().GetResult().Content.ReadAsStringAsync();
//pedido de criação de registo
using (var client = new HttpClient())
{
client.Timeout = TimeSpan.FromMinutes(10);
var request = new HttpRequestMessage
{
RequestUri = new Uri(Endpoint_CreateITSM),
Method = HttpMethod.Post
};
request.Headers.Add("Authorization", body.Result.ToString());
if (!string.IsNullOrEmpty(registos.Objeto.fileName))
{
registos.Objeto.Registo.z2AF_WIAttachment1 = registos.Objeto.fileName;
}
string json = JsonConvert.SerializeObject(new { values = registos.Objeto });
byte[] file_bytes = System.Convert.FromBase64String(registos.Objeto.fileEncoded);
MemoryStream memoryStream = new MemoryStream();
using (BsonDataWriter writer = new BsonDataWriter(memoryStream))
{
JsonSerializer serializer = new JsonSerializer();
serializer.Serialize(writer, registos.Objeto.Registo);
}
var data_entry_bytes = memoryStream.ToArray();
// we need to send a request with multipart/form-data
var multiForm = new MultipartFormDataContent();
ByteArrayContent data_entry_json_content = new ByteArrayContent(data_entry_bytes);
data_entry_json_content.Headers.ContentType = new MediaTypeHeaderValue("application/json");
data_entry_json_content.Headers.ContentDisposition = new ContentDispositionHeaderValue("entry")
{
FileName = "data_entry.txt",
Name = "entry",
};
multiForm.Add(data_entry_json_content);
ByteArrayContent z2AF_WIAttachment1_content = new ByteArrayContent(file_bytes);
z2AF_WIAttachment1_content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
z2AF_WIAttachment1_content.Headers.ContentDisposition = new ContentDispositionHeaderValue("attach-z2AF_WIAttachment1")
{
FileName = registos.Objeto.fileName,
Name = "attach-z2AF_WIAttachment1",
};
multiForm.Add(z2AF_WIAttachment1_content);
request.Content = multiForm;
var result = await client.SendAsync(request);
var resBody = result.Content.ReadAsStringAsync().Result.ToString();//.ConfigureAwait(false);
dynamic _resBody = JsonConvert.DeserializeObject<dynamic>(resBody);
string registoID = _resBody["values"].SysRequestID;
return ResponseHandler<string>.Resposta(false, "resposta api bit criar registos", registoID);
}
}
catch (Exception e)
{
string classname = this.GetType().Name;
CentralLibrary.Services.ErrorLoggingService.ErrorLogsForCore(classname, e, _env.WebRootPath);
return ResponseHandler<string>.Resposta(true, "EXCEPTION : resposta api bit criar registos", e.Message);
}
Here is a better solution.
I had a problem with the last, but for someone who doesnt wnat to use de library RestClient that's the way. But this is working 100% and i have JsonProperty Names for NewtonSoft.Json so this workin with names like
[JsonProperty("z1D Action")]
public string z1D_Action { get; } = "CREATE";
so, my code is, and using an object AbrirRegistosITSM with nested object AbrirRegistosITSM_com_anexo my final solution is
AbrirRegistosITSM _registo = new AbrirRegistosITSM
{
Values = new AbrirRegistosITSM_com_anexo
{
Details = registos.Objeto.Comentario,
Customer_Login = registos.username,
Login_ID = registos.username,
SR_Type_Field_3 = registos.Objeto.Tipologia,
SR_Type_Field_28 = registos.Objeto.Categoria,
z2AF_WIAttachment1 = registos.Objeto.FicheiroNome
}
};
var client = new RestClient(Endpoint_CreateITSM);
string baseFolder = _env.WebRootPath;
string pathDir = Path.Combine(baseFolder, DateTime.Now.ToString().Replace('/', '_').Replace(' ', '_').Replace(':', '_'));
Directory.CreateDirectory(pathDir);
string pathDirFile = Path.Combine(pathDir, registos.Objeto.FicheiroNome);
File.WriteAllBytes(pathDirFile, Convert.FromBase64String(registos.Objeto.FicheiroBase64));
string pathEntryDir = Path.Combine(baseFolder, DateTime.Now.ToString().Replace('/', '_').Replace(' ', '_').Replace(':', '_'));
Directory.CreateDirectory(pathEntryDir);
string patnEntrydirFile = Path.Combine(pathEntryDir, "data_entry.txt");
File.WriteAllText(patnEntrydirFile, JsonConvert.SerializeObject(new { values = _registo.Values }));
var request = new RestRequest();
request.Method = Method.Post;
request.AddHeader("Authorization", token);
request.AddFile("entry", patnEntrydirFile, "application/json");
request.AddFile("attach-z2AF_WIAttachment1", pathDirFile, "application/octet-stream");
var reqbody = JsonConvert.SerializeObject(_registo);
