How do you convert a string such as 2009-05-08 14:40:52,531 into a DateTime?
Since you are handling 24-hour based time and you have a comma separating the seconds fraction, I recommend that you specify a custom format:
DateTime myDate = DateTime.ParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff",
System.Globalization.CultureInfo.InvariantCulture);
You have basically two options for this. DateTime.Parse() and DateTime.ParseExact().
The first is very forgiving in terms of syntax and will parse dates in many different formats. It is good for user input which may come in different formats.
ParseExact will allow you to specify the exact format of your date string to use for parsing. It is good to use this if your string is always in the same format. This way, you can easily detect any deviations from the expected data.
You can parse user input like this:
DateTime enteredDate = DateTime.Parse(enteredString);
If you have a specific format for the string, you should use the other method:
DateTime loadedDate = DateTime.ParseExact(loadedString, "d", null);
"d" stands for the short date pattern (see MSDN for more info) and null specifies that the current culture should be used for parsing the string.
try this
DateTime myDate = DateTime.Parse(dateString);
a better way would be this:
DateTime myDate;
if (!DateTime.TryParse(dateString, out myDate))
{
// handle parse failure
}
Use DateTime.Parse(string):
DateTime dateTime = DateTime.Parse(dateTimeStr);
Nobody seems to implemented an extension method. With the help of #CMS's answer:
Working and improved full source example is here: Gist Link
namespace ExtensionMethods {
using System;
using System.Globalization;
public static class DateTimeExtensions {
public static DateTime ToDateTime(this string s,
string format = "ddMMyyyy", string cultureString = "tr-TR") {
try {
var r = DateTime.ParseExact(
s: s,
format: format,
provider: CultureInfo.GetCultureInfo(cultureString));
return r;
} catch (FormatException) {
throw;
} catch (CultureNotFoundException) {
throw; // Given Culture is not supported culture
}
}
public static DateTime ToDateTime(this string s,
string format, CultureInfo culture) {
try {
var r = DateTime.ParseExact(s: s, format: format,
provider: culture);
return r;
} catch (FormatException) {
throw;
} catch (CultureNotFoundException) {
throw; // Given Culture is not supported culture
}
}
}
}
namespace SO {
using ExtensionMethods;
using System;
using System.Globalization;
class Program {
static void Main(string[] args) {
var mydate = "29021996";
var date = mydate.ToDateTime(format: "ddMMyyyy"); // {29.02.1996 00:00:00}
mydate = "2016 3";
date = mydate.ToDateTime("yyyy M"); // {01.03.2016 00:00:00}
mydate = "2016 12";
date = mydate.ToDateTime("yyyy d"); // {12.01.2016 00:00:00}
mydate = "2016/31/05 13:33";
date = mydate.ToDateTime("yyyy/d/M HH:mm"); // {31.05.2016 13:33:00}
mydate = "2016/31 Ocak";
date = mydate.ToDateTime("yyyy/d MMMM"); // {31.01.2016 00:00:00}
mydate = "2016/31 January";
date = mydate.ToDateTime("yyyy/d MMMM", cultureString: "en-US");
// {31.01.2016 00:00:00}
mydate = "11/شعبان/1437";
date = mydate.ToDateTime(
culture: CultureInfo.GetCultureInfo("ar-SA"),
format: "dd/MMMM/yyyy");
// Weird :) I supposed dd/yyyy/MMMM but that did not work !?$^&*
System.Diagnostics.Debug.Assert(
date.Equals(new DateTime(year: 2016, month: 5, day: 18)));
}
}
}
I tried various ways. What worked for me was this:
Convert.ToDateTime(data, CultureInfo.InvariantCulture);
data for me was times like this 9/24/2017 9:31:34 AM
Try the below, where strDate is your date in 'MM/dd/yyyy' format
var date = DateTime.Parse(strDate,new CultureInfo("en-US", true))
Convert.ToDateTime or DateTime.Parse
DateTime.Parse
Syntax:
DateTime.Parse(String value)
DateTime.Parse(String value, IFormatProvider provider)
DateTime.Parse(String value, IFormatProvider provider, DateTypeStyles styles)
Example:
string value = "1 January 2019";
CultureInfo provider = new CultureInfo("en-GB");
DateTime.Parse(value, provider, DateTimeStyles.NoCurrentDateDefault););
Value: string representation of date and time.
Provider: object which provides culture specific info.
Styles: formatting options that customize string parsing for some date and time parsing methods. For instance, AllowWhiteSpaces is a value which helps to ignore all spaces present in string while it parse.
It's also worth remembering DateTime is an object that is stored as number internally in the framework, Format only applies to it when you convert it back to string.
Parsing converting a string to the internal number type.
Formatting converting the internal numeric value to a readable
string.
I recently had an issue where I was trying to convert a DateTime to pass to Linq what I hadn't realised at the time was format is irrelevant when passing DateTime to a Linq Query.
DateTime SearchDate = DateTime.Parse(searchDate);
applicationsUsages = applicationsUsages.Where(x => DbFunctions.TruncateTime(x.dateApplicationSelected) == SearchDate.Date);
Full DateTime Documentation
string input;
DateTime db;
Console.WriteLine("Enter Date in this Format(YYYY-MM-DD): ");
input = Console.ReadLine();
db = Convert.ToDateTime(input);
//////// this methods convert string value to datetime
///////// in order to print date
Console.WriteLine("{0}-{1}-{2}",db.Year,db.Month,db.Day);
You could also use DateTime.TryParseExact() as below if you are unsure of the input value.
DateTime outputDateTimeValue;
if (DateTime.TryParseExact("2009-05-08 14:40:52,531", "yyyy-MM-dd HH:mm:ss,fff", System.Globalization.CultureInfo.InvariantCulture, System.Globalization.DateTimeStyles.None, out outputDateTimeValue))
{
return outputDateTimeValue;
}
else
{
// Handle the fact that parse did not succeed
}
I just found an elegant way:
Convert.ChangeType("2020-12-31", typeof(DateTime));
Convert.ChangeType("2020/12/31", typeof(DateTime));
Convert.ChangeType("2020-01-01 16:00:30", typeof(DateTime));
Convert.ChangeType("2020/12/31 16:00:30", typeof(DateTime), System.Globalization.CultureInfo.GetCultureInfo("en-GB"));
Convert.ChangeType("11/شعبان/1437", typeof(DateTime), System.Globalization.CultureInfo.GetCultureInfo("ar-SA"));
Convert.ChangeType("2020-02-11T16:54:51.466+03:00", typeof(DateTime)); // format: "yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffzzz"
Put this code in a static class> public static class ClassName{ }
public static DateTime ToDateTime(this string datetime, char dateSpliter = '-', char timeSpliter = ':', char millisecondSpliter = ',')
{
try
{
datetime = datetime.Trim();
datetime = datetime.Replace(" ", " ");
string[] body = datetime.Split(' ');
string[] date = body[0].Split(dateSpliter);
int year = date[0].ToInt();
int month = date[1].ToInt();
int day = date[2].ToInt();
int hour = 0, minute = 0, second = 0, millisecond = 0;
if (body.Length == 2)
{
string[] tpart = body[1].Split(millisecondSpliter);
string[] time = tpart[0].Split(timeSpliter);
hour = time[0].ToInt();
minute = time[1].ToInt();
if (time.Length == 3) second = time[2].ToInt();
if (tpart.Length == 2) millisecond = tpart[1].ToInt();
}
return new DateTime(year, month, day, hour, minute, second, millisecond);
}
catch
{
return new DateTime();
}
}
In this way, you can use
string datetime = "2009-05-08 14:40:52,531";
DateTime dt0 = datetime.TToDateTime();
DateTime dt1 = "2009-05-08 14:40:52,531".ToDateTime();
DateTime dt5 = "2009-05-08".ToDateTime();
DateTime dt2 = "2009/05/08 14:40:52".ToDateTime('/');
DateTime dt3 = "2009/05/08 14.40".ToDateTime('/', '.');
DateTime dt4 = "2009-05-08 14:40-531".ToDateTime('-', ':', '-');
String now = DateTime.Now.ToString("YYYY-MM-DD HH:MI:SS");//make it datetime
DateTime.Parse(now);
this one gives you
2019-08-17 11:14:49.000
Different cultures in the world write date strings in different ways. For example, in the US 01/20/2008 is January 20th, 2008. In France this will throw an InvalidFormatException. This is because France reads date-times as Day/Month/Year, and in the US it is Month/Day/Year.
Consequently, a string like 20/01/2008 will parse to January 20th, 2008 in France, and then throw an InvalidFormatException in the US.
To determine your current culture settings, you can use System.Globalization.CultureInfo.CurrentCulture.
string dateTime = "01/08/2008 14:50:50.42";
DateTime dt = Convert.ToDateTime(dateTime);
Console.WriteLine("Year: {0}, Month: {1}, Day: {2}, Hour: {3}, Minute: {4}, Second: {5}, Millisecond: {6}",
dt.Year, dt.Month, dt.Day, dt.Hour, dt.Minute, dt.Second, dt.Millisecond);
This worked for me:
CultureInfo provider = CultureInfo.InvariantCulture;
DateTime dt = DateTime.ParseExact("2009-05-08 14:40:52,531","yyyy-MM-dd HH:mm:ss,fff", provider);
Do you want it fast?