request.AddParameter("application/json", reqbody, ParameterType.RequestBody);
RestResponse response = client.Execute(request);
var respostaBody = response.Content.ToString();//.ConfigureAwait(false);
dynamic _respostaBody = JsonConvert.DeserializeObject<dynamic>(respostaBody);
string _registoID = _respostaBody["values"]["Request Number"];
then i return the request number that what i need, but you have a lot of values there. I use NewtonSoft remember that. I dont use JsonSerializer because i wasn't able to save the json property names with spaces with JsonSerializer.
I'm not entirely sure what's going wrong here. It can be a lot of things, but I might be able to get you going. The last couple of weeks I build a HttpClient that sends a file with metadata to a GraphQL endpoint.
Please ensure the following:
I think you are requesting the file through an call. Please store it in a variable as a Byte[] using the ReadAsByteArrayAsync(). Do note decode it or cast it to a string or anything. You'll just corrupt the file.
var response = client.GetAsync(fileUrl);
var downloadedFile = await response.Result.Content.ReadAsByteArrayAsync();
The following code might not work entirely in your case, but should help you get going building the right request, since I'm also sending metadata in my request containing the file extension and some other information. This will most likely send the file to your API without a file extension.
using (var client = new HttpClient())
{
var file = new byte[] { 1, 2, 3 };
var fileToUpload = new ByteArrayContent(file);
var formData = new MultipartFormDataContent
{
{ fileToUpload, "entry", "passInFileExtensionForExample"},
{ fileToUpload, "attach-z2AF_WIAttachment1", "passInFileExtensionForExample" }
};
var response = await client.PostAsync("endpoint", formData);
}
Add the Bearer token using the following code:
client.DefaultRequestHeaders.Authorization = new AuthenticationHeaderValue("Bearer", accessToken);
So i've discover the solution for my problem. I'm gonna to submit only one file. I have to submit also the Json body as a file "entry" "data_entry.txt" and for HttpRequestMessage you have to have a content MultipartFormDataContent and here you can add as many files as you have. i have to convert the Json body to a file ( in this case i converted to binary Array) with the name entry, and the name of the file data_entry.txt, but it's what the endpoint needs, so...whatever.
using (var client = new HttpClient())
{
client.Timeout = TimeSpan.FromMinutes(10);
MultipartFormDataContent content = new MultipartFormDataContent();
//adicionar ficheiro
byte[] file_bytes = System.Convert.FromBase64String(registos.Objeto.fileEncoded);
StreamContent fileContent = new StreamContent(new MemoryStream(file_bytes));
fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "files[attach-z2AF_WIAttachment1]",
FileName = registos.Objeto.fileName
};
fileContent.Headers.ContentType = MediaTypeHeaderValue.Parse("application/octet-stream");
content.Add(fileContent);
//adicionar ficheiro entry
StreamContent entryStreamContent = new StreamContent(new MemoryStream(ObjectToByteArray(registos.Objeto.Registo)));
entryStreamContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "files[entry]",
FileName = "data_entry.txt"
};
entryStreamContent.Headers.ContentType = MediaTypeHeaderValue.Parse("application/json");
content.Add(entryStreamContent);
var request = new HttpRequestMessage
{
RequestUri = new Uri(Endpoint_CreateITSM),
Method = HttpMethod.Post,
Content= content
};
request.Headers.Add("Authorization", body.Result.ToString());
string json = JsonConvert.SerializeObject(new { values = registos.Objeto.Registo});
request.Content = new ByteArrayContent(Encoding.UTF8.GetBytes(json));
request.Content.Headers.ContentType = new MediaTypeHeaderValue("application/json");
var resposta = await client.SendAsync(request);
var respostaBody = resposta.Content.ReadAsStringAsync().Result.ToString();//.ConfigureAwait(false);
dynamic _respostaBody = JsonConvert.DeserializeObject<dynamic>(respostaBody);
string _registoID = _respostaBody["values"].SysRequestID;
return ResponseHandler<string>.Resposta(false, "resposta api bit criar registos", _registoID);
So this is my solution. and it's working :)