Let's say you have a date with format yyMMdd.
The fastest way to convert it that I found is:
var d = new DateTime(
(s[0] - '0') * 10 + s[1] - '0' + 2000,
(s[2] - '0') * 10 + s[3] - '0',
(s[4] - '0') * 10 + s[5] - '0')
Just, choose the indexes according to your date format of choice. If you need speed probably you don't mind the 'non-generic' way of the function.
This method takes about 10% of the time required by:
var d = DateTime.ParseExact(s, "yyMMdd", System.Globalization.CultureInfo.InvariantCulture);
I'm using Infragisitics 17.1 UltraGrid.
The Grid has 2 columns.
I want the formatted string of the second column, just like below.
'20170102123456' => '2017-01-02 12:34:56"
The data type of the second column is 'string' not 'date'.
This grid will have huge data, so any conversion is worry to me.
But any adive is welcome.
DataSoure just like below.
private void SetTestData()
{
DataTable dtDataSource = new DataTable("table1");
dtDataSource.Columns.Add("OrderDate", typeof(DateTime));
dtDataSource.Columns.Add("RequiredDate", typeof(string));
ultraGrid1.DataSource = dtDataSource;
DataRow rowNew = dtDataSource.NewRow();
rowNew["OrderDate"] = DateTime.Now;
rowNew["RequiredDate"] = "20170101123456";
dtDataSource.Rows.Add(rowNew);
}
And I Initialize Grid Just like below,
private void UltraGrid1_InitializeLayout(object sender, Infragistics.Win.UltraWinGrid.InitializeLayoutEventArgs e)
{
// Fit columns
e.Layout.AutoFitStyle = AutoFitStyle.ExtendLastColumn;
// Set date formats
e.Layout.Bands[0].Columns["OrderDate"].Format = "yyyy-MM-dd HH:mm:ss";
e.Layout.Bands[0].Columns["RequiredDate"].Format = "yyyy-MM-dd HH:mm:ss";
}
The first column works fine, but the second column does not.
How i can display the second column just like below?
'20170102123456' => '2017-01-02 12:34:56"
UltraGrid will not be able to do this conversation alone. What you can do in this specific case is implement your own custom IEditorDataFilter. To do so change your InitializeLayuot like this:
private void UltraGrid1_InitializeLayout(object sender, InitializeLayoutEventArgs e)
{
// Fit columns
e.Layout.AutoFitStyle = AutoFitStyle.ExtendLastColumn;
// Set date formats
e.Layout.Bands[0].Columns["OrderDate"].Format = "yyyy-MM-dd HH:mm:ss";
// You do not need this as the column data type is string
//e.Layout.Bands[0].Columns["RequiredDate"].Format = "yyyy-MM-dd HH:mm:ss";
// Set the column's editor DataFilter instead
e.Layout.Bands[0].Columns["RequiredDate"].Editor.DataFilter = new DF();
}
Then create your custom DataFilter like this:
internal class DF : IEditorDataFilter
{
public object Convert(EditorDataFilterConvertArgs conversionArgs)
{
switch(conversionArgs.Direction)
{
case ConversionDirection.DisplayToEditor:
break;
case ConversionDirection.EditorToDisplay:
var valueAsString = conversionArgs.Value.ToString();
var year = int.Parse(valueAsString.Substring(0, 4));
var month = int.Parse(valueAsString.Substring(4, 2));
var day = int.Parse(valueAsString.Substring(6, 2));
var hours = int.Parse(valueAsString.Substring(8, 2));
var minutes = int.Parse(valueAsString.Substring(10, 2));
var result = new DateTime(year, month, day, hours, minutes, 0).ToString("yyyy-MM-dd HH:mm:ss");
conversionArgs.Handled = true;
conversionArgs.IsValid = true;
return result;
case ConversionDirection.OwnerToEditor:
break;
case ConversionDirection.EditorToOwner:
break;
default:
break;
}
return conversionArgs.Value;
}
}
private void btntest_Click(object sender, EventArgs e)
{
DateTime d = new DateTime(2016,2,13);
LunarDate ld1 = LunarYearTools.SolarToLunar(d);
lblamlich.Text = (ld1.ToString());
}
Note DateTime d = new DateTime(Int year,Int month,Int day)
How to insert datetimepicker's value into new DateTime(2016,2,13) ???