Upload video on Twitter without 3rd library

I use Hammock in the project and I want to upload videos to Twitter. I also get the "media type unrecognized" error when I try with the following code. Where part am I doing wrong?
var restClient = new Hammock.RestClient
{
Authority = "https://upload.twitter.com",
Encoding = Encoding.UTF8,
};
var restRequest = new Hammock.RestRequest
{
Credentials = credentials,
Path = "/1.1/media/upload.json",
Method = Hammock.Web.WebMethod.Post,
Encoding = Encoding.UTF8,
};
Stream stream = new MemoryStream(images);
restRequest.AddFile("media", "test", stream);
var asyncResult = restClient.BeginRequest(restRequest);
var response = restClient.EndRequest(asyncResult);
var jsonData = JsonConvert.DeserializeObject<Image>(response.Content);

Attaching pdf with sendGrid not working in c#

I have write a mail sending functionality using sendGrid in c#. It works properly but when attaching the generated pdf as attachement, it's not working.
var client = new SendGridClient(apiKey);
var msg = new SendGridMessage()
{
From = new EmailAddress(senderMailID, senderName),
Subject = "ABCD",
};
var attach = new Attachment();
attach.Filename = "ABC.pdf";
attach.Content = "~/Templates/output.pdf";
msg.AddAttachment(attach);
msg.AddTo(new EmailAddress(receiverMailID,receiverName));
var result = await client.SendEmailAsync(msg);
}
You should be converting the file to a base64 representation (as seen in examples here) of the file rather than adding a path to it.
A sample of the code needed:
var client = new SendGridClient(apiKey);
var msg = new SendGridMessage()
{
From = new EmailAddress(senderMailID, senderName),
Subject = "ABCD",
};
var bytes = File.ReadAllBytes("~/Templates/output.pdf");
var file = Convert.ToBase64String(bytes);
msg.AddAttachment("ABC.pdf", file);
var response = await client.SendEmailAsync(msg);

Upload audio file to server c#

How to upload audio file to server using HttpClient().
My audio file format is "testaudio.3gpp"
I want to do it using
await httpClient.PostAsync(uploadServiceBaseAddress, content);
Please suggest me the solution.
Full code below
string path = "sdcard/testaudio.3gpp";
var content = new MultipartFormDataContent();
var httpClient = new HttpClient();
var uploadServiceBaseAddress = "https://example.com/UploadaudioFile.aspx";
var httpResponseMessage = await httpClient.PostAsync(uploadServiceBaseAddress, content);
string resp = await httpResponseMessage.Content.ReadAsStringAsync();
I think stream content or something have to add into content variable.
How about something like:
string path = "sdcard/testaudio.3gpp";
var content = new MultipartFormDataContent();
var audioContent = new ByteArraycontent(System.IO.File.ReadAllBytes(path));
audioContent.Headers.ContentType = MediaTypeHeaderValue.Parse("audio/3gpp");
content.Add(audioContent, "audio", "testaudio.3gpp");
var httpClient = new HttpClient();
var uploadServiceBaseAddress = "https://example.com/UploadaudioFile.aspx";
var httpResponseMessage = await httpClient.PostAsync(uploadServiceBaseAddress, content);
string resp = await httpResponseMessage.Content.ReadAsStringAsync();

How to send a file and form data with HttpClient in C#

How can I send a file and form data with the HttpClient?
I have two ways to send a file or form data. But I want to send both like an HTML form. How can I do that? Thanks.
This is my code:
if (openFileDialog1.ShowDialog() == DialogResult.OK)
{
var client = new HttpClient();
var requestContent = new MultipartFormDataContent();
filename = openFileDialog1.FileName;
array = File.ReadAllBytes(filename);
var imageContent = new ByteArrayContent(array);
imageContent.Headers.ContentType = MediaTypeHeaderValue.Parse("audio/*");
requestContent.Add(imageContent, "audio", "audio.wav");
var values = new Dictionary<string, string>
{
{ "token", "b53b99534a137a71513548091271c44c" },
};
var content = new FormUrlEncodedContent(values);
requestContent.Add(content);
var response = await client.PostAsync("localhost", requestContent);
var responseString = await response.Content.ReadAsStringAsync();
txtbox.Text = responseString.ToString();
}
Here's code I'm using to post form information and a csv file
using (var httpClient = new HttpClient())
{
var surveyBytes = ConvertToByteArray(surveyResponse);
httpClient.DefaultRequestHeaders.Add("X-API-TOKEN", _apiToken);
httpClient.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));
var byteArrayContent = new ByteArrayContent(surveyBytes);
byteArrayContent.Headers.ContentType = MediaTypeHeaderValue.Parse("text/csv");
var response = await httpClient.PostAsync(_importUrl, new MultipartFormDataContent
{
{new StringContent(surveyId), "\"surveyId\""},
{byteArrayContent, "\"file\"", "\"feedback.csv\""}
});
return response;
}
This is for .net 4.5.
Note the \" in the MultipartFormDataContent. There is a bug in MultipartFormDataContent.
In 4.5.1 MultipartFormDataContent wraps the data with the correct quotes.
Update: This link to the bug no longer works since the have retired Microsoft Connect.
Here's code I'm using a method to send file and data from console to API
static async Task uploaddocAsync()
{
MultipartFormDataContent form = new MultipartFormDataContent();
Dictionary<string, string> parameters = new Dictionary<string, string>();
//parameters.Add("username", user.Username);
//parameters.Add("FullName", FullName);
HttpContent DictionaryItems = new FormUrlEncodedContent(parameters);
form.Add(DictionaryItems, "model");
try
{
var stream = new FileStream(#"D:\10th.jpeg", FileMode.Open);
HttpClient client = new HttpClient();
client.BaseAddress = new Uri(#"http:\\xyz.in");
HttpContent content = new StringContent("");
content.Headers.ContentDisposition = new ContentDispositionHeaderValue("form-data")
{
Name = "uploadedFile1",
FileName = "uploadedFile1"
};
content = new StreamContent(stream);
form.Add(content, "uploadedFile1");
client.DefaultRequestHeaders.Add("Authorization", "Bearer eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.dsfdsfdsfdsfsdfkhjhjkhjk.vD056hXETFMXYxOaLZRwV7Ny1vj-tZySAWq6oybBr2w");
var response = client.PostAsync(#"\api\UploadDocuments\", form).Result;
var k = response.Content.ReadAsStringAsync().Result;
}
catch (Exception ex)
{
}
}

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