I tried use casting datetime to Int but it didn't work:
string a = dateTimePicker1.Value.ToString();
int b = (int)(a);
DateTime d = new DateTime(b);
LunarDate ld1 = LunarYearTools.SolarToLunar(d);
lblamlich.Text = (ld1.ToString());
If I have understood you correctly, it should be as simple as this:
var d = dateTimePicker1.Value;
var newD = new DateTime(d.Year, d.Month, d.Day);
The DateTimePicker.Value property is already a DateTime. Just reference it:
DateTime d = dateTimePicker1.Value;
If you're only interested in the date and wish to ignore the time, use the DateTime.Date property:
DateTime d = dateTimePicker1.Value.Date;
I want to compare dates. One date will be hard coded other will be picked from system.
My code is giving formatting error in this line:
string iStringdate = "05-05-2015";
DateTime oDate = DateTime.ParseExact(iStringdate, "dd-mm-yyyy", null);
Complete code:
private void button1_Click(object sender, EventArgs e)
{
string iStringdate = "05-05-2015";
DateTime oDate = DateTime.ParseExact(iStringdate, "dd-mm-yyyy", null);
//MessageBox.Show(oDate.ToString());
string iStringtime = "10:12 pm";
DateTime oTime = DateTime.ParseExact(iStringtime, "HH:mm tt", null);
//MessageBox.Show(oTime.ToString());
DateTime time = DateTime.Now;
DateTime date = DateTime.Today;
if (oDate < date)
{
Console.WriteLine("successfull");
}
else {
Console.WriteLine("fail");
}
}
Also how can I just get the system date and not the system time along with it?
Where am I wrong?
"mm" stands for minutes while "MM" means months.
DateTime.ParseExact(iStringdate, "dd-MM-yyyy", null);
Click here for a complete list of date formatting options.
And DateTime.Now returns the date and time, while DateTime.Today returns the current date and 00:00:00 as time.
I have date represented as integer like 20140820 and I want to parsing it as datetime, like 2014.08.20.
Do I need to parse each integer value (2014)(08)(02) using index or is there simpler way?
If your CurrentCulture supports yyyyMMdd format as a standard date and time format, you can just use DateTime.Parse method like;
int i = 20140820;
DateTime dt = DateTime.Parse(i.ToString());
If it doesn't support, you need to use DateTime.ParseExact or DateTime.TryParseExact methods to parse it as custom date and time format.
int i = 20140820;
DateTime dt;
if(DateTime.TryParseExact(i.ToString(), "yyyyMMdd",
CultureInfo.InvariantCulture,
DateTimeStyles.None, out dt))
{
Console.WriteLine(dt);
}
Then you can format your DateTime with .ToString() method like;
string formattedDateTime = dt.ToString("yyyy.MM.dd", CultureInfo.InvariantCulture);
The easiest and most performance way would be something like:
int date = 20140820;
int d = date % 100;
int m = (date / 100) % 100;
int y = date / 10000;
var result = new DateTime(y, m, d);
Try This :-
string time = "20140820";
DateTime theTime= DateTime.ParseExact(time,
"yyyyMMdd",
CultureInfo.InvariantCulture,
DateTimeStyles.None);
OR
string str = "20140820";
string[] format = {"yyyyMMdd"};
DateTime date;
DateTime.TryParseExact(str,
format,
System.Globalization.CultureInfo.InvariantCulture,
System.Globalization.DateTimeStyles.None,
out date))
now date variable will have required converted date of string '20140820'
int sampleDate = 20140820;
var dateFormat = DateTime.ParseExact(sampleDate.ToString(), "yyyyMMdd",
CultureInfo.InvariantCulture).ToString("yyyy.MM.dd");
result:
2014.08.20
So, we have two competing implementations,
using System;
using System.Globalization;
public class Program
{
public static void Main()
{
int i = 20140820;
Console.WriteLine($"StringParse:{StringParse.Parse(i)}");
Console.WriteLine($"MathParse:{MathParse.Parse(i)}");
}
}
public static class StringParse
{
public static DateTime Parse(int i)
{
return DateTime.ParseExact(
i.ToString().AsSpan(),
"yyyyMMdd".AsSpan(),
CultureInfo.InvariantCulture);
}
}
public static class MathParse
{
public static DateTime Parse(int i)
{
return new DateTime(
Math.DivRem(Math.DivRem(i, 100, out var day), 100, out var month),
month,
day);
}
}
The string approach is probably safer and probably handles edge cases better.
Both will be fast and unlikely to be a performance bottle neck but it is my untested assertion that the math approach probably has better performance